Name of the table to find the workbook columns

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  Column of Outlook Express folder in find

  When Outlook Express 6 detects emails from a name in the right column indicates the folder in which it is in. How can you tell which folder this folder is located in?

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• I want to get only year sysdate with my name of the defined column. but not able to get it.

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  Hi guys Cela made some time.

  I am trying to add several *.csv files while retaining the original file name in the first column, the real data set is about 40 cases.

  file a.csv contains:
  1, line an a.csv
  2, line 2 in a.csv

  file b.csv contains:
  1, line a b.csv
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  Can I have a column name variable for a text box, such as this one source
  
  Select (: P2_column_name) of the budget where id =: P2_id;
  
  I get the: P2_column_name variable and not really the content of the column.
  what I am doing wrong, thank you, Doug

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  Webster, TX

  I cried because I don't have an office with a door until I met a man who had no cubicle.
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• Return all column names of the cells that match a value in a single cell

  

  I want to be able to scan all the cells in column 1 in column 3 (there could be several) which belong to the same line and check if they all have a value y (X). If they have no value, I want all columns to display all the names of the matching columns as follows: "column 1, column 2" for Elemento.

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  B2 = if (counta (C2) > 0, C$ 1, "" ") & IF (COUNTA (D2) > 0', ' & D$ 1," ") & IF (COUNTA (E2) > 0', ' & E$ 1," "") & IF (COUNTA (F2) > 0', '& F$ 1,' ')

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  = IF (counta (C2) > 0, C$ 1, "" ") & IF (COUNTA (D2) > 0', ' & D$ 1," ") & IF (COUNTA (E2) > 0', ' & E$ 1," "") & IF (COUNTA (F2) > 0', '& F$ 1,' ')

  Select cell B2, copy

  Select the cells B2 the bottom of column D, dough

  To add additional columns, you copy the atomic unit:

  & IF (COUNTA (D2) > 0', '& D$ 1,' ')

  and update D2 with the new column and D$ 1 with the new column.

  then... If you add a new column (G, for example) that you want to change it:

  and IF (COUNTA (D2) > 0', '&D$1,' ')

  TO

  and IF (COUNTA (G2) > 0', "&G$1," ")

  and the updated formula would be:

  = IF (counta (C2) > 0, C$ 1, "" ") & IF (COUNTA (D2) > 0', ' & D$ 1," ") & IF (COUNTA (E2) > 0', ' & E$ 1," "") & IF (COUNTA (F2) > 0', ' & F$ 1,"") & IF (COUNTA (G2) > 0', '& G$ 1,' ')

  fill down like before

• Get the name of the column of row

  All,
  
  In my Jdev 11.1.2 app I want to know the name of the attribute column that is modified. I am able to get the attribute name that currently use the getAttrbute() on the line (if you open the VO we see name |) Type of | Column, etc.). How can I get the name of the column?
  
  For example: the name of the attribute is Nom_tiers, column name can be Party_Name. I am able to do Nom_tiers but not Party_Name.
  
  thnks
  
  Published by: in the line of fire on 14 December 2011 14:13

  getEntityAttrForAttribute("attribute_name_here").getColumnName)

• Display the role name in the field "descriptive data.

  Hello
  
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  Help, please.
  Kind regards.

  The role name field is available in the form of process? If Yes, go to design console open your definition of process and then click descriptive field map select role name.

• Validate the XML column when inserting

  Hello

  I'm on 11 GR 2.

  I have a table

  create table root_table (id number, text xmltype);

  I tried to sign up:

  Start

  dbms_xmlschema.registerSchema ('test', xmltype)

  "' < xs: schema xmlns: XS ="http://www.w3.org/2001/XMLSchema"xmlns:xdb ="http://xmlns.oracle.com"elementFormDefault ="unqualified">

  < name XS: complexType 'RootType' = >

  < xs: SEQUENCE >

  < xs: element name = "Required" / >

  < xs: element name = "Énumération" >

  < xs:simpleType >

  < xs:restriction base = "XS: String" >

  < xs:enumeration value = 'A' / >

  < xs:enumeration value = 'B' / >

  < xs:enumeration value = 'C' / >

  < / xs:restriction >

  < / xs:simpleType >

  < / xs: element >

  < xs: element name = "MinLength" >

  < xs:simpleType >

  < xs:restriction base = "XS: String" >

  < xs:minLength value = "4" / >

  < xs:maxLength value = "20" / >

  < / xs:restriction >

  < / xs:simpleType >

  < / xs: element >

  < xs: element name = "MaxLength" >

  < xs:simpleType >

  < xs:restriction base = "XS: String" >

  < xs:minLength value = "1" / >

  < xs:maxLength value = "4" / >

  < / xs:restriction >

  < / xs:simpleType >

  < / xs: element >

  < xs: element name = "MaxOccurs" type = "xs: String" maxOccurs = "2" / >

  < xs: element name = "MinOccurs" minOccurs = '2' maxOccurs = "2" / >

  < xs: element name = "Optional" type = "xs: String" minOccurs = "0" / >

  < / xs: SEQUENCE >

  < / xs: complexType >

  < xs: element name = "root" type = "RootType" xdb:defaultTable = "ROOT_TABLE" / >

  ((< / xs: Schema > '));

  end;

  /

  table should point to the table where the XML column is default, I guess that

  is the 'root' in the same line a reference to the name of the xmltype column?

  Now - how do I ensure the XML I have insert in the column "change" is validated against the schema above?

  concerning

  Mette

  
  

  For both options, save the diagram with these options (you can substitute the url of course):

  Start

  () dbms_xmlschema.registerSchema

  schemaURL-online "test.xsd.

  schemaDoc-online xmltype (bfilename ('TEST_DIR', 'test.xsd'), 873)

  local-online true

  genTypes-online fake

  genTables-online fake

  enableHierarchy-online dbms_xmlschema. ENABLE_HIERARCHY_NONE

  options-online dbms_xmlschema. REGISTER_BINARYXML

  );

  end;

  /

  Then the #1 option:

  create table root_table)

  Identification number

  text xmltype

  )

  XMLType column can store as xml binary securefile

  XmlSchema 'test.xsd' element 'root '.

  ;

  SQL > insert into root_table values (1,

  2 xmlparse (document

  3'

  4

  5    A

  6 XXXX

  7 12345

  8

  9

  10

  11  ')

  (12);

  insert into root_table values (1,

  *

  ERROR on line 1:

  ORA-31061: error XDB: XML error event

  ORA-19202: an error has occurred in the processing of XML

  LSX-00222: "12345" is too long (maximum is 4)

  SQL >

  SQL > insert into root_table values (1,

  2 xmlparse (document

  3'

  4

  5    A

  6 XXXX

  7 1234

  8

  9

  10

  11 ')

  (12);

  insert into root_table values (1,

  *

  ERROR on line 1:

  ORA-31061: error XDB: XML error event

  ORA-19202: an error has occurred in the processing of XML

  LSX-00213: only 1 occurrences of the 'MinOccurs' particle, the minimum is 2

  SQL > insert into root_table values (1,

  2 xmlparse (document

  3'

  4

  5    D

  6 XXXX

  7 1234

  8

  9

  10

  11

  12  ')

  (13);

  insert into root_table values (1,

  *

  ERROR on line 1:

  ORA-31061: error XDB: XML error event

  ORA-19202: an error has occurred in the processing of XML

  LSX-00290: invalid enumeration choice "D".

  SQL > insert into root_table values (1,

  2 xmlparse (document

  3'

  4

  5    A

  6 XXXX

  7 1234

  8

  9

  10

  11

  12  ')

  (13);

  1 line of creation.

  For the #2 option:

  create table root_table2)

  Identification number

  text xmltype

  )

  XMLType column can store it as clob securefile

  ;

  create or replace trigger root_table2_biu_t

  before the insert or update

  on root_table2

  for each line

  declare

  doc xmltype: =: new.tekst.createSchemaBasedXML ('test.xsd');

  Start

  doc.schemaValidate ();

  end;

  /

  SQL > insert into root_table2 values (1,

  2 xmlparse (document

  3'

  4

  5    D

  6 XXXX

  7 1234

  8

  9

  10

  11

  12  ')

  (13);

  insert into root_table2 values (1,

  *

  ERROR on line 1:

  ORA-31154: invalid XML document

  ORA-19202: an error has occurred in the processing of XML

  LSX-00290: invalid enumeration choice "D".

  ORA-06512: at "SYS." XMLTYPE", line 354

  ORA-06512: at DEV. "" ROOT_TABLE2_BIU_T ", line 4

  ORA-04088: error during execution of trigger ' DEV. ROOT_TABLE2_BIU_T'

  Both options will perform a validation of strict type.

  There are other possible configurations, such as CLOB based on a storage schema, but this approach is now obsolete.

  If you are only interested in whether the XML instance is valid or not, you can also use a constraint check with the XMLisValid function.

• Stored in the BLOB column display PDF problem

  Hello everyone.
  
  I tried to follow this tutorial http://asktom.oracle.com/pls/asktom/f?p=100:11:0:p11_question_id:232814159006 on the display of PDF files stored in BLOB columns. This is done on Apex 4.2, with my DB 11 g running. I have my procedure, which I will post below:
  

  create or replace procedure "PDF" (p_id IN gvo_documents.doc_id%type)
  is
      l_lob    blob;
      l_amt    number default 30;
      l_off   number default 1;
      l_raw   raw(4096);
  begin
      select contents into l_lob
          from gvo_documents 
           where doc_id = p_id;
  
   -- make sure to change this for your type!
      owa_util.mime_header( 'application/pdf' );
  
  
      begin
          loop
            dbms_lob.read( l_lob, l_amt, l_off, l_raw );
            htp.prn( utl_raw.cast_to_varchar2( l_raw ) );
            l_off := l_off+l_amt;
            l_amt := 4096;            
      end loop;
          exception
             when no_data_found then 
                NULL;
          end;
  
  end;
  

  I am trying to run this through a region dynamic PL/SQL, and even if I don't get any error, the content displayed is a huge mess of truncated text and strange characters. I tried to run this procedure on many other types of documents, including word and jpeg image files, all with the necessary changes in my inside, and regardless of what I use, I always get a big mess of strange characters. Does anyone have information or ideas why this is happening?

  If I understand correctly, your needs must be broken down into two problems:
  1) click the link that opens a window showing a new APEX page
  (2) an APEX page displays the document, download it not.

  I did not (yet) #1.
  However, you can generate a URL that points to the new page in the select for the report.

  It's a related issue, but no response yet:
  Open the pdf file in the browser window

  The key is to target = "_blank" to the anchor tag.
  To generate the URL, you must use the APEX_UTIL.prepare_URL () function.

  If this does not work, a dynamic Action that makes magical things of JavaScript may be necessary.

  # 2, I lost the URL that showed how to display a PDF file in a page "form.
  From what I remember:
  Start with a blank page with a pristine area of HTML (all items will in the HTML area)
  Add an element to the PK/annual
  part I forgot Create a Data Manipulation process
  -Automated row Fetch
  -By loading - after the header
  -(stuff for your table/view)
  part I forgot Create a (I think) "File browser" item type. For the parameters:
  -Storage of Type "BLOB column specified in the Source element" (and put the name of the BLOB column)
  -MIME Type column: (column name) - since there are several types, this is a MUST HAVE
  -Filename column: (column name) - I highly recommend you have this.
  -Provision of content is INLINE<-- this="" is="" the="">

  In addition, you will need a browser for each of the Types MIME Plugin (if not, the browser may try to "Download" the file)
  Browsers can manage the types of images internally. Plugin Adobe can handle PDF files. I do not know Word/Excel.

  Yet once again, I don't remember the exact details, but that should cover most of it.

  MK

• Rename the FK columns

  In the Data Modeler, a FK column takes its name from the name of the associated column in the PK.
  
  Is there a way to display the name of the FK column to something else?
  
  For example, table emp a PK emp_id. If I create a FK to dept to represent the Director of this Department, the FK column is called emp_id. I call it mgr_emp_id.

  Go to tools - > Preferences-> Data Modeler-> logic-> FK attribute synchronization and uncheck the option name. Now, you can replace the name of column gene4rated with your name mentioned.

• Combine the two columns of text

  I have two columns of text (say that name is a column and the name is the other)

  I would like to combine the two columns for the text of these two columns are in a column. (First name and last name in the same column)

  Is this possible? If so is there a tutorial somewhere?

  Hi Danielle,

  The & (concatenation operator) is your friend.

  

  Formula in D2 (fill down)

  "B2 &" "& C2.

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  "" inserts a space.

  Kind regards

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• Find the name of the column in all tables

  How to find the name of the column in all tables in the database for any column to reveal the name of the person?

  
  We have over 1000 tables looking for.and in some places, the name column FNAME LNAME, First_NAME, DNAME

  For example we have Customer table, Table EMPLOYEE and the ORDER Table

  --------------------------------

  Customer table
  --------------------------------

  LNMAE

  EMPLOYEE table

  EMP_ID
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  Last_name (he must propose this column because it is named)

  ----------------------------

  CONTROL Panel

  -----------------------------

  ORDER_ID
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  Last_name (he must propose this column because it is named)

  -------------------------

  Dept table

  -------------------------

  Dept_ID
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  Please advise...

  Thank you.

  Hello

  What exactly do you do?

  If you want to display the tables containing these columns, you can query the view data dictionary USER_TAB_COLS (or ALL_TAB_COLS, or, if you have privileges, DBA_TAB_COLS).

  For example:

  SELECT table_name, column_name

  Of user_tab_cols

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  ;

• Find the name and the table constraint type based on the name of the field

  I have a field name or a column with me... I want to find the name of the table is a primary key... Any request to make this work so that the running costs are low...

  Currently, I mix dba_constraints and ALL_TAB_COLUMNS to get this... is possible to extract the data of a process cost effective single table/any other is appreciated

  You must include the USER/ALL_CONSTRAINTS with USER/ALL_CONS_COLUMNS to achieve your desired results. For your specific condition, you can try this query.

  Select constraint_name

  column_name

  de)

  Select c.constraint_name

  cc.column_name

  count on column_count (c.constraint_name score) (cc.column_name)

  from user_constraints c

  Join user_cons_columns cc

  on c.constraint_name = cc.constraint_name

  where constraint_type = 'P '.

  )

  where column_name = 'EMPNO '.

  and column_count = 1;

  I used USER_CONSTRAINTS and USER_CONS_COLUMNS. If you use ALL or DBA dictionary table add join OWNER condition as well.

• cannot find the table name of the multiple tables which has more columns.

  Hello
  
  I'm trying to find the NAME of the TABLE from multiple tables which has more columns. I can't count the number of columns in the table, but cannot find the name of the table that has larger columns in other tables.
  
  SELECT TABLE_NAME, COUNT (*) FROM THE USER_TAB_COLUMNS WHERE TABLE_NAME LIKE '% LOC' GROUP TABLE_NAME
  
  
  Thank you.

  in SQL, you can try this:

  var v_name varchar2(40)
  
  begin
     with
        subq1 as ( select table_name, count(*) as column_count from user_tab_columns where table_name like 'FIBER%'
                       group by table_name
                       order by count(*) desc )
     select table_name
       into :v_name
      from subq1
     where rownum = 1;
  end;
  

  To get the result:

  select :v_name from dual
  

  The clause "with" brings together all the tables and ordered them all first, by the greatest number of columns
  The final query uses the rownum restriction so that it takes the first name from the table of results of the subquery.

  The restriction of rownum also exactly guarantees a result each time so that it will work with the variable binding.

  RP