name.table in ODI datastore schema name

Similar Questions

• How to find the same column name in different tables in the same schema

  Hello
  
  I find the 'ename' column name in different tables in the same schema.
  
  Thank you
  Nr

  Hello

  Try this query

  Select column_name, table_name from user_tab_columns where column_name = 'ENAME ';

  Award points and end the debate, if your question is answered or mark if she was...

  Kind regards

  Lacouture.

• Join of two tables in two different schemas

  Hi all
  
  I have an obligation to join two tables on two different schemas. How to join these two tables in the object view.
  
  Thanks in advance.
  
  Concerning
  Kaushik Guillaumin

  You can do just that using schema name in the +' view object.table name ' + according to the query object and also grant select the another schema to this schema user

  ex
  you need schem is test and another Act you need to a view object based on the test to join a table on shcema Act

  you write semply object sql view code:

  Act.table name

  and you can also give him select statement on Bill schem table to test

  concerning

• How can find data in a colum prj_no in all the table of the same schema

  Hi all
  
  I find the list of tables with data that has prj_no = "Axis_11" for all tables in the same schema.
  
  
  
  Thank you
  Nr

  PNR wrote:
  I find the list of tables with data that has prj_no = "Axis_11" for all tables in the same schema.

  1. find the tables with a column of PRJ_NO name. You can find it in USER_TAB_COLUMNS
  2 write a query to read the data in each table, using the UNION/UNION ALL operators to merge the results for each table

• Moved to subpartitions in a table doubles in another schema.

  + NOTE: I asked this question on the forum SQL and PL/SQL , but came here as I think it is more appropriate to this forum. I placed a pointer to this post on the original post. +
  
  Hello ladies and gentlemen.
  
  We are currently involved in an exercise on my place of work where we're trying to logically organize our data by world region. For more information, our database of production is currently at version 10.2.0.3 and will soon become 10.2.0.5.
  
  For the moment, all our data "lives" in the same schema. We are trying to produce a proof of concept to migrate this data to the identically structured (and named) tables in separate database schemas. Each schema to represent a world region.
  
  In our current schema, our data are partitioned to date range and then list partitioned on a column named OFFICE. I want to spend the subpartitions of OFFICE of a schema in a same table named and structured in a new scheme. The tablespace will remain the same for the two tables with the same name in the two schemas.
  
  Any of you have an opinion on the best way to do it? Ideally in the new scheme, I would like to create each table an empty array with the appropriate range and list partitions that are defined. I did a few tests in our development environment with the EXCHANGE PARTITION statement, but this needs to be non partitioned, the destination table.
  
  I was wondering if, for the migration of partition in all drawings bearing the name of the table and tablespace remains constant, there is a formal method of 'best practices' to accomplish such a move subpartition cleanly, quickly and elegantly?
  
  Welcome any helpful response.
  
  See you soon.
  
  James

  You CAN exchange a subpartition in another table by using a 'temporary' (intermediate) as an intermediate table.

  See:

  SQL> drop table part_subpart purge;
  
  Table dropped.
  
  SQL> drop table NEW_part_subpart purge;
  
  Table dropped.
  
  SQL> drop table STG_part_subpart purge;
  
  Table dropped.
  
  SQL>
  SQL> create table part_subpart(col_1  number not null, col_2 varchar2(30))
    2  partition by range (col_1) subpartition by list (col_2)
    3  (
    4  partition p_1 values less than (10) (subpartition p_1_s_1 values ('A'), subpartition p_1_s_2 values ('B'), subpartition p_1_s_3 values ('C'))
    5  ,
    6  partition p_2 values less than (20) (subpartition p_2_s_1 values ('A'), subpartition p_2_s_2 values ('B'), subpartition p_2_s_3 values ('C'))
    7  )
    8  /
  
  Table created.
  
  SQL>
  SQL> create index part_subpart_ndx on part_subpart(col_1) local;
  
  Index created.
  
  SQL>
  SQL>
  SQL> insert into part_subpart values (1,'A');
  
  1 row created.
  
  SQL> insert into part_subpart values (2,'A');
  
  1 row created.
  
  SQL> insert into part_subpart values (2,'B');
  
  1 row created.
  
  SQL> insert into part_subpart values (2,'B');
  
  1 row created.
  
  SQL> insert into part_subpart values (2,'C');
  
  1 row created.
  
  SQL> insert into part_subpart values (11,'A');
  
  1 row created.
  
  SQL> insert into part_subpart values (11,'C');
  
  1 row created.
  
  SQL>
  SQL> commit;
  
  Commit complete.
  
  SQL>
  SQL> create table NEW_part_subpart(col_1  number not null, col_2 varchar2(30))
    2  partition by range (col_1) subpartition by list (col_2)
    3  (
    4  partition n_p_1 values less than (10) (subpartition n_p_1_s_1 values ('A'), subpartition n_p_1_s_2 values ('B'), subpartition n_p_1_s_3 values ('C'))
    5  ,
    6  partition n_p_2 values less than (20) (subpartition n_p_2_s_1 values ('A'), subpartition n_p_2_s_2 values ('B'), subpartition n_p_2_s_3 values ('C'))
    7  )
    8  /
  
  Table created.
  
  SQL>
  SQL> create table STG_part_subpart(col_1  number not null, col_2 varchar2(30))
    2  /
  
  Table created.
  
  SQL>
  SQL> -- ensure that the Staging table is empty
  SQL> truncate table STG_part_subpart;
  
  Table truncated.
  
  SQL> -- exchanging a subpart out of part_subpart
  SQL> alter table part_subpart exchange subpartition
    2  p_2_s_1 with table STG_part_subpart;
  
  Table altered.
  
  SQL> -- exchanging the subpart into NEW_part_subpart
  SQL> alter table NEW_part_subpart exchange subpartition
    2  n_p_2_s_1 with table STG_part_subpart;
  
  Table altered.
  
  SQL>
  SQL>
  SQL> select * from NEW_part_subpart subpartition (n_p_2_s_1);
  
       COL_1 COL_2
  ---------- ------------------------------
          11 A
  
  SQL>
  SQL> select * from part_subpart subpartition (p_2_s_1);
  
  no rows selected
  
  SQL>
  

  I traded subpartition p_2_s_1 out of the part_subpart table in the NEW_part_subpart table - even with a different name for the subpartition (n_p_2_s_1) If you wish.

  NOTE: because the source and target tables are in different schemas, you need to move (or copy) the intermediate table STG_part_subpart from the schema of the first towards the second scheme after that first "Exchange subpartition' is done. You will need to do this for each subpartition to Exchange.

  Hemant K Collette

  Published by: Hemant K deal April 4, 2011 10:19
  Added details for cross-schema exchange.

• Compare the table structures in different schemas. help please

  Hi all
  
  I have a question...
  
  
  I have pictures on different schemas something like
  
  
  Diagram A
  -------------
  Table 1
  Table 2
  Table 3
  
  
  Diagram B
  ------------
  Table 1
  Table 2
  Table 3
  
  
  Now situation is table 1 and table 2 will have a similar structure or table 1 in Figure B will have additional columns.
  
  like so... on... for all other tables...
  
  example!
  

  Schema A:
  
  Desc Table 1;
  
  Name                                  Type            Null
  -------------                             -------             -------
  No                                Number            Notnull
  Name                           Varchar2(10)     Not null
  Fee                              Number (10,2)   Not null
  
  
  
  Scheam B;
  
  Desc Table1;
  
  Name                                  Type               Null
  -------------                             -------             -------
  DX_No                                Number            Notnull
  DX_Name                           Varchar2(10)      Not null
  DX_Fee                              Number (10,2)   Not null
  comments                          Varchar(2)        

  Now I need to write some sort of procedure for the thing to compare these tables which are in different in the column names in the schema and get it had exported to an Excel sheet.
  and here it's first three columns SHOULD BE CONSIDERED AS SAME even if the DX_ prefix are from the REST OF the PART OF THE COLUMN NAME IS SAME.
  
  and the same way commit coloumn new schema B only... So it should be noted that excel sheets...
  
  I don't know how the ADO or SQL Developer handle this... Is there any plsql block that I can write to do it...
  
  Thanks in advance...

  Comparison of columns on all the tables in the two schema

  select tc1.owner,tc1.TABLE_NAME,tc1.COLUMN_NAME,
         tc2.owner,tc2.TABLE_NAME,tc2.COLUMN_NAME
  from
    all_tab_columns tc1
    full outer
    join all_tab_columns tc2 on &user1=tc2.owner
                             and tc1.TABLE_NAME=tc2.TABLE_NAME
                             and tc1.COLUMN_NAME like '%'||tc2.COLUMN_NAME
  where
  tc1.owner=&user2
  and tc1.TABLE_NAME in (
                        select t1.table_name
                        from all_tables t1
                        join all_tables t2 on t2.owner=&user2 and t1.table_name=t2.table_name
                        where t1.owner=&user1)
  

  Published by: xtender on 06.11.2010 12:43

• ODI Datastore length differs with the length DB - IKM throws value too large

  ODI datastore when reverse engineering a different length than the datalength in actual db.
  
  The Datastore ODI column details: tank (44)
  Column db target: varchar2 (11 char)
  
  The I$ table inserts char44 in varchar2 (11char) in the target. As the value of the source column is empty ODI throws
  "ORA-12899: value too large for column (size: 44, maximum: 11)."

  You must always include the ODI version you are using.

  I assume that you are using the standard method or not an RKM of reverse engineering.
  Because of a bug in JDBC driver (ojdbc14.jar is), using reverse engineering standard will multiply the lengths of all varchar2 by 4.
  Upgrade the jdbc driver or use oracle RKM to reverse engineer the data store.

  PS. Please indicate as good/useful answers when you're done.

• How can I import tables to a different schema in the relational model existing... to add these tables in the existing model? PLSS help

  How can I import tables from a different schema in the relational model... to add these tables in the existing relational/logic model? PLSS help

  Notes; I already have a schema ready relational/logic model... and I need to add more tables to this relational/logic model

  can I import the same way like I did before?

  But even if I do the same how can I add it in the template? as the logic model has been designed...

  Help, please...

  Thank you

  To view the diagram of logic model in Bachman notation, you right-click on a blank area of the diagram and select the rating > Bachman Notation.

  David

• Change all the triggers table in the oracle schema by using a script - possible?

  
  Is it possible to modify all the triggers table in the oracle schema using a single script or modify each trigger table separately is the only way?

  A couple of alternatives come to mind.

  (1) you can go in SQL Develolper, go to the schema, expand the node for triggers and select all the triggers that you want to change.  Right-click and choose the fast DDL--> save spreadsheet.  Find and replace in the worksheet and then run the script.

  (2) if the trigger is the same for all 70 tables, you can move the PL/SQL out of the trigger and in a procedure in a package and just call the procedure of 70 triggers.  Now, the code is kept in the same place.  For new tables, you can add a call to the procedure and you are done.  If all 70 triggers are not the same, see if you can pass parameters to allow a generalized procedure that they can all use.

  You have not indicated what your triggers.  Are insert you columns of auditing, archiving data, inserting into a table of log, update another table or something else?  What type of trigger is it?  What you trying to accomplish with your triggers?

  Marcus Bacon

• Large table must be moved schema

  Hi guru Oracle

  IM using AIX 5.3 with oracle 11.2.0.2

  I just finished a job where I took a LOW partition of a partitioned table on our production database and installs all the data table into its own not partitioned our database archive.  This table on Archive is 1.5 to.

  Just to give you a brief overview of what I've done, successfully:

  -Created a partition no table on Production with exactly the same structure as the partitioned table set apart from the partitions.  Then, I moved all the subject segments in the same tablespace as the table to make it TRANSPORTABLE.

  -J' then took an expdp of the metadata tables by using the transport_tablespaces parameter.

  -Take the tablespace to read write I used the cp command to transfer the data files to the new directory.

  -Then on the database to ARCHIVE, I used impdp to import metadata and direct them to new files.

  parfile =

  DIRECTORY = DATA_PUMP_DIR

  DUMPFILE = dumpfile.dmp

  LOGFILE logfile.log =

  REMAP_SCHEMA = schema1:schema2

  DB11G = "xx", "xx", "xx"...

  My problem now is that there is some confusion and I traced the wrong schema, this isn't a major problem, but I wouldn't like to groom, so instead of saying REMAP_SCHEMA = schema1:schema2 must be REMAP_SCHEMA = schema1:schema3

  To the question: what is the best way to occupy the table schema3 (1.5 to in scheam2).

  
  

  To the question: what is the best way to occupy the table schema3 (1.5 to in scheam2).

  The easiest way is to use EXCHANGE PARTITTION to just 'swap' in the segment.

  You can only 'swap' between a partitioned table and a non-partitioned table, and you already have a non-partitioned table.

  So, create a table that is partitioned with a score in the new schema and table not partitioned in the same pattern again.

  Then exchange the old schema with the partition table in the new schema. Then share this new partition with the new table not partitioned in the new scheme. No data should move at all - just a data dictionary operation.

  Using patterns HR and SCOTT. Suppose you have a copy of the EMP table in SCOTT that you want to move to HR.

  - as SCOTT
  grant all on emp_copy HR

  - as HR

  CREATE TABLE EMP_COPY AS SELECT * FROM SCOTT. EMP_COPY WHERE 1 = 0;

  -create a partitioned temp table with the same structure as the table
  CREATE TABLE EMP_COPY_PART
  PARTITION OF RANGE (empno)
  (partition ALL_DATA values less than (MAXVALUE)
  )
  AS SELECT * FROM EMP_COPY;

  -the Bazaar in the segment of the table - very fast
  ALTER TABLE EXCHANGE PARTITION ALL_DATA EMP_COPY_PART TABLE SCOTT. EMP_COPY;

  -now share again in the target table
  ALTER TABLE EXCHANGE PARTITION ALL_DATA WITH TABLE EMP_COPY EMP_COPY_PART;

• How to collect statistics on the table for tables in a different schema

  Hi all
  
  I have a table in a schema, and I want to collect statistics for the table in a different schema.
  
  I gave GRANT ALL ON SCHEMA1. T1 TO SCHEMA2;
  
  And when I tried to run the command to collect statistics to help
  
  DBMS_STATS. GATHER_TABLE_STATS (OWNNAME = > 'SCHMEA1', TABNAME = > 'T1');
  
  The function will fail.
  
  Is there a way we can collect statistics of the table for tables in a schema into another schema.
  
  Thank you
  MK.

  You must grant analyze to schema2.

  SY.

• empty table USER_COLL_TYPES in custom schema

  Hi all
  
  We created a custom schema and connect to the schema custom via JDBC.
  When you call a procedure stored via JDBC, I get the error message:
  ORA-00920: invalid relational operator
  However, if called from the APPS schema, the procedure returns successfully.
  
  When you look in the SQL trace, it seems that anytime jdbc, runs a query on the user_coll_types table:
  
  SELECT ELEM_TYPE_NAME, ELEM_TYPE_OWNER FROM USER_COLL_TYPES WHERE TYPE_NAME =: 1
  
  And if no entry is found, the following query is executed (which causes the error with the statement "NOCYCLE"):
  
  SELECT ELEM_TYPE_NAME, ELEM_TYPE_OWNER FROM USER_COLL_TYPES WHERE TYPE_NAME in (SELECT TABLE_NAME FROM USER_SYNONYMS START WITH SYNONYM_NAME =: CONNECT BY NOCYCLE PRIOR TABLE_NAME = SYNONYM_NAME UNION SELECT 1: 1 FROM DUAL)
  
  
  Conclusion: When the procedure is called from the schema APPS the second query is not executed, the entrances are with the first, while in the custom schema not entries are found with the first request that led to the second query.
  
  So my question is, why a select * on table USER_COLL_TYPES returns all entries in my custom schema, although USER_COLL_TYPES is granted to the PUBLIC?
  Do I have to establish any other priivileges to get the entries in the USER_COLL_TYPES table in my custom schema?
  
  Thank you
  Carolin

  The query select USER_COLL_TYPES is not explicitly run in my code - it's something that is generated internally by JDBC...

  Does that mean I have to load all types of collection to my custom schema?

  Yes, I think so.

  Run this query in as user APPS and your CUSTOM user to check the number of records:

  SQL> select count(*)
  from USER_COLL_TYPES;
  

  Thank you
  Hussein

• Data pump import a table in to another schema in 11g

  Hi all
  
  I have an Oracle 11.2 database and I have a requirement to import a few tables in a new scheme using my export from the previous month. I can't import any scheme as it is very large. I check REMAP_TABLE option, but it is enough to create the table in the same pattern and only rename the table.
  
  
  For example, I TABLE GAS. EMPLOYE_DATA I want to import the to GASTEST. EMPLOYEE_DATA
  
  Is there a way to do it using datapump?
  
  
  
  Appriciate any advice.

  Hello

  You can use the parameter INCLUDE in order to only select one Table:

  REMAP_SCHEMA=SCOTT:SCOTT_TEST
  INCLUDE=TABLE:"IN ('EMP')"
  

  Hope this helps.
  Best regards
  Jean Valentine

• Access DB & insert long distance column in a table in the current schema

  I have a new requirement as:
  I have to create a table in my current schema, selection of data in a table in different schema using the database link and the table contains a column LONG.
  I wrote code like:
  
  CREATE TABLE tmp as
  SELECT a.index_name, a.index_type, a.uniqueness and a.table_name,
  b.column_name, c.column_expression, b.column_position
  User_indexes@FRISKDEVI41B_ORCL a.,
  b user_ind_columns@FRISKDEVI41B_ORCL,
  c user_ind_expressions@FRISKDEVI41B_ORCL
  WHERE b.index_name = a.index_name
  AND a.table_name = b.table_name
  AND b.index_name = c.index_name (+)
  AND c.table_name (+) = b.table_name
  AND b.column_position = c.column_position (+)
  ORDER BY a.table_name;
  
  and when I try to run this am getting an error like "ora-00997 illegal of the long data type using", can any1 help me solve this

  Hello

  SQL> create or replace type tmp_type as object(
    2    index_name       varchar2(30),
    3    table_name       varchar2(30),
    4    column_expression clob,
    5    column_position   number(10)
    6  )
    7  /
  
  Type created.
  
  SQL> create type tmp_tab as table of tmp_type;
    2  /
  
  Type created.
  
    1  create or replace function user_ind_expr return tmp_tab pipelined as
    2    cl clob;
    3  begin
    4    for r in (select * from user_ind_expressions@FRISKDEVI41B_ORCL) loop
    5      cl := r.column_expression;
    6      pipe row (tmp_type(r.index_name, r.table_name, cl, r.column_position));
    7    end loop;
    8    return;
    9* end;
  SQL> /
  
  Function created.
  
  SQL> CREATE TABLE tmp as
    2  SELECT a.index_name,a.index_type,a.uniqueness,a.table_name,
    3  b.column_name,c.column_expression,b.column_position
    4  FROM user_indexes@FRISKDEVI41B_ORCL a,
    5  user_ind_columns@FRISKDEVI41B_ORCL b,
    6  table(user_ind_expr) c
    7  WHERE b.index_name = a.index_name
    8  AND b.table_name = a.table_name
    9  AND b.index_name = c.index_name (+)
   10  AND b.table_name = c.table_name (+)
   11  AND b.column_position = c.column_position (+)
   12  ORDER BY a.table_name
  SQL> /
  
  Table created.
  

  Bartek

• Need info of table based on the schema name

  I need the following information for a given schema name:

  1. Table
     name
  2. Schema
     name
  3. Number or rows for each table (column catalogs num_rows)
  4. Size of the table (MB)

  I tried the query nelow but I can't make it work.
  

  Select col.table_name,
  Col.col_cnt as column_count,
  RC.row_cnt as row_count.
  s.size_in_MB as table_size_in_MB
  Of
  (
  / * number of columns * /.
  SELECT upper (table_name), COUNT (*) col_cnt
  FROM dba_tab_columns
  Owner WHERE = 'V500.
  Upper group (table_name)
  ) col

  Join

  (
  / * number of rows * /.
  Select
  table_name,
  TO_NUMBER (extractvalue (xmltype (dbms_xmlgen.getxml ("select count (*) c to ' |")))) ((table_name)), ' / LINES/LINES/C ')) as row_cnt
  from dba_tables
  where (iot_type! = 'IOT_OVERFLOW' or iot_type is null)
  and owner = 'SCOTT '.
  ) rc
  We upper (col.table_name) = upper (rc.table_name)

  
  Join

  (
  / * the size in MB of table * /.
  SELECT
  owner, table_name, (sum (bytes) / 1024/1024) size_in_MB
  Of
  (SELECT table_name, nom_segment, owner, bytes)
  FROM dba_segments
  WHERE segment_type = 'TABLE '.
  and owner = 'SCOTT '.
  )

  
  Group by owner, table_name

  ) s
  We upper (col.table_name) = upper (s.table_name);

  Paul

  
  
  
  

  
  
  
  
  

  I think you need this query:

  Select T.table_name,

  -to_number (extractvalue (xmltype (dbms_xmlgen.getxml ("select count (*) BSB_GL c.' |")))) ((table_name)), ' / LINES/LINES/C ')) as row_cnt

  Row_cnt T.Num_Rows,

  County (tc. Column_name) column_count;

  (sum (s.bytes) / 1024 / 1024) size_in_MB

  from dba_tables T

  
  

  Join the tc dba_tab_columns

  on tc. OWNER = "BSB_GL."

  and tc. Table_name = t.table_name

  
  

  Join dba_segments s

  on s.segment_name = t.table_name

  and s.OWNER = 'BSB_GL. '

  
  

  where (t.iot_type! = 'IOT_OVERFLOW' or t.iot_type is null)

  and t.owner = 'BSB_GL. '

  T.table_name group, T.NUM_ROWS

  If you gather stats column NUM_ROWS in dba_tables gives you cumber of rows in table correctly. And this will be faster than yous query

  ----

  Ramin Hashimzade