Need a script to display the hidden field if number = 568845

Hi all

Using Acrobat Pro 9.1 on iMac with OS 10.6.8

I am working on a form to fill out and need a script to display a hidden field when a button is clicked.

I've set up a numeric field to type a number, and the hidden field is "text1".

Now, I need a script to the button open only the hidden field, if the field number = 568845

In this way the customer can fill in the code and then show and type in the field.

Any help would be appreciated.

Ron

Given that you use it by a button, you can't use event.value because a button has no value, and in any case, you want to check the value of another field. So this place like your button MouseUp event (of course, you have to adapt the name of the text field...):

If (this.getField("Text1").value == "568845") {this.getField ("Hidden_Field") .display = display.visible} else {this.getField('Hidden_Field').

display = display.hidden}

Tags: Acrobat

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