ORA-01427: einreihig subquery returns multiple rows

I've been off queries running for awhile, and this error is making me take what I left little hair.   I searched and found a lot of topics about this, but it does not appear to meet this request.  Rather than continue blabbering...


SELECT THE DME. ITEM_Description, IMPC. ITEM_NUM

Y2006 as Sum2006, Y2007 as Sum2007, Y2008 as Sum2008, as Sum2009, as Sum2010 Y2010 Y2009

,(Select Y2011)

of TestDB.Book_Sect02_ImpleCosts, TestDB.Book_Sect02_ImpleDesc

where recommended = 'PM' and BUDGETTYPE = 'MDY' and BUDGETFY = 2016

and shareby = 'ME' and recommended in (select TestDB.Book_Recommendations recommended)

and Book_Sect02_ImpleCosts.ITEM_NUM = Book_Sect02_ImpleDesc.ITEM_NUM

and Book_Sect02_ImpleDesc.Item_Description = DME. Item_Description) as Sum2011

OF IMPC, TestDB.Book_Sect02_ImpleDesc DME TestDB.Book_Sect02_ImpleCosts

WHERE the recom = 'PM' and BUDGETTYPE = 'DMY' and BUDGETFY = 2016

and shareby = 'ME' and recommended in (select TestDB.Book_Recommendations recommended)

and IMPC. ITEM_NUM = DME. ITEM_NUM

ORDER OF IMPC. ITEM_NUM;

Basically, I want to find and eliminate the duplicate line, but I'm not.  The other problem is, I have no direct access to the database.  I am a contractor and must be based on e-mailing a DBA Government to execute the query for me.  Thank you in advance.


Considering the hoops I need to jump through to solve this problem, it is clear to me... the error does not occur, with the same query on my Production System and it does on my Test System.  I have requested that data be deleted at the Test and updated with Production data.  I hope that this will solve the problem.   I need to keep the data, because it's test, so hopefully this will allow me to move forward.   Thank you all for your help.

Tags: Database

Similar Questions

  • Why this sql returns ORA-01427: einreihig subquery returns multiple rows.

    Select

    case when 'Y'=(select  emp_sw

    of the customer

    where cust_co_num =   :custconum   )

    then ( Select cust_id from )

    client where

    cust_co_num = :custconum 

    )

    on the other

    (select...)

    end while pays_id

    of the double

    or any other solution for this?

    Thank you!!

    Maybe

    with

    data in the form of

    (select cust_id 100, 'Y' emp_sw, 1 cust_co_num of all the double union)

    Select 200, "n", 1 Union double all the

    Select 300, 'Y', 3 double Union all

    Select 400, ', 2 double

    )

    Select cust_id, emp_sw, cust_co_num

    data d

    where cust_id = case when exists (select null

    from the data

    where cust_co_num =: custconum

    and emp_sw = 'Y '.

    )

    then cust_id

    end

    or cust_id in (select cust_id

    from the data

    where cust_co_num =: custconum

    and emp_sw = n

    )

    Concerning

    Etbin

  • "ORA-01427: einreihig subquery returns more than one line.

    Hi all
    I have a SQL query where I need a subquery for certain fields (like fields are optional), and the thing is some of the subqueries are works well, but when I use some, it gives me an error * "ORA-01427: einreihig subquery returns more rows" *, so I looked to the top of the internet and found if I give *' and rownum = 1' * in the subquery ". It eliminates the error and there certainly, but the thing is I have test the XML data. I have two addresses that should appear on the report and both follow the same path, but one is required optional and another so I put the option in the subquery, but in the XML data, I see that both addresses are the same, but they need to be different, because the status of the relationship with that I question is different. I ALSO POST MY SQL so that if anyone of you has an idea can help out me. Once more, the sql, I put here has the SQL subqueries with ' and rownum = 1', which gives me bad output

    Select S_FN_INCEXP_CON. RELATION_TYPE_CD as RELATION_TYPE_CD,
    S_ORDER. ORDER_NUM as ORDER_NUM,
    S_ORDER. FRGHT_AMT as FRGHT_AMT,
    S_ORDER. ORDER_DT as ORDER_DT,
    S_ORDER. CARRIER_CD as CARRIER_CD,
    S_ORDER. CARRIER_PRIO_CD as CARRIER_PRIO_CD,
    S_ORDER. ACCNT_ORDER_NUM as ACCNT_ORDER_NUM,
    S_CONTACT. FST_NAME as FST_NAME,
    S_CONTACT. Last_name like LAST_NAME,
    S_ADDR_PER. ADDR_NAME as ADDR_NAME-> it's the address required
    S_ADDR_PER. POSTAL CODE such as POSTAL code,
    S_CON_ADDR. ADDR_MAIL_CD as ADDR_MAIL_CD,
    S_ADDR_PER. EMAIL_ADDR as EMAIL_ADDR,
    S_ADDR_PER. PH_NUM as PH_NUM,
    S_SRC_PAYMENT. PAYMENT_NUM as PAYMENT_NUM,
    S_ORDER. STATUS_CD as STATUS_CD,
    (select S_FN_INCEXP_CON_1.RELATION_TYPE_CD
    of SIEBEL. S_CONTACT S_CONTACT_1,
    SIEBEL. S_FN_INCEXP_CON S_FN_INCEXP_CON_1
    where S_ORDER. ROW_ID = S_FN_INCEXP_CON_1.FN_INCM_EXP_ID
    and S_FN_INCEXP_CON_1.CONTACT_ID = S_CONTACT_1.ROW_ID
    and S_FN_INCEXP_CON_1.RELATION_TYPE_CD! = ALL ('Donor', 'Notified Party', ' in memory of ', ' in honor of ')) RELATION_TYPE_CD_1

    , (select S_CONTACT_1.FST_NAME |') '|| S_CONTACT_1.LAST_NAME
    of SIEBEL. S_CONTACT S_CONTACT_1,
    SIEBEL. S_FN_INCEXP_CON S_FN_INCEXP_CON_1
    where S_ORDER. ROW_ID = S_FN_INCEXP_CON_1.FN_INCM_EXP_ID
    and S_FN_INCEXP_CON_1.CONTACT_ID = S_CONTACT_1.ROW_ID
    and S_FN_INCEXP_CON_1.RELATION_TYPE_CD! = ALL ('Donor', 'Notified Party', ' in memory of ', ' in honor of ')) NAME.

    (select S_ORDER_TYPE.NAME
    of SIEBEL. S_ORDER_TYPE S_ORDER_TYPE
    where S_ORDER. ORDER_TYPE_ID = S_ORDER_TYPE. ROW_ID
    and S_ORDER_TYPE.NAME = 'Général'), GENERAL

    (select S_ORDER_TYPE.NAME
    of SIEBEL. S_ORDER_TYPE S_ORDER_TYPE
    where S_ORDER. ORDER_TYPE_ID = S_ORDER_TYPE. ROW_ID
    and S_ORDER_TYPE.NAME = 'Memory') MEMORY,

    (select S_ORDER_TYPE.NAME
    of SIEBEL. S_ORDER_TYPE S_ORDER_TYPE
    where S_ORDER. ORDER_TYPE_ID = S_ORDER_TYPE. ROW_ID
    and S_ORDER_TYPE.NAME = 'Honour') HONOR,.

    (select S_FN_INCEXP_CON_1.RELATION_TYPE_CD
    of SIEBEL. S_CONTACT S_CONTACT_1,
    SIEBEL. S_FN_INCEXP_CON S_FN_INCEXP_CON_1
    where S_ORDER. ROW_ID = S_FN_INCEXP_CON_1.FN_INCM_EXP_ID
    and S_FN_INCEXP_CON_1.CONTACT_ID = S_CONTACT_1.ROW_ID
    and S_FN_INCEXP_CON_1.RELATION_TYPE_CD = ' in memory of ') R1,.

    (select S_FN_INCEXP_CON_1.RELATION_TYPE_CD
    of SIEBEL. S_CONTACT S_CONTACT_1,
    SIEBEL. S_FN_INCEXP_CON S_FN_INCEXP_CON_1
    where S_ORDER. ROW_ID = S_FN_INCEXP_CON_1.FN_INCM_EXP_ID
    and S_FN_INCEXP_CON_1.CONTACT_ID = S_CONTACT_1.ROW_ID
    and S_FN_INCEXP_CON_1.RELATION_TYPE_CD = ' in honor of ") R2,.


    (select S_FN_INCEXP_CON_1.RELATION_TYPE_CD
    of SIEBEL. S_CONTACT S_CONTACT_1,
    SIEBEL. S_FN_INCEXP_CON S_FN_INCEXP_CON_1
    where S_ORDER. ROW_ID = S_FN_INCEXP_CON_1.FN_INCM_EXP_ID
    and S_FN_INCEXP_CON_1.CONTACT_ID = S_CONTACT_1.ROW_ID
    and S_FN_INCEXP_CON_1.RELATION_TYPE_CD = 'notified Party') R3.

    (select S_ADDR_PER. ADDR_NAME | ',' | S_ADDR_PER. Zip code
    of SIEBEL. S_ADDR_PER S_ADDR_PER,
    SIEBEL. S_CON_ADDR S_CON_ADDR,
    SIEBEL. S_CONTACT S_CONTACT_1,
    SIEBEL. S_FN_INCEXP_CON S_FN_INCEXP_CON_1
    where S_ORDER. ROW_ID = S_FN_INCEXP_CON_1.FN_INCM_EXP_ID
    and S_FN_INCEXP_CON_1.CONTACT_ID = S_CONTACT_1.ROW_ID
    and S_CONTACT. ROW_ID = S_CON_ADDR. CONTACT_ID
    and S_CON_ADDR. ADDR_PER_ID = S_ADDR_PER. ROW_ID
    and rownum = 1
    and S_FN_INCEXP_CON_1.RELATION_TYPE_CD IN 'Notified Party') NP_ADDR-> it's the optional address


    (select S_PARTY_REL. REL_TYPE_CD
    of SIEBEL. S_PARTY_REL S_PARTY_REL,
    SIEBEL. S_CONTACT S_CONTACT_1,
    SIEBEL. S_FN_INCEXP_CON S_FN_INCEXP_CON_1
    where S_ORDER. ROW_ID = S_FN_INCEXP_CON_1.FN_INCM_EXP_ID
    and S_FN_INCEXP_CON_1.CONTACT_ID = S_CONTACT_1.ROW_ID
    and S_PARTY_REL. REL_PARTY_ID = S_CONTACT_1.ROW_ID
    and S_FN_INCEXP_CON_1.RELATION_TYPE_CD = ' in memory of ') RLNSHIP


    of SIEBEL. S_CONTACT S_CONTACT,
    SIEBEL. S_FN_INCEXP_CON S_FN_INCEXP_CON,
    SIEBEL. S_ORDER S_ORDER,
    SIEBEL. S_ADDR_PER S_ADDR_PER,
    SIEBEL. S_CON_ADDR S_CON_ADDR,
    SIEBEL. S_SRC_PAYMENT S_SRC_PAYMENT
    where S_ORDER. ROW_ID = S_FN_INCEXP_CON. FN_INCM_EXP_ID
    and S_FN_INCEXP_CON. CONTACT_ID = S_CONTACT. ROW_ID
    and S_CONTACT. ROW_ID = S_CON_ADDR. CONTACT_ID
    and S_CON_ADDR. ADDR_PER_ID = S_ADDR_PER. ROW_ID
    and S_FN_INCEXP_CON. RELATION_TYPE_CD = 'donor '.
    and S_SRC_PAYMENT. ORDER_ID = S_ORDER. ROW_ID

    Use
    ' and S_CONTACT_1.ROW_ID = S_CON_ADDR. CONTACT_ID'
    your 3rd condition in where clause.

    So it would be to get the address of the 'notified part' information instead of the donor

  • einreihig subquery returns multiple rows

    Hello


    In the sub query, I get the error "ORA-01427: einreihig subquery returns more than one line. In this query below, I must also display only the bsr_ind_id from rm_cust where are.bsr_borr_ctg_id = '1' and also all cust_name and client_id

    How can I modify this query?

    Select cust_name
    client_id
    , (select bsr_ind_id from rm_cust r where are.bsr_borr_ctg_id = '1') as "SSB".
    of rm_cust

    I haven't used the pivotal enough to help with that without doing some research which I do not have time for this moment. But back to your original problem: there is obviously more than 1 line in rm_cust with bsr_borr_ctg_id = '1', so what one do you? You can guarantee that you will not get the error if you use:

    select cust_name
          ,client_id
          ,(select max(bsr_ind_id) from rm_cust r where r.bsr_borr_ctg_id = '1') as "BSR"
    from rm_cust
    

    Or you can use min max. Either avoid the error you get. If both give you the same result, then that is what you need. If they give different results, then you need to determine what (if) is correct.

  • updated - einreihig subquery returns multiple rows

    I'm trying to update the values in a column in a table to match the value in a table of validation/look-up. Why do I get an error with this sql?

    UPDATE TABLE_A
    SET field_x = (SELECT field_x
    OF TABLE_B, TABLE_A
    WHERE TABLE_A.field_Y = TABLE_A.field_Y)
    WHERE THERE ARE
    (SELECT field_x
    OF TABLE_B, TABLE_A
    WHERE TABLE_A.field_Y = TABLE_A.field_Y)

    I get the error "einreihig subquery returns several lines.
    I can run the subquery only without any problem.

    ideas?

    Hello
    You get this error because

    Your request

    SELECT field_x
    FROM TABLE_B, TABLE_A
    WHERE TABLE_A.field_Y = TABLE_A.field_Y
    

    Returns a value greater than 1 for field_x.
    You may wan to check your data.

    Now, it depends entirely on your data if the following query will work ok or not?
    Try this

    UPDATE TABLE_A
    SET field_x = (SELECT field_x
    FROM TABLE_B
    WHERE TABLE_A.field_Y = TABLE_A.field_Y)
    WHERE EXISTS
    (SELECT field_x
    FROM TABLE_B
    WHERE TABLE_A.field_Y = TABLE_A.field_Y) 
    

    Kind regards
    Bobin

    Published by: Buga added second query

  • First 4.0.0.12.84 (ORA-01427 einreihig subquery returns more than one line)

    Hi Jeff,

    I use the ai2 since September 13 and I got this error when I run several reports from the RAC (2 knots) databases.

    For ex.    in the DBA Panel, according to the Performance option, when I try to launch ASHES for las 5 minutes, the ORA-01427 out immediately.

    I want just to be sure you're already aware of this problem and taken into account for the next version.

    Thanks in advance,

    Andraly Ng

    EA3 just came out a few hours ago - have a go at it and let us know what you think!

  • Error: einreihig subquery returns multiple rows

    Hai All

    I have two tables namely Daily_attend, Train_mast

    The Daily_attend are made up of fields are Train_mast are made up of fields are

    Name varchar form no var

    Date of empcode Num V_DATE

    Intimate Date Train_name var

    Outtime date Late_hrs var

    Number IND_IN

    Number IDE_OUT

    Date of Attend_date



    I need to update the table Depend of IDE_IN in Daily_attend in late_hrs in the Train_mast table

    I got through in the select statement, it is my select statement


    Select to_number (TO_DATE (TO_CHAR(Intime,'DD-MON-YYYY') |)) » '||
    To_char (0815, '0000'), 'MON-DD-YYYY HH24') + late_hrs /(24*60)-respondent
    ) * 24 * 60 dail_Att, train_mast;


    How can I convert to update

    Any help is highly appricateable

    Thanks in advance

    Concerning

    Srikkanth.M

    Published by: Srikkanth.M on April 13, 2010 10:21

    If empcode is the primary key in your table of daily_att and attend_date = V_DATE returns only one row per employee

    then try this

    update dail_att d set d.idein =(select to_number(TO_DATE(TO_CHAR(Intime,'DD-MON-YYYY')||' '||
    TO_CHAR(0815,'0000'),'DD-MON-YYYY HH24:MI')+late_hrs/(24*60)-intime) * 24*60
    from dail_Att,train_mast where attend_date =t_date AND empcode = d.empcode)
    

    Kind regards
    Prazy

  • Help in the treatment of "subquery returns multiple rows.

    Appreciate your help on this.

    I have under sql query fails with the error "ORA-01427: einreihig subquery returns multiple lines"

    WITH t
         AS (SELECT 'A' Col1, 'B' Col2, 'C' Col3 FROM DUAL
             UNION
             SELECT 'D', 'E', 'F' FROM DUAL
             UNION
             SELECT 'E', 'F', 'G' FROM DUAL
             UNION
             SELECT 'A', 'T', 'U' FROM DUAL),
         t1
         AS (SELECT 'A' Col1, 'B' Col2, 'C' Col3 FROM DUAL
             UNION
             SELECT 'D1', 'E1', 'F1' FROM DUAL
             UNION
             SELECT 'D', 'E', 'F' FROM DUAL
             UNION
             SELECT 'S', 'V', 'W' FROM DUAL),
         t2
         AS (SELECT 'A' Col1, 'B' Col2, 'C' Col3 FROM DUAL
             UNION
             SELECT 'A', 'E1', 'F1' FROM DUAL
             UNION
             SELECT 'D', 'E', 'F' FROM DUAL)
    SELECT t.col1,
           (SELECT distinct col2
              FROM t2
             WHERE t2.col1 = t.col1) RND_COL
      FROM t, t1
    WHERE t.col1 = t1.col1
    
    WhenI checked the count using below query
    
    WITH t
         AS (SELECT 'A' Col1, 'B' Col2, 'C' Col3 FROM DUAL
             UNION
             SELECT 'D', 'E', 'F' FROM DUAL
             UNION
             SELECT 'E', 'F', 'G' FROM DUAL
             UNION
             SELECT 'A', 'T', 'U' FROM DUAL),
         t1
         AS (SELECT 'A' Col1, 'B' Col2, 'C' Col3 FROM DUAL
             UNION
             SELECT 'D1', 'E1', 'F1' FROM DUAL
             UNION
             SELECT 'D', 'E', 'F' FROM DUAL
             UNION
             SELECT 'S', 'V', 'W' FROM DUAL),
         t2
         AS (SELECT 'A' Col1, 'B' Col2, 'C' Col3 FROM DUAL
             UNION
             SELECT 'A', 'E1', 'F1' FROM DUAL
             UNION
             SELECT 'D', 'E', 'F' FROM DUAL)
    SELECT t.col1,
           (SELECT count(col2)
              FROM t2
             WHERE t2.col1 = t.col1) RND_COL
      FROM t, t1
    WHERE t.col1 = t1.col1 (+)
    
    it shows as below
    -----------------
    COL1    RND_COL
    A    2
    A    2
    D    1
    E    0
    
    My Requirement is for all the values in the column 'RND_COL' > 1 it should display text as 'Multiple', for 'RND_COL' = 1 display actual value returned by sub query and 'RND_COL' = 0 display it as NULL.
    
    expected output
    -------------------
    COL1    RND_COL
    A       Multiple
    A       Multiple
    D       E
    E       NULL
    
    
    
    

    Hello

    Here's another way.  It's like the solution in response #1, but it does not use a subquery:

    SELECT t.col1

    CASE

    WHEN COUNT (DISTINCT t2.col2) > 1

    THEN "Multiple."

    For ANOTHER MIN (t2.col2)

    END AS rnd_col

    T

    LEFT OUTER JOIN t2 ON t2.col1 = t.col1

    GROUP OF t.col1, t.col2, t.col3

    ORDER BY t.col1

    ;

    This assumes that in table t (col1, col2, col3) combination is unique.  If theat is not the case, change the GROUP BY clause, but you need to ensure that all lines of t becomes a separate group.

  • single line sub query returns multiple rows

    Hi, please help me to solve this, working with oracle 11g.


    Update t1 set t1.twyindex = twypoly (select twyindex from twyinfo where t1.id = t2.id t2);

    the error message is:
    *
    ERROR on line 1:
    ORA-01427: einreihig subquery returns multiple rows

    Thank you

    don123 wrote:
    Hi paul, thanks...

    duplicate existing due to the business logic data.

    can I use the SQL mentioned above for all cases?

    is it mandatory to remove duplicates?

    Please provide your suggestions...

    If the company says duplicates are allowed, you have to ask the person who wants what, of the different twyindexes, that they want to use
    updating twyinfo table...

    I use the SQL proposed until they tell you that twyindex to use.

  • 01427 00000 - "einreihig subquery returns several lines.

    Hi all
    How can I solve it
    SELECT 
           v.code
          ,v.bar_code
          ,v.arb_name
          ,v.eng_name
          ,v.branch_no
          ,(SELECT sum(quantity) FROM viw_whs_items_movement GROUP BY branch_no)
    FROM  viw_whs_items_movement V
    This code gives me this error
    01427 00000 - "einreihig subquery returns several lines.
    I know that I have more value, but I need this value

    Result group
    SELECT sum(v.quantity) 
    FROM viw_whs_items_movement v 
    GROUP BY v.branch_no
    ##########################
    SUM(V.QUANTITY)
    ---------------
             114453 
               2501 
               8137 
              13270 
              15230 
             120626 
              22536 
               2926 
              12848 
              37509 
              20911 
               7503 
               6248 
              17221 
                462 
                 24 
              15041 
              10307 
              12524 
             526627 
              10564 
               8230 
              13204 
               2840 
              80769 
            1418238 
             215694 
              15238 
               5063 
             104187 
                913 
             147079 
              11293 
              12678 
              18855 
    
     35 rows selected 

    Must be scalar subqueries. You demonstrate your subquery returns more than one line. Where the error.

    A solution would be to establish a correlation between the results of the subquery by joining the branch_id with branch_id of the outer query. However, as the two queries use the same table, you can simply use an analytical SUM():

    SELECT
           v.code
          ,v.bar_code
          ,v.arb_name
          ,v.eng_name
          ,v.branch_no
          ,sum(quantity) over (partition by branch_no) as branch_tot
    FROM  viw_whs_items_movement V      
    

    Cheers, APC

  • Einreihig subquery returns more than one query

    Hello

    I get the following error: einreihig subquery returns more than one request. I don't know how I should debug this application. As far as I know, subqueries can return only 1 row...: S

    I've only Oracle SQL Developer to run/test of my queries. I can run the query with ROWNUM < 5000, which gives no error. If I run with ROWNUM > 5000 and ROWNUM < 6000 then the error pops up...

    This is the query:
    with
    DATES as 
      (select (select min(REC_DATE) from STOCK) as FROM_DT, (select max(CHANGE_DATE) from STOCK_ADJUST) as TO_DT from DUAL),
    MONTHS as 
      (select add_months(trunc(FROM_DT,'MM'),ROWNUM-1) as DT from DATES connect by ROWNUM <= months_between(TO_DT, FROM_DT)+1),
    CALCULATIONS as
      (select 
        PNM.PNM_AUTO_KEY PNM_KEY,
        MONTHS.DT DT, 
        NVL((select sum(stm.qty_rec) from stock stm WHERE STM.REC_DATE < MONTHS.DT AND STM.PNM_AUTO_KEY = PNM.PNM_AUTO_KEY GROUP BY pnm_auto_key),0) INCOMING, 
        NVL((select sum(saj.qty_adj) from stock_adjust saj 
                                    inner join stock stm on saj.stm_auto_key = stm.stm_auto_key 
                                    inner join parts_master pnm on stm.pnm_auto_key = pnm.pnm_auto_key where SAJ.CHANGE_DATE < MONTHS.DT AND STM.PNM_AUTO_KEY = PNM.PNM_AUTO_KEY group by pnm_auto_key),0) OUTGOING
      from MONTHS, PARTS_MASTER PNM)
    SELECT
      ROWNUM, CALCULATIONS.PNM_KEY PNM_AUTO_KEY, CALCULATIONS.DT COUNT_DATE,CALCULATIONS.INCOMING QTY_RECEIVED, CALCULATIONS.OUTGOING QTY_USED, (CALCULATIONS.INCOMING + CALCULATIONS.OUTGOING) QTY_BALANCE
    FROM
      CALCULATIONS;
    Published by: layout of the code user574699 on November 17, 2008 02:10

    the problem is that you use the same alias in your view online as well as in your main query in the second statement-nvl...

    HTH

  • ORA-01422 exactly fetch returned more rows than expected

    Hi all

    Some1 can you please suggest what is the difference between "ORA-01422 exactly fetch returned more rows than expected" and too many errors of lines.

    Concerning
    Arpit

    TOO_MANY_ROWS is a predefined exception that allows to capture the ORA-01422. It simply means that we don't need to declare our own exception to cope.

    SQL> DECLARE
      2
      3      lv_Dummy        dual.dummy%TYPE;
      4
      5  BEGIN
      6
      7      SELECT
      8          dummy
      9      INTO
     10          lv_Dummy
     11      FROM
     12          (   SELECT dummy FROM DUAL UNION ALL
     13              SELECT dummy FROM DUAL
     14          );
     15  END;
     16  /
    DECLARE
    *
    ERROR at line 1:
    ORA-01422: exact fetch returns more than requested number of rows
    ORA-06512: at line 7
    
    SQL> set serveroutput on
    SQL> DECLARE
      2
      3      lv_Dummy        dual.dummy%TYPE;
      4
      5  BEGIN
      6
      7      SELECT
      8          dummy
      9      INTO
     10          lv_Dummy
     11      FROM
     12          (   SELECT dummy FROM DUAL UNION ALL
     13              SELECT dummy FROM DUAL
     14          );
     15  EXCEPTION
     16      WHEN TOO_MANY_ROWS THEN
     17          dbms_output.put_line('TOO_MANY_ROWS is built in exception to allow us to capture ORA-01422');
     18
     19  END;
     20  /
    TOO_MANY_ROWS is built in exception to allow us to capture ORA-01422
    
    PL/SQL procedure successfully completed.
    
    SQL> DECLARE
      2
      3      lv_Dummy        dual.dummy%TYPE;
      4      lex_TooManyRows EXCEPTION;
      5
      6      PRAGMA EXCEPTION_INIT(lex_TooManyRows, -1422);
      7  BEGIN
      8
      9      SELECT
     10          dummy
     11      INTO
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     17  EXCEPTION
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     20
     21  END;
     22  /
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    David

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