Passing the ID of a record to add in another table

I have a database of base with candidates and profiles of boards in two tables, as well as interconnection table CandidateProfiles.

I have here a page that I use to add new candidates and we hope to fix all the profiles for each candidate, which, upon presentation, will add new candidates ot in detail the candidates table and add records to the table of CandidateProfiles based on the ID of the newly created candidate and regardless of the check boxes are selected.

It is the page Add candidates .

The PHP code that I have check boxes add to the CandidateProfiles table is:

$sql = "INSERT INTO CandidateProfiles (CandidateID, ProfileID) VALUES";

$ck = $_POST ['ckbox"];

foreach ($ck As $GetIndex = > $GetValue) {}
If ($GetValue == 'on') {}
$sql. = "("{$_POST ['CandidateID']}', '$GetIndex'), ";"
}
}

$sql = rtrim ($sql, ",");

mysql_query ($SQL);

The bold line is the error line 69.

It works however in part - as added new records in the CandidateProfiles table with the correct profileIDs but with a 0 CandidateID. So I just need to figure out how to change the CandidateID being added to the CandidateProfiles table between 0 and the ID of the new record added...

Iain

Just to say that I managed to get everything make-it did pretty much what I needed IE a page where new candidates can be added to a table of candidates, subject to a second page where profiles can be attached to the candidate just added - so the newly added candidate CandidateID is passed to the page AddProfiles where profiles are added by selecting however several checkboxes.

Tags: Dreamweaver

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