Please help me fix this SQL query...

Hi, please consider following:
create table test (col varchar2 (255))
insert into test values ("TERM").
Insert test values ("VOLUME");

Select the test pass where pass in ('TIME', 'VOLUME');
This property returns the rows.

but my input string is a comma-separated list:
DURATION, VOLUME

so I try
Select the test pass where col to (replace (' DURATION, VOLUME, ',' "'," '));
but no result. Or:
Select the test pass where col in ("' | replace (' DURATION, VOLUME, ','" ', "') |") ') ;

However
Select "' | Replace (' DURATION, VOLUME, ',' "'," ') | " ' the double
gives "DURATION", "VOLUME".

then why does it work?

hope you can help. Thank you

convert stringlist in lines and then use in the clause...

SELECT col
   FROM test
  WHERE col IN
  (SELECT    *
     FROM
    (SELECT TRIM( SUBSTR ( txt , INSTR (txt, ',', 1, level ) + 1 , INSTR (txt, ',', 1, level+1 ) - INSTR (txt, ',', 1, level) -1 ) ) AS token
       FROM
      ( SELECT ','||'DURATION,VOLUME'||',' AS txt FROM dual
      )
      CONNECT BY level <= LENGTH(txt)-LENGTH(REPLACE(txt,',',''))-1
    )
  )

Ravi Kumar

Tags: Database

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Please help me write this SQL query...

Hi everyone,

Please help me in this query.
A patient can multiple types of Adresses (types P,M,D).If they have all the 3 types i need to select type: p and
if they have (M and D) i need to select type M,and if they have only type D i have to select that.
For each address i need to validate whether that particular address is valid or not (by start date and end date and valid flag)

Patient table
=============

Patient_id          First_name    last_name

1                   sanjay        kumar
2                   ajay          singh
3                   Mike          John


Adress table
============

address_id       patient_id       adresss       city       type       startdate        enddate      valid_flg

1                   1             6222         dsadsa           P          01/01/2007       01/01/2010
2                   1             63333        dsad             M          01/02/2006       01/01/2007      N
3                   1             64564         fdf              M          01/01/2008       07/01/2009      
4                   1             654757       fsdfsa          D          01/02/2008       09/10/2009  
5                   2             fsdfsd       fsdfsd            M          01/03/2007       09/10/2009   
6                   2             jhkjk        dsad              D          01/01/2007       10/10/2010   
7                   3             asfd         sfds               D          01/02/2008       10/10/2009      


output
=====

1        sanjay       kumar            6222       dsadsa      P          01/01/2007        01/01/2010     
2        ajay         singh            fsdfsd     fsdfsd       M          01/03/2007        09/10/2009 
3        mike         john              asfd       sfds        D          01/02/2008        10/10/2009

Thanks in advance
Phani

Hello, Fabienne,.

This race for you (twisted code of Sarma):

SELECT patient_id, first_name, last_name, address, city, type, startdate, enddate
 FROM (
  SELECT a.patient_id patient_id, first_name, last_name, address, city, type, startdate, enddate,
             ROW_NUMBER() OVER (PARTITION BY p.patient_id ORDER BY CASE type WHEN 'P' THEN 1
                                                                      WHEN  'M' THEN 2
                                                                      WHEN  'D' THEN 3
                                                                    END) rn
    FROM  patient p
    JOIN  address a ON (p.patient_id = a.patient_id )
   WHERE NVL(valid_flg, 'X') != 'N'
     AND SYSDATE BETWEEN startdate AND  NVL(enddate, SYSDATE)
     )
WHERE rn = 1;

Edit, currently in the trial:

With Patient AS (
SELECT 1  Patient_id , 'sanjay' First_name, 'kumar'  last_name FROM DUAL UNION ALL
SELECT 2, 'ajay', 'singh' FROM DUAL UNION ALL
SELECT 3, 'Mike', 'John' FROM DUAL),
Address AS (
SELECT 1   address_id, 1  patient_id, '6222'    address, 'dsadsa'   city, 'P'  type, to_date('01/01/2007', 'DD/MM/YYYY')  startdate, to_date('01/01/2010', 'DD/MM/YYYY')  enddate, NULL  valid_flg FROM DUAL UNION ALL
SELECT 2,1,'63333','dsad','M', to_date('01/02/2006', 'DD/MM/YYYY'), to_date('01/01/2007', 'DD/MM/YYYY'),  ' N'  FROM DUAL UNION ALL
SELECT 3,1,'64564','fdf','M', to_date('01/01/2008', 'DD/MM/YYYY'), to_date('07/01/2009', 'DD/MM/YYYY'), NULL  FROM DUAL UNION ALL
SELECT 4,1,'654757','fsdfsa','D', to_date('01/02/2008', 'DD/MM/YYYY'), to_date('09/10/2009', 'DD/MM/YYYY'),  NULL  FROM DUAL UNION ALL
SELECT 5,2,'fsdfsd ','fsdfsd','M', to_date('01/03/2007', 'DD/MM/YYYY'), to_date('09/10/2009', 'DD/MM/YYYY'), NULL  FROM DUAL UNION ALL
SELECT 6,2,' jhkjk','dsad','D', to_date('01/01/2007', 'DD/MM/YYYY'), to_date('10/10/2010', 'DD/MM/YYYY'),  NULL  FROM DUAL UNION ALL
SELECT 7,3,'asfd',' sfds',' D', to_date('01/02/2008', 'DD/MM/YYYY'), to_date('10/10/2009', 'DD/MM/YYYY'),  NULL  FROM DUAL)
-- end test data
 SELECT patient_id, first_name, last_name, address, city, type, startdate, enddate
 FROM (
  SELECT a.patient_id patient_id, first_name, last_name, address, city, type, startdate, enddate,
             ROW_NUMBER() OVER (PARTITION BY p.patient_id ORDER BY CASE type WHEN 'P' THEN 1
                                                                      WHEN  'M' THEN 2
                                                                      WHEN  'D' THEN 3
                                                                    END) rn
    FROM  patient p
    JOIN  address a ON (p.patient_id = a.patient_id )
   WHERE NVL(valid_flg, 'X') != 'N'
     AND SYSDATE BETWEEN startdate AND  NVL(enddate, SYSDATE)
     )
WHERE rn = 1; 

PATIENT_ID FIRST_ LAST_ ADDRESS CITY   TY STARTDATE ENDDATE
---------- ------ ----- ------- ------ -- --------- ---------
         1 sanjay kumar 6222    dsadsa P  01-JAN-07 01-JAN-10
         2 ajay   singh fsdfsd  fsdfsd M  01-MAR-07 09-OCT-09
         3 Mike   John  asfd     sfds  D 01-FEB-08 10-OCT-09

Please help me with this SQL query
I'm practicing of SQL queries and met one involving the extraction of data from 3 different tables.

The three paintings are as below

< pre >
Country
Location_id country
LOC1 Spain
loc2 England
LOC3 Spain
loc4 USA
loc5 Italy
loc6 USA
loc7 USA
< / pre >
< pre >

User
user_id location_id
loc1 U1
loc1 U2
loc2 U3
loc2 U4
loc1 U5
U6 loc3
< / pre >
< pre >

Publish
user_id post_id
P1 u1
P2 u1
U2 P3
P4 u3
P5 u1
P6 u2
< / pre >

I am trying to write a SQL query - for each country of the users, showing the average number of positions

I understand the logic behind all this that we must first consolidate all locations, and then the users in one country and then find the way to their positions.
But, I'm having a difficulty to this format SQL. Could someone help me please with this request.

Thank you.
Select
Country.Country,
Count (*) Totalpostspercountry,
Count (distinct post.user_id) Totaldistincuserspercountry,
count (*) / count (distinct post.user_id) Avgpostsperuserbycountry
Of
countries, have, post
where country.location_id = muser.location_id
and muser.user_id = post.user_id
Country.country group

The output is like this for your sample data - hope that's what you're looking for :)

COUNTRY, TOTALPOSTSPERCOUNTRY, TOTALDISTINCUSERSPERCOUNTRY, AVGPOSTSPERUSERBYCOUNTRY
In England, 1, 1, 1.
Spain, 5, 2, 2.5.

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http://www.Vistax64.com/Vista-security/125044-open-file-security-warning.html

How to repair the operating system and how to restore the configuration of the operating system to an earlier point in time in Windows Vista
http://support.Microsoft.com/kb/936212/#appliesTo

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Please explain to me this sql query
Select * from emp e
where 2 > (select count (sal) from emp where the e.sal < sal)

It gives higher and the second highest salary, but how it works I HAV eno no idea please let me know briefly.
Hello
is
Welcome to the forum!

Thus, you have a query like
```
SELECT  *
FROM    emp     e
WHERE   2 > x;
```
and you want to understand how it works. I guess the part that you don't understand is so x, x display.
```
SELECT  e.*
,       x
FROM    emp     e
WHERE   2 > x;
```
Since the clause WHERE eliminates most of the lines, we will not use a WHERE clause for now. Also, we will simply display a couple of columns, just so that we can concentrate on the important parts better. We will only display the sal (because the query has something to do with the highest sal) and something unique on each line, like ename. Is, try to run something like this:
```
SELECT       ename, sal
,       (
         SELECT  COUNT (sal)
         FROM    emp
         WHERE   e.sal     < sal
       )     AS x
FROM       emp     e
ORDER BY  sal
;
```
Output:
```
ENAME             SAL          X
---------- ---------- ----------
SMITH             800         13
JAMES             950         12
ADAMS            1100         11
WARD             1250          9
MARTIN           1250          9
MILLER           1300          8
TURNER           1500          7
ALLEN            1600          6
CLARK            2450          5
BLAKE            2850          4
JONES            2975          3
SCOTT            3000          1
FORD             3000          1
KING             5000          0
```
You see what x is now? This is the number of lines where sal is higher than sal on the current line.
Nobody has one of its KING sal, so x = 0 to the rank of KING.
Only 1 person (that is, the KING) has a higher sal of SCOTT, so x = 1 on the line for SCOTT.
13 persons (that is, everyone except SMITH) has a greater sal then SMITH, so x = 13 on the BOF SMITH line.

How to prevent a user not to access a table of perticular? This user has select any table privilege. Please help me solve this problem.

Hello
How to prevent a user not to access a table special (xxx)?
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But there is access able as select * from schema.table;
How can I revoke this privilege.
Please help me solve this problem.
Thank you
Lacombe

1623609 wrote:

How can I select privilege on specific tables at the same time?

I want to create a new user and grants the right to select for tables, except a table (xxxx).

It will be possible without the keystone of the database?

One way, in several sql

coil doit.sql

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clean a http://www.adobe.com/support/contact/cscleanertool.html

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install the cc desktop application, use of the desktop application cloud creative to manage your applications and services

Please let me know how I can add a new column with a constraint not null, table already has data, without falling off the table... Please help me on this issue...

Hello
I have an emp_job_det with a, b, c columns table. Note that this TABLE ALREADY has DATA OF THESE COLUMNS
IAM now add a new column "D" with forced not null
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(GOLD)
In other words, if I put the query
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Please help me fix the script

I try to write a script by my slef but not work
app.findGrepPreferencest = firstLineIndent:8, leftIndent:8;
app.changeGrepPreferences = firstLineIndent:8, leftIndent:16;
app.changeGrep ();
app.findGrepPreferences = app.changeGrepPreferences = null;
Can someone please help me fix the script, please.

Hello

Try this.

app.findGrepPreferences = app.changeGrepPreferences = null;

app.findGrepPreferences.firstLineIndent = '8 ';

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app.changeGrepPreferences.firstLineIndent = '8 ';

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Kind regards

Cognet

Please help me fix my script!

Please help me fix my script
I use this script that copy from the adobe forum:
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Hello

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If the target is doc ==> it runs through all doc

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In your use case

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Jarek

Need help to write the SQL query
Hello
Please help me to write a query. My requirement is as below.

Hello
I have a table say XYZ in the following format.

product_id local min_order_quntity
========================================
1 en 10
1 ch 10
2 en 20
2 ch 20
3 en 30
3 ch 30
4 en 40
4 NC 10

Now I want to find the product_id where min_order_quantity is different for cn and locale

now I want the result of the following

product_id local min_order_quantity
=============================================
4 en 40
4 ch 10

This is different for local in and cn for product_id 4 min_order_quantity

min_order_quantity should be the same for both the locale(en,ch) for any product_id.

I want to find the product_id where min_order_quantity is different for ch and fr local

Thank you..
Hello

This query should do the job
```
select * from xyz t1
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```
See you soon

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https://support.Apple.com/en-us/HT201252

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I bought the iphone 6 s more time face in Saudi Arabia. I need to check if the original phone to apple or duplicated. So please help me find this problem.

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Please help me fix this SQL query...

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