PreparedStatement, creation of syntax error.

The poblem is in the first query prepared if I get the value directly in the works of everying string statement very well. However, when I use one? placeholder and a supply then the same value of sting, I would have entered the education channel, I get a syntax error.

import java.sql.*; import javax.swing.*; import java.awt.BorderLayout; import java.awt.event.*; public class Exercise34_5 extends JFrame { private JTextField jtfInput = new JTextField(10); private JButton jbShowTable = new JButton("Show Table"); private JTextArea jta = new JTextArea(); private PreparedStatement pstmt1; private PreparedStatement pstmt2; private PreparedStatement pstmt3; public Exercise34_5() { JPanel northPanel = new JPanel(); northPanel.add(new JLabel("Table Name")); northPanel.add(jtfInput); northPanel.add(jbShowTable); add(northPanel, BorderLayout.NORTH); add(new JScrollPane(jta)); try { Class.forName("com.mysql.jdbc.Driver"); Connection connection = DriverManager.getConnection("jdbc:mysql://localhost/test" , "root", "root"); pstmt1 = connection.prepareStatement("describe ?"); pstmt2 = connection.prepareStatement("select count(*) from enrollment"); pstmt3 = connection.prepareStatement("select * from enrollment"); }catch(Exception ex) { ex.printStackTrace(); } jbShowTable.addActionListener(new ActionListener() { public void actionPerformed(ActionEvent e) { String table = jtfInput.getText(); try{ pstmt1.setString(1, "enrollment"); /*pstmt2.setString(1, "enrollment"); pstmt3.setString(1, "enrollment");*/ ResultSet rset1 = pstmt1.executeQuery(); ResultSet rset3 = pstmt3.executeQuery(); int count = 0; while(rset1.next()) { jta.append(rset1.getString(1) + "\t"); count++; } jta.append("\n"); System.out.println(count); while(rset3.next()) { for(int i = 1; i <= count; i++) { jta.append(rset3.getString(i) + "\t"); } jta.append("\n"); } }catch(Exception ex) { ex.printStackTrace(); } } }); } public static void main(String[] args) { Exercise34_5 frame = new Exercise34_5(); frame.setSize(400, 200); frame.setLocationRelativeTo(null); frame.setDefaultCloseOperation(EXIT_ON_CLOSE); frame.setVisible(true); } }

java.sql.SQLException: syntax error or access violation of the server message: "you have an error in your syntax SQL; consult the manual for your version of the MySQL server for the right syntax to use near "entry" on line 1 "
at com.mysql.jdbc.MysqlIO.checkErrorPacket(MysqlIO.java:1997)
at com.mysql.jdbc.MysqlIO.sendCommand(MysqlIO.java:1167)
at com.mysql.jdbc.MysqlIO.sqlQueryDirect(MysqlIO.java:1278)
at com.mysql.jdbc.Connection.execSQL(Connection.java:2251)
at com.mysql.jdbc.PreparedStatement.executeQuery(PreparedStatement.java:1586)
to Exercise34_5$ 1.actionPerformed(Exercise34_5.java:47)

Alyosha says:
I don't understand.

You can not just put a? setting any old place in a prepared statement. That's all just a simple string substitution. For example, you cannot use a? setting for a table name or a column.

// wrong
ps = conn.prepareStatement("select * from ? where ? = ?");
ps.setString(1, tableName);
ps.setString(2, columnName);
ps.setString(3, columnValue);

// right
ps = conn.prepareStatement("select * from " + tableName = " where " + columnName + " = ?");
ps.setString(1, columnValue);

Tags: Oracle

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