Re: How to get Max (all values of columns) records on a partition interval

Hello
Hours      Days            Name     used_size
1     01-09-012     R1     1100
10     01-09-012     R1     1150
15     01-09-012     R1     1160
23     01-09-012     R1     1200

1     01-08-012     R1     1600
10     01-08-012     R1     1700
15     01-08-012     R1     1800
23     01-08-012     R1     1500

1     01-09-012     J1     10
10     01-09-012     J1     20
15     01-09-012     J1     30
23     01-09-012     J1     60

1     01-08-012     J1     70
10     01-08-012     J1     5
15     01-08-012     J1     17
23     01-08-012     J1     22


Needed o/p:

23     01-09-012     R1     1200
23     01-08-012     R1     1500
23     01-09-012     J1     60
23     01-08-012     J1     22
We have table as above, IE. everyday, there are records at regular intervals of hours for different users.

I want to get a single record of every day for one hour on this day for all users.


Please let me know if my question was unclear?

-Thank you

Another way, maybe more simple here, here could be just group by user, day.

SELECT user, day, Max(hours) max_hours, Max (used_size) KEEP (DENSE_RANK LAST ORDER BY hours) mh_used_size
  FROM (table)
 GROUP BY user, day
 ORDER BY user, day

Tags: Database

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