Reading about the digital data into the Scanner, followed of a string

I am a student, new to Java and will be picking up in the semester at College next.

I did my self-study using online tutorials and noticed that when I do this:

Entrance to the parser = new Scanner (System.in);
System.out.Print ("enter a number :");
Try
{
double d = input.nextDouble ();
System.out.println ("the number is:" + d);

System.out.Print ("enter a number :");
String s = input.nextLine ();
d = Double.parseDouble (s);
System.out.println ("the number 2 is:" + d);
}
catch the exception here irrelevant code

Reading the data for education String s = input.nextLine (); is ignored. I guess it's because of the character "\n" remains in the buffer, am I right?

My solution would be to put a statement (); input.nextLine before the String s = input.nextLine (); and it works. But it feels inelegant to remove the newline like that. Is there a suitable or more 'recognised the market' best way to do this?

863720 wrote:
I guess it's because of the character "\n" remains in the buffer, am I right?

Yes.

My solution would be to put a statement (); input.nextLine before the String s = input.nextLine (); and it works. But it feels inelegant to remove the newline like that. Is there a suitable or more 'recognised the market' best way to do this?

It is the "standard". I wouldn't be too worried about this, the Scanner also is widely used in the real world as tutorials might make you believe.

Tags: Java

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