REF. order. give the constraint when built in table

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• Get the error when switching from table

  
  Hi all

  I'm moving my procedure table values but no luck. your help in this regard will be highly appreciated. Thanks in advance.

  I created the following procedure:

  -------------

  CREATE OR REPLACE PROCEDURE send_coll

  IS

  TYPE c_dept_no IS TABLE OF THE dept.deptno%TYPE;

  v_dept_no c_dept_no: = c_dept_no();

  BEGIN

  SELECT DeptNo

  TO COLLECT FEES IN BULK

  IN v_dept_no

  EMP;

  END;

  ------------------------

  Now, I want to spend all the values of v_dept_no to one of my name of the procedure as rec_coll that receives the value of v_dept_no and print the value against v_dept_no. for example:

  When v_dept_no = 10 then print all empno against deptno 10 and so on...

  I think I have to do something like below but no luck so far.

  CREATE OR REPLACE PROCEDURE send_coll

  IS

  TYPE c_dept_no IS TABLE OF THE dept.deptno%TYPE;

  v_dept_no c_dept_no: = c_dept_no();

  BEGIN

  SELECT DeptNo

  TO COLLECT FEES IN BULK

  IN v_dept_no

  EMP;

  I'm looping 1.v_dept_no

  rec_coll (v_dept_no (i)); - call the rec_coll procedure and pass in the value

  end loop;

  end;

  ---------------

  create another procedure that will receive the value for v_dept_no

  ------------

  CREATE OR REPLACE PROCEDURE rec_coll (v_emp_no c_dept_no) - create collection with c_dept_no type

  IS

  BEGIN

  I'm looping 1.v_emp_no.count

  dbms_output.put_line (v_emp_no (i));

  END loop;

  END;

  -----------

  I get the error message to create these procedures and if someone help me so I really appreciate it. Thank you

  Concerning

  Shu

  I would just write a single SELECT statement joining EMP and Dept. If this exercise is University (collections of learning PL/SQL types), then you can do something like that.

  I used a PACKET to this implementation. Again, this is not how things are done in the real world.

  SQL > create or replace package coll_pkg
  2 as
  3 type dept_no_tbl is table of the dept.deptno%type;
  4
  5 procedure rec_coll (p_dept_no in dept_no_tbl);
  6 procedure send_coll;
  7 end;
  8.

  Package created.

  SQL > show err
  No errors.

  SQL > create or replace package body coll_pkg
  2 as
  3 procedure rec_coll (p_dept_no in dept_no_tbl)
  4 is
  5. start
  6 because me in 1.p_dept_no.count
  7 loop
  8 d in)
  9 select empno, ename
  10 of PEM
  11 where deptno = p_dept_no (i)
  12                 )
  loop 13
  14 dbms_output.put_line (p_dept_no (i) |) ':' || j.EmpNo | ':' || j.ename);
  15 end loop;
  16 end loop;
  end 17;
  18
  procedure send_coll 19
  20 is
  21 l_dept_no dept_no_tbl: = dept_no_tbl();
  start at 22
  23 deptno select bulk collect into l_dept_no
  24 of the Department;
  25
  26 rec_coll (l_dept_no);
  27 end;
  28 end;
  29.

  Package body created.

  SQL > show err
  No errors.

  SQL > set serveroutput on
  SQL > exec coll_pkg.send_coll
  10:7782:CLARK
  10:7839:KING
  20:7369:SMITH
  20:7566:JONES
  20:7788:SCOTT
  20:7876:ADAMS
  30:7499:ALLEN
  30:7521:WARD
  30:7654:MARTIN
  30:7698:BLAKE
  30:7844:TURNER

  PL/SQL procedure successfully completed.

  SQL >

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• Order of the columns to index

  Hello
  
  When you create an index say on table emp as below:
  
  SQL & gt; / / desc emp
  
  EMPNO
  ENAME
  JOB
  MGR
  HIREDATE
  SAL
  COMM
  DEPTNO
  
  If you create an index on (EMPNO, DEPTNO) say - that is the same as creating an index on (DEPTNO, EMPNO)? I mean, it is of the order of the columns when the index is created? For example, when you run your select, in which article, you use the same order as in the creation of the index?
  Any comment is welcome.
  Thank you very much
  VIC

  you're welcome... but why POracle becomes all the point? ;)

• disable the constraint

  Hello

  to remove an index PK I disabled the constraint.

  CHANGE TABLE DISABLE CONSTRAINT MAKEY_PK MYTABLE CASCADE;

  Drop INDEX MAKEY_PK;

  Now I'll recreate this KP index.

  Should I do something more to have the same constraints where they were?

  Thank you.

  Just re-create the index and select the constraint.

  SQL > conn aman/aman

  Connected.

  SQL > create table test (number, number of b).

  create table test (a number, b number)

  *

  ERROR on line 1:

  ORA-00955: name is already used by an existing object

  SQL > drop table test is serving;

  create table test (a number const

  Deleted table.

  SQL > Ravel prm primary key number, b);

  Table created.

  SQL > select index_name table_name from user_indexes where table_name ='TEST;

  INDEX_NAME

  --------------------------------------------------------------------------------

  TABLE-NAME

  --------------------------------------------------------------------------------

  PRM

  TEST

  8 selected lines.

  SQL > alter table test disable constraint prm;

  Modified table.

  SQL > drop index prm;

  Drop index prm

  *

  ERROR on line 1:

  ORA-01418: specified index does not exist

  SQL > create index prm on test (a);

  The index is created.

  SQL >

  SQL > insert into test (a) values (1);

  1 line of creation.

  SQL > /.

  1 line of creation.

  SQL > alter table test enable constraint prm;

  ALTER table test forced enable prm

  *

  ERROR on line 1:

  ORA-02437: impossible to validate (AMAN. (PRM) - primary key violated

  SQL > removal of the test;

  2 deleted rows.

  SQL > alter table test enable constraint prm;

  Modified table.

  SQL > insert into test (a) values (1);

  1 line of creation.

  SQL > /.

  insert into test (a) values (1)

  *

  ERROR on line 1:

  ORA-00001: unique constraint (AMAN. PRM) violated

  SQL >

  HTH

  Aman...