RegEx replace exact string

Similar Questions

• Find + replace text (string constant) does not work for screw Statechart module

  Hello

  I tried to do a mass find + replace a string in my code. Using Ctrl + F, LabVIEW 2012 correctly locates all the places where this string exists, including within the States transitions guards who have paths in this form:

  XYZ.lvsciagram.vi / Transition: Guard - diagram, Transition, data/part

  However, when I've specified that a replacement string, then click on 'Replace all', only 'normal' instances of screws replaced - instances in my diagrams had not changed.

  What is going on? Is there anything else I need to do?

  Thanks in advance.

  Looks like those that does not include how to find and replace is implemented in LabVIEW. You can try to replace just the statechart and see if that makes a difference, but it may simply not work.

• Search and replace the string formatting

  Hello

  I try to do a search and replace the formatting of a string.

  In the example, I'm looking for the string 'SUCCESSFUL', but it must also begin by usbflash and some number + PASSED.

  I can't get the format to have a number between 1 and 99. The number of replacements should add up to 6 in this case. I tried with \d for any number, and I also tried [1-99].

  Make a right-click on the function search and replace the string.  There is an option to use regular Expressions.  Then give it a try.

  

  EDIT: You need to set the entry replace all to TRUE.

• Scan chain corresponds to all adjacent spaces when a sequence of scanning to match an exact string ends in a space

  Recently, I wrote code to parse a string using the string function analysis.  The string contains a descriptive text as well as some of the settings I want to recover the chain.  My approach has been using a format string that match an exact string (descriptive text), that deletes or ignores the exact string and then corresponds to a parameter in the input string.  The remaining string contains more data which are analysed later.

  The problem I encountered is that corresponding to an exact string doesn't seem to work as I expect if the exact string ends with a space.  In this case, the exact string is offset, and other white space characters that immediately follow the exact string.  Let me illustrate by examples (------codes are displayed).

  Case 1: input string = "Line\s1\s\s\nLine\s2".

  string format = "Line\s%d".

  remaining string = "\s\s\nLine\s2".

  Note that spaces and the supply line after that '1' are moved to the remaining string in this case.

  Case 2: input string = "Line\s1\s\s\nLine\s2".

  string format = "Line\s%d\s".

  remaining string = "Line\s2".

  Note that all the spaces and line power immediately after that '1' are deleted and are NOT passed to the remaining string in this case.

  Behavior in case 2, it's not what I was expecting.  Can someone comment on that?  I can probably work around this problem, but would like to understand how the channel Scan function is supposed to work.  Is this a bug?

  Citing the detailed help:

  A space in the format string matches any amount of white space, such as spaces, tabs, line breaks and forms RSS.

• replace a string

  is it possible to replace a string? I mean, as in any programming language when you:

  String data = "abc";

  data = 'zxc ';

  I am trying to get the substrings of an initial string like '123.456.789.432.567' separated by the "." character, and when I get "123" at the first iteration, I do not know how to init the second iteration with "456.789.432.567" that I can't change the original string the process gets.

  Thank you

  A quick detour to the String\ vi.llb\Advanced might help a little to that.

  

  but the Crossrulz method has merit too.

  

  This period can be a delicate delimiter!

• I need to replace a string in a text using BACK file.

  I need to replace a string in a text using BACK file. I can't do it manually because the file size is about 2 GB. Please suggest me a solution. Thanks in advance.

  Hi ArunVL,

  See the Microsoft article below and check if it helps.

  With the help of MS-DOS Edlin utility to edit text files

  http://support.Microsoft.com/kb/67706

• How to replace the string "\" on json webservice?

  Hello

  I have problem with this json

  "{\"search_result\":[{\"name\":\"Mall Summarecon\",\"category\":\"BusinessEntity\",\"id\":\"1\"},{\"name\":\"Bamboo Dim Sum\",\"category\":\"BusinessEntity\",\"id\":\"2\"},{\"name\":\"Dimsum Ceker\",\"category\":\"Item\",\"id\":\"1\"}]}"
  

  I want to replace the string "\".

  the json are already working on my app via .cpp file

  I already add json.replace on my qml

  function simpleSearch(response){
          indicator.stop()
          model.clear()
          console.log("Response: "+response)
          var json = JSON.parse(response)
          json = json.replace('\\', ' ') // this is how the way i replace
          if (json == "[]")
              notFound.visible = true
  
          else
              model.append(json.search_result)
      }
  

  but still does not work

  is there a different way to replace it?

  Thank you

  Change your simpleSearchFinished as follows

  ....simpleSearchFinished()
  {
      QNetworkReply *reply = qobject_cast(sender());
      if (!reply->error()){
          QByteArray response = reply->readAll();
          response.replace("\\", "");
          if (response.startsWith("\"")){
              response.remove(0, 1);
          }
          if (response.endsWith("\"")){
              response.remove(response.length()-1, 1);
          }
          emit simpleSearchDone(response);
      }else{
          const int httpCode = reply->attribute(QNetworkRequest::HttpStatusCodeAttribute).toInt();
          qDebug() << "ErrorCode" << httpCode << endl << \
                  "ErrorString" << reply->errorString();
          emit error(httpCode, reply->errorString());
      }
      reply->deleteLater();
      manager->deleteLater();
  }
  

  and QML

  function simpleSearch(response){
      indicator.stop()
      model.clear()
      var json = JSON.parse(response)
      if (json){ // is VALID/PARSED
          model.append(json.search_result)
      }
  }
  

  As I wrote, it is not a good workaround solution. The best is to send VALID JSON string directly from your server. But it works

  

• Replace the string with the formatted text

  Hello all - I'm back to my beloved project...

  I want to replace a string by a TextSelction (formatted text) and began with the famous feature of Jang FindAndReplaceString.
  Since my replacement comes from another document (sourceDoc), I edited to targetDoc activeDoc and introduced a second document (sourceDoc).
  The replacePara actually comes from a stone where he had been placed to avoid switch backwards between the documents in a book (where to find and replace) and source documents. In another function, I learned that information on the table requires the sourceDoc must remain open.

  • Of course, everything works fine until I want to insert the replacelement:
    erase line 26 is the string
  • Given that I do not insert a string, I skip lines 28 and 29 and try try line 30
  • On line 30 DocumentSource is Document object and replacePare object TextSelection. However, sourceDoc.replacePara is not set and
  • (as a result?) line 31 past the current contents of the Clipboard.

  Of course, there is a fog around me... and I need some sunshine.

  function FindAndReplacePara (targetDoc, findString, sourceDoc, replacePara, loopMax) {
    var tr = new TextRange();
    var restoreTR, frame = 0, loopCounter = 0, replacementCounter = 0;
    var findParams = new PropVals();
    var firstPgf = targetDoc.MainFlowInDoc.FirstTextFrameInFlow.FirstPgf;
    
    tr.beg.obj = tr.end.obj = firstPgf;             //  set up the starting text range as the very beginning
    tr.beg.offset = tr.end.offset = 0;              // of the flow. We'll move straight from beginning to end.
    trSaved = tr                                    // to come back after work
  
    findParams = AllocatePropVals(2);
    
    findParams[0].propIdent.num = Constants.FS_FindText;
    findParams[0].propVal.valType = Constants.FT_String;
    findParams[0].propVal.sval = findString;
    
    findParams[1].propIdent.num = Constants.FS_FindCustomizationFlags;
    findParams[1].propVal.valType = Constants.FT_Integer;
    findParams[1].propVal.ival = Constants.FF_FIND_CONSIDER_CASE;
  
    FA_errno = Constants.FE_Success;                // errno global, to be used to track the progress of the find and replace
    tr = targetDoc.Find(tr.beg, findParams);        // and do an initial find to get started.
    
    while(FA_errno === Constants.FE_Success && loopCounter++ < 2*loopMax) { //find and replace loop as long as we keep finding
      targetDoc.TextSelection = tr;                 // set up the text range to clear the original text
      targetDoc.Clear(0);                           // clear it
      
  //    targetDoc.AddText(tr.beg, replacePara);       // insert the new text at the original beginning of the text range
  //    tr.beg.offset += replacePara.length;          //  lets jimmy the text range in memory to place it directly after
      targetDoc.TextSelection = sourceDoc.replacePara;        // paste the whole replacement paragraph
      targetDoc.Paste (0);                          // <-- Current contents of clipboard is pasted !!!!
      if(FA_errno === Constants.FE_Success) {       // increment our return counter
        replacementCounter++;
      }
      FA_errno = Constants.FE_Success;              // ...  find the next instance. We'll reset FA_errno again just in case
      tr = targetDoc.Find(tr.beg, findParams);      // something screwy happened while we were replacing text.
    }
    targetDoc.ScrollToText(trSaved);                // we're done. Restore the document to it's original area of display
    return replacementCounter;
  } // --- end FindAndReplacePara
  

  Hi Klaus,

  Thanks for the explanation. I remember something like that GetTabRange of the way back. You have been quite patient and persistent with this project, indeed.

  So, as we are dealing with ranges of text here, I think that the only simple approach is to perform a copy and paste. There is no way to save a 'formatted' in a variable. The only super precise way would be to get a data structure of each text range TextItems in the sourceDoc, then meticulously recreate every element of the targetDoc. It would be very complicated, I think, so copy and paste seems the most logical. I wonder, though, if Miss me something, because I think that maybe you would have tried already so yes (?)

  In any case, I would do something like that, from line 30 of your original code sample (code untested here):

  App. ActiveDoc = sourceDoc;

  sourceDoc.TextSelection = replacePara;

  sourceDoc.Copy (0);

  App. ActiveDoc = targetDoc;

  targetDoc.Paste (0);

  ... etc.

  Does make sense, or am I barking the wrong tree, as they say?

  Russ

• Replace the string value of table

  with cte as)

  Select val '123', 'abwec' double val1

  Union of all the

  Select "456" val, "mowerw" double val1

  Union of all the

  Select val '709', 'wkwere' double val1

  Union of all the

  Select val '078', 'awerwewerwreq' double val1

  )

  Select * from cte;

  -incoming string

  "asdasd123ewrwer@87w8eopiu456werwer@asdwer709@ewrwerewrwqqwezxder078 @..."

  need to replace like 'abwec' 123 and 456 as "mowerw" and 709 as wkwere and 078 as 'awerwewerwreq '.

  How to replace the string value of the string

  I'm going to the table which will have mapping information I need to see the incoming string and replace the appropriate value of the val to val1

  something like

  Of

  "asdasd123456werwer@asdwer709@ewrwerewrwqqwezxder078ewrwer@87w8eopiu @..."

  TO

  "asdasdabwecewrwer@87w8eopiumowerwwerwer@asdwerwkwere@ewrwerewrwqqwezxderawerwewerwreq@..."

  By using the TYPE clause.

  with cte as

  (

  Select val '123', 'abwec' double val1

  Union of all the

  Select "456" val, "mowerw" double val1

  Union of all the

  Select val '709', 'wkwere' double val1

  Union of all the

  Select val '078', 'awerwewerwreq' double val1

  ),

  input_tbl

  as

  (

  Select "asdasd123ewrwer@87w8eopiu456werwer@asdwer709@ewrwerewrwqqwezxder078 @..." input_str

  of the double

  )

  Select max (input_str) Dungeon (first order by desc NWR dense_rank) input_str

  de)

  Select rno, input_str

  de)

  Select rownum NWR

  val

  val1

  input_str

  count (*) over() cnt

  from cte

  Cross

  Join input_tbl

  )

  model

  dimension (NWR)

  measures (val, val1, cnt, CAST (input_str AS VARCHAR2 (4000)) input_str)

  (

  input_str [any] = replace (nvl (input_str [cv () - 1], input_str [cv ()]), val [cv ()], val1 [cv ()])

  )

  )

• Replace a string in the data of the element - OSB / Xquery

  I want to replace a string in a piece of XML data in OSB/XQuery. Pls help me... (by something in the XPATH expression or actions of the OSB)
  
  Scenario looks like - I want to remove "IND_" of the field type in the code xml.
  
  Input XML (OSB or XQuery) - stored in a variable say $cricInfo
  
  < CricInfo >
  < player >
  < drive >
  Sachin < name > < / name >
  * < Type > IND_BAT < / name >. *
  < / player >
  < drive >
  Barouk < name > < / name >
  < Type > IND_BOWL < / name >
  < / player >
  < drive >
  Dhoni < name > < / name >
  WK of < type > < / name >
  < / player >
  < / players >
  < / CricInfo >
  
  Output XML file
  
  < CricInfo >
  < player >
  < drive >
  Sachin < name > < / name >
  < * type > BAT < / name >. *
  < / player >
  < drive >
  Barouk < name > < / name >
  BOWL of < type > < / name >
  < / player >
  < drive >
  Dhoni < name > < / name >
  WK of < type > < / name >
  < / player >
  < / players >
  < / CricInfo >
  
  Best regards, Sesha

  may also adapt the 'identity Transform' to do some filtering on the item 'type ':

  Here the transformation of base:

  http://en.Wikipedia.org/wiki/Identity_transform#Using_XQuery

  at least you would avoid having to reproduce the overall structure of the document in your XQuery, which is always a Bad Thing (TM)...

  by the way, your XML file is not well formed, I fixed it here

  
  Sachin
  IND_BAT
  
  
  Barro
  IND_BOWL
  
  
  Dhoni
  WK
  
  
  

• Replace the exact string only

  I'm out content text on my page by querying our database using a simple method, which works very well.
  

  Quote:
  
  < cfoutput query = "getPageContent" StartRowOptional = "" #vPageContent # "LignesMax ="1"> #vContent # < / cfoutput >"
  

• Display the exact string of the file as a hexadecimal display data

  I'll send control messages via a serial port, which are built in a series of bytes.  Currently, I have all these messages in an excel file which is 8 columns of 224 lines.  The messages are the exact hex display, I need for my program works.  To check my installation, I tested a few messages by manually typing in messages using a string constant and the value display hexadecimal and everything works well.  How can I get the strings in my file to be recognized as they use hexadecimal display.

  Thanks for your suggestions.

  So if I understand, you read an ASCII representation to hexadecimal format of the command strings.

  You must convert ASCII bytes, then the chain, in this way:

  

  The entrance on the left string must be read from your file, of course.

  Notice that the representation of the integer constant must be U8.

  You don't need the Trim function spaces if you are sure that the string does not contain additional characters beyond the last hexagonal number.

• The search for exact strings (and the right formula)

  I am using FIND instruction to search multiple strings in a larger formula. The original formula that I do stand out is the following:

  = IF (ISNUMBER (FIND ('INC', A1)),' ', 'Y')

  Of course, this gives a Y if he finds some text in "". "" However, I have several channels for which I would check, and they need to be exact. That is to say when I search Inc. and Inc., I don't want Inc. to be counted. So, I tried the following formulas.

  = IF (ISNUMBER (FIND (OR("INC",inc"), A1)),' ', 'Y')

  = IF (SUM (COUNTIF (A1, "* INC. *","{* Inc. *}")),' ',' Y')

  The second works better, but it also counts Inc. as a football game. Any suggestions?

  This issue is beyond the scope of this site and must be placed on Technet or MSDN

  http://social.technet.Microsoft.com/forums/en-us/home

  http://social.msdn.Microsoft.com/forums/en-us/home

• Find and replace the string function replaces line breaks when I only replaced spaces?

  I need to replace all instances of a space or a series of spaces to a line with commas (or tabs) multi string so I can throw in a worksheet.

  I use the regular expression [\s]+ and it works, but it is also to replace the end of lines (\r\n) too.

  How can I replace the spaces but leave the end of the lines intact?

  Right-click on the search string and to take '-' code display. Enter the space character (\s) correctly - you \\s right now.

• Replace a string in QML

  I want to enter a number of float as 3.42 in a textbox control.

  The problem is that the keypad has no period, so I wanted to do a simple thing like this on onChanged:

  var mytext = textfield.text;
  mytext.replace("*",".");
  textfield.text = mytext;
  

  (if the user can use * as a period for the decimal places)

  But it does not work. String.Replace is not supported in QML? Or I do something wrong?

  Hello!
  It returns a copy, try:
  myText = mytext.replace ("*",".")