replace a string

is it possible to replace a string? I mean, as in any programming language when you:

String data = "abc";

data = 'zxc ';

I am trying to get the substrings of an initial string like '123.456.789.432.567' separated by the "." character, and when I get "123" at the first iteration, I do not know how to init the second iteration with "456.789.432.567" that I can't change the original string the process gets.

Thank you

A quick detour to the String\ vi.llb\Advanced might help a little to that.

but the Crossrulz method has merit too.

This period can be a delicate delimiter!

Tags: NI Software

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Find + replace text (string constant) does not work for screw Statechart module

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I tried to do a mass find + replace a string in my code. Using Ctrl + F, LabVIEW 2012 correctly locates all the places where this string exists, including within the States transitions guards who have paths in this form:

XYZ.lvsciagram.vi / Transition: Guard - diagram, Transition, data/part

However, when I've specified that a replacement string, then click on 'Replace all', only 'normal' instances of screws replaced - instances in my diagrams had not changed.

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Thanks in advance.

Looks like those that does not include how to find and replace is implemented in LabVIEW. You can try to replace just the statechart and see if that makes a difference, but it may simply not work.

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I try to do a search and replace the formatting of a string.

In the example, I'm looking for the string 'SUCCESSFUL', but it must also begin by usbflash and some number + PASSED.

I can't get the format to have a number between 1 and 99. The number of replacements should add up to 6 in this case. I tried with \d for any number, and I also tried [1-99].

Make a right-click on the function search and replace the string. There is an option to use regular Expressions. Then give it a try.

EDIT: You need to set the entry replace all to TRUE.

I need to replace a string in a text using BACK file.

I need to replace a string in a text using BACK file. I can't do it manually because the file size is about 2 GB. Please suggest me a solution. Thanks in advance.

Hi ArunVL,

See the Microsoft article below and check if it helps.

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http://support.Microsoft.com/kb/67706

How to replace the string "\" on json webservice?

Hello

I have problem with this json

"{\"search_result\":[{\"name\":\"Mall Summarecon\",\"category\":\"BusinessEntity\",\"id\":\"1\"},{\"name\":\"Bamboo Dim Sum\",\"category\":\"BusinessEntity\",\"id\":\"2\"},{\"name\":\"Dimsum Ceker\",\"category\":\"Item\",\"id\":\"1\"}]}"

I want to replace the string "\".

the json are already working on my app via .cpp file

I already add json.replace on my qml

function simpleSearch(response){
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        model.clear()
        console.log("Response: "+response)
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        else
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but still does not work

is there a different way to replace it?

Thank you

Change your simpleSearchFinished as follows

....simpleSearchFinished()
{
    QNetworkReply *reply = qobject_cast(sender());
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        response.replace("\\", "");
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        }
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    }else{
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    }
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}

and QML

function simpleSearch(response){
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}

As I wrote, it is not a good workaround solution. The best is to send VALID JSON string directly from your server. But it works

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Hello all - I'm back to my beloved project...

I want to replace a string by a TextSelction (formatted text) and began with the famous feature of Jang FindAndReplaceString.
Since my replacement comes from another document (sourceDoc), I edited to targetDoc activeDoc and introduced a second document (sourceDoc).
The replacePara actually comes from a stone where he had been placed to avoid switch backwards between the documents in a book (where to find and replace) and source documents. In another function, I learned that information on the table requires the sourceDoc must remain open.

Of course, everything works fine until I want to insert the replacelement:
erase line 26 is the string
Given that I do not insert a string, I skip lines 28 and 29 and try try line 30
On line 30 DocumentSource is Document object and replacePare object TextSelection. However, sourceDoc.replacePara is not set and
(as a result?) line 31 past the current contents of the Clipboard.

Of course, there is a fog around me... and I need some sunshine.

function FindAndReplacePara (targetDoc, findString, sourceDoc, replacePara, loopMax) {
  var tr = new TextRange();
  var restoreTR, frame = 0, loopCounter = 0, replacementCounter = 0;
  var findParams = new PropVals();
  var firstPgf = targetDoc.MainFlowInDoc.FirstTextFrameInFlow.FirstPgf;
  
  tr.beg.obj = tr.end.obj = firstPgf;             //  set up the starting text range as the very beginning
  tr.beg.offset = tr.end.offset = 0;              // of the flow. We'll move straight from beginning to end.
  trSaved = tr                                    // to come back after work

  findParams = AllocatePropVals(2);
  
  findParams[0].propIdent.num = Constants.FS_FindText;
  findParams[0].propVal.valType = Constants.FT_String;
  findParams[0].propVal.sval = findString;
  
  findParams[1].propIdent.num = Constants.FS_FindCustomizationFlags;
  findParams[1].propVal.valType = Constants.FT_Integer;
  findParams[1].propVal.ival = Constants.FF_FIND_CONSIDER_CASE;

  FA_errno = Constants.FE_Success;                // errno global, to be used to track the progress of the find and replace
  tr = targetDoc.Find(tr.beg, findParams);        // and do an initial find to get started.
  
  while(FA_errno === Constants.FE_Success && loopCounter++ < 2*loopMax) { //find and replace loop as long as we keep finding
    targetDoc.TextSelection = tr;                 // set up the text range to clear the original text
    targetDoc.Clear(0);                           // clear it
    
//    targetDoc.AddText(tr.beg, replacePara);       // insert the new text at the original beginning of the text range
//    tr.beg.offset += replacePara.length;          //  lets jimmy the text range in memory to place it directly after
    targetDoc.TextSelection = sourceDoc.replacePara;        // paste the whole replacement paragraph
    targetDoc.Paste (0);                          // <-- Current contents of clipboard is pasted !!!!
    if(FA_errno === Constants.FE_Success) {       // increment our return counter
      replacementCounter++;
    }
    FA_errno = Constants.FE_Success;              // ...  find the next instance. We'll reset FA_errno again just in case
    tr = targetDoc.Find(tr.beg, findParams);      // something screwy happened while we were replacing text.
  }
  targetDoc.ScrollToText(trSaved);                // we're done. Restore the document to it's original area of display
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} // --- end FindAndReplacePara

Hi Klaus,

Thanks for the explanation. I remember something like that GetTabRange of the way back. You have been quite patient and persistent with this project, indeed.

So, as we are dealing with ranges of text here, I think that the only simple approach is to perform a copy and paste. There is no way to save a 'formatted' in a variable. The only super precise way would be to get a data structure of each text range TextItems in the sourceDoc, then meticulously recreate every element of the targetDoc. It would be very complicated, I think, so copy and paste seems the most logical. I wonder, though, if Miss me something, because I think that maybe you would have tried already so yes (?)

In any case, I would do something like that, from line 30 of your original code sample (code untested here):

App. ActiveDoc = sourceDoc;

sourceDoc.TextSelection = replacePara;

sourceDoc.Copy (0);

App. ActiveDoc = targetDoc;

targetDoc.Paste (0);

... etc.

Does make sense, or am I barking the wrong tree, as they say?

Russ

Replace the string value of table

with cte as)
Select val '123', 'abwec' double val1
Union of all the
Select "456" val, "mowerw" double val1
Union of all the
Select val '709', 'wkwere' double val1
Union of all the
Select val '078', 'awerwewerwreq' double val1
)
Select * from cte;
-incoming string
"asdasd123ewrwer@87w8eopiu456werwer@asdwer709@ewrwerewrwqqwezxder078 @..."
need to replace like 'abwec' 123 and 456 as "mowerw" and 709 as wkwere and 078 as 'awerwewerwreq '.
How to replace the string value of the string
I'm going to the table which will have mapping information I need to see the incoming string and replace the appropriate value of the val to val1
something like
Of
"asdasd123456werwer@asdwer709@ewrwerewrwqqwezxder078ewrwer@87w8eopiu @..."
TO
"asdasdabwecewrwer@87w8eopiumowerwwerwer@asdwerwkwere@ewrwerewrwqqwezxderawerwewerwreq@..."

By using the TYPE clause.

with cte as

(

Select val '123', 'abwec' double val1

Union of all the

Select "456" val, "mowerw" double val1

Union of all the

Select val '709', 'wkwere' double val1

Union of all the

Select val '078', 'awerwewerwreq' double val1

),

input_tbl

as

(

Select "asdasd123ewrwer@87w8eopiu456werwer@asdwer709@ewrwerewrwqqwezxder078 @..." input_str

of the double

)

Select max (input_str) Dungeon (first order by desc NWR dense_rank) input_str

de)

Select rno, input_str

de)

Select rownum NWR

val

val1

input_str

count (*) over() cnt

from cte

Cross

Join input_tbl

)

model

dimension (NWR)

measures (val, val1, cnt, CAST (input_str AS VARCHAR2 (4000)) input_str)

(

input_str [any] = replace (nvl (input_str [cv () - 1], input_str [cv ()]), val [cv ()], val1 [cv ()])

)

)

Replace a string in the data of the element - OSB / Xquery
I want to replace a string in a piece of XML data in OSB/XQuery. Pls help me... (by something in the XPATH expression or actions of the OSB)

Scenario looks like - I want to remove "IND_" of the field type in the code xml.

Input XML (OSB or XQuery) - stored in a variable say $cricInfo

< CricInfo >
< player >
< drive >
Sachin < name > < / name >
* < Type > IND_BAT < / name >. *
< / player >
< drive >
Barouk < name > < / name >
< Type > IND_BOWL < / name >
< / player >
< drive >
Dhoni < name > < / name >
WK of < type > < / name >
< / player >
< / players >
< / CricInfo >

Output XML file

< CricInfo >
< player >
< drive >
Sachin < name > < / name >
< * type > BAT < / name >. *
< / player >
< drive >
Barouk < name > < / name >
BOWL of < type > < / name >
< / player >
< drive >
Dhoni < name > < / name >
WK of < type > < / name >
< / player >
< / players >
< / CricInfo >

Best regards, Sesha
may also adapt the 'identity Transform' to do some filtering on the item 'type ':

Here the transformation of base:

http://en.Wikipedia.org/wiki/Identity_transform#Using_XQuery

at least you would avoid having to reproduce the overall structure of the document in your XQuery, which is always a Bad Thing (TM)...

by the way, your XML file is not well formed, I fixed it here

Sachin
IND_BAT

Barro
IND_BOWL

Dhoni
WK

RegEx replace exact string

I am trying to replace a string of HTML. Here is what I have
```
public function convertToXHtml(str:String):String {
var pattern:RegExp;
 
// Check for all carriage returns or breaks
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str = str.replace(pattern," ");
 
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```
I have this shortcut down for better readability.
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What Miss me?

http://www.Adobe.com/2006/mxml"layout ="vertical ".
horizontalAlign = "center" verticalAlign = "middle" >

 Import mx.formatters.DateFormatter;

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Donec lacinia, metus vitae tristique laoreet
';

public void convertToXHtml(str:String):String {}
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<\ pan=""><\>/IG;
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return str;
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]]>

Find and replace the string function replaces line breaks when I only replaced spaces?

I need to replace all instances of a space or a series of spaces to a line with commas (or tabs) multi string so I can throw in a worksheet.

I use the regular expression [\s]+ and it works, but it is also to replace the end of lines (\r\n) too.

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Right-click on the search string and to take '-' code display. Enter the space character (\s) correctly - you \\s right now.

Replace a string in QML

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```
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```
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Hello!
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Hello
I have a table T1 with a (large binary BLOB) column, I need (you) to update the Blob string with replacement of a chain (in the Blob) with another string.
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IS
FUNCTION BLOBREPLACE ()p_blob BLOB p_what VARCHAR2 p_with_what VARCHAR2()RETURN BLOB
IS
START
RETURN CLOB2BLOB () REPLACE (BLOB2CLOB()p_blob), p_what p_with_what( ) );
END BLOBREPLACE ;
------------------------------ BLOB2CLOB -------------------------
FUNCTION BLOB2CLOB (p_blob in BLOB) RETURN CLOB
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offset INTEGER := 1 ;
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p_blob ,
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dest_offset ,
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FUNCTION CLOB2BLOB (p_clob CLOB) RETURN BLOB
ACE
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l_dest_offset INTEGER := 1 ;
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l_source_offset ,
DBMS_LOB. DEFAULT_CSID,
lang_context ,
l_warning
);
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END;
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Djam

It works well for me.

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Where IDSQL > 2 = 1;

0 lines to date.

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ST%26G

PL/SQL procedure successfully completed.
```

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