Replace the strings inside SWF's AS2/3

There are, on some Board there are a few foreign flashes that predate the internet and effectively anonymous pertaining to the creator, if someone used a program to get the strings in the SWF file (programmed in AS3), machine to translate them and put back them.

Deal is a machine translation. It's funny, but it's still wrong and I would like to do a good job of translating.

So to get to the point, I would like to know where I might be able to find a program that can get the strings inside a SWF file that is programmed in AS2 or AS3, show them to me and I would like to replace them with custom text. The reason why I want to do it this way is that I must not decompile SWF. Decompile a SWF is bound to generate errors and I could not have certain fonts inside so I also have little to do with the opening of the thing I can.

I tried a few solutions, including FLASM (only works on AS2) and others don't bother naming such that they are no longer capable of displaying the AS3 code and not edit or replacement of classes.

I'm not 'try' anything. I inform you of your options.

If you do not find the source files and that you can not use a decompiler, you cannot change the source code.

Tags: Adobe Animate

Similar Questions

Search and replace the string formatting

Hello

I try to do a search and replace the formatting of a string.

In the example, I'm looking for the string 'SUCCESSFUL', but it must also begin by usbflash and some number + PASSED.

I can't get the format to have a number between 1 and 99. The number of replacements should add up to 6 in this case. I tried with \d for any number, and I also tried [1-99].

Make a right-click on the function search and replace the string. There is an option to use regular Expressions. Then give it a try.

EDIT: You need to set the entry replace all to TRUE.

How to replace the string "\" on json webservice?

Hello

I have problem with this json

"{\"search_result\":[{\"name\":\"Mall Summarecon\",\"category\":\"BusinessEntity\",\"id\":\"1\"},{\"name\":\"Bamboo Dim Sum\",\"category\":\"BusinessEntity\",\"id\":\"2\"},{\"name\":\"Dimsum Ceker\",\"category\":\"Item\",\"id\":\"1\"}]}"

I want to replace the string "\".

the json are already working on my app via .cpp file

I already add json.replace on my qml

function simpleSearch(response){
        indicator.stop()
        model.clear()
        console.log("Response: "+response)
        var json = JSON.parse(response)
        json = json.replace('\\', ' ') // this is how the way i replace
        if (json == "[]")
            notFound.visible = true

        else
            model.append(json.search_result)
    }

but still does not work

is there a different way to replace it?

Thank you

Change your simpleSearchFinished as follows

....simpleSearchFinished()
{
    QNetworkReply *reply = qobject_cast(sender());
    if (!reply->error()){
        QByteArray response = reply->readAll();
        response.replace("\\", "");
        if (response.startsWith("\"")){
            response.remove(0, 1);
        }
        if (response.endsWith("\"")){
            response.remove(response.length()-1, 1);
        }
        emit simpleSearchDone(response);
    }else{
        const int httpCode = reply->attribute(QNetworkRequest::HttpStatusCodeAttribute).toInt();
        qDebug() << "ErrorCode" << httpCode << endl << \
                "ErrorString" << reply->errorString();
        emit error(httpCode, reply->errorString());
    }
    reply->deleteLater();
    manager->deleteLater();
}

and QML

function simpleSearch(response){
    indicator.stop()
    model.clear()
    var json = JSON.parse(response)
    if (json){ // is VALID/PARSED
        model.append(json.search_result)
    }
}

As I wrote, it is not a good workaround solution. The best is to send VALID JSON string directly from your server. But it works

Replace the string value of table

with cte as)
Select val '123', 'abwec' double val1
Union of all the
Select "456" val, "mowerw" double val1
Union of all the
Select val '709', 'wkwere' double val1
Union of all the
Select val '078', 'awerwewerwreq' double val1
)
Select * from cte;
-incoming string
"asdasd123ewrwer@87w8eopiu456werwer@asdwer709@ewrwerewrwqqwezxder078 @..."
need to replace like 'abwec' 123 and 456 as "mowerw" and 709 as wkwere and 078 as 'awerwewerwreq '.
How to replace the string value of the string
I'm going to the table which will have mapping information I need to see the incoming string and replace the appropriate value of the val to val1
something like
Of
"asdasd123456werwer@asdwer709@ewrwerewrwqqwezxder078ewrwer@87w8eopiu @..."
TO
"asdasdabwecewrwer@87w8eopiumowerwwerwer@asdwerwkwere@ewrwerewrwqqwezxderawerwewerwreq@..."

By using the TYPE clause.

with cte as

(

Select val '123', 'abwec' double val1

Union of all the

Select "456" val, "mowerw" double val1

Union of all the

Select val '709', 'wkwere' double val1

Union of all the

Select val '078', 'awerwewerwreq' double val1

),

input_tbl

as

(

Select "asdasd123ewrwer@87w8eopiu456werwer@asdwer709@ewrwerewrwqqwezxder078 @..." input_str

of the double

)

Select max (input_str) Dungeon (first order by desc NWR dense_rank) input_str

de)

Select rno, input_str

de)

Select rownum NWR

val

val1

input_str

count (*) over() cnt

from cte

Cross

Join input_tbl

)

model

dimension (NWR)

measures (val, val1, cnt, CAST (input_str AS VARCHAR2 (4000)) input_str)

(

input_str [any] = replace (nvl (input_str [cv () - 1], input_str [cv ()]), val [cv ()], val1 [cv ()])

)

)

Get the string inside parentheses - to help scan from string

I have a very basic question here. I would like to extract a part of a chain that is inside the brackets (example: I work with [National Instruments]). In the string, I want to extract only of National Instruments, I know logical extraction in finding media and their extraction. But I am interested in the use of analysis of the chain or possibly any other primitive with a single blow. Please suggest if someone has an idea, I'm not use to the format specifiers. I got this link for reference, but I'm not able to find a solution.

Find and replace the string function replaces line breaks when I only replaced spaces?

I need to replace all instances of a space or a series of spaces to a line with commas (or tabs) multi string so I can throw in a worksheet.

I use the regular expression [\s]+ and it works, but it is also to replace the end of lines (\r\n) too.

How can I replace the spaces but leave the end of the lines intact?

Right-click on the search string and to take '-' code display. Enter the space character (\s) correctly - you \\s right now.

Replace the string with the formatted text

Hello all - I'm back to my beloved project...

I want to replace a string by a TextSelction (formatted text) and began with the famous feature of Jang FindAndReplaceString.
Since my replacement comes from another document (sourceDoc), I edited to targetDoc activeDoc and introduced a second document (sourceDoc).
The replacePara actually comes from a stone where he had been placed to avoid switch backwards between the documents in a book (where to find and replace) and source documents. In another function, I learned that information on the table requires the sourceDoc must remain open.

Of course, everything works fine until I want to insert the replacelement:
erase line 26 is the string
Given that I do not insert a string, I skip lines 28 and 29 and try try line 30
On line 30 DocumentSource is Document object and replacePare object TextSelection. However, sourceDoc.replacePara is not set and
(as a result?) line 31 past the current contents of the Clipboard.

Of course, there is a fog around me... and I need some sunshine.

function FindAndReplacePara (targetDoc, findString, sourceDoc, replacePara, loopMax) {
  var tr = new TextRange();
  var restoreTR, frame = 0, loopCounter = 0, replacementCounter = 0;
  var findParams = new PropVals();
  var firstPgf = targetDoc.MainFlowInDoc.FirstTextFrameInFlow.FirstPgf;
  
  tr.beg.obj = tr.end.obj = firstPgf;             //  set up the starting text range as the very beginning
  tr.beg.offset = tr.end.offset = 0;              // of the flow. We'll move straight from beginning to end.
  trSaved = tr                                    // to come back after work

  findParams = AllocatePropVals(2);
  
  findParams[0].propIdent.num = Constants.FS_FindText;
  findParams[0].propVal.valType = Constants.FT_String;
  findParams[0].propVal.sval = findString;
  
  findParams[1].propIdent.num = Constants.FS_FindCustomizationFlags;
  findParams[1].propVal.valType = Constants.FT_Integer;
  findParams[1].propVal.ival = Constants.FF_FIND_CONSIDER_CASE;

  FA_errno = Constants.FE_Success;                // errno global, to be used to track the progress of the find and replace
  tr = targetDoc.Find(tr.beg, findParams);        // and do an initial find to get started.
  
  while(FA_errno === Constants.FE_Success && loopCounter++ < 2*loopMax) { //find and replace loop as long as we keep finding
    targetDoc.TextSelection = tr;                 // set up the text range to clear the original text
    targetDoc.Clear(0);                           // clear it
    
//    targetDoc.AddText(tr.beg, replacePara);       // insert the new text at the original beginning of the text range
//    tr.beg.offset += replacePara.length;          //  lets jimmy the text range in memory to place it directly after
    targetDoc.TextSelection = sourceDoc.replacePara;        // paste the whole replacement paragraph
    targetDoc.Paste (0);                          // <-- Current contents of clipboard is pasted !!!!
    if(FA_errno === Constants.FE_Success) {       // increment our return counter
      replacementCounter++;
    }
    FA_errno = Constants.FE_Success;              // ...  find the next instance. We'll reset FA_errno again just in case
    tr = targetDoc.Find(tr.beg, findParams);      // something screwy happened while we were replacing text.
  }
  targetDoc.ScrollToText(trSaved);                // we're done. Restore the document to it's original area of display
  return replacementCounter;
} // --- end FindAndReplacePara

Hi Klaus,

Thanks for the explanation. I remember something like that GetTabRange of the way back. You have been quite patient and persistent with this project, indeed.

So, as we are dealing with ranges of text here, I think that the only simple approach is to perform a copy and paste. There is no way to save a 'formatted' in a variable. The only super precise way would be to get a data structure of each text range TextItems in the sourceDoc, then meticulously recreate every element of the targetDoc. It would be very complicated, I think, so copy and paste seems the most logical. I wonder, though, if Miss me something, because I think that maybe you would have tried already so yes (?)

In any case, I would do something like that, from line 30 of your original code sample (code untested here):

App. ActiveDoc = sourceDoc;

sourceDoc.TextSelection = replacePara;

sourceDoc.Copy (0);

App. ActiveDoc = targetDoc;

targetDoc.Paste (0);

... etc.

Does make sense, or am I barking the wrong tree, as they say?

Russ

Search and replace the string in a column

Hello

In the table the data stored with "" (double quotes), I need to remove these quotes please suggest me how to remove

Select the address of TECH_SOURCING_EMPLOYEE_DETAILS

"No. 12/32"-> data recorded in this format in the table. I need to remove the double quotes

Thank you
Sudhir

Hello

UPDATE to modify existing rows in a table
REPLACE to delete a given sub - a to a string.

UPDATE     tech_sourcing_employee_details
SET     address     = REPLACE (address, '"')
WHERE     INSTR (address, '"')         > 0          -- Maybe
;

This will remove all the quotes of the address.
If you want to remove the quotes only from the beginning and the end of the string, then use TRIM instead of REPLACE:

UPDATE     tech_sourcing_employee_details
SET     address     = TRIM ('"' FROM address)
WHERE     INSTR (address, '"')         > 0          -- Maybe
;

The WHERE clause is only for effectiveness.
So, whenever the column contains quotes, of the double quotation mark is always the first character in the string, then you can change the WHERE clause to:

WHERE     address  LIKE '"%'
{code}

Search and replace the string from a result
Hi all
I want to search a "("or ")" of the chain and all want the string before replacing "(" with a blank space...

for example
If the result comes like this
name
12 #122 (on the opening balance)
I want the result as

name
on the opening balance)

means
12 #122 is replaced by "" how

thanking you
Gaurav Sontakke
Like this?
```
WITH t AS
     (SELECT '10 #10 (moving standard to msp1004)' str
        FROM DUAL
      UNION ALL
      SELECT '13208 #0' str
        FROM DUAL
      UNION ALL
      SELECT '2002-02-22 #10' str
        FROM DUAL)
SELECT SUBSTR (str, 1, INSTR (str, '#') - 1)
  FROM t
```

Replace the string in BPEL
Hey all,.

I need to replace the & with a + since the & just breaks the bpel process. Any ideas on how to make a replacement string to find all the the & and replace it with the +, I looked in the transformation and the entitlement activity, but did not find all the functions to help me with this.

Any help would be appreciated.

Thank you
You can create an XSL template for string replacements, see the link given below:
http://geekswithblogs.NET/Erik/archive/2008/04/01/120915.aspx

If you are familiar with Java you can add a Java embedding activity and string replacement using the method of the replacement of the java.lang.String class.

Diakité
http://SOA-HOWTO.blogspot.com

Replace the string

Hi all
I need like below. FONT-FAMILY string twice, repeat with the lowercase and uppercase, highlited blue color.
What ever after FONT FAMILY contains data must replace it with our new channel.
Select ' it is arial black14pt '
of the double
Power required:
 it is arial black14pt 

Like this?

SQL > ed
A written file afiedt.buf

1 with t as (select"

= "" color: #ff0000; "> it is arial black14pt"
"as double txt).
2 --
3 end of test data
4 --
5 Select regexp_replace (txt, "([Ff][Oo][Nn][Tt]-[Ff][Aa][Mm][Ii][Ll][Yy]:).*?)" ",' \1Calibri" ') as txt
6 * t
SQL > /.

TXT
----------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------

It is arial black14pt
/ SPAN >

Replace the string, each value should double quotes around it
How can I replace this basic string with double quotes around each value?

dog, cat, john, mark

I would like to:

'dog', 'cat', 'john', 'brand '.

Thank you

-weStsIdE
Hello

I answered my own question. Well nice for someone else. The function ListQualify will insert what you need before and after each element of individual list.

Actually powerful enough that you can just insert double quotation marks, for example around channels and leave intact numeric values.

-weStSidE

Replace the string on a specific line

Hi everyone thanks in advance for your time.

I have almost finished a project, (a software to manage the booking of hotel rooms and a database of passengers).

I made a function that writes a .txt file a cluster with some personal information string type fields, each field is separated by tabs, and each client separated by a line news.

Example: name address phone etc.

Robert xxxxxx yyyyyyy

Patrick xxxxxx yyyyyyy

Mila xxxxxx yyyyyyy

Now I don't know how I can do to perform a search by name and to be able to change each field.

Example:

If I search for Patrick, I want to be able to change the address or phone number or any other field.

I know how to search in a text file, until I reach the word, but I don't find a way to change the field and write once again the information in the same file in the same line of origin.

Any contribution will be great! Thanks again.

How empy and replace the buttons inside the Manager of horizontal management.

Hello! So basically, I have 2 buttons at the top of the screen and a set of buttons inside a HorizontalFieldManager (let's call is Set 1 and 2). Now, when I click on the first button it should appear a Set 1 and then appear Set 2 and remove the Set1 on screen. How can I do this? Thank you!

-Ryan

The details in the referenced thread, you should get going.

Basically, you add and remove fields.

I suggest that you have a Manager to Set 1 and a Manager for value 2. Add the two managers to the screen, with nothing in it,

Make sure that Manager 2 is empty (deleteAll) and add fields associated with the value 1 to the Manager for the value 1, when they should be displayed - i.e. trigger it by pressing button 1.

Remove the fields in Manager 1 and add the fields associated with the value 2 to the Manager for Set 2, when they should be displayed - i.e. trigger this by pressing button 2.

I hope this helps.

Replace the string with quouts

Hi all
I use the oracle version below:
12 c Oracle database Release 12.1.0.1.0 - 64 bit Production
PL/SQL Release 12.1.0.1.0 - Production
CORE Production 12.1.0.1.0
AMT for Linux: Version 12.1.0.1.0 - Production
NLSRTL Version 12.1.0.1.0 - Production
I have a string like:
0,1,5,9,10,58... so now
I need to convert the above string in form below:
'0 ', '1', '2',' 3'... well now
Here, I want to add quotes to open and closing of all the numbers that are separated by a comma.
Select '0,1,2,3' double;
but I pulled out as:
'0 ', '1', '2',' 3'
Here, there are a lot of numbers in a string, but all are separated by commas.
Thank you

something like:

WITH the DATA (str) AS (SELECT ' 0,1,5,9,10,58' FROM dual)

Select regexp_replace (str, '(\d+)', q '{' \1'}')

from the data

/

?

HTH

Replace the strings inside SWF's AS2/3

Similar Questions

Maybe you are looking for