Scan/Format in the string Question

Similar Questions

• 5132: "the format of the string is not supported.

  Hello

  I'm listening channels of my new USB-5132 on the disk at the same time, using the c# example "scope: live stream To Disk.  I entered "0:1" (without the quotes) in the channel name box.  The result is the error "the format of the string is not supported.  Is there another syntax or example that will allow me to broadcast two channels of 5132 on disk?

  Thank you

  Penny

  Hi Penny,

  Channel string syntax

  If you try an empty string or a string separated by commas (as in "0.1") do you still see this error?

  What version of NOR-SCOPE do you use?  You can find it in Measure & Automation Explorer under software.

  Also, I would be interested to know if you have other devices (besides the 5132) which show the same behavior.

  -Andrew

• change the format of a string

  Hi all

  Now what I'll do is to convert a string to an array.

  The string I got is shown on the photo as an attachment with my code.

  Of course, the table is not correct.

  I wonder if there is a way to change the format of the string without empty lines and concatenate each number after another.

  in order to have a correct table with my code.

  Or someone has idea to a new code for the conversion of a string like this in the table?

  Thank you

  Chao

  I think they are referring to something like this.

• Scan for float to string

  Hello

  I'm reading a float of 4 IEEE 754 bytes from a string (char array) using the scan function. I tried all kinds of setting shaped versions described in the help, but I can't get this good work. I get a string from a COM port. It looks like this in hexadecimal (the floating point number is between [brackets]):

  FF FF FF FF 86 1E 1A 6 82 22 01 07 00 00 11 [C0 52 8F 9F] DB FF...

  The format of the string is always like that. The first 15 bytes are some commands I want to jump and then I need to read bytes, 16, 17, 18 and 19. The result in this case should be - 3.290016.

  Here are the last of my many attempts to remove the float:

  buffer character [24];

  float myFloatVal = 0;

  ...

  Scan (buffer, "% 4f [i15b4]", & myFloatVal);

  This example returns '0' for myFloatVal.

  Any advice would be welcome!

  Frequency conversion seems a bit tough: while he plays well with double I'm not be able to make it work with floats too

  I can suggest possible workaround with sscanf:

  sscanf (buffer + 15, "%c %c %c %c", (char *) & myFloatVal + 3, (char *) & myFloatVal + 2, (char *) & myFloatVal + 1, (char *) & myFloatVal);

• Get the string inside parentheses - to help scan from string

  I have a very basic question here. I would like to extract a part of a chain that is inside the brackets (example: I work with [National Instruments]). In the string, I want to extract only of National Instruments, I know logical extraction in finding media and their extraction. But I am interested in the use of analysis of the chain or possibly any other primitive with a single blow. Please suggest if someone has an idea, I'm not use to the format specifiers. I got this link for reference, but I'm not able to find a solution.

  

• How to set the string in spreadsheet format

  Hi all, I have what I hope, it's a simple question...  I am writing a data table in a spreadsheet and I want the first number, which is the clock (ms) to be written in decimal format, but the rest of the bytes to write to the spell.  I'm not coming with a format string that will do.  Any ideas?

  Thank you

  Jason

  Because the entry in the spreadsheet uses the table to a spreadsheet string, and there is one type of entry - the digital table in your case. If you want to write your own handwriting worksheet function, you can index each element of the array and use in the string instead of the table on the worksheet.

• a stupid question about the string conversion error

  I learn generic

  well generic allows setting the data type that you add to the fields of the object, right?

  I made a simple example

  class generic < String >

  {

  The name of the string;

  void set (String name)

  {myIdName = name ;}

  String get() {return myIdName ;}

  }

  class using {}

  Public Shared Sub main (String [] args)

  {

  generic < String > gn = new

  (generics) < String >;

  GN. Set (90);

  System.out.println ("name entered is:" + gn.get ());

  }

  }

  now the line

  GN. Set (90);

  I know that I send a string to the value method, but I wanted to see the error that comes when I send the argument of type other than a string and sent 90 to set method (without quotes)

  the error that slammed me is

  method defined in the class generic < String > cannot be applied to the given types

  required: java.lang.String

  found: int

  reason: int real argument cannot be converted to a java.lang.String by method invocation conversion

  corresponding to a variable of type String: String extends the object declared in the class generic

  OK here is my stupid question

  I know that int cannot be converted to a string and put 90 quotes will correct the error

  What intrigued me is the last line

  "Chain extends object declared in the class generic.

  
  

  I know that everything is under the object class

  that means that means line... ??

  thnq

  What intrigued me is the last line

  "Chain extends object declared in the class generic.

  
  

  I know that everything is under the object class

  that means that means line... ??

  Which refers to the class definition you provided:

  generic class

  You "stated" in your 'generic' class a 'collar' stretching ' the object '. It reads as if it said "String declared in the class generic.

  See "Generic Types" in the Java Tutotial

  http://docs.Oracle.com/javase/tutorial/Java/generics/types.html

  Search for the word 'object' and you'll see that word highlighted in the world. Although it appears highlighted read this line:

  As you can see, all instances of the object are replaced by T. A variable of type can be any non-primitive type you specify: any type of class, any interface, any type of table or even another variable of type.

  On this page, you will see this:

  A generic class is defined with the following format:

  class name { /* ... */ }
  

  Where each one is read as: T1 extends object ', "T2 extends object", etc.

  When you said this:

  generic class

  You replaced "T1 extends object" with "String extends object".

• digital conversion (in the format of the time) to string

  Hello

  I have a digital control (at the time format) in which I hours: minutes: seconds and I want to convert it to a string. The problem is that the number of hours is incremented by one, and if I insert a number of hours exceeds 24 the string is not displayed correctly.

  What should I do to make this work?

  Thank you

  You use a function that should be a numeric value that is based on the UTC clock and then convert it to a clock display based on your current time zone.  My guess is that you are in GMT + 1, which is why you see an hour added to it.

  You must use the Format function in the string for this with appropriate time for the format codes codes.    %t is relative time.  It takes number you enter and turns it into hours, minutes, and seconds, rather than trying to create a view of time for her.  This is why your code cannot ride beyond 24 hours.   (There is no 25 hours on a clock face).

  

• Search and replace the string formatting

  Hello

  I try to do a search and replace the formatting of a string.

  In the example, I'm looking for the string 'SUCCESSFUL', but it must also begin by usbflash and some number + PASSED.

  I can't get the format to have a number between 1 and 99. The number of replacements should add up to 6 in this case. I tried with \d for any number, and I also tried [1-99].

  Make a right-click on the function search and replace the string.  There is an option to use regular Expressions.  Then give it a try.

  

  EDIT: You need to set the entry replace all to TRUE.

• Transform a string that displays hex data in normal format, in a string that has the same data in hexadecimal format

  I have a string of arbitrary length - say, 1AB1C0 - normal format. I would like to have a function that takes this string in and generates the same accurate, but in hexadecimal characters. If the entry will read 1AB1C0 in the normal string format, and the output will read 1AB1C0 as a hexadecimal string.

  I'm doing this because I found that the terminal works better if I send the bytes string hexadecimal vs as an array of U8. Furthermore, I handle a lot of byte stream in my program and I find the chain tools less cumbersome to use against the array of bytes to analysis of analysis tools - however, they operate only on strings as they appear in normal mode. So I have reasons in different parts of my program to have the channel under conditions normal vs formats hexadecimal; but I can't understand anyway elegant remotely to cast from one to the other.

  CraigRem wrote:

  If the entry will read 1AB1C0 in the normal string format, and the output will read 1AB1C0 as a hexadecimal string.

  Well, you must sweep the bytes of the string formatting hexagonal two at a time for a digital U8 and then cast to a string. There are several ways to do it, here are the two possibilities. (Sure to use the correct representation as Mkae labels).

  

  (I still don't understand your reasoning why you need).

• Replace the string with the formatted text

  Hello all - I'm back to my beloved project...

  I want to replace a string by a TextSelction (formatted text) and began with the famous feature of Jang FindAndReplaceString.
  Since my replacement comes from another document (sourceDoc), I edited to targetDoc activeDoc and introduced a second document (sourceDoc).
  The replacePara actually comes from a stone where he had been placed to avoid switch backwards between the documents in a book (where to find and replace) and source documents. In another function, I learned that information on the table requires the sourceDoc must remain open.

  • Of course, everything works fine until I want to insert the replacelement:
    erase line 26 is the string
  • Given that I do not insert a string, I skip lines 28 and 29 and try try line 30
  • On line 30 DocumentSource is Document object and replacePare object TextSelection. However, sourceDoc.replacePara is not set and
  • (as a result?) line 31 past the current contents of the Clipboard.

  Of course, there is a fog around me... and I need some sunshine.

  function FindAndReplacePara (targetDoc, findString, sourceDoc, replacePara, loopMax) {
    var tr = new TextRange();
    var restoreTR, frame = 0, loopCounter = 0, replacementCounter = 0;
    var findParams = new PropVals();
    var firstPgf = targetDoc.MainFlowInDoc.FirstTextFrameInFlow.FirstPgf;
    
    tr.beg.obj = tr.end.obj = firstPgf;             //  set up the starting text range as the very beginning
    tr.beg.offset = tr.end.offset = 0;              // of the flow. We'll move straight from beginning to end.
    trSaved = tr                                    // to come back after work
  
    findParams = AllocatePropVals(2);
    
    findParams[0].propIdent.num = Constants.FS_FindText;
    findParams[0].propVal.valType = Constants.FT_String;
    findParams[0].propVal.sval = findString;
    
    findParams[1].propIdent.num = Constants.FS_FindCustomizationFlags;
    findParams[1].propVal.valType = Constants.FT_Integer;
    findParams[1].propVal.ival = Constants.FF_FIND_CONSIDER_CASE;
  
    FA_errno = Constants.FE_Success;                // errno global, to be used to track the progress of the find and replace
    tr = targetDoc.Find(tr.beg, findParams);        // and do an initial find to get started.
    
    while(FA_errno === Constants.FE_Success && loopCounter++ < 2*loopMax) { //find and replace loop as long as we keep finding
      targetDoc.TextSelection = tr;                 // set up the text range to clear the original text
      targetDoc.Clear(0);                           // clear it
      
  //    targetDoc.AddText(tr.beg, replacePara);       // insert the new text at the original beginning of the text range
  //    tr.beg.offset += replacePara.length;          //  lets jimmy the text range in memory to place it directly after
      targetDoc.TextSelection = sourceDoc.replacePara;        // paste the whole replacement paragraph
      targetDoc.Paste (0);                          // <-- Current contents of clipboard is pasted !!!!
      if(FA_errno === Constants.FE_Success) {       // increment our return counter
        replacementCounter++;
      }
      FA_errno = Constants.FE_Success;              // ...  find the next instance. We'll reset FA_errno again just in case
      tr = targetDoc.Find(tr.beg, findParams);      // something screwy happened while we were replacing text.
    }
    targetDoc.ScrollToText(trSaved);                // we're done. Restore the document to it's original area of display
    return replacementCounter;
  } // --- end FindAndReplacePara
  

  Hi Klaus,

  Thanks for the explanation. I remember something like that GetTabRange of the way back. You have been quite patient and persistent with this project, indeed.

  So, as we are dealing with ranges of text here, I think that the only simple approach is to perform a copy and paste. There is no way to save a 'formatted' in a variable. The only super precise way would be to get a data structure of each text range TextItems in the sourceDoc, then meticulously recreate every element of the targetDoc. It would be very complicated, I think, so copy and paste seems the most logical. I wonder, though, if Miss me something, because I think that maybe you would have tried already so yes (?)

  In any case, I would do something like that, from line 30 of your original code sample (code untested here):

  App. ActiveDoc = sourceDoc;

  sourceDoc.TextSelection = replacePara;

  sourceDoc.Copy (0);

  App. ActiveDoc = targetDoc;

  targetDoc.Paste (0);

  ... etc.

  Does make sense, or am I barking the wrong tree, as they say?

  Russ

• I have Acrobat Pro on my computer and I work with the drawing that have been digitized in PDF format. The scanners are not aligned or place because of the poor scanning process. Anyway is to align the document even if it requires me to crop or lose

  I have Acrobat Pro on my computer and I work with the drawing that have been digitized in PDF format. The scanners are not aligned or place because of the poor scanning process. Is there anyway to align the document even if it requires me to crop or lose some on the edges?

  Hi brad.

  Yes. You can use the analysis tools to straighten and crop your document. Here is a link to a new tutorial. The key to activate the sliding options recovery is to choose the option of the camera Image in the drop to Enhance, and gives you tools to set the correct page for smoothing areas.

  fundamental https://helpx.adobe.com/Acrobat/How-to/scan-Paper-documents-Searchable-PDF.html?Set=Acroba--principes t - create a pdf file

  Donna.

• Format of the connection string to connect to Oracle DB via LDAP

  Hello
  
  I have an Oracle database and its details are configured in LDAP. I have the c# code that I want to connect to Oracle DB using LDAP details. So I wrote the code to connect to the Oracle DB, but not able to connect. Implementation error at the con. Open() statement: "ORA-12154: TNS: could not resolve the connect identifier specified.
  
  Code:
  --------
  String s = "Data Source = @ldap://abc.pq.xyz.com: 11389/myldap, cn = OracleContext, dc = pq, dc = xyz, dc = com; User Id = MyDB; Password = MyPass";
  
  Con OracleConnection = new OracleConnection (constr.);
  con. Open();
  
  I need help in the formation of the connection string.

  user8786648 wrote:
  Hello

  I have an Oracle database and its details are configured in LDAP. I have the c# code that I want to connect to Oracle DB using LDAP details. So I wrote the code to connect to the Oracle DB, but not able to connect. Implementation error at the con. Open() statement: "ORA-12154: TNS: could not resolve the connect identifier specified.

  Code:
  --------
  String s = "Data Source = @ldap://xyz.us.oracle.com: 11389/xyz_ldap, cn = OracleContext, dc =, dc = oracle, dc = com; User Id = xyz; Password = xyz";

  Con OracleConnection = new OracleConnection (constr.);
  con. Open();

  I need help in the formation of the connection string.

  This isn't how you use LDAP for Oracle name resolution.

  You must configure the LDAP protocol. ORA and SQLNET. ORA files properly.

  For example, you can review the LDAP protocol. Documentation of ORA here:

  http://docs.Oracle.com/CD/E11882_01/network.112/e10835/LDAP.htm#i500397

  And the SQLNET. Documentation of ORA here:

  http://docs.Oracle.com/CD/E11882_01/network.112/e10835/SQLNET.htm#i500318

  A quick search on the terms "example of oracle ldap.ora", shot to the top of several examples.

  Also, if these are real values that you posted in your example of a connection string, you can change.

• Export of string in csv format, keeping the commas and new lines

  Hello

  I export the string to the csv format and have been removeing of new lines with commas as so

  thing.toString ().replace(/\n/g,_'').replace (',', ");

  How can I make this iwthout lose line breaks and commas? I can't have in atm as mess up the csv file.

  JSON is more 'transfer' information that can be gathered in number, string, array, object, etc format later.

  Excel can import CSV, but it cannot interpret the complexity of the information. Typically what you would do is serialize complex information with JSON, receive on the other side (where it is perhaps) and then to deserialize. After you are deserializing it using the capabilities of JSONs to put your information into what is was (numbers, strings, arrays, and object) it is up to you how you restructure the data to the format of your choice.

  Your original intent of preserving CSV is the best for Excel or OpenOffice Calc. You don't mention your intention. JSON would package these \n's (CRLF) for you.

• Error "ORA-01861: literal does not match the format ORA-06512 string.

  Hello
  I am getting error on EBS page when I click on the button
  
  I wrote the code in CO to insert values in table when the button is clicked
  
  but when I click the button it gives an error
  

  ORA-01861: literal does not match the format ORA-06512 string

  I think that his error of date format
  
  but I tried many styles of formatting but not yet able to fix it

  KAO

  You are right, that this is due to the error in the data type. Share the code that you have coded for button click here.

  Kind regards
  GYAN