Separation of the characters in a string

Similar Questions

• separate the characters in a string

  Hello

  Y at - it an easy way of seprerate characters in a string

  For example if I have a string 'abcdef '.

  I want to seprate it in an array of 7 elements, where each element is a character in the string.

  Thank you

  Hi reza_sed,

  the attached picture shows one solution.

  Mike

• Get all the characters in a string of 2nd

  Hello

  Know you what is CF do I need to get each character 2nd a string?  Basically, I have a string: w3f587j8a9.  I want to get every 2nd, 4th, 6th, 8th, 10th, ect...  So, the result would be 35789.  Of course the loop limit will be as 4 characters or something like that.

  Thank you.

  Something like that you mean?

  #newstr #.

• Changeparticular the characters of a string using regular expressions...

  Hi all
  I'm writing a function using the function of expression regular oracles REGEXP_REPLACE but I could not succeed until now.
  
  My problem is as follows, I have a text in a column say "Scott Sdfdfs Sdfd" I want to replace all the s and S with X characters and make the text looks like "XdfXdf XdfdfX Xdfd".
  
  It is possible by using regular expressions in oracle?
  Can you give me some clue?
  
  Thank you

  select
    regexp_replace('sdfsdf Sdfdfs Sdfd',
                   's|S', 'X') Replaced
  from dual;
  

  REPLACED
  ------------------
  XdfXdf XdfdfX Xdfd 
  

• How to extract the characters of mixed string?

  "I have a string like ' ORA123CLE * () ^ % ^ & NET + -* / WORK"

  I need output like-> ORACLENETWORK

  Hello Bharathoracle

  SELECT REGEXP_REPLACE (' (ORA123CLE) * ^ % ^ & NET + -* / WORK ',' [^ [: alpha:]]', ") FROM DUAL;

  Kind regards

  David

• To delete the characters only at the beginning of a string using regexp_replace

  I want to be able to delete the characters in a string only until the first numeric value.  If it takes place after the digital, I want to keep them.

  "for example"AB1234' becomes '1234', 'AB1234C' becomes ' 1234 C.

  It might be also spaces and other types of characters at the beginning.  I tried this:

  Select

  regexp_replace ('ABC1234', ' [^ [: digit:]]').

  regexp_replace ('AB 1234',' [^ [: digit:]]').

  regexp_replace ('AB 01234',' [^ [: digit:]]').

  regexp_replace ('AB1234C', ' [^ [: digit:]]').

  regexp_replace ('^ 1234', ' [^ [: digit:]]').

  regexp_replace ('* #1234Z ',' [^ [: digit:]]')

  OF THE DOUBLE

  For all except "AB 01234' returned '1234' so it retains the digital.    For "AB 01234' it returns correctly '01234'

  The bad are those with a character after digital, for example "AB1234C".

  I know it I'm missing something here, can someone please help with this?

  Thank you

  SQL> with t
    2  as
    3  (
    4  select 'ABC1234' str from dual
    5  union all
    6  select 'AB 1234' str from dual
    7  union all
    8  select 'AB 01234' str from dual
    9  union all
   10  select 'AB1234C' str from dual
   11  union all
   12  select '^1234' str from dual
   13  union all
   14  select '*#1234Z' str from dual
   15  )
   16  select str
   17       , regexp_replace(str, '^[^[:digit:]]+') str_new
   18    from t;
  
  STR      STR_NEW
  -------- --------
  ABC1234  1234
  AB 1234  1234
  AB 01234 01234
  AB1234C  1234C
  ^1234    1234
  *#1234Z  1234Z
  
  6 rows selected.
  

• How to remove the first few characters of a string of liquid

  I would like to delete the first three characters of a string of liquid. The question is how.

  If I use the markup according to liquid when I know what are the first characters

  {{it. {{["Estate status'] | strip_html | remove_first:"11."}}

  It will remove the 11 characters.

  But if I don't know what are the first characters, this markup can I use to get "RID" of the first three characters?

  I tried 'split' and 'slice', but it must always know what characters to split or slice.

  Thanks for any help.

  Kind regards

  Carla

  Assign a value into slices and you can have table data that you can get out.

• Bunch of Oracle on the special characters in a string - translate?

  How to remove special characters in a string, it can contain. , (space), etc.

  SELECT TRANSLATE('123.456 (90-90)', '', '') FROM DUAL
  

  Basically I want to undress and to compare with the db value.

  WHERE TRANSLATE(TABLE.NUMCODE, '', '')  = TRANSLATE('123.456 (90-90)', '', '') 
  

  Use TRANSLATE, since you're on 9i. For example:

  TRANSLATE (your_string,'X,. #! % @$ ^ & * () _-+=', 'X')

  Removes all the s characters in ', #! % @$ ^ & * () _-+=' of your_string.

  SY.

• work with strings, substring, pulling the characters after a certain word

  Hello please see this string:

  var String1:String = "we invite you to join our celebration of the world day of intellectual property 2015 brain where: 149 Swan St., Buffalo, NY 14203 handlebars when: Thursday, April 23, 2015, 05:30 - 19:30 there will be drink specials and complimentary hors d'oeuvres!" And prizes! ";

  What I want to do is to remove all characters after the word ' where: ' in a string so that it hits "when:" & do the same thing to grab the string of the moment: until it hits PM

  What is the best way to do it?

  Thanks in advance.

  String.indexOf allows you to find the position of a string in the main string, substr years or a substring out pieces. Something like this:

  trace (string1. Substring (string1. IndexOf("WHERE:") + 6, String1.indexOf ('When :")));

  trace (string1. Substring (string1. IndexOf("When:") + 5, String1.indexOf ("PM") + 2));

• How to divide the characters in table 1 d

  I am looking for a way to divide the 'print' to a string 1-d subarray. For example instead of:

  1 / AAAABBBB

  2 / CCCCDDDD

  3 / EEEEFFFF

  ...

  etc.

  then there would be two tables 1 d separated where before there was a:

  1 / AAAA and BBBB

  2 / CCCC and Delalande

  3 / EEEE and FFFF

  ...

  etc.

  Something like that?

  

  You need better on where the split to take place?  I doubt somehow you want just a simple divided into a constant place.

• Remove 10 characters of this string

  How to remove the last 10 characters of any string?

  

  \

  Keep throwing me these easier!

• Is there a function to adjust the length of a string to 8 multiple bytes?

  Hello

  I have a function to encrypt a password.

  FUNCTION encodeit (p_name IN VARCHAR2, p_password IN VARCHAR2) RETURN VARCHAR2
     IS
        l_password   VARCHAR2 (4000);
        l_salt       VARCHAR2 (4000) := 'hdjikndbbhitasuihfnnkqyhiplwmneuyndnloidj';
     BEGIN
        l_password :=
           UTL_RAW.cast_to_raw (
              DBMS_OBFUSCATION_TOOLKIT.md5 (
                 input_string => p_password ||
                                 SUBSTR (l_salt, 10, 13)||
                                 LOWER (p_name)||
                                 SUBSTR (l_salt, 4, 10)));
        RETURN l_password;
     END;
  

  I want to decrypt the password to send to users when they forget it.  I wrote this function:

  FUNCTION decodeit (p_name IN VARCHAR2, p_password in VARCHAR2) RETURN VARCHAR2 IS
      l_salt       VARCHAR2 (4000) := 'hdjikndbbhitasuihfnnkqyhiplwmneuyndnloidj';
      BEGIN
        RETURN DBMS_OBFUSCATION_TOOLKIT.desdecrypt(input_string =>  p_password ||
                                                                    SUBSTR (l_salt, 10, 13)||
                                                                    LOWER (p_name)||
                                                                    SUBSTR (l_salt, 4, 10),
                                                   key_string   => l_salt) ;
      END;
  

  The problem is that the DBMS_OBFUSCATION_TOOLKIT.desdecrypt function needs a multiple of the input string of 8 bytes. And p_name and p_password are not of fixed length. Is there a function to adjust the length of a string to 8 multiple bytes?

  Best regards.

  They used to work - could be almost ten years (I think version 9 - not tested yet)

  As you can see, you can 'encode' the number of characters, padded in order to set the right length of the decrypted string

  
  

  create or replace FUNCTION ' CRYPTIN "(p_str in varchar2) return varchar2 as". "

  l_data VARCHAR2 (255);

  function pad_DES (p_string in varchar2) return varchar2 is

  -platelets p_string with pad_chr containing the number of characters padded (1 to 8)

  -make the string length a multiple of 8 as required by decipher

  pad_length pls_integer;

  pad_char char: = chr (0);

  pad_chars varchar2 (8);

  Start

  pad_length: = 8 - mod (length (p_string), 8);

  pad_chars: = chr (pad_length);

  Return concat (p_string, rpad (pad_chars, pad_length, pad_chars));

  end;

  Start

  l_data: = pad_DES (p_str);

  dbms_obfuscation_toolkit. Decrypt (input_string-online l_data, key_string => 'MagicKey' encrypted_string-online l_data);

  return UTL_RAW. CAST_TO_RAW (l_data);

  end;

  create or replace FUNCTION ' CRYPTOUT "(p_str in varchar2) return varchar2 as". "

  l_data VARCHAR2 (255);

  function unpad_DES (p_string in varchar2) return varchar2 is

  -Removes from p_string upholstered characters (1 to 8)

  pad_length pls_integer;

  Start

  pad_length: = length (p_string);

  pad_length: = pad_length - ascii (substr(p_string,pad_length,1));

  Return substr(p_string,1,pad_length);

  end;

  Start

  l_data: = p_str;

  dbms_obfuscation_toolkit. DESDecrypt (input_string-online l_data, key_string => 'MagicKey', decrypted_string-online l_data);

  Return unpad_DES (l_data);

  end;

  Concerning

  Etbin

• Advice on the use of APEX_JSON with a CLOB in the body as a string

  Hello all and thanks for any help in advance.

  I have the task of liaising with a 3rd party API via JSON to send information to our database.  First warning is the HOST for us is not and race so I have no way of properly this test until tomorrow, but I wanted to ask this question to try to overcome a potential problem.

  In the body of the JSON object, we must add a chunk of xml (already created/kept or can be created on the fly) and it must be validated on as a long string.  Now, this question is that the string can be up to 20000 characters long so when its processed is stored as a CLOB in the database (not made by me).

  Now my thoughts early to do this was to create a procedure allowing certain parameters get the relevant piece of data and xml stored as a CLOB.  Then and that's where I maybe need some tips, follow these steps.

  This host requires JSON in this format

  {

  'batchcode': 1234562,

  'XML string': 'THIS WILL BE a MASSIVE XML STRING',

  ""bounding ":" ",".

  "ID": "123456465",

  'field1 ':

  .

  .

  etc.

  }

  We currently have a few apex applications so I got a good look at the documentation and allows to generate the required using JSON:

  Thus to collect information of input parameters

  APEX_JSON. INITIALIZE_CLOB_OUTPUT;

  APEX_JSON. OPEN_OBJECT();

  APEX_JSON. WRITE ("batchcode," value from database");

  APEX_JSON. WRITE ("XML string ', our xml database that is stored as a CLOB string");

  APEX_JSON. WRITE (bounding "," value of database");

  APEX_JSON. WRITE ('ID', 'Value of database');

  .

  .

  .

  etc.

  APEX_JSON. CLOSE_OBJECT();

  Then validate using endpoint:

  APEX_WEB_SERVICE. () MAKE_REST_REQUEST

  p_url = > 'URL of the end point. "

  p_http_method = > 'MESSAGE ',.

  p_username = > API_USER,

  p_password = > API_KEY,.

  p_body = > apex_json.get_clob_output

  );

  Now assuming that my method is correct only the APEX_JSON. WRITING literally accept its entry as a type CLOB and he will be able to properly analyze or will it arrive at a mansion that will actually write the string itself?

  Edit I found that if I APEX_JSON. WRITE ("XML", "CLOB table column") that it exported the CLOB but not in the format I want.  This is due to the fact that my CLOB has characters like <>etc in II and the output is burning out in unicode, so for example <? XML version = "1.0" encoding = "UTF-8"? "> as stored in the object CLOB becomes \u003C?xml version=\"1.0\ ' encoding =------"UTF - 8\ '? \u003E\n in the output using APEX_JSON. To write.

  The only other way to do it, I think it is so divided in pieces as follows:

  SELECT ROWNUM as XML_PIECE_NO, TO_CHAR (SUBSTR (a.xmldoc, (ROWNUM-1) * 4000, 4000)) AS SECTION

  Of ast_xmldata one

  CONNECT (ROWNUM-1) * 4000 < = LENGTH (a.xmldoc)

  Then maybe concat in the JSON long xml string field.

  I hope I have explained what I want to do but if not please respond any help will be greatly appreciated.

  Concerning

  Post edited by: K4E

  EDIT I CAME FROM WITH a SOLUTION

  Post edited by: K4E - found solution 02/04/2016

  Thanks for the response of Christian, logical exit that way.

  Through some trial and error, I found a solution to my problem that seems effective enough without having to worry about unicode characters written.  There is seemingly a procedure without papers in the APEX_JSON package called apex_json.write_raw that does what it says.  All I had to do then was to use escape characters in my CLOB for things like "then I get a few good valid JSON in the format of the API, I work with love."

  Hope this helps someone else with the situation.

  K4E

• Formula to replace characters in a string

  Hi all

  Is it possible to replace characters in a string somewhere if the string has no specific pattern for these characters? I use the replacestr function to replace characters in a string (i.e. ABC), but the chain is in the ABC format * where * are two random characters. The result I'm looking for is to replace ABC * with the NodeID.

  ReplaceStr (propvalue (Core.Abbrev), ABC, ID (), T),) This formula works, but is either two additional characters in the end, after ABC. How can I cut that?

  Thank you

  If)

  Not (Equals (Integer, length (PropValue (Core.ABBREV)), length (ReplaceStr (PropValue (Core.ABBREV), ABC, T))),

  ReplaceStr (PropValue (Core.Abbrev), PropValue (Core.Abbrev), ID (), T),

  PropValue (Core.Abbrev)

  )

• get the length of each string in a column

  Hi all

  Is there a way to get the length of each string in a column:

  for example:

  If the table contains lines like below:

  Select 'test test1 test31' col1 of double

  Union of all the

  Select 'sectest1 sectest234' double col1

  The output should be as below:

  col1

  ------------

  4 5 6

  8 10

  That is to say get the count of each separated from the chain of space in a column. Is this possible using regexpr_substr?

  Thanks in advance.

  Roy.

  Try the below

  SELECT LISTAGG(val1,' ') IN ONE GROUP)

  New_val ORDER BY lvl)

  Of

  (SELECT LENGTH (REGEXP_SUBSTR (col1,'[^] +', 1, LEVEL)) val1,)

  RN,

  LEVEL lvl

  Of

  (SELECT col1,

  ROWNUM rn

  Of

  (SELECT 'test test1 test31' col1 OF double)

  UNION ALL

  SELECT 'sectest1 sectest234' double col1

  )

  )

  CONNECT BY LEVEL<= regexp_count(col1,'="">

  AND PRIOR rn = rn

  AND PRIOR DBMS_RANDOM. VALUE IS NOT NULL

  )

  GROUP BY rn;

  OUTPUT:-

  =======

  col1

  ----

  4 5 6

  8 10

  Thank you

  Ann