Simplify this query
When I run this query, it will be 1 hour to run it. can we change this query to do this?SELECT /*+ CHOOSE */a.*, b.*
FROM (SELECT ( TO_DATE (ucraudt_new_value, 'DD-MON-YYYY')
- TO_DATE (ucraudt_old_value, 'DD-MON-YYYY')
) AS diff,
ucraudt.*
FROM ucraudt
WHERE ucraudt_column_code = '1GED'
AND ucraudt_new_value IS NOT NULL
AND ucraudt_old_value IS NOT NULL
AND ucraudt_user_id LIKE 'UCPVCRV%') a,
ucrserv b
WHERE a.diff > 74
AND a.ucraudt_cust_code = b.ucrserv_cust_code
AND a.ucraudt_prem_code = b.ucrserv_prem_code
AND b.ucrserv_status_ind = 'A'
Try following
SELECT
a.*, b.*
FROM
ucraudt a,
ucrserv b
WHERE (TO_DATE (a.ucraudt_new_value, 'DD-MON-YYYY') - TO_DATE (a.ucraudt_old_value, 'DD-MON-YYYY')) > 74
AND a.ucraudt_cust_code = b.ucrserv_cust_code
AND a.ucraudt_prem_code = b.ucrserv_prem_code
AND b.ucrserv_status_ind = 'A'
and a.ucraudt_column_code = '1GED'
AND a.ucraudt_new_value IS NOT NULL
AND a.ucraudt_old_value IS NOT NULL
AND a.ucraudt_user_id LIKE 'UCPVCRV%'
Also post the query execution plan
Tags: Database
Similar Questions
-
Can anyone simplify this query
Here's a DOF from two tables
1. CREATE TABLE (EMPL)
NUMBER OF SNO
ENAME VARCHAR2 (25).
USE VARCHAR2 (25).
KEY ELEMENTARY SCHOOL (SNO)
);
2. CREATE TABLE EMPL_DET)
NUMBER OF SNO
SAL VARCHAR2 (25)
);
Here are tables LMD
INSERT INTO EMPL (SNO, ENAME, JOB) VALUES (1, 'SMITH', 'CLERK');
INSERT INTO EMPL (SNO, ENAME, JOB) VALUES (2, 'SMITH', 'MANAGER');
INSERT INTO EMPL (SNO, ENAME, JOB) VALUES (3, 'TOM', 'CLK');
INSERT INTO EMPL_DET (SNO, SAL) VALUES (1, '1000');
INSERT INTO EMPL_DET (SNO, SAL) VALUES (2, "10000");
INSERT INTO EMPL_DET (SNO, SAL) VALUES (3, '900');
I want to calculate TotalSAL (column: empl_det.) SAL) of each employee (empl.ename) with job-description (empl.job).
Means I want following the lines of output
1.(Job,TotalSAL,Ename)-> (CLERK, 11000, SMITH)
2->.(Job,TotalSAL,Ename) (MANAGER, 11000, SMITH)
3->.(Job,TotalSAL,Ename) (CLK, 900, TOM)
I tried to write down to unique ename
Select JOB, x.sal, ename in empl,
(
Select sum (sal) sal empl_det where sno in
(select sno to empl where ename = 'SMITH')
) x
where ename = 'SMITH '.
order by ename
each ename, I draw from this query. How can I make the ename list (TOM SMITH) to this request?
Or can anyone simplify this query?Hello
in this case, you need to use is analytical functions:
that is to say:
SELECT e.job, SUM (d.sal) OVER (PARTITION BY e.ename) AS "TotalSal" , e.ename FROM empl e, empl_det d WHERE d.sno = e.sno AND e.ename IN ('SMITH', 'TOM') ORDER BY e.ename; JOB TotalSal ENAME ------------------------- ---------- ------------------------- CLERK 11000 SMITH MANAGER 11000 SMITH CLK 900 TOMKind regards.
AlPublished by: Alberto Faenza on 27 November 2012 15:34
Corrected query -
How to simplify this query in sql simple select stmt
Hello
Please simplify the query
I want to convert this query in a single select statement. Is this possible?
If uarserq_choice_ind is not null then
Select ubbwbst_cust_code
From ubbwbst,utrchoi
Where utrchoi_prop_code=ubbwbst_cancel_prod
Else
Select max(utvsrvc_ranking)
From utvsrvc,ubbwbst
Where utvsrvc_code=ubbwbst_cancel_prod
End ifSelect ubbwbst_cust_code as val From ubbwbst,utrchoi Where utrchoi_prop_code=ubbwbst_cancel_prod AND uarserq_choice_ind is not null union all Select max(utvsrvc_ranking) as val From utvsrvc,ubbwbst Where utvsrvc_code=ubbwbst_cancel_prod and uarserq_choice_ind is nullWithout more information, we are unable to combine the two queries in 1 without a union.
Looks like you select values totally disperate of totally different tables -
[8i] not to simplify this query?
In my application, I need to pick up three possible prices for each part number in an array.
The three possible prices that I need to recover are:
(1) the price paid on the order more recently closed,
(2) the price mentioned on the first pending order, and
(3) the price on the furthest on pending order.
However, there is a complication in that. Orders include the part number, but may also include a prefix of 4 characters (always the same) on a reference number which should be treated the same as the reference database. For example, "DSB-part1" should be considered "part1", "DSB-part2" should be regarded as 'part 2', etc.
In addition, it is quite possible for several orders expected or closed on the same day, and I want to only return the price of one of these lines for each of the 3 methods of pricing.
(Technically, there is another level of complication to this, but if I have problems with it later, I'll create a new job for him...)
Some examples of data:
And here's my ugly query to get the results I want. It can be simplified?CREATE TABLE part ( part_no VARCHAR2(9) NOT NULL, part_desc VARCHAR2(25), qty_instock NUMBER, CONSTRAINT part_pk PRIMARY KEY (part_no) ); INSERT INTO part VALUES ('part1 ','description 1 here',5); INSERT INTO part VALUES ('part2 ','description 2 here',10); INSERT INTO part VALUES ('part3 ','description 3 here',0); CREATE TABLE ords ( ord_no NUMBER NOT NULL, ord_part_no VARCHAR2(9), date_closed DATE, orig_dock_date DATE, date_due_instock DATE, unit_price NUMBER, qty_order NUMBER, ord_stat VARCHAR2(2), CONSTRAINT ords_pk PRIMARY KEY (ord_no) ); INSERT INTO ords VALUES (1,'part1 ',To_Date('01/01/2009','mm/dd/yyyy'),To_Date('12/01/2008','mm/dd/yyyy'),To_Date('12/15/2008','mm/dd/yyyy'),100,10,'CL'); INSERT INTO ords VALUES (2,'part1 ',To_Date('01/31/2009','mm/dd/yyyy'),To_Date('01/01/2009','mm/dd/yyyy'),To_Date('01/05/2009','mm/dd/yyyy'),105,15,'CL'); INSERT INTO ords VALUES (3,'part1 ',To_Date('01/31/2009','mm/dd/yyyy'),To_Date('01/15/2009','mm/dd/yyyy'),To_Date('01/20/2009','mm/dd/yyyy'),100,20,'CL'); INSERT INTO ords VALUES (4,'part1 ',To_Date('12/31/1900','mm/dd/yyyy'),To_Date('01/15/2009','mm/dd/yyyy'),To_Date('01/25/2009','mm/dd/yyyy'),103,10,'OP'); INSERT INTO ords VALUES (5,'ORD-part1',To_Date('12/31/1900','mm/dd/yyyy'),To_Date('01/20/2009','mm/dd/yyyy'),To_Date('01/31/2009','mm/dd/yyyy'),101,10,'OP'); INSERT INTO ords VALUES (6,'ORD-part2',To_Date('01/01/2009','mm/dd/yyyy'),To_Date('12/01/2008','mm/dd/yyyy'),To_Date('12/15/2008','mm/dd/yyyy'),100,10,'CL'); INSERT INTO ords VALUES (7,'part2 ',To_Date('01/31/2009','mm/dd/yyyy'),To_Date('01/01/2009','mm/dd/yyyy'),To_Date('01/05/2009','mm/dd/yyyy'),105,15,'CL'); INSERT INTO ords VALUES (8,'ORD-part2',To_Date('01/31/2009','mm/dd/yyyy'),To_Date('01/15/2009','mm/dd/yyyy'),To_Date('01/20/2009','mm/dd/yyyy'),100,20,'CL'); INSERT INTO ords VALUES (9,'part2 ',To_Date('12/31/1900','mm/dd/yyyy'),To_Date('01/15/2009','mm/dd/yyyy'),To_Date('01/25/2009','mm/dd/yyyy'),103,10,'OP'); INSERT INTO ords VALUES (10,'ORD-part2',To_Date('12/31/1900','mm/dd/yyyy'),To_Date('01/20/2009','mm/dd/yyyy'),To_Date('01/31/2009','mm/dd/yyyy'),101,10,'OP'); INSERT INTO ords VALUES (11,'part3 ',To_Date('01/01/2009','mm/dd/yyyy'),To_Date('12/01/2008','mm/dd/yyyy'),To_Date('12/15/2008','mm/dd/yyyy'),100,10,'CL'); INSERT INTO ords VALUES (12,'part3 ',To_Date('01/31/2009','mm/dd/yyyy'),To_Date('01/01/2009','mm/dd/yyyy'),To_Date('01/05/2009','mm/dd/yyyy'),105,15,'CL'); INSERT INTO ords VALUES (13,'ORD-part3',To_Date('01/31/2009','mm/dd/yyyy'),To_Date('01/15/2009','mm/dd/yyyy'),To_Date('01/20/2009','mm/dd/yyyy'),100,20,'CL'); INSERT INTO ords VALUES (14,'ORD-part3',To_Date('12/31/1900','mm/dd/yyyy'),To_Date('01/15/2009','mm/dd/yyyy'),To_Date('01/25/2009','mm/dd/yyyy'),103,10,'OP'); INSERT INTO ords VALUES (15,'part3 ',To_Date('12/31/1900','mm/dd/yyyy'),To_Date('01/20/2009','mm/dd/yyyy'),To_Date('01/31/2009','mm/dd/yyyy'),101,10,'OP');
And here are the results, I expect to get, according to data from the sample:SELECT p.part_no , p.part_desc , p.qty_instock , a2.unit_price AS last_closed_price , a2.qty_order AS last_closed_qty , a2.date_closed AS last_closed_date , b2.unit_price AS first_open_price , b2.qty_order AS first_open_qty , b2.date_due_instock AS first_open_date , c2.unit_price AS last_open_date , c2.qty_order AS last_open_qty , c2.date_due_instock AS last_open_date FROM part p , ( SELECT lc.part_no , lc.unit_price , lc.qty_order , lc.date_closed , ROW_NUMBER() OVER(PARTITION BY lc.part_no ORDER BY lc.orig_dock_date DESC) AS rnk_nbr FROM ( SELECT CASE WHEN SUBSTR(o.ord_part_no,1,4) = 'ORD-' THEN SUBSTR(o.ord_part_no,5) ELSE o.ord_part_no END AS part_no , o.date_closed , o.orig_dock_date , o.unit_price , o.qty_order FROM ords o ) lc --for last closed , ( SELECT a.part_no , MAX(a.date_closed) AS last_closed_date FROM ( SELECT CASE WHEN SUBSTR(o.ord_part_no,1,4) = 'ORD-' THEN SUBSTR(o.ord_part_no,5) ELSE o.ord_part_no END AS part_no , o.date_closed FROM ords o ) a GROUP BY a.part_no ) a1 WHERE lc.part_no = a1.part_no AND lc.date_closed = a1.last_closed_date ) a2 , ( SELECT fo.part_no , fo.unit_price , fo.qty_order , fo.date_due_instock , ROW_NUMBER() OVER(PARTITION BY fo.part_no ORDER BY fo.orig_dock_date DESC) AS rnk_nbr FROM ( SELECT CASE WHEN SUBSTR(o.ord_part_no,1,4) = 'ORD-' THEN SUBSTR(o.ord_part_no,5) ELSE o.ord_part_no END AS part_no , o.date_due_instock , o.orig_dock_date , o.unit_price , o.qty_order FROM ords o WHERE o.ord_stat = 'OP' ) fo --for first open , ( SELECT b.part_no , MIN(b.date_due_instock) AS first_open_date FROM ( SELECT CASE WHEN SUBSTR(o.ord_part_no,1,4) = 'ORD-' THEN SUBSTR(o.ord_part_no,5) ELSE o.ord_part_no END AS part_no , o.date_due_instock FROM ords o WHERE o.ord_stat = 'OP' ) b GROUP BY b.part_no ) b1 WHERE fo.part_no = b1.part_no AND fo.date_due_instock = b1.first_open_date ) b2 , ( SELECT lo.part_no , lo.unit_price , lo.qty_order , lo.date_due_instock , ROW_NUMBER() OVER(PARTITION BY lo.part_no ORDER BY lo.orig_dock_date DESC) AS rnk_nbr FROM ( SELECT CASE WHEN SUBSTR(o.ord_part_no,1,4) = 'ORD-' THEN SUBSTR(o.ord_part_no,5) ELSE o.ord_part_no END AS part_no , o.date_due_instock , o.orig_dock_date , o.unit_price , o.qty_order FROM ords o WHERE o.ord_stat = 'OP' ) lo --for last open , ( SELECT c.part_no , MAX(c.date_due_instock) AS last_open_date FROM ( SELECT CASE WHEN SUBSTR(o.ord_part_no,1,4) = 'ORD-' THEN SUBSTR(o.ord_part_no,5) ELSE o.ord_part_no END AS part_no , o.date_due_instock FROM ords o WHERE o.ord_stat = 'OP' ) c GROUP BY c.part_no ) c1 WHERE lo.part_no = c1.part_no --EDIT: changed from l1 to c1 AND lo.date_due_instock = c1.last_open_date --EDIT: changed from l1 to c1 ) c2 WHERE p.part_no = a2.part_no AND a2.part_no = b2.part_no AND b2.part_no = c2.part_no AND a2.rnk_nbr = 1 AND b2.rnk_nbr = 1 AND c2.rnk_nbr = 1
Published by: user11033437 on February 5, 2010 08:48. LAST_ LAST_ LAST_ FIRST_ FIRST_ FIRST_ LAST_ LAST_ LAST_ . QTY_ CLOSED_ CLOSED_ CLOSED_ OPEN_ OPEN_ OPEN_ OPEN_ OPEN_ OPEN_ PART_NO PART_DESC INSTOCK PRICE QTY DATE PRICE QTY DATE PRICE QTY_ DATE_ --------------------------------------------------------------------------------------------------------------------------------- part1 description 1 here 5 100 20 1/31/2009 103 10 1/25/2009 101 10 1/31/2009 part2 description 2 here 10 100 20 1/31/2009 103 10 1/25/2009 101 10 1/31/2009 part3 description 3 here 0 100 20 1/31/2009 103 10 1/25/2009 101 10 1/31/2009
Correction of errors (see the comments in the request above for changes)Hello
It is a little bit shorter than what you have posted, probably more effective and (in my opinion) much easier to debug and maintain:
SELECT p.part_no , p.part_desc , p.qty_instock , o.last_closed_price , o.last_closed_qty , o.last_closed_date , o.first_open_price , o.first_open_qty , o.first_open_date , o.last_open_price , o.last_open_qty , o.last_open_date FROM part p , ( -- Begin in-line view o for pivoted order data SELECT part_no , MAX (CASE WHEN lc_num = 1 THEN unit_price END) AS last_closed_price , MAX (CASE WHEN lc_num = 1 THEN qty_order END) AS last_closed_qty , MAX (CASE WHEN lc_num = 1 THEN date_closed END) AS last_closed_date , MAX (CASE WHEN fo_num = 1 AND ord_stat = 'OP' THEN unit_price END) AS first_open_price , MAX (CASE WHEN fo_num = 1 AND ord_stat = 'OP' THEN qty_order END) AS first_open_qty , MAX (CASE WHEN fo_num = 1 AND ord_stat = 'OP' THEN date_due_instock END) AS first_open_date , MAX (CASE WHEN lo_num = 1 AND ord_stat = 'OP' THEN unit_price END) AS last_open_price , MAX (CASE WHEN lo_num = 1 AND ord_stat = 'OP' THEN qty_order END) AS last_open_qty , MAX (CASE WHEN lo_num = 1 AND ord_stat = 'OP' THEN date_due_instock END) AS last_open_date FROM ( -- Begin in-line view to get lc_, fo_, lo_num SELECT gpo.* , ROW_NUMBER () OVER ( PARTITION BY part_no ORDER BY date_closed DESC , ord_no DESC ) AS lc_num , ROW_NUMBER () OVER ( PARTITION BY part_no ORDER BY CASE WHEN ord_stat = 'OP' THEN 1 ELSE 2 END , orig_dock_date , ord_no ) AS fo_num , ROW_NUMBER () OVER ( PARTITION BY part_no ORDER BY CASE WHEN ord_stat = 'OP' THEN 1 ELSE 2 END , orig_dock_date DESC , ord_no DESC ) AS lo_num FROM ( -- Begin in-line view gpo to get part_no SELECT ords.* , RTRIM ( CASE WHEN ord_part_no LIKE 'ORD-%' THEN SUBSTR (ord_part_no, 5) ELSE ord_part_no END ) AS part_no FROM ords ) gpo -- End in-line view gpo to get part_no ) -- End in-line view to get lc_, fo_, lo_num GROUP BY part_no ) o -- End in-line view o for pivoted order data WHERE RTRIM (p.part_no) = o.part_no ORDER BY p.part_no ;Whenever you want to have a WHERE clause only applies to certain columns, think about a pivot and expression BOX.
Is there a reason to have raw triling part_no or ord_part_no?
Published by: Frank Kulash, February 5, 2010 13:26
After this announcement, I saw that Max had posted essentially the same query.
In general, where the solution of Max seems more simple, I like her way better.
The only possible exception is tested for "OP" at the derivation of the values first_open and last_open. If none of the lines to an ord_stat part_no = "OP", solution of Max will be used a the lines with another ord_stat. That does not occur in the sample data, and I don't know if this is still possible in your application, but if this is the case, I don't know this isn't what you want. -
Hello
I have a query like this:
Merge into the table st1
using (select * from (select pk, value, diff_value, m_date, row_number () over (PARTITION pk ORDER BY diff_value) rnk)
from (select distinct / * + Full (t1) full (t2) * / t1.pk, t2.m_date)
, Case when (t1.m_date = t2.m_date) then "CORRESPONDENCE".
When (t2.m_date BETWEEN t1.m_date-1 and t1.m_date + 1) then ' MATCHED WITH +/-1gg.
When (t2.m_date BETWEEN t1.m_date-2 and t1.m_date + 2) then "MATCHED WITH +/-2 days.
else "
end value_match
Case when (t1.m_date = t2.m_date) then 0
Where (t2.m_date BETWEEN t1.m_date + 1 and t1.m_date - 1) then 1
Where (t2.m_date BETWEEN t1.m_date + 1 and t1.m_date - 1) then 2
else "
end diff_value
of table t2, t1 table
where t1.value is null
and t1.id = t2.id)
where value_match is not null)
where rnk = 1) s
on (st1.pk = s.pk)
WHEN MATCHED THEN
Update set st1.value = s.value_match, st1.diff_value = s.diff_value, st1.up_date = s.m_date
where st1.value is null.
Explain the plan:
Table1 a record 3Million and table 2 has 1 million records.
I used gather stats before you run this query and 'Full' trick, even in this case, he is running for 45 minutes.
Please suggest the best solution to optimize this query.
Thanks in advance.
Remove the tips.
No need for the separate.
Get the diff by ceil (abs(t2.m_date-t1.m_date)) and the filter for that where value_diff<>
Assing the statement ".. MATCHED" lately in the update clause.
Maybe give exactly to your needs with a small example may be the query may be getting more simplified or not what you want it to do.
-
How to write this query in the hierarchy
Hi gurus,
Really need your help on this query. Thank you very much in advance.
SELECT t1.key as root_key , (SELECT t2.unit_id AS unit_id level-1 AS level , t2.name, t2.creator FROM tab t2 START WITH t2.unit_id = t1.unit_id -----check each node as root CONNECT BY prior t2.unit_id = t2.parent_unit_id ) t1.name as parent_unit_name FROM tab t1
I'll write a query of the hierarchy as above, and that EACH line (node, totally more than 10200) is checked as root node to see how many sheets are accessible for her... It must be implemented in a single query.
I know inline query should NOT return multiple rows or multiple columns, but the inline elements are necessary and can certainly be made in a correct solution.
(env):
Database Oracle 12 c Enterprise Edition Release 12.1.0.2.0 - 64 bit Production
PL/SQL Release 12.1.0.2.0
)
Test data:
select 1 as unit_id, null as parent_organization_unit_id, 'U1' as name from dual union all select 2, 1, 'U2' FROM DUAL UNION ALL SELECT 3, NULL, 'U3' FROM DUAL UNION ALL SELECT 4, 3, 'U4' FROM DUAL UNION ALL SELECT 5, 2, 'U5' FROM DUAL UNION ALL SELECT 6, 5, 'U6' FROM DUAL UNION ALL SELECT 7, 6, 'U7' FROM DUAL UNION ALL SELECT 8, 5, 'U8' FROM DUAL UNION ALL SELECT 9, 5, 'U9' FROM DUAL;
Final result should be like this
key unit_id, level, name, parent_name 1 1 0 u1 u1 1 2 1 u2 u1 1 5 2 u5 u1 1 6 3 u6 u1 1 7 4 u7 u1 1 8 3 u8 u1 1 9 3 u9 u1 2 2 0 u2 u2 2 5 1 u5 u2 2 6 2 u6 u2 2 7 3 u7 u2 2 8 2 u8 u2 2 9 2 u9 u2
Don't know how get you your output, it does not match your data...
with tab as)
Select 1 as unit_id, null as parent_organization_unit_id 'U1' as the name of double
Union of all the
Select 2, 1, 'U2' FROM DUAL
UNION ALL
SELECT 3, NULL, 'U3' FROM DUAL
UNION ALL
SELECT 4, 3, 'U4' FROM DUAL
UNION ALL
SELECT 5, 2, 'U5' OF THE DOUBLE
UNION ALL
SELECT 6, 5, 'U6' OF THE DOUBLE
UNION ALL
SELECT 7, 6, "U7" OF THE DOUBLE
UNION ALL
SELECT 8, 5, 'U8' FROM DUAL
UNION ALL
9. SELECT, 5, 'U9' FROM DUAL
)
Select dense_rank() key (order by connect_by_root unit_id), unit_id, level - 1 as 'LEVEL', connect_by_root name root_parent_name
t tab
Start with parent_organization_unit_id is null
Connect prior unit_id = parent_organization_unit_id
KEY UNIT_ID LEVEL ROOT_PARENT_NAME 1 1 0 "U1". 1 2 1 "U1". 1 5 2 "U1". 1 6 3 "U1". 1 7 4 "U1". 1 8 3 "U1". 1 9 3 "U1". 2 3 0 "U3". 2 4 1 "U3". -
How to optimize the performance of this query SQL
Hello
I need to find the age for each day, but I need for all previous dates in a single query. So I used the following query:
Select trunc (sysdate) - level + 1 DATE
trunc (sysdate) - level + 1 - created_date AGE
elements
connect by trunc (sysdate) - level + 1 - created_date > 0
I get output (FOR the DATE and AGE) that is fine and correct:
DATE AGE
--------- ----------
6 JULY 15 22
5 JULY 15 21
4 JULY 15 20
3 JULY 15 19
2 JULY 15 18
JULY 1, 15 17
JUNE 30, 15 16
JUNE 29, 15 15
JUNE 28, 15 14
JUNE 27, 15 13
JUNE 26, 15 12
25 JUNE 15 11
24 JUNE 15 10
Now I need to calculate the average age for each day and I added the average in the following query:
Select trunc (sysdate) - level + 1 DATE .
AVG (trunc (sysdate) - level + 1 - created_date) AVERAGE_AGE
elements
connect by trunc (sysdate) - level + 1 - created_date > 0
Group of trunc (sysdate) - level + 1
This query is correct? When I add the aggregate (avg) function to this query, it takes 1 hour to retrieve the data. When I remove the average request function that gives the result in 2 seconds? What is the solution to calculate the average without affecting performance? Help, please
Maybe you are looking for something like this...
SQL > ed
A written file afiedt.buf1 with t (point, created_date) :)
2 Select 1, date '' 2015-06-24 from all the double union
3 select 2, date ' 2015-06-29 the Union double all the
4 Select 3, date ' 2015-06-17' of the double
5 )
6 --
7. end of test data
8 --
9. Select item
10, trunc (sysdate) - level + 1 as dt
11, trunc (sysdate) - level + 1-created_date age
12, round (avg (trunc (sysdate) - level + 1 - created_date) on (trunc (sysdate) partition - level + 1), 2) as avg_in_day
13 t
14 connect by level<=>
15-point point = prior
sys_guid() 16 and prior is not null
17 * order by 1.2
SQL > /.
POINT DT AGE AVG_IN_DAY
---------- ----------- ---------- ----------
1 JUNE 24, 2015 0 3.5
1 25 JUNE 2015 1 4.5
1 26 JUNE 2015 2 5.5
1 27 JUNE 2015 3 6.5
1 28 JUNE 2015 4 7.5
1 29 JUNE 2015 5 5.67
1 30 JUNE 2015 6 6.67
1 1 JULY 2015 7 7.67
1-2 JULY 2015 8 8.67
1-3 JULY 2015 9 9.67
1 TO 4 JULY 2015 10 10.67
1 5 JULY 2015 11 11.67
1 6 JULY 2015 12 12.67
2 JUNE 29, 2015 5.67 0
2 30 JUNE 2015 1 6.67
2 1 JULY 2015 2 7,67
2 2 JULY 2015 3 8.67
2-3 JULY 2015 4 9.67
2-4 JULY 2015 5 10.67
2-5 JULY 2015 6 11.67
2-6 JULY 2015 7 12.67
3 JUNE 17, 2015 0 0
3 18 JUNE 2015 1 1
3 19 JUNE 2015 2 2
3 20 JUNE 2015 3 3
3 21 JUNE 2015 4 4
3 22 JUNE 2015 5 5
3 23 JUNE 2015 6 6
3 24 JUNE 2015 7 3.5
3 25 JUNE 2015 8 4.5
3 26 JUNE 2015 9 5.5
3 27 JUNE 2015 10 6.5
3 28 JUNE 2015 11 7.5
3 29 JUNE 2015 12 5.67
3 30 JUNE 2015 13 6.67
3 1 JULY 2015 14 7.67
3 2 JULY 2015 15 8.67
3 3 JULY 2015 16 9.67
3-4 JULY 2015 17 10.67
3-5 JULY 2015 18 11.67
3 6 JULY 2015 19 12.6741 selected lines.
-
Hi people,
I need to get a query in which a set of records, I get ONLY those which previous registry has a field with a value to this topic. Other values, the field can contain are not necessary.
I know that sounds easy but... I can't get it.
So, for Oracle 10 g 2... Here's my query:
SELECT a.person_id, a.person_status, a.message_id, a.order_id
OF t_HR one
WHERE a.person_status = "rejected".
AND a.id >
(SELECT max (b.id)
OF t_HR b
WHERE b.person_id = a.person_id
and b.order_id = a.order_id
AND b.person_status! "revised =".
B.ID AND < a.id)
ORDER BY desc a.id
Let me explain:
1 - HR table is a table of people. These people has serveral STATUS.
2 - ID is a sequential (each www.voyages-sncf.com has a different identification number).
3 - the application must get THAT all people "rejected".
4. - However, (subquery) I need ONLY those that previous register (the second register) holds a status of "OK". If the person holds a "revised" status he's not, he should be the next register (the third)
5.-L' ORDER ID DESC, so is the first register must have a STATUS = "rejected" and the second a 'OK '. IF the second register = "revised", then the third register must be 'OK '. And I need this query.
HOW DO?
My problem: the subquery gives you previous register of the same guy, but... it does not give you the value of the State, I need, which is 'OK '.
I tried to add to the subquery...
SELECT max (b.id)
OF mod_human_resource b
WHERE b.person_id = a.person_id
and b.order_id = a.order_id
AND b.person_status = 'OK '.
AND b.id < a.id
... but if I have 5 records of that person, the first is "rejected", the second is "accepted", the third is 'new' and the fourth is 'OK'... the subquery gives you the 4th register and which is not correct for me, it must be only the second one (prior to the first State registry).
I need to be a query, because I need to use it on a MERGER for a DWH.
If there is another way (function, or even a procedure) to make the MERGER rather than with a request, which would be ok too. I am poor DWH knowledge.
Thanks in advance.
Hello
So, you need to know if a line is the 'first' line, and you should also know what is the 'next' status, (even the 'first' and 'next' are already defined). This sounds like a job for analytical functions. ROW_NUMBER can tell you if a line is first or not, and LEAD can tell you what a value on the next row.
Since you post CREATE TABLE and INSERT statements for your own table, I'll use the table scott.emp to illustrate.
Consider these data from scott.emp:
SELECT DeptNo
ename
work
FROM scott.emp
ORDER BY deptno
ename DESC
;
Output:
DEPTNO ENAME JOB
---------- ---------- ---------
10 MILLER CLERK
PRESIDENT OF KING 10
MANAGER 10 CLARK
20 SMITH CLERK
ANALYST SCOTT 20
20 JONES MANAGER
20 FORD ANALYST
20 ADAMS CLERK
30 WARD SALESMAN
SELLER OF 30 TURNER
30 MARTIN SALESMAN
30 JAMES CLERK
MANAGER BLAKE 30
30 ALLEN SALESMAN
Now, let's say we want only who know the departments where the forefront (in order descending ename) a job = 'CLERK', and the following line (also in descending by ename order) = "ANALYST" job, and we want to know the ename of the first row. In other words, the correct output is:
DEPTNO ENAME
---------- ----------
20 SMITH
Note that deptno = 10 is not included, even if the first task is to "CLERK." that was because the second job in deptno = 10 is the "PRESIDENT", not "ANALYST."
Here's a way to get these results:
WITH got_analytics AS
(
SELECT ename, deptno, job
ROW_NUMBER () OVER (PARTITION BY deptno
ORDER BY ename DESC
) AS r_num
LEAD (employment) OVER (PARTITION BY deptno
ORDER BY ename DESC
) AS next_job
FROM scott.emp
)
SELECT deptno, ename
OF got_analytics
WHERE r_num = 1
AND job = 'CLERK '.
AND next_job = 'ANALYST '.
;
I hope that answers your question.
If this isn't the case, then, as Dan (and the FAQ forum) said, post CREATE TABLE and INSERT statements for some sample data and the exact results you want from these data.
Post your query, based on the one I have posted more top and ponit out where he gets results.
Always say what version of Oracle you are using (for example, 11.2.0.2.0).
See the FAQ forum: https://forums.oracle.com/message/9362002#9362002
-
Dialog box that says ' Creative Cloud Installer wants to make changes. Type your password for this purpose"- I type my password for Adobe ID (creative cloud), but it will not accept it. who should I go for help with this query?
It does not ask the cloud your computer admin password password!
-
What is the name of this query
Hi all
I want to know the name of this query to learn about it, because I don't understand how it works.
Select the columns tab "(select table columns)" table.
I saw him, but I don't know how it works.
Thanks in advance
It is a scalar subquery expression.
"An expression of scalar subquery is a subquery that returns exactly one column of a line."
The value of the scalar subquery expression is the value of the select item from the list of the subquery.
If the subquery returns 0 rows, then the value of the scalar subquery expression is NULL.
If the subquery returns more than one line, then Oracle returns an error. »
See:
http://docs.Oracle.com/CD/E16655_01/server.121/e17209/expressions013.htm#SQLRF52093
For example, we can write
Select empno,
Ename,
DEPTNO,
(select dname dept where deptno = emp.deptno) dname
WCP
order by empno
/
Instead of
Select e.empno,
e.Ename,
e.DEPTNO,
d.DNAME
from emp e,.
d Dep.
where e.deptno = d.deptno
order by empno
/
-
Need a help with this query max
Select SEARCH_ID, SEARCH_KEYWORD, ASSET_TYPE, COUNT of RELEVANCY_TABLE
where SEARCH_KEYWORD = 'search_keyword '.
and ASSET_TYPE is not null
558 search_keyword 3 Office 559 search_keyword 7 Table In fact, I have to get the asset_type which the count is the maximum. In this case, it should be "table". Any help?
adfSonal wrote:
Is there another way? I have to write this query in Java. So, I prefer avoiding rank or such functions.
I will not get the desired result using simply select, where, max, rownum clauses?
What do you mean by "I must write this query in Java? Means of the query will be run against a database of Oracle, correct?
Any means using ROWNUM
Select *.
de)
Select search_id
search_keyword
County
asset_type
of relevancy_table
where search_keyword = 'search_keyword '.
and asset_type is not null
Order
by count desc
)
where rownum = 1
-
This query may be fixed/rewritten?
Version: 11.2
The following query retrieves data from three sources. 1 query SELECT and 2 table (TAB1, tab 3) internal (TAB2).
The stats are updated in the tables involved. But this query is very slow. Any room for improvement?
This is the query
The plan of the explain commandselect sum(TAB2.N_AVL_BAL) as c1, sum(TAB2.N_AVL_BAL_LCY) as c2 from WMS_XTDI_CUST TAB1, ( SELECT A.* FROM WMS_XTF_ACCT_BALANCE A INNER JOIN WMS_STDI_REPFLAG C ON A.C_CRM_INST = C.C_CRM_INST AND A.N_LATEST_REC_SEQ = C.N_REP_FLAG) TAB2, WMS_XTDI_CUST_ACCT_REL TAB3 where (TAB1.C_CRM_INST = TAB3.C_CRM_INST and TAB1.ID_CUST = TAB3.ID_CUST and TAB2.C_ACCT_CCY = TAB3.C_ACCT_CCY and TAB2.C_CRM_INST = TAB3.C_CRM_INST and TAB2.C_SRC_SYST = TAB3.C_SRC_SYST and TAB2.X_ACCOUNT_NO = TAB3.X_ACCOUNT_NO and TAB1.X_RLSHIP_MGR_ID = '7883943')
SQL >---------------------------------------------------------------------------------------------------------------------------------------- | Id | Operation | Name | Rows | Bytes |TempSpc| Cost (%CPU)| Time | Pstart| Pstop | ---------------------------------------------------------------------------------------------------------------------------------------- | 0 | SELECT STATEMENT | | 1 | 92 | | 231K (2)| 00:46:16 | | | | 1 | SORT AGGREGATE | | 1 | 92 | | | | | | |* 2 | HASH JOIN | | 3527K| 309M| | 231K (2)| 00:46:16 | | | | 3 | PART JOIN FILTER CREATE | :BF0000 | 233 | 3262 | | 36 (0)| 00:00:01 | | | | 4 | TABLE ACCESS BY GLOBAL INDEX ROWID| WMS_XTDI_CUST | 233 | 3262 | | 36 (0)| 00:00:01 | ROWID | ROWID | |* 5 | INDEX RANGE SCAN | IDX_XT_CUST_08 | 233 | | | 3 (0)| 00:00:01 | | | |* 6 | HASH JOIN | | 2240K| 166M| 247M| 231K (2)| 00:46:15 | | | | 7 | PART JOIN FILTER CREATE | :BF0001 | 4556K| 195M| | 163K (2)| 00:32:44 | | | |* 8 | HASH JOIN | | 4556K| 195M| | 163K (2)| 00:32:44 | | | | 9 | PART JOIN FILTER CREATE | :BF0002 | 6 | 54 | | 3 (0)| 00:00:01 | | | | 10 | TABLE ACCESS FULL | WMS_STDI_REPFLAG | 6 | 54 | | 3 (0)| 00:00:01 | | | | 11 | PARTITION RANGE ALL | | 14M| 495M| | 163K (2)| 00:32:43 | 1 | 40 | | 12 | PARTITION LIST JOIN-FILTER | | 14M| 495M| | 163K (2)| 00:32:43 |:BF0002|:BF0002| | 13 | TABLE ACCESS FULL | WMS_XTF_ACCT_BALANCE | 14M| 495M| | 163K (2)| 00:32:43 | 1 | 400 | | 14 | PARTITION LIST AND | | 7096K| 223M| | 40133 (1)| 00:08:02 |KEY(AP)|KEY(AP)| | 15 | TABLE ACCESS FULL | WMS_XTDI_CUST_ACCT_REL | 7096K| 223M| | 40133 (1)| 00:08:02 |KEY(AP)|KEY(AP)| ---------------------------------------------------------------------------------------------------------------------------------------- Predicate Information (identified by operation id): --------------------------------------------------- 2 - access("TAB1"."C_CRM_INST"="TAB3"."C_CRM_INST" AND "TAB1"."ID_CUST"="TAB3"."ID_CUST") 5 - access("TAB1"."X_RLSHIP_MGR_ID"='7883943') 6 - access("A"."C_CRM_INST"="TAB3"."C_CRM_INST" AND "A"."C_ACCT_CCY"="TAB3"."C_ACCT_CCY" AND "A"."C_SRC_SYST"="TAB3"."C_SRC_SYST" AND "A"."X_ACCOUNT_NO"="TAB3"."X_ACCOUNT_NO") 8 - access("A"."C_CRM_INST"="C"."C_CRM_INST" AND "A"."N_LATEST_REC_SEQ"="C"."N_REP_FLAG") 31 rows selected.
SQL >
-Line account tables involved in the query
SQL> select count(*) From WMS_XTDI_CUST; COUNT(*) ---------- 1943009 SQL> select count(*) From WMS_STDI_REPFLAG; COUNT(*) ---------- 6 SQL> select count(*) From WMS_XTF_ACCT_BALANCE; COUNT(*) ---------- 14430174 SQL> SQL> select count(*) from WMS_XTDI_CUST_ACCT_REL; COUNT(*) ---------- 7096125Omega-3 wrote:
Thanks Jac.
I tested your version EXISTS in the query. But the result set is different.Why you use two tables - WMS_XTDI_CUST TAB1 and WMS_XTDI_CUST_ACCT_REL?
No column is selected among them?
And it seems that they do not have a relationship 1:1 or n: 1 with the basic query...
-
What is the problem with this query?
Hello
I need some advice on how to change the following query (with perhaps some analytical function) to speed it up. Currently, it takes 6 + minutes. This query is executed in response to a request from the front-end application and 6 + min is certainly unacceptable.
I am trying to provide as much information I can think, but if more information is needed, please let me know.
I have a table called "wave_result". It contains millions of rows. PK is Wave_Id, Version_nbr, node_nbr and prod_nbr. For each 'wave_id + node_NBR + prod_nbr' there are several versions (version_nbr). In the following query, I try to extract a line with MAX version_nbr for combination of ' wave_id + node_NBR + prod_nbr.
H3. Request:
H3. Rank of charges:SELECT ip1.fnln_cat, ip1.sub_cat, ip1.bus_cat, NVL (SUM (ip1.lsu), 0) val FROM ideal_prod ip1, ideal_store s, wave_result wr WHERE wr.wave_id = 51 AND wr.prod_nbr = ip1.prod_nbr AND wr.wave_id = ip1.wave_id AND wr.version_nbr = (SELECT MAX (wr1.version_nbr) FROM wave_result wr1 WHERE wr1.wave_id = wr.wave_id AND wr1.node_nbr = wr.node_nbr AND wr1.prod_nbr = wr.prod_nbr) AND NVL (wr.ovrd_dcsn_nm, wr.dcsn_nm) = 'Add' AND s.wave_id = wr.wave_id AND s.node_nbr = wr.node_nbr GROUP BY ip1.fnln_cat, ip1.sub_cat, ip1.bus_cat
========
"wave_result" is the largest table with millions of rows.
H3. StatsTable Total Rows Rows for wave_id = 51 Ideal_prod 188K 38K Ideal_store 3K 574 Wave_result 90M 19M
are updated almost daily by the DBA (not sure if that's a good or bad).
H3. Explain the Plan:
=========
H3. Sample data:SELECT STATEMENT ALL_ROWS Cost: 330,737 Bytes: 401,787 Cardinality: 14,881 12 HASH GROUP BY Cost: 330,737 Bytes: 401,787 Cardinality: 14,881 11 VIEW VIEW SYS.VM_NWVW_2 Cost: 330,737 Bytes: 401,787 Cardinality: 14,881 10 FILTER 9 HASH GROUP BY Cost: 330,737 Bytes: 2,425,603 Cardinality: 14,881 8 HASH JOIN Cost: 327,183 Bytes: 41,233,784 Cardinality: 252,968 1 INDEX RANGE SCAN INDEX (UNIQUE) APAPOPR.XPKIDEAL_STORE Cost: 4 Bytes: 13,202 Cardinality: 574 7 HASH JOIN Cost: 327,178 Bytes: 35,415,520 Cardinality: 252,968 5 HASH JOIN Cost: 198,619 Bytes: 18,764,328 Cardinality: 183,964 3 TABLE ACCESS BY INDEX ROWID TABLE APAPOPR.IDEAL_PROD Cost: 939 Bytes: 2,272,380 Cardinality: 37,873 4 TABLE ACCESS FULL TABLE APAPOPR.WAVE_RESULT Cost: 197,063 Bytes: 7,974,414 Cardinality: 189,867 6 INDEX RANGE SCAN INDEX (UNIQUE) APAPOPR.XPKWAVE_RESULT Cost: 82,467 Bytes: 721,495,854 Cardinality: 18,986,733
===========
H3. Version of database information are below to:For wave_id = 51 there are 28466854 rows in "wave_result" table For wave_id = 51 and node_nbr = '0201' and prod_nbr = '0226960' there are 3 rows in "wave_result" table
=========================
Thank you very much!!Oracle Database 11g Enterprise Edition Release 11.1.0.7.0 - 64bit Production PL/SQL Release 11.1.0.7.0 - Production CORE 11.1.0.7.0 Production TNS for IBM/AIX RISC System/6000: Version 11.1.0.7.0 - Production NLSRTL Version 11.1.0.7.0 - Production
ConcerningFor wave_id = 51 there are 28466854 rows in "wave_result" table For wave_id = 51 and node_nbr = '0201' and prod_nbr = '0226960' there are 3 rows in "wave_result" tableAs you mentioned that this particular request is called by a front screen, how different search criteria you get it to show on the front end?
Assuming that if the user is searching just of wave_id = 51 which lines returns to 28466854, it is certainly not a good approach to go look up many records to put end Front end is very light and can not hold many records and will be finally the web server will throw off out of memory exception. Always a limit on the number of records that you retrieve from the database and display it on the front plane.
OR
The second case where the user makes a search by wave_id, node_nbr and prod_nbr, even if she returns to 3 lines, behind the scens, he still made a full scan on the wave_result table. If we go with analytical function, we can reduce a sweep of extra table on the wave_result table. Also the table has millions of lines and the max (version_nbr) seems to be a frequently used on this table sub query. While inserting a record into the table wave_result, you must probably have a calculated value that will tell you its value max and you will choose just the rank of this value, instead of at each time max(). something like below...SELECT ip1.fnln_cat, ip1.sub_cat, ip1.bus_cat, NVL (SUM (ip1.lsu), 0) val FROM ideal_prod ip1, ideal_store s, wave_result wr WHERE ipl.wave_id = 51 AND wr.prod_nbr = ip1.prod_nbr AND wr.wave_id = ip1.wave_id AND wr.wave_id = s.wave_id AND wr.node_nbr = s.node_nbr AND wr.precomputed_max_value = 'MAX' AND NVL (wr.ovrd_dcsn_nm, wr.dcsn_nm) = 'Add' GROUP BY ip1.fnln_cat, ip1.sub_cat, ip1.bus_cat; -
Sorting and grouping - two months in this query
Hi all
Thanks a lot for JAC
I am doing a project for the construction company, I faced this problem by grouping points according to the relationship between these points the
Relationship is from 1 to 100. If the point between what means there is relationship between these points has come.
resolve this question already, but the results does not correct when the table contains more data.
Jac and thanks a lot to him.
This example for more details
for example, I have these points
In addition, we can see the relationship between these points as followsid location percentage comments 1 loc 1,2 20% that mean point 1 and 2 close to each other by 20% 2 loc 1,3 40% that mean point 1 and 3 close to each other byy 40% 3 Loc 8,6 25% that mean point 8 and 6 close to each other by 25% 4 Loc 6,10 20% 5 LOC 11,10 10 % 6 LOC 15,14 0%
-points 1,2,3 in a group why because close 1.2 and 1.3 a relationship which means 1.3 also hid the relationship.
-Points 6,8,10,11 in the second group there are the relationships between them.
- but no relationship between 1, 2 or 3 with any point of 6,8,9,10,11
-as well as no relationship between 15, 14, which means 14 in the third group and 15 in the fourth group.
Whati need?
to group the points that growing a relationship according to the percentage value
The most important part is to group the points. For EXAMPLE, the query below, the gropuing is not correct.
I have the following table with data
When I used this query, the results is not correctdrop table temp_value; create table temp_value(id number(10),location varchar2(20), percentage number(9)); insert into temp_value values (1,'LOC 1,2',10); insert into temp_value values (2,'LOC 1,3',0); insert into temp_value values (3,'LOC 1,4',0); insert into temp_value values (4,'LOC 1,5',0); insert into temp_value values (5,'LOC 1,6',0); insert into temp_value values (6,'LOC 2,3',0); insert into temp_value values(7,'LOC 2,4',0); insert into temp_value values (8,'LOC 2,5',30); insert into temp_value values (9,'LOC 2,6',0); insert into temp_value values (10,'LOC 3,4',0); insert into temp_value values (11,'LOC 3,5',0); insert into temp_value values (12,'LOC 4,5',40); insert into temp_value values (13,'LOC 4,6',0); insert into temp_value values (14,'LOC 6,7',40); insert into temp_value values (15,'LOC 7,2',0); insert into temp_value values (16,'LOC 8,2',60); insert into temp_value values (17,'LOC 8,3',0); insert into temp_value values (18,'LOC 3,1',0); insert into temp_value values (19,'LOC 9,6',30); insert into temp_value values (20,'LOC 11,2',0); insert into temp_value values (22,'LOC 12,3',10); insert into temp_value values (23,'LOC 19,3',0); insert into temp_value values (24,'LOC 17,3',0); insert into temp_value values (24,'LOC 20,3',0);
resultswith t as (select percentage,loc1,loc2,sum(case when percentage = 0 then 1 when loc1 in (l1,l2) then 0 when loc2 in (l1,l2) then 0 when l1 is null and l2 is null then 0 else 1 end) over(order by rn) sm from ( select id,location,percentage, regexp_substr(location,'\d+',1,1) LOC1, regexp_substr(location,'\d+',1,2) LOC2, lag(regexp_substr(location,'\d+',1,1)) over(order by percentage desc) l1, lag(regexp_substr(location,'\d+',1,2)) over(order by percentage desc) l2, row_number() over(order by percentage desc) rn from temp_value order by percentage desc ) ) select loc,min(sm)+1 grp from( select loc,rownum rn,sm from( select percentage,decode(rn,1,loc1,loc2) loc,sm from t a, (select 1 rn from dual union all select 2 from dual ) b order by percentage desc,decode(rn,1,loc1,loc2) asc ) ) group by loc order by min(sm),min(rn);
SQL > /.
SQL >LOC GRP -------------------- ---------- 2 1 8 1 6 2 7 2 4 3 5 3 9 4 1 5 12 6 3 6 11 13 LOC GRP -------------------- ---------- 19 14 17 15 20 22 14 rows selected.
but the just is
Thanks in advance.Location group No 2 1 8 1 4 1 5 1 1 1 6 2 7 2 9 2 12 3 3 3 19 4 17 5 20 6
Published by: Isabelle on November 30, 2012 03:07OK, I thought an it once again and found out how to include with any such percentage points.
In your example expected output you missed the 11 that's why we got 7 groups now.
The order of the Group 2 and 3 is ambiguous, because the highest percentage of these groups is the same.with connects as ( select distinct loc1 ,loc2 ,connect_by_root(loc1) grp ,percentage per from temp_value --start with --percentage != 0 connect by nocycle (prior loc2 = loc1 or prior loc1 = loc2 or prior loc1 = loc1 or prior loc2 = loc2) and percentage != 0 and prior percentage != 0 ) select loc ,dense_rank() over (order by decode(per,0,1,0), grp) grp from ( select loc ,max(grp) keep (dense_rank first order by per desc, grp) grp ,max(per) keep (dense_rank last order by per nulls first) per from ( select loc1 loc ,grp ,per from connects union select loc2 ,grp ,per from connects ) group by loc ) order by 2,per desc,1 LOC GRP 2 1 8 1 4 1 5 1 1 1 12 2 3 2 6 3 7 3 9 3 11 4 17 5 19 6 20 7Think we are done now ;-)
Edited by: chris227 at 30.11.2012 16:46Edited by: chris227 at 30.11.2012 17:12
order correctedEdited by: chris227 at 30.11.2012 17:15
simplification, no need to rank in linking subqueryEdited by: chris227 at 30.11.2012 17:26
-
How can I change this query? to get the results I want
This query
Returnsselect SHRTGPA_pidm, SZSTCLA_TERM_CODE, SHRTGPA_GPA_HOURS from szstcla,SHRTGPA where szstcla_pidm = 74246 and SHRTGPA_pidm = szstcla_pidm and SZSTCLA_TERM_CODE <> SZSTCLA_TERM_CODE_MATRIC and SHRTGPA_TERM_CODE = SZSTCLA_TERM_CODE
I want to group the query will return74246 201020 4 74246 201120 4 74246 201110 4 74246 201210 4 74246 201220 4
201220 2074246 201020 4 74246 201120 8 74246 201110 12 74246 201210 16Two copies
Published by: Frank Kulash, November 8, 2012 11:32
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