Single SQL query for the analysis of the date of customs declaration under the table of Stock codes

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• SQL query for the table in the schema

  Hi user;
  
  Imagine that we have 10 schema in oracle db. I wonder all the name of the table as shcema A1. I want to find these tables name everything first (let us suppose schema A1 has 100,000 tables)
  
  Then, I want to give select grant the user A for these 100,000 tables. I don't want to use grant any table. I just want to give A user to select right for tables (100,000) which is under schema A1. How can I do? Please give me some ideas or the path
  
  Thank you

  AAAAA says:
  Hi Nicholas.

  Its system of prod and I'm afraid to be confused :)

  Yes, I understand very well you're scared, then why not you plan some tests in front on a dummy database?

  Nicolas.

• SQL query for the apex report

  Hi team,
  
  For example if I have a demo table with 4 columns (A, B, C, D) DEMO.
  
  I want a report on this table, such that the report contains the headers and the Details section.
  
  For each unique combination of (A, B) I must first of all show header based on the header information I want to display the detailed section.
  In my header section I want to display 2 columns (A, B) that are common to the detailed section. Remaining 2 columns in the detailed section.
  
  
  Here is an example: -.
  
  A B C D
  1 5 9 3
  1 5P8
  1 5 P O
  1-5-9
  1 8 9
  1     D     *     /
  2 8 33 P
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  2 P L L
  
  YOU WILL SEE
  A AND B
  1 5
  
  C D
  9 3
  P 8
  P O
  
  
  A AND B
  1 D
  
  C D
  5 9
  8 9
  *     /
  
  
  
  A AND B
  2 P
  
  C D
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  Please suggest the solution (sql query) for above the problem and how to nest gernerated headers dynamically in the report area.
  I use APEX 4.0
  Any position in this regard is very significant.
  
  Thanks and greetings
  Rajendra

  Try this:

  SQL> select * from tab;
  1 5 9 3
  1 5 P 8
  1 5 P O
  1 D 5 9
  1 D 8 9
  1 P 8 3
  1 P O O
  
  7 rows selected.
  
  SQL> select a,b from
  (select r,a,b from
  ( select to_char(rownum)||'a' r, 'A' a,'B' b from
          (select distinct a, b from tab order by a,b))
          union
  ( select to_char(rownum)||'c' r, 'C' c,'D' d from
          (select distinct a, b from tab order by a,b))
  union
  ( select to_char(rownum)||'b' r, a,b from
  (select distinct a, b from tab order by a,b))
  union
  select parent.r, tab.c, tab.d from
  ( select to_char(rownum)||'d' r, a,b from
  (select distinct a, b from tab order by a,b)) parent ,
  tab
  where parent.a=tab.a and
  parent.b=tab.b
  ) order by r
  ;
  A B
  1 5
  C D
  9 3
  P 8
  P O
  A B
  1 D
  C D
  5 9
  8 9
  A B
  1 P
  C D
  8 3
  O O
  

• JDev11g - prevention of query for the table running until ExecWithParams press

  JDev 11 g ADF-Faces with task flow creation web app - test a single page.
  
  I have five variable bind I have installed with reference LOV to display the name return ID's, two are dates that work now! I have the ExecWithParams button, then on a table that uses a VO with a custom query with the dregs.
  
  I need links to be filled, but the page takes a while to load, and my guess is that the request for the table tries to run, but does not receive all the data since the lie is empty at the start. The query runs great once I have complete binding and press the ExecWithParams button.
  
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  Thank you, Ken

  Something that I use occasionally is the substitution of the VO executeQuery method.

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          super.executeQuery();
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  It works for running dynamic bind variable.

  For your case, you could do something like...

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• SQL query for the region of the tree

  Hello

  I was wondering if someone is able to help me work on a SQL query, to format the data in the table required in a part of the tree... I've never used a tree and I'm fighting to get the right data (if possible).

  The data in the table looks like this:

  

  I want to put it in a tree, using level 1 level6 with a final layout that would look like this:

  

  As you can see, the data are formatted in level6 down in the tree, but are filled in the table from level 1. Not all of the columns will be filled, so level2 for anyone 4 (France) is the equivalent of level in the tree like level6 to person 1 (Spain).

  This is Apex 4.2.5

  Oracle 11.2.0.3.0

  Sample data:

  CREATE TABLE employees
     ( employee VARCHAR2(100),
       level1 VARCHAR2(100),
       level2 VARCHAR2(100),
       level3 VARCHAR2(100),
       level4 VARCHAR2(100),
       level5 VARCHAR2(100),
       level6 VARCHAR2(100)   
     );
  
  INSERT INTO employees (employee, level1, level2, level3, level4, level5, level6) VALUES ('Person1','Team One','Recruitment','Human Resources','Fictituous Company','Murcia','Spain');
  INSERT INTO employees (employee, level1, level2, level3, level4, level5, level6) VALUES ('Person2','Team Four','Testing','IT','Big Corporate','Hanover','Germany');
  INSERT INTO employees (employee, level1, level2, level3, level4, level5, level6) VALUES ('Person3','Big Corporate','Hanover','Germany', null, null, null);
  INSERT INTO employees (employee, level1, level2, level3, level4, level5, level6) VALUES ('Person4','Brittany','France', null, null, null, null);
  INSERT INTO employees (employee, level1, level2, level3, level4, level5, level6) VALUES ('Person5','Team Three','Testing','IT','Big Corporate','Hanover','Germany');
  INSERT INTO employees (employee, level1, level2, level3, level4, level5, level6) VALUES ('Person6','Public Relations','Government Agency','Brittany','France', null, null);
  
  

  Added example given.

  Hello

  Apex-user wrote:

  Thanks Frank, this is a good example, I can work with that! Your assumptions are correct.

  A question I came, however, is that I have a data segment that comes across poorly formatted so to speak... where only the lower levels (1-2, etc.) have been filled from the bottom up.

  An example of this data would be:

  1. INSERT INTO employees (employee, level 1, 2, level3, level4, level5, level6) VALUES ('Person7', 'One Team', 'Test', null, null, null, null);

  As you can see that if you rerun the select, the test team is now duplicated, both at the level of the root in the tree as it should.

  You are not sure if the sql can be adjusted to account for this, or if it's too hard?

  It is obviously a question of data and I am trying to solve this separately (extracted data from another system out of my control).

  Thank you!

  Sorry, I'm confused.

  You say that my assumptions were correct.  What includes supported that "If test ' occurs under 'IT' in a row, then the extent of the 'Testing' occurs, it must be under"IT "?  Right after you say that assumptions are correct, you give an example where 'Testing' occurs under 'IT' to a single line, but it is not less 'IT' to another line and where is 'One Team' under 'Testing' in a line, but is 'One Team' under 'Recruitment' in another row.

  When a situation like this occurs, how you cope?  Whenever you have a problem, please post the exact results you want from the given sample data, and an explanation of how you get these results.  If you don't know about what would be the ideal results, or if you are flexible on the exact results, then at least give an example and explain your reasons.

  Maybe you want to change the got_parent of subquery like this:

  WITH unpivoted_data AS

  (

  SELECT *.

  Employees

  UNPIVOT (node_name

  FOR lvl (level1 AS 1

  level2 AS 2

  level3 AS 3

  level4 AS 4

  level5 AS 5

  level6 AS-6

  )

  )

  )

  got_parent AS

  (

  SELECT c.node_name

  MIN (p.node_name) AS a parent

  Of unpivoted_data c

  LEFT OUTER JOIN unpivoted_data p ON p.employee = c.employee

  AND p.lvl = c.lvl + 1

  GROUP BY c.node_name

  )

  SELECT LPAD (' ' ')

  2 * (LEVEL - 1)

  ) || Node_name AS entity

  OF got_parent

  START WITH parent IS NULL

  Parent = node_name PRIOR CONNECTION

  ;

  In this way, if 'Test' is current 'IT' in one line, but not under what in another line, whether under would consider the 'IT' request and not to be a root.  If 'One Team' sudden 'Testing' in a line, but under "Recruitment" in another line, it will be (arbitrarily) consider it under "recruitment".

• SQL query for the set of data rows not values

  Hello!
  
  I use Oracle 10 g (10.2.0.1.0) and I need help to solve this difficult task. I have a huge table with more than 145000 records and I shows you only a sample of it:
  
  ID TEAMNAME_EN DT TEAMNAME_EN HPROB AM APROB FT
  324813 31/8 / 2012 DEN HAAG GRONINGEN 1.90 3.30 3.10 2
  324823 31/8 / 2012 MAINZ GREUTHER FÜRTH 1.75 3.25 3.65 2
  324805 31/8 / 2012 GAZELEC DIJON 1.60 3.15 4.75 1
  324810 31/8 / 2012 ÖREBRO DJURGÅRDEN 2.80 3.25 2 2.05
  324795 31/8 / 2012 FC KÖLN COTTBUS 1.85 3.20 3.35 2
  324837 31/8 / 2012 PORTLAND WOOD COLORADO RAPIDS 2,00 3.20 2.95 1
  324828 31/8 / 2012 DROGHEDA UNITED, DUNDALK 1.45 3.65 5.25 1
  324827 31/8 / 2012 CORK CITY SHAMROCK ROVERS 3,30 3,80 1.70 2
  324833 31/8 / 2012 BARUERI ASA 2.45 3.20 1-2.30
  324798 31/8 / 2012 GENÇLERBIRLIGI ORDUSPOR'A 2.00 3,10 X 3.00
  324814 31/8 / 2012 ALMERE CITY FC OSS 1,80 3,50 3,20 2
  324830 31/8 / 2012 CRICIÚMA BRAGANTINO 1.25 4.35 1 8.00
  324820 31/8 / 2012 VOLENDAM FC EINDHOVEN 1.80 3.25 3.45 1
  324818 31/8 / 2012 MVV MAASTRICHT TELSTAR 1.40 4.00 X 5.25
  324819 31/8 / 2012 DORDRECHT VEENDAM 1.80 3.25 3.45 1
  324834 31/8 / 2012 CEARÁ GUARATINGUETÁ 1.40 3.85 X 5.50
  
  If this table consists of
  dates
  teams (hometeam, awayteam)
  numbers for homewin, shoot, awaywin probability
  and the final result as 1, X, 2
  
  What I want is a sql query that returns to me for each hometeam, awayteam and (if possible in a single line)
  all documents of the hometeam which had the same number of prior probability. For example:
  CEARÁ (last line), I would like to the sql to show me all the records of CEARA who had _1.40 3.85 or 5.50_ in each of the three issues of probability, BUT the problem is that I do want separate lines... I can do so far is to calculate a sum of House probability, probability of drawing, close probability for each team but the same records are calculated again in each game of probability!
  
  This means if CEARÁ has 1.40-3.85-5.50 in the past it will return me this line only once, and not 3 times (one for each set of probability)
  
  I hope that I've done my duty,
  Thank you for your time and lights
  N. Saridakis

  Is that what you are looking for:

  select hometeam,
         awayteam,
         hw,
         hd,
         hl
  from  (select hometeam,
                awayteam,
                ft,
                SUM(CASE ft
                    WHEN '1' THEN 1
                    ELSE 0
                    END) OVER (PARTITION BY hometeam) hw,
                SUM(CASE ft
                    WHEN 'X' THEN 1
                    ELSE 0
                    END) OVER (PARTITION BY hometeam) hd,
                SUM(CASE ft
                    WHEN '2' THEN 1
                    ELSE 0
                    END) OVER (PARTITION BY hometeam) hl
         from   plays)
  where ft is null
  

• SQL query for the report?

  Hi all
  I have a large table with column:
  the code, street, data_type, credit, debt, saldo, date
  
  I created query as
  
  sum (saldo), code of Select tableA where data_types = 1 and date < ' 201010 "group by code
  
  but cannot develop this request to be in the report as
  
  COLUMN1 COLUMN2 COLUMN3 COLUMN4
  Sum (saldo) - where type = 1 and date = '201201', sum (saldo) where type = 2, sum (saldo) If date = '201205', code
  
  What is the best solution for sums of report for diferent data_types on a single line with just one code per lines?
  concerning
  Gordan
  
  Published by: useruseruser on May 14, 2013 10:52

  Hello

  useruseruser wrote:
  Hi all
  I have a large table with column:
  the code, street, data_type, credit, debt, saldo, date

  I created query as

  sum (saldo), Select tableA where data_types = 1 and date code<'201010' group="" by="">

  but cannot develop this request to be in the report as

  COLUMN1 COLUMN2 COLUMN3 COLUMN4
  Sum (saldo) - where type = 1 and date = '201201', sum (saldo) where type = 2, sum (saldo) If date = '201205', code

  What is the best solution for sums of report for diferent data_types on a single line with just one code per lines?
  concerning
  Gordan

  Published by: useruseruser on May 14, 2013 10:52

  You can use CASE what

   
  
  sum(saldo) -, sum(saldo) where type=2, sum(saldo) where date ='201205' , code
  
  select code,
    sum(case when type=1 and date = '201201' then saldo else 0 end) AS COLUMN1,
    sum(case when type=2 then saldo else 0 end) AS COLUMN2,
    sum(case when  date ='201205' then saldo else 0 end) AS COLUMN3,
    sum(saldo)
   from tableA
  group by code
  

  Concerning
  Mr. Mahir Quluzade

• SQL query for the mapping of a set of prizes to a group of classrooms

  Hi all
  
  I use Oracle database 11g Release 2.
  
  I have the following data set:
  
  Classrooms
  ClassId ClassName ability group
  ------ ----------------------------------------------      --------------     -----------
  Babbage/software Engg Lab 1 24 1
  Basement 2 - block PG 63 1
  3 1 56 1 class
  Class 4 1 24 10
  Class 5 1 24 11
  Class 6 1 35 12
  7 13 42 1 class
  8 14 42 1 class
  9 15 42 1 class
  10 2 35 1 class
  11 3 35 1 class
  12 4 35 1 classroom
  13 5 35 1 class
  14 6 25 1 class
  15 7 25 1 class
  16 1 24 8 class
  17 9 24 1 class
  18 control Sys Lab 1 24
  19 dig & Embd Sys Lab 20 1
  20 PSD & Comm 20 1 Lab
  21 electromechanical system Lab 28 1
  Farabi 22/Web Tech Lab 1 36
  23 gen purpose Lab 40 1
  Shirazi/24dB Tech Lab 1 36
  ADV 25 elect Lab 30 2
  26 16 42 2 class
  27 17 49 2 class
  28 18 56 2 class
  29 19 42 2 class
  30 20 49 2 class
  Class 31 21 35 3
  32 22 35 3 class
  33 20 3 MDA lab
  
  DegreeBatches
  BatchId BatchName force
  ---------------     ----------------------- --------------
  1 BIT - 11 79
  2 BIT - 12 28
  3 BS (CS)-1 35
  4 BS (CS) 78-2
  5 BE (SE)-1 69
  6. BE (SE) 84-2
  7 BE (SE) 64-3
  8 84 BYTČA-7
  9 43 BYTČA-8
  BEE-1 10, 112
  11 151 BEE-2
  BEE-3 12, 157
  13 BEE-4 157
  
  I want to map a combination of batch of degree for a class rooms group of such distance that they make full use of the maximum capacity of the class rooms within a group (ideally), or as close to this as possible. Can it be done with a SQL query?
  
  Any response will be appreciated.
  
  The SQL Scripts to generate the required tables and populate data is less to:
  CREATE TABLE classrooms (ClassId NUMBER, ClassName VARCHAR2 (50), capacity NUMBER, group NUMBER);
  INSERT INTO the classrooms of the VALUES (1, "Babbage/software Engg Lab', 24, 1");
  INSERT INTO the classrooms of the VALUES (2, 'basement - PG block', 63, 1);
  INSERT INTO the classrooms of the VALUES (3, '1 class room', 56, 1);
  INSERT INTO the classrooms of the VALUES (4, '10 class room', 24, 1);
  INSERT INTO the classrooms of the VALUES (5, '11 class room', 24, 1);
  INSERT INTO the classrooms of the VALUES (6, 'class room 12', 35, 1);
  INSERT INTO the classrooms of the VALUES (7, 'class room 13', 42, 1);
  INSERT INTO the classrooms of the VALUES (8, 'class room 14', 42, 1);
  INSERT INTO the classrooms of the VALUES (9, '15 'class, 42, 1);
  INSERT INTO the classrooms of the VALUES (10, 'class 2', 35, 1);
  INSERT INTO the classrooms of the VALUES (11, 'class room 3', 35, 1);
  INSERT INTO the classrooms of the VALUES (12, 'class room 4', 35, 1);
  INSERT INTO the classrooms of the VALUES (13, 'class room 5', 35, 1);
  INSERT INTO the classrooms of the VALUES (14, 'class room 6', 25, 1);
  INSERT INTO the classrooms of the VALUES (15, '7 class room', 25, 1);
  INSERT INTO the classrooms of the VALUES (16, 'class Room 8', 24, 1);
  INSERT INTO the classrooms of the VALUES (17, 'class room 9', 24, 1);
  INSERT INTO the classrooms of the VALUES (18, 'Control Sys Lab', 24, 1);
  INSERT INTO the classrooms of the VALUES (19, 'Dig & Embd Sys Lab', 20, 1);
  INSERT INTO the classrooms of the VALUES (20, 'DSP & Comm Lab', 20, 1);
  INSERT INTO the classrooms of the VALUES (21, 'system ELECTROMECHANICAL Lab', 28, 1);
  INSERT INTO the classrooms of the VALUES (22, ' Farabi/Web Tech Lab', 36, 1);
  INSERT INTO the classrooms of the VALUES (23, 'Gen purpose Lab', 40, 1);
  INSERT INTO the classrooms of the VALUES (24, ' Shirazi/DB Tech Lab', 36, 1);
  INSERT INTO the classrooms of the VALUES (25, 'Elected Adv Lab', 30, 2);
  INSERT INTO the classrooms of the VALUES (26, 'class room 16', 42, 2);
  INSERT INTO the classrooms of the VALUES (27, 'class room 17', 49, 2);
  INSERT INTO the classrooms of the VALUES (28, '18 'class, 56, 2);
  INSERT INTO the classrooms of the VALUES (29, '19 'class, 42, 2);
  INSERT INTO the classrooms of the VALUES (30, 'class room 20', 49, 2);
  INSERT INTO the classrooms of the VALUES (31, 'class room 21', 35, 3);
  INSERT INTO the classrooms of the VALUES (32, 'room 22', 35, 3);
  INSERT INTO the classrooms of the VALUES (33, 'MDA Lab', 20, 3);
  
  CREATE TABLE DegreeBatches (BatchId NUMBER, BatchName VARCHAR2 (50), membership NUMBER);
  INSERT INTO DegreeBatches VALUES(1,'BIT-11',79);
  INSERT INTO DegreeBatches VALUES(2,'BIT-12',28);
  INSERT INTO DegreeBatches VALUES (3, 'BS (CS) - 1', 35);
  INSERT INTO DegreeBatches VALUES (4, 'BS (CS) - 2', 78);
  INSERT INTO DegreeBatches VALUES (5,'BE (SE) - 1', 69);
  INSERT INTO DegreeBatches VALUES (6,'BE (SE) - 2', 84);
  INSERT INTO DegreeBatches VALUES (7,'BE (SE) - 3', 64);
  INSERT INTO DegreeBatches VALUES(8,'BICSE-7',84);
  INSERT INTO DegreeBatches VALUES(9,'BICSE-8',43);
  INSERT INTO DegreeBatches VALUES(10,'BEE-1',112);
  INSERT INTO DegreeBatches VALUES(11,'BEE-2',151);
  INSERT INTO DegreeBatches VALUES(12,'BEE-3',157);
  INSERT INTO DegreeBatches VALUES(13,'BEE-4',157);
  
  Best regards
  Bilal
  
  Published by: Bilal on December 27, 2012 09:52
  
  Published by: Bilal on December 27, 2012 10:07

  Bilal, thanks for the nice problem! Another possibility to double check is to write a small PL/SQL function that returns 1 if a duplicate id is found, then equate to 0: "NUMBER of RETURN of Duplicate_Token_Found (p_str_main in VARCHAR2, p_str_trial VARCHAR2). It should analyze the second string and could use p_str_main LIKE '%', | l_id | ', %' for each id. In any case, the query complete (without that) is given below:

  Solution with names
  SQL> WITH rsf_itm (con_id, max_weight, nxt_id, lev, tot_weight, tot_profit, path, root_id, lev_1_id) AS (
    2  SELECT c.id,
    3         c.max_weight,
    4         i.id,
    5         0,
    6         i.item_weight,
    7         i.item_profit,
    8         ',' || i.id || ',',
    9         i.id,
   10         0
   11    FROM items i
   12   CROSS JOIN containers c
   13   UNION ALL
   14  SELECT r.con_id,
   15         r.max_weight,
   16         i.id,
   17         r.lev + 1,
   18         r.tot_weight + i.item_weight,
   19         r.tot_profit + i.item_profit,
   20         r.path || i.id || ',',
   21         r.root_id,
   22         CASE WHEN r.lev = 0 THEN i.id ELSE r.nxt_id END
   23    FROM rsf_itm r
   24    JOIN items i
   25      ON i.id > r.nxt_id
   26     AND r.tot_weight + i.item_weight <= r.max_weight
   27   ORDER BY 1, 2
   28  ) SEARCH DEPTH FIRST BY nxt_id SET line_no
   29  , rsf_con (nxt_con_id, nxt_line_no, con_path, itm_path, tot_weight, tot_profit, lev) AS (
   30  SELECT con_id,
   31         line_no,
   32         To_Char(con_id),
   33         ':' || con_id || '-' || (lev + 1) || ':' || path,
   34         tot_weight,
   35         tot_profit,
   36         0
   37    FROM rsf_itm
   38   UNION ALL
   39  SELECT r_i.con_id,
   40         r_i.line_no,
   41         r_c.con_path || ',' || r_i.con_id,
   42         r_c.itm_path ||  ':' || r_i.con_id || '-' || (r_i.lev + 1) || ':' || r_i.path,
   43         r_c.tot_weight + r_i.tot_weight,
   44         r_c.tot_profit + r_i.tot_profit,
   45         r_c.lev + 1
   46    FROM rsf_con r_c
   47    JOIN rsf_itm r_i
   48      ON r_i.con_id > r_c.nxt_con_id
   49   WHERE r_c.itm_path NOT LIKE '%,' || r_i.root_id || ',%'
   50     AND r_c.itm_path NOT LIKE '%,' || r_i.lev_1_id || ',%'
   51     AND r_c.itm_path NOT LIKE '%,' || r_i.nxt_id || ',%'
   52  )
   53  , paths_ranked AS (
   54  SELECT itm_path || ':' itm_path, tot_weight, tot_profit, lev + 1 n_cons,
   55         Rank () OVER (ORDER BY tot_profit DESC) rnk,
   56         Row_Number () OVER (ORDER BY tot_profit DESC) sol_id
   57    FROM rsf_con
   58  ), best_paths AS (
   59  SELECT itm_path, tot_weight, tot_profit, n_cons, sol_id
   60    FROM paths_ranked
   61   WHERE rnk = 1
   62  ), row_gen AS (
   63  SELECT LEVEL lev
   64    FROM DUAL
   65  CONNECT BY LEVEL <= (SELECT Count(*) FROM items)
   66  ), con_v AS (
   67  SELECT  b.itm_path, r.lev con_ind, b.sol_id, b.tot_weight, b.tot_profit,
   68          Substr (b.itm_path, Instr (b.itm_path, ':', 1, 2*r.lev - 1) + 1,
   69            Instr (b.itm_path, ':', 1, 2*r.lev) - Instr (b.itm_path, ':', 1, 2*r.lev - 1) - 1)
   70             con_nit_id,
   71          Substr (b.itm_path, Instr (b.itm_path, ':', 1, 2*r.lev) + 1,
   72            Instr (b.itm_path, ':', 1, 2*r.lev + 1) - Instr (b.itm_path, ':', 1, 2*r.lev) - 1)
   73             itm_str
   74    FROM best_paths b
   75    JOIN row_gen r
   76      ON r.lev <= b.n_cons
   77  ), con_split AS (
   78  SELECT itm_path, con_ind, sol_id, tot_weight, tot_profit,
   79         Substr (con_nit_id, 1, Instr (con_nit_id, '-', 1) - 1) con_id,
   80         Substr (con_nit_id, Instr (con_nit_id, '-', 1) + 1) n_items,
   81         itm_str
   82    FROM con_v
   83  ), itm_v AS (
   84  SELECT  c.itm_path, c.con_ind, c.sol_id, c.con_id, c.tot_weight, c.tot_profit,
   85          Substr (c.itm_str, Instr (c.itm_str, ',', 1, r.lev) + 1,
   86            Instr (c.itm_str, ',', 1, r.lev + 1) - Instr (c.itm_str, ',', 1, r.lev) - 1)
   87             itm_id
   88    FROM con_split c
   89    JOIN row_gen r
   90      ON r.lev <= c.n_items
   91  )
   92  SELECT v.sol_id,
   93         v.tot_weight s_wt, v.tot_profit s_pr, c.id c_id, c.name c_name, c.max_weight m_wt,
   94         Sum (i.item_weight) OVER (PARTITION BY v.sol_id, c.id) c_wt,
   95         i.id i_id, i.name i_name, i.item_weight i_wt, i.item_profit i_pr
   96    FROM itm_v v
   97    JOIN containers c
   98      ON c.id = To_Number (v.con_id)
   99    JOIN items i
  100      ON i.id = To_Number (v.itm_id)
  101   ORDER BY sol_id, con_id, itm_id
  102  /
  
      SOL_ID S_WT S_PR  C_ID C_NAME          M_WT C_WT  I_ID I_NAME     I_WT I_PR
  ---------- ---- ---- ----- --------------- ---- ---- ----- ---------- ---- ----
           1  255  255     1 SEECS UG Block   100  100     1 BIT-10       35   35
                                                           2 BIT-11       40   40
                                                           6 BICSE-7      25   25
                           2 IAEC Building     70   70     4 BSCS-3       40   40
                                                           7 BESE-3       30   30
                           3 RIMMS Building    90   85     3 BSCS-2       35   35
                                                           5 BEE-4        50   50
           2  255  255     1 SEECS UG Block   100   95     4 BSCS-3       40   40
                                                           6 BICSE-7      25   25
                                                           7 BESE-3       30   30
                           2 IAEC Building     70   70     1 BIT-10       35   35
                                                           3 BSCS-2       35   35
                           3 RIMMS Building    90   90     2 BIT-11       40   40
                                                           5 BEE-4        50   50
           3  255  255     1 SEECS UG Block   100  100     3 BSCS-2       35   35
                                                           4 BSCS-3       40   40
                                                           6 BICSE-7      25   25
                           2 IAEC Building     70   65     1 BIT-10       35   35
                                                           7 BESE-3       30   30
                           3 RIMMS Building    90   90     2 BIT-11       40   40
                                                           5 BEE-4        50   50
           4  255  255     1 SEECS UG Block   100  100     3 BSCS-2       35   35
                                                           4 BSCS-3       40   40
                                                           6 BICSE-7      25   25
                           2 IAEC Building     70   70     2 BIT-11       40   40
                                                           7 BESE-3       30   30
                           3 RIMMS Building    90   85     1 BIT-10       35   35
                                                           5 BEE-4        50   50
           5  255  255     1 SEECS UG Block   100   95     2 BIT-11       40   40
                                                           6 BICSE-7      25   25
                                                           7 BESE-3       30   30
                           2 IAEC Building     70   70     1 BIT-10       35   35
                                                           3 BSCS-2       35   35
                           3 RIMMS Building    90   90     4 BSCS-3       40   40
                                                           5 BEE-4        50   50
           6  255  255     1 SEECS UG Block   100  100     2 BIT-11       40   40
                                                           3 BSCS-2       35   35
                                                           6 BICSE-7      25   25
                           2 IAEC Building     70   65     1 BIT-10       35   35
                                                           7 BESE-3       30   30
                           3 RIMMS Building    90   90     4 BSCS-3       40   40
                                                           5 BEE-4        50   50
           7  255  255     1 SEECS UG Block   100  100     2 BIT-11       40   40
                                                           3 BSCS-2       35   35
                                                           6 BICSE-7      25   25
                           2 IAEC Building     70   70     4 BSCS-3       40   40
                                                           7 BESE-3       30   30
                           3 RIMMS Building    90   85     1 BIT-10       35   35
                                                           5 BEE-4        50   50
           8  255  255     1 SEECS UG Block   100  100     1 BIT-10       35   35
                                                           4 BSCS-3       40   40
                                                           6 BICSE-7      25   25
                           2 IAEC Building     70   70     2 BIT-11       40   40
                                                           7 BESE-3       30   30
                           3 RIMMS Building    90   85     3 BSCS-2       35   35
                                                           5 BEE-4        50   50
           9  255  255     1 SEECS UG Block   100  100     1 BIT-10       35   35
                                                           4 BSCS-3       40   40
                                                           6 BICSE-7      25   25
                           2 IAEC Building     70   65     3 BSCS-2       35   35
                                                           7 BESE-3       30   30
                           3 RIMMS Building    90   90     2 BIT-11       40   40
                                                           5 BEE-4        50   50
          10  255  255     1 SEECS UG Block   100  100     1 BIT-10       35   35
                                                           3 BSCS-2       35   35
                                                           7 BESE-3       30   30
                           2 IAEC Building     70   65     2 BIT-11       40   40
                                                           6 BICSE-7      25   25
                           3 RIMMS Building    90   90     4 BSCS-3       40   40
                                                           5 BEE-4        50   50
          11  255  255     1 SEECS UG Block   100  100     1 BIT-10       35   35
                                                           3 BSCS-2       35   35
                                                           7 BESE-3       30   30
                           2 IAEC Building     70   65     4 BSCS-3       40   40
                                                           6 BICSE-7      25   25
                           3 RIMMS Building    90   90     2 BIT-11       40   40
                                                           5 BEE-4        50   50
          12  255  255     1 SEECS UG Block   100   95     1 BIT-10       35   35
                                                           3 BSCS-2       35   35
                                                           6 BICSE-7      25   25
                           2 IAEC Building     70   70     2 BIT-11       40   40
                                                           7 BESE-3       30   30
                           3 RIMMS Building    90   90     4 BSCS-3       40   40
                                                           5 BEE-4        50   50
          13  255  255     1 SEECS UG Block   100   95     1 BIT-10       35   35
                                                           3 BSCS-2       35   35
                                                           6 BICSE-7      25   25
                           2 IAEC Building     70   70     4 BSCS-3       40   40
                                                           7 BESE-3       30   30
                           3 RIMMS Building    90   90     2 BIT-11       40   40
                                                           5 BEE-4        50   50
          14  255  255     1 SEECS UG Block   100  100     1 BIT-10       35   35
                                                           2 BIT-11       40   40
                                                           6 BICSE-7      25   25
                           2 IAEC Building     70   65     3 BSCS-2       35   35
                                                           7 BESE-3       30   30
                           3 RIMMS Building    90   90     4 BSCS-3       40   40
                                                           5 BEE-4        50   50
  
  98 rows selected.
  
  Elapsed: 00:00:01.42
  

  Published by: BrendanP on January 20, 2013 11:25
  I found the need to deduplicate regular expression:

  AND RegExp_Instr (r_c.itm_path | r_i.path, ',(\d+),.*?,\1,') = 0)

• R12 Payables: SQL query for the list of invoices and their status of Validation

  Hi all
  
  I am looking for a SQL query that gives me the list of all invoices of AP and their Validation status.
  
  Thank you
  Anil

  Select invoice_id, invoice_num, invoice_amount, invoice_currency_code, AP_INVOICES_V approval_status_lookup_code;

  Prasanna-

• SQL query for the combination of characters

  Hi all

  I need an outlet on different combinations of characters.

  with t as)
  Select col1 ('124:369'), ('598:192') col2, col3 as ('547:541:965')
  of the double
  )
  Select * from t;

  output:
  =====
  124:369, 369:124
  598:192, 192:598
  547:541:965, 965:541:547, 541:547:965, 541:965:547, 965:547:541, 547:965:541

  Thank you and best regards,

  ajraj

  Hi, Ajraj,

  G2500 wrote:

  Hi all

  I need an outlet on different combinations of characters.

  ...

  Actaully, 'combination' means that any order, then "124:369" is the same combination as "369:124".  It looks like you want all the different Permutations, combinations of no.

  You can do this by dividing each separate points colon-delimited string (that is, splitting '124:369', ' 124 'and ' 369') and then re - combine in every possible way.  You can use CONNECT BY (without START WITH clause) for both steps.

  Here's a way to do it:

  WITH unpivoted_data AS

  (

  SELECT str

  REGEXP_SUBSTR (str,

  , '[^:]+'

  1

  LEVEL

  ), Element

  T

  UNPIVOT (str

  FOR the collar (col1, col2, col3)

  )

  CONNECT BY LEVEL<= regexp_count="" (str,="">

  AND PRIOR str = str

  AND PRIOR SYS_GUID () IS NOT NULL

  )

  got_perm AS

  (

  SELECT str

  , SUBSTR (SYS_CONNECT_BY_PATH (point, ' :')))

  2

  ) AS perm

  Of unpivoted_data

  WHERE CONNECT_BY_ISLEAF = 1

  CONNECT BY NOCYCLE str = str PRIOR

  AND point <> point PRIOR

  )

  SELECT LISTAGG (perm, ",") THE Group (ORDER BY perm) AS perm_list

  OF got_perm

  GROUP BY str

  ;

  Output:

  PERM_LIST

  --------------------------------------------------------------------------------

  124:369, 369:124

  541:547:965, 541:965:547, 547:541:965, 547:965:541, 965:541:547, 965:547:541

  192:598, 598:192

  Why is your data?  What is the best way to keep it?

  Relational databases work best when each column of each row contains 1 single piece of information.  It is so fundamental to the design of table that he called the first normal form.  This problem (and, I bet, many other problems) would be easier if your data is stored in a standard table.

• SQL query for the date picker

  Page reports there are two 2 day points of selector (a datefrom and dateto a) as well as a text field with AutoComplete element
  
  When the page load query is called
  
  SELECT
  "COL1",.
  "COL2",.
  "COL3",.
  the "table".
  WHERE MYDATES BETWEEN: DATEFROM AND: DATETO
  
  Which returns no records as no dates have been set.
  
  How can I modify this search in the clause WHERE on the date element is called only when the dates are chosen, and by default, all the records are displayed.
  
  The other related issue is when I chose a from and to date and research when I return in the view page of report after consulting other pages in the application of the apex, the form fields are always met, how can I delete the session down for these fields when the user leaves the page?
  
  I hope that all makes sense?

  To_date('01.01.2100', 'dd.mm.yyyy')
  

  will give erroneous results on 02.01.2100 :D

  A solution (perhaps there's a cleaner...):

  WHERE
  ((:DATEFROM IS NOT NULL AND mydates >= :DATEFROM) OR :DATEFROM IS NULL)
  AND
  ((:DATETO IS NOT NULL AND mydates <= :DATETO) OR :DATETO IS NULL)
  

  You can change the message "No data found" by changing the attribute of report "when no. found data Message."

  EDIT: And for the 2nd question, Alex is right, but also be aware that Firefox retains the values of form element when the page refreshes, you must change the Security page 'Form Auto Complete' to 'Disabled' attribute if you do not want to keep the form element values.

  Published by: Yann39 on June 27, 2012 06:30

• SQL query for the list of Menu for a responsibility

  Dear all
  
  I want a query to extract all invites menu for a responsibility as
  
  Responsibility - menu with guest
  System administrator - Concurrent\Requests
  System administrator - Concurrent\Set
  Sysadmin - Concurrent\Conflicts areas
  System administrator - Concurrent\Manager\Administer
  System administrator - Concurrent\Manager\Define
  System administrator - Concurrent\Manager\WorkShifts
  System administrator - Concurrent\Manager\Rule
  System administrator - Concurrent\Program\Define
  System administrator - Concurrent\Program\Executable
  System administrator - Concurrent\Program\Types
  System administrator - Profile\System
  System administrator - Profile\Personal
  
  ---------------------------------------------------------
  
  list should be in order that is defined in the applications menu.
  
  I'll be very grateful you all.
  
  Concerning
  
  Abdelouahed

  I didn't know that the procedure has bugs. Sorry about that.
  It took time to understand, but once set, the script works correctly.
  I can't post the full code (due to restrictions of Metalink) but here are the fixes I had to do.

  (1) do not cut and paste all of the code. It does not get formatted correctly. Do a small section at a time.
  (2) change the quotes around the "STACK OVERFLOW". They are not adequate.
  (3) the code needs of labels for goto statements work. Replace the first <> with >. Replace the 2 <> with >

  Sandeep Gandhi

• SQL query for the scenario below

  Here's my table structure:

  Rule ID	Col1	Col2
  1	A	B
  2	B	A
  3	C	D
  4	D	C

  I need to display lines 1 and 3 or 2 and 4.

  Can someone tell me please how to write a SQL to do this.

  Thanks in advance.

  A guess, that you were not very clear.

  with t

  (Rule ID

  col1

  col2

  )

  as

  (select 1, 'A', 'B' from dual union all)

  Select 2, 'B', 'A' from dual union all

  Select 3, 'C', would be "union double all the"

  Select option 4, had ", 'C' of the double"

  )

  Select min (RuleId)

  , the less (col1, col2) col1

  more grand (col1, col2) col2

  t

  Group of less (col1, col2)

  more grand (col1, col2);

  to indicate a change 2 & 4 Max (RuleId)

• Dynamic SQL query in the DB adapter

  Hello
  I want to use the following custom SQL query in the DB adapter:
  
  SELECT EMP_ID, EMP_NAME, EMP_LOCATION FROM EMP WHERE EMP_ID IN (#iNPUT_PARAMETER)
  
  the problem I'm facing is that I don't know at the time of the development that EMP_ID how much will be passed to the process so that I can not use the input parameter specific number. I cannot use it IN the query within which statement I concatenate all the EMP_ID separated by comma and passed under INPUT_PARAMETER, but when running, he read the full concatenated string as a single string rather than identify them as a list of different: with comma separation. could someone help me in this case
  
  Thank you
  Sunil

  Use the following query with two parameters. Build the string with delimiter when running and pass this string and delimiter to query... (in this example, the input value would be the same for both Delimiter1 and Delimiter2.)

  Select * from EMP WHERE deptno IN (SELECT SUBSTR (STRING_TO_TOKENIZE, DECODE (LEVEL, 1, 1, INSTR (STRING_TO_TOKENIZE, SEPARATOR, 1, LEVEL-1) + 1), INSTR (STRING_TO_TOKENIZE, SEPARATOR, 1, LEVEL)-DECODE (LEVEL, 1, 1, INSTR (STRING_TO_TOKENIZE, SEPARATOR, 1, LEVEL-1) + 1)) FROM (SELECT #StringToTokenizer | #Delimiter1 AS STRING_TO_TOKENIZE, #Delimiter2 AS DELIMITER FROM DUAL) CONNECT BY INSTR (STRING_TO_TOKENIZE SEPARATOR) ((, 1, LEVEL) > 0)

  Thank you
  -Sreeny

• Vs. runtime vs. ViewObject ViewObject SQL query in the xml file.

  Hello

  I wonder what is the difference between query SQL in the long term, creating a view object in the duration and the creation of a display with an XML object.

  I'm not trying to have the result set cached just to pick once.

  
  

  My code for a creation of a view in a run-time object:

  HashSet<Integer> allPersonIdThatUserHasAccessTo = new HashSet<Integer>();
              AppModuleImpl am = (AppModuleImpl)ADFUtils.getApplicationModuleForDataControl("AppModuleDataControl");
  
              String sqlStr = "SELECT up.person_id FROM user_person up where up.user_id = " + userId;
              ViewObjectImpl vo = (ViewObjectImpl)am.createViewObjectFromQueryStmt("AllPeopleUserHasAccessToVo", sqlStr);
              vo.executeQuery();
              RowSetIterator rsi = vo.createRowSetIterator(null);
              while (rsi.hasNext()) {
                  Row personRow = rsi.next();
                  Integer personId = ((BigDecimal)personRow.getAttribute(0)).intValue();
                  allPersonIdThatUserHasAccessTo.add(personId);
              }
  
              rsi.closeRowSetIterator();
              vo.remove();
  

  When should I use SQL query, when the view object use at time of execution and time to create the view object to an xml file?

  In general you should not write this code in a managed bean. Access code or in your case creating a VO belongs behind the façade in the module of the application.

  You can create the original Version, but the main difference is that it takes more time. Code everything that the definition of VO created in the data model of the application module would make too and it clears directly after the query only to create the same code again the next time you call the method.

  If the goal is not to keep the data, you can create the hashset class and call executeEmptyRowSet() on the VO (https://blogs.oracle.com/smuenchadf/entry/what_does_executeemptyrowset_d for details). This way you only need a VO that takes a parameter and gets you the same result in less time.

  Timo