Special characters in sql

Similar Questions

• Resolution IASCI games for (slang word) special characters in SQL

  It comes with the special character slang word in the varchar2 column.
  
  For example, one of my table receives the values in the columns of website... In colunm, we used to receive the varchar to e o words as values in the normal English word.
  
  Column values are like "Hellò Dàvid". Have we not all features standard oracle to replace these words in slang (in o (e) normal English words (a, e, o a - z, A - Z).

  SQL> select translate('Hellò Dàvid','àéò','aeo') from dual;
  
  TRANSLATE('
  -----------
  Hello David
  

• replace special characters in sql select

  Hello

  I have a little problem with one colunm blob in a db.

  A blob contains a text with decimal characters (an application writes this colunm in HTML), for example:

  Kedves Koll & #233 g & #225; k!

  & #193; He's & #225; sfoglal & #225; sotokat k & #233; RJ & #252; k a csatolt panasz & #252; gyben (PI-1167/2014.).

  & #220; gyf & #233; ladatok

  n & #233; v: lives & #225; RIS Anetta

  How could I replace the decimal characters with ascii characters?

  Thans a lot

  set define off

  SELECT UTL_I18N. UNESCAPE_REFERENCE ('Kedves Kollegak!)

  Allasfoglalasotokat Kerjuk a. csatolt panaszugyben (PI-1167/2014.)

  Ugyfeladatok

  Nev: Anetta Vitaris') FROM dual

  UTL_I18N. UNESCAPE_REFERENCE('KEDVESKOLLéGáK!) Allasfoglal & #225

  --------------------------------------------------------------------------------

  Kedves Kollegak!

  Allasfoglalasotokat Kerjuk a. csatolt panaszugyben (PI-1167/2014.)

  Ugyfeladatok

  Nev: Vitaris Anetta

  1 selected line.

• special characters in sql developer

  Hello

  on 11.2.0.4

  I have this request:

  update set mytable = col1' about & law ';

  in sqlplus or sqldevloper

  Then I asked: Bill:?

  Then according to the documentation, I rewrite as:

  Update mytable set col1 = 'about\ & law;

  or:

  Update mytable set col1 = {subject & Bill};

  But I'm always invited.

  Thanks for the help.

  set define off

• Special characters could not load DB via SQL * MORE

  Hi, I have a pl as .accidentally sets sql script which will insert data in database. The question is there are some records are missing and these missing records contains a special character: Sansao and Strasse. The strange was if I run the script via F5 (Toad), all data can be inserted successfully but run through SQL * MORE (Toad), all records that contain special characters are not inserted.

  Anyone here know why it didn't load these special characters via SQL * MORE?

  Probably because you have given unicode (multi byte charsets) you read with a customer of standard single-byte character set.

  It's SILLY to loading data using SQL * more. It's the wrong tool used for loading the data. It does not support the bind variable. It doesn't support liaison in bulk. It does not support direct path inserts. It is not SQL * Loader.

• Replace special characters

  Hello

  I need SQL or PL/SQL code to replace special characters such as!, @, #, $, %, ^ of the given string.

  For example, if the given string is

  "it is - test * strin #g to @ spe % ial charact!" ERS"he should replace all special characters and provide the output voltage

  It's test string with special characters

  Please enter the code

  Thank you

  You have commas in the character set block and the [[: alnum:]] is equivalent to [a-zA-Z0-9], you may want to include a space in this updated chacter block.

  Select REGEXP_REPLACE ("This is test * strin #g to @ spe % ial charact!") ERS ',' [^ [: alnum:]] *', ")

  of the double

  Output

  It's test string with blue characters

  EDIT: I do not know what will want the characters allow the OP. For example, a comma, question mark, comma, colon, apostrophe, full stop etc. are all valid in a sentence.

• What is the differece between a Standard report column and that is set to display text (escape special characters)?

  Hello friends,

  My requirement is

  I want to create a table. Presents some columns to display text.

  so my question is,

  What is the difference between a Standard report column and display text (escape special characters) in the attribute column property?

  Kind regards

  Arianne.

  Hi ujwala1234,

  ujwala1234 wrote:

  Hello friends,

  My requirement is

  I want to create a table. Presents some columns to display text.

  so my question is,

  What is the difference between a Standard report column and display text (escape special characters) in the attribute column property?

  Kind regards

  Arianne.

  Here is the difference:

  • Standard report column: this is used when your column in the SQL query returns the HTML markup. For example the query SQL with APEX_ITEM API columns or columns where you have mixed data in the column with the markup. In short, APEX rendering engine treats the column as HTML markup and analysis accordingly to display the required HTML element.
  • Display text (escape special characters): this type analysis the column data in the form of data stored in the database (no HTML). During analysis if the data contains special characters then it escapes and displays the data.

  Yes, you can mix the manual in the form of built on APEX_ITEM with normal standard report (display text) columns.

  I hope this helps!

  Kind regards

  Kiran

• How to remove special characters from the string using translate() without typing all special characters?

  Hi all

  I am trying to remove special characters without the help of regular expressions.

  translate (the column name or string,'!@#$ & * (* () _) * "" :} {?}) >? /, «, » ')

  I want to eliminate this manual process to give all special characters using a chr() or ascii() function.

  Please show me the way.

  Thanks in advance

  Similar to the solution of Michael...

  SQL > ed
  A written file afiedt.buf

  1 with t as (select "[it comes of the #] [more amazing!") Test @# "$* & $%) assuming chain cost $ 5 000' double Str)
  2, i like (select level 1 c from dual connect by level<=>
  3 less
  4 Select + 32 (level-1) double connect by level<=>
  5 less
  6 select + 58 (level-1) double connect by level<=>
  7 less
  8 select + 91 (level-1) double connect by level<=>
  9 less
  10. Select 123 + (level-1) from dual connect by level<=>
  11 less
  12. Select 255 double
  13            )
  14, ts as (select level r, substr (str, level 1) c
  15 t
  16 connect by level<=>
  17             )
  18, tf as (select row_number() (order for r) r
  19                    ,ts.c
  20 TS
  21 I join on (i.c = ascii (ts.c))
  22             )
  23 select replace (sys_connect_by_path(c,'!'),'! ') Str
  24 TF
  25 where connect_by_isleaf = 1
  26 connect r = prior r + 1
  27 * start with r = 1
  SQL > /.

  STR
  -----------------------------------------------------------------------------------------------------------------------
  Thisisthemostamazingtest¸astringcosting5000

  Or something as horrible as this...

  SQL > ed
  A written file afiedt.buf

  1 with t as (select "[it comes of the #] [more amazing!") Test @# "$* & $%) assuming chain cost $ 5 000' double Str)
  2, I like (select replace (sys_connect_by_path (chr (c), 'A'), 'A') as tr)
  3 of)
  4 select c, rownum r
  5 (select 32 + (level-1) as the double connection by level c<=>
  6                         union
  7 select + 58 (level-1) double connect by level<=>
  8                         union
  9 select + 91 (level-1) double connect by level<=>
  10 the union
  11. Select 123 + (level-1) from dual connect by level<=>
  12 union
  13. Select 255 double
  14 tri 1
  15                        )
  16                  )
  17 where connect_by_isleaf = 1
  18 log r = prior r + 1
  19 start with r = 1
  20            )
  21 select translate (str, 'A' |) TR, 'A') as str
  22 * t, I
  SQL > /.

  STR
  --------------------------------------------------------------------
  Thisisthemostamazingtest¸astringcosting5000

• How to implement insert and put implement with special characters

  Hi all

  Scenario: I have a table and that is having e-mail column.

  condition:-my e-mail column should meet under the condition when the data is inserted.

  It should not allow any of the special characters ('@ ','.') and a ' @'.

  
  

  Thank you
  

  SQL> create table t
    2  (
    3    email varchar2(100) not null
    4  , constraint email_check check
    5                           (
    6                                 regexp_replace(email, '[@|.|[:alnum:]]') is null
    7                             and length(email) - length(replace(email, '@')) = 1
    8                           )
    9  );
  
  Table created.
  

  I used two conditions.

  1 regular expression to see if there is any character that is NOT @ or. or Digital Alpha.

  2 length check if @ is this several times.

  SQL> insert into t values ('[email protected]');
  
  1 row created.
  
  SQL> insert into t values ('karthick.p@@abcd.com');
  
  insert into t values ('karthick.p@@abcd.com')
  *
  ERROR at line 1:
  ORA-02290: check constraint (KARTHICK.EMAIL_CHECK) violated
  
  SQL> insert into t values ('[email protected]');
  
  insert into t values ('[email protected]')
  *
  ERROR at line 1:
  ORA-02290: check constraint (KARTHICK.EMAIL_CHECK) violated
  

• very special characters in columns

  I am trying to remove special characters from a db column using the below query, but I'm not getting results can someone help

  Select replace (CHR. (5) |) ' ABC'. Chr (1) | ' lkaljsk', Chr (5) | » '|| Chr (1)) double

  SQL > select regexp_replace (CHR. (5) |) ' ABC'. Chr (1) | ' lkaljsk ',' [' | CHR. (5) |] » ' || Chr (1) | ') of double
  2.

  A
  ----------
  abclkaljsk

  SQL >

  SY.

• Function to remove special characters in a column.

  Hi all

  In one of my column, we get special characters, as well as others. The data are extracted and loaded through Informatica. We are not face any problem while loading into the target, but when we try to extract these data through the report, it fails with the error:

  ORA-29275: partial multibyte character sets

  When we check this column, we find the special characters. Initially, we have implemented logic with the CHR to replace these NULL values. But every time we get different values. To make the permanent solution, we decided to remove all characters except available on Board of the key.

  Now, to this end, I need to write a function in Oracle's PL/SQL. I do not know more easy way from there to achieve. If I go with the CHR() function, I have to write for all these characters, which I think is not the right solution.

  Enjoy, if someone can help me identify the function or the way to get there.

  Thanks in advance.

  Hello

  AceNovice wrote:

  ... we have decided to remove all characters except available on key board...

  It depends on your keyboard.

  All that is on the keyboard you, something similar to this shoud work:

  REGEXP_REPLACE (string_column

  , '[^]0-9A-Za-z~!@#$%^&*()_+`={}| [\:";'' <>?,./-]'

  )

  This will return a copy of string_column, but with all the characters that are not not in the 2nd deleted argument.

  [Inside the brackets, ']' must come first (immediately after the ' ^') and '-' must come last.

• How to enter special characters with the Run statement (@).

  Hello

  Oracle10g (R1)

  NLS_CHARACTERSET = "AL32UTF8.

  When I insert record with special characters like "hastened" with the customer tool insert it works fine, but I run the same INSERT statement execution i.e. statement "SQL > @/ path/Script_File_Name.sql ' special characters has not inserted correctly and it become something like 'h¿ta'.»»

  How to enter special characters correctly race (@) statement?
  
  Thank you

  If you create a file in Notepad, select the ANSI or the encoding UTF-8 in the dialog box save as.  Copy the Linux file in binary mode. Set the variable NLS_LANG ".» WE8MSWIN1252 ", if the file was saved with the ANSI coding or to. AL32UTF8", if the file was saved with UTF-8 encoding. Be sure to export the variable.  Then, start SQL * more and run the script.  I guess that you are on a U.S. or Western Europe of Windows version.

  Thank you

  Sergiusz

• Special characters in password?

  What are the rules for passwords? Thank you.
  
  We felt to create a problem when the password included a character @.
  
  Published by: davejjj on April 2, 2013 09:17

  davejjj wrote:
  So why Oracle accept passwords that include the character @? Why didn't he simply reject them? Or how can they be rejected in the future? Thank you.

  Published by: davejjj on April 2, 2013 10:18

  they can be denied using a function of complexity of password, such as specified in the user profile. See http://docs.oracle.com/cd/B28359_01/network.111/b28531/authentication.htm#i1007341 for a discussion. After reading it, before you do anything, think about these points, which are perhaps not so obvious

  (1) you don't have to use the provided, either in the content or name. The name of the function to use is specified in the profiledefinition. And since you can have multiple profiles (for example, one for ordinary users, the other for the DBA) each profile can specify its own audit function.

  (2) the function is just a bunch of PL/sQL code. There is no magic here. You can code to do what you want - apply different rules of complexity, to require that certain characters, reject some characters, etc. At my last store I specifically rejected 3 different special characters that had proved to be problematic, because the password could pass through systems which would take these characters as a kind of beacon. '@' in a connection string. ' $' in a shell script. And believe it or not, "#" when used by Oracle Forms.

• How to limit the special characters for a specific column

  Dear gurus,
  
  I have a table with a field Champ_1 emp
  
  in this particular Champ_1 is an address column where the data can be as ' 12 st first floor"but suppose by mistake the user has entered data as 12 st first floor & ' must be restricted (not using relaxation but can this be possible using constraints) so for this we can how to restrict the special characters only not to get entered in the column.
  
  
  Kind regards
  friend

  Yes you can do it like this

  SQL> create table t (field_1 varchar2(4000));
  
  Table created.
  
  SQL> alter table t add constraint t_chk check(length(regexp_replace(field_1, '[[:alnum:]|[:space:]]'))=0);
  
  Table altered.
  
  SQL> insert into t (field_1) values ('12 st first floor');
  
  1 row created.
  
  SQL> insert into t (field_1) values ('12 st first floor & ');
  insert into t (field_1) values ('12 st first floor & ')
  *
  ERROR at line 1:
  ORA-02290: check constraint (ARBORU.T_CHK) violated
  
  SQL> 
  

• Does not not special characters in the password

  Here's the function I used to apply the oracle password. I can able to use all the numbers, characters, but when I use special as cat (punctarray: ='!) » #$% & ()'' * +,-/ : ; <>=? _';) I can able to use only the characters # when I'm with all the other amazing it gives me an error
  
  
  SQL > alter user u1 identified by nira86 #* wad456j;
  change the u1 user identified by nira86 #* wad456j
  *
  ERROR on line 1:
  ORA-00922: missing or not valid option
  
  
  
  Here's the function
  
  FUNCTION to CREATE or REPLACE verify_function
  (username varchar2,
  password varchar2,
  VARCHAR2 old_password of past)
  RETURNS boolean IS
  Boolean n;
  whole m;
  different integer;
  Boolean IsDigit;
  because Boolean;
  ispunct Boolean;
  digitarray varchar2 (20);
  punctarray varchar2 (25);
  CharArray varchar2 (52);
  
  BEGIN
  digitarray: = "0123456789";
  CharArray: = 'abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ ';
  punctarray: ='! » #$% & ()'' * +,-/ : ; <>=? _';
  
  -Check if the password is the same as the user name
  IF (password) NLS_LOWER = NLS_LOWER (username) THEN
  raise_application_error ("-20001, ' identical or similar to the user password");
  END IF;
  
  -The minimum length of the password checking
  IF (password) length < 15 THEN
  raise_application_error (-20002, 'length of less than 15 password');
  END IF;
  
  -Check if the password is too simple. A dictionary of words can be
  -maintained and can be verified so does not allow the words
  -which are too simple for the password.
  IF NLS_LOWER (password) IN ('Welcome', 'database', 'account', 'user', 'password', 'oracle', 'PC', 'abcd') THEN
  raise_application_error ('-20002, ' simple password ');
  END IF;
  
  -Check if the password contained at least a letter, a number and a
  -punctuation mark.
  -- 1. Check for the digit
  IsDigit: = FALSE;
  m: = length (password);
  FOR I IN 1.10 LOOP
  FOR j IN LOOP 1.m
  IF substr (password, j, 1) = substr(digitarray,i,1) THEN
  IsDigit: = TRUE;
  GOTO findchar;
  END IF;
  END LOOP;
  END LOOP;
  IF IsDigit = FALSE THEN
  raise_application_error (-20003, 'password must contain at least one digit, a character and a punctuation');
  END IF;
  -- 2. Check the character
  < < findchar > >
  car: = FALSE;
  FOR i IN 1.length (chararray) LOOP
  FOR j IN LOOP 1.m
  IF substr (password, j, 1) = substr(chararray,i,1) THEN
  car: = TRUE;
  GOTO findpunct;
  END IF;
  END LOOP;
  END LOOP;
  Because IF = FALSE THEN
  raise_application_error (-20003, ' password must contain at least one------)
  Figure, a character and a punctuation ');
  END IF;
  -- 3. Search for punctuation
  < < findpunct > >
  ispunct: = FALSE;
  FOR i IN 1.length (punctarray) LOOP
  FOR j IN LOOP 1.m
  IF substr (password, j, 1) = substr(punctarray,i,1) THEN
  ispunct: = TRUE;
  GOTO endsearch;
  END IF;
  END LOOP;
  END LOOP;
  Ispunct IF = FALSE THEN
  raise_application_error (-20003, ' password must contain at least one------)
  Figure, a character and a punctuation ');
  END IF;
  
  < < endsearch > >
  -Check if the password is different from the previous password at least
  -3 letters
  Old_password past IF IS NOT NULL THEN
  differ: = length (old_password) - length (password);
  
  IF abs (differ) < 3 THEN
  IF (password) length < length (old_password) THEN
  m: = length (password);
  ON THE OTHER
  m: = length (old_password);
  END IF;
  
  differ: = abs (differ);
  I'm IN 1.m LOOP
  IF substr (password, i, 1). = substr(old_password,i,1) THEN
  differ: = differ + 1;
  END IF;
  END LOOP;
  
  IF different < 3 THEN
  raise_application_error (-20004, ' password should differ by to)
  (minimum 3 characters);
  END IF;
  END IF;
  END IF;
  -Everything all right; Return TRUE;
  RETURN (TRUE);
  END;
  /

  What version of Oracle are you using? Before 11 g I think only allowed special characters were '_', ' $' and ' # '.

  And 11 g, you need to put the password in quotation marks and must not use comma, backslash or double quote.