SQL query to get a total number of calls date in 72hrs of another
I'm writing a query that returns a total percentage complete within 72 hours.where appt_dt 72hrs of referral_gen_dt I do not know how to configure it?
For 72 hours is 3 days...
where abs (appt_dt - referral_gen_dt)<=>=>
(oops)
Published by: SomeoneElse on December 10, 2008 11:34
Tags: Database
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SQL query to find the total number of source based nonsource passangersbetween source and destination station and passenger station on the same chekindate.
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SQL query to get employees ranks changed between given dates
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I have a requirement for employees whose quality has changed in these dates.
Create the table per_all_assignments_f
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Date of Effective_end_date,
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;
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;
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100 January 1, 2015 31-dec-2015 2 101 01-jan-2014 31-dec-2014 1
101 January 1, 2015 31-dec-2015 1 Above the ground changed only for person_id 100 to 1 January 2015 and 31-dec-2015.
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Kind regards
Afzal.
Then try this...
SELECT Person_id,
effective_start_date,
effective_end_date,
grade_id
Of
(SELECT person_id,
effective_start_date,
effective_end_date,
grade_id,
LAG(grade_id,1,grade_id) OVER(PARTITION BY person_id ORDER BY effective_start_date,effective_end_date) lag_val
OF per_all_assignments_f
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Details of the environment
======================
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Hi fatimakhellil
Try the following code and mark it as correct if your problem be resolved.
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MSI. Description,
MSI.primary_uom_code,
MSI.inventory_item_id,
MSI.organization_id,
Ms.secondary_inventory_name,
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AND msi.organization_id = organization_id) last_transaction_date
OF mtl_system_items_b msi.
Ms. mtl_secondary_inventories
WHERE ms.organization_id (+) = msi.organization_id
AND msi.source_subinventory = ms.secondary_inventory_name (+)
AND NOT EXISTS (SELECT *)
OF mtl_material_transactions mmt
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AND msi.organization_id = mmt.organization_id
AND mmt.subinventory_code = ms.secondary_inventory_name
AND mmt.organization_id = ms.organization_id
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SQL query to get the NULL records after the last matching flag
I have a xx1 table with id and flag columns. So I want the data in this table, after the last flag matched. I want that data to id 7 in the rooms. Even if the id 2,3,5 are null flag 'Y' was at 6. ID so I need a query to get the data of the xx1 table after the last correspondence flag (from 7 to 9 id).
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2 (identification number,
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---------- ----------
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2
3
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8
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SQL >
Hello
user11164339 wrote:
Hi Frank - when I run the query, I don't see the results data.
I get
FLAG OF THE ID
----- ----------
7
8
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What you do differently?
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-----
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I know that you guys will be of help because you are all awesome. Thank you all
Published by: 1001275 on April 19, 2013 20:07
Published by: 1001275 on April 19, 2013 20:18Hello
1001275 wrote:
Hi sb92075,You are right that it is available with this version. But our system doesn't put queries that use subquery factoring.
What system are you talking about? If you really have something that prevents you from using all the features of Oacle, you should seriously think about fixing it.
Any other ideas on how we can do this without help WITH clause?
Yes; If a WITH clause is referenced that once, it can be re-written as a point of view online:
SELECT wipdatavalue , slot , ROW_NUMBER () OVER ( PARTITION BY slot ORDER BY low_number ) AS m , COUNT (*) OVER ( PARTITION BY slot ) AS n FROM ( -- Begin in-line view (got_numbers) SELECT wipdatavalue , slot , TO_NUMBER ( SUBSTR ( wipdatavalue , 1 , INSTR ( wipdatavalue || '-' , '-' ) - 1 ) ) AS low_number , TO_NUMBER ( SUBSTR ( wipdatavalue , 1 + INSTR ( wipdatavalue , '-' ) ) ) AS high_number FROM trprinting ) -- End in-line view got_numbers CONNECT BY LEVEL <= high_number + 1 - low_number AND low_number = PRIOR low_number AND PRIOR SYS_GUID () IS NOT NULL ORDER BY low_number , m ;
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30 sep-2013
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26 sep-2013
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-----------------------------
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27 - Sep - 2013 13:04:52
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