SQL to find logical replication

Similar Questions

• There is no sql to find no matching rows

  Hi all

  I want to optimize the sql where I find the column (junction of two columns) presents in a table (tab1) but not in other (tab2). I tried something like that, but it is showing me no line.

  SELECT COL1 | COL2

  OF e TAB1

  where there is NO

  (

  Select 1 in TAB2 rd

  Join e TAB1 on e.COL1 | e.COL2 = RD. COL1 | RD. COL2

  )

  When I use the simple sql (which takes a lot of time hell) I get good output: 0

  SELECT COL1 | COL2

  OF e TAB1

  where COL1 | Col2 not in

  (

  Select COL1 | Col2 from TAB2 rd

  )

  What is wrong in the query "EXISTS NOT", or suggest me best way to achieve the same thing. Thank you!

  Few things

  1. do not concatenate columns, and then compare. They can cause an incorrect result. Consider this

  tab1.col1 = 'KAR' and tab1.col2 = 'THICK'
  
  and
  
  tab2.col1 = 'KARTHI' and tab2.col2 = 'CK'
  

  Concatenation and join them will result in the return line. But in fact they do not condition.

  2. NO EXISTS and NOT IN are not the same. The two manage NULL value very differently. If there is a NULL value in the sub operator NOT IN the entire State query fails.

  https://asktom.Oracle.com/pls/asktom/f?p=100:11:0:no:P11_QUESTION_ID:442029737684

  Says, try something like this

  select t1.*
    from tab1 t1
  where not exists
         (
             select null
                from tab2 t2
               where t1.col1 = t2.col1
                 and t1.col2 = t2.col2
         )
  

• Modeler data SQL cannot find the java sdk

  Hello

  I want to install 4.0.3 - 853 on windows xp 32-bit.

  In the first inning, message "could not find a java sdk SE way...» »

  I had already installed first jre 1.7.0_45 - as indicated on the installation notes page that produces this error message.

  After reading other peoples problems I replaced it with the jdk 1.7.0_45 because the request for enforcement is the path to the java JDK home.

  Still get the same message as above.

  I tried to change the SetJavaHome in datamodeler.conf, but that didn't work or the other.

  I tried pointing the Launcher to d:\oracle\java\jdk1.7.0_45 as d:\oracle\java\jdk1.7.0_45\bin and d:\oracle\java\jdk1.7.0_45\bin\java.exe all to nothing does not.

  On a light off the coast of the chance - like cleaning the windshield when the car won't start - I installed SQL Developer 4.0.3.16.84 in case the treatment was slightly different.

  Same result

  Very frustrating every previous version of the developer and grouped data with java maker has just installed in a few minutes.

  All of the inspiring thoughts / solutions would be extremely appreciated

  Thank you

  Stem

  Ok

  It seems that - maybe - jdk1.7.0_71 high is needed and jdk1.7.0_45 is not acceptable whatever the installation notes which stipulate that jre 1.7 is suitable. Mind the same version of SQLDeveloper says he wants to 1.8, but seems to work very well with 7u71

  I had stayed in 7u45 to minimize disruptions to the installation of 10g of shapes on the same machine which of course do not now

  It's looking no doubt easier to get this working with 7u71 than the other way around.

  Stem

• The shortcomings of SQL to find missing persons

  Hi gurus,

  I have a simple SQL question on how to find the gaps. I have a Table: GLHDR_M with ACUTE flange as key field with an ID of account from 'A1000001' to 'A3999999', but with gaps inbetween. I want to reassign the missing IDS to those newly created. How can I find the missing ID with a simple SQL statement?

  Thank you

  Otherwise, you can simply add the condition "AND PRIOR DBMS_RANDOM. VALUE don't IS NOT NULL' with the connect by clause

  SELECT 'A ' | LPAD (TO_NUMBER (LTrim (Replace ('A0904000', 'A'), '0')) +(rowNum-1), 7, '0') accide

  OF THE DOUBLE

  CONNECT BY LEVEL<= to_number(ltrim(replace('a0904999','a'),'0'))-to_number(ltrim(replace('a0904000','a'),'0'))="" +="">

  AND PRIOR DBMS_RANDOM. VALUE IS NOT NULL

  LESS

  SELECT acid glhdr_m acid WHERE BETWEEN 'A0904000' AND 'A0904999 ';

  I don't have a 9i environment to test this. Then you can try it, and if you get the error, you can try with the function table in pipeline I gave already.

• Bluetooth cannot find logical error code turn 10

  Acer aspire 6920 with bluetooth.    try to only synchronize sound logic itower, acer vcm no external audio device and the bluetooth connection Center disabled

  Hello

  Method 1:

  Check the link and see if it helps:

  Description of errors related to the 10 Code that generates the Device Manager in Windows on computers

  http://support.Microsoft.com/kb/943104

  Method 2:

  Check the link and try to run the Microsoft Fix it:

  Hardware devices do not work or are not detected in Windows

  http://support.Microsoft.com/mats/hardware_device_problems/en-us

  Method 3:

  I would say as update you the drivers for the device and check if the problem persists:

  Updated a hardware driver that is not working properly

  http://Windows.Microsoft.com/en-us/Windows-Vista/update-a-driver-for-hardware-that-isn ' t-work correctly

  Let us know if it helps.

• SQL to find different files in path

  Hi Experts,

  Please help me this sql

  I have a table

  file tracking template

  P1 m1 f1

  P1 m1 f2

  P1 f3 m2

  P2 f11 m11

  P2 f12 m12

  ------------------

  I need output of

  P1 f3 m2 (m2 model in path p1 is LESS THAN m1)

  P2 f11 m11 (case model m11 in road p2 is equal to m12)

  OR

  P1 f3 m2 (m2 model presence in path p1 is more than m1)

  P2 f12 m12 (case model m12 in road p2 is equal to m11)

  ---------------------

  Thanks in advance

  Thanks to user12222981 for providing the scripts of creation and insertion. These scripts using my request could be simplified as below.

  () AS T2

  SELECT THE PATH,

  FILES,

  MODELS,

  COUNT (*) IN THE CNT (PARTITION PATH, MODELS)

  OF TEST_PATH)

  SELECT THE PATH,

  FILES,

  MODELS

  DE)

  SELECT THE PATH,

  MODELS,

  FILES,

  NTC,

  MIN (MODELS) MORE MIN_MODEL (PATH PARTITION)

  THE T2

  WHERE NTC IN (SELECT MIN (CNT) OF THE T2

  GROUP BY PATH))

  WHERE MODELS = MIN_MODEL;

  OUTPUT:

  PATH OF THE TEMPLATES FILES

  -------------------- -------------------- -----------

  p1                   f3                   m2

  p2                   f11                  m11

• How to force a return, even if the sql cannot find a record

  Hello
  I ' l try explan, what I'm looking for:
  I have a SQL query (Oracle 10 g) as
  
  Select system, A, B T where system = 0
  
  In the table T is no record with system = 0, so I don't get anything back from the SQL. It's OK, but I need to get something like * 0, "," * as a return. I tried with NVL(SysT,0)... but it seems not to be the solution.
  
  Does anyone has an idea how to solve this problem?
  
  Best regards
  Carsten

  Hi, Carsten,

  Another way to do this is to use an outer join:

  SELECT  0 AS SysT, a, b
  FROM               dual
  LEFT OUTER JOIN  t    ON  t.SysT  = 0
  ;
  

  UNION, Saurabh suggested, is a way to do it. If the combination (System, a, b) is not unique in table t, then you need to make UNION ALL , which is more efficient anyway, to avoid losing lines.
  If the original query is longer than what you have posted, you will not want to repeat. Write it only once, in a WITH clause, like this:

  WITH       original_query     AS
  (
       SELECT  SysT, a, b
       FROM      t
       WHERE      SysT     = 0
  )
  SELECT     *
  FROM     origianl_query
      UNION ALL
  SELECT     0 AS SysT, a, b
  FROM     dual
  WHERE     NOT EXISTS  (
                        SELECT     1
                 FROM     original_query
                    )
  ;
  

  Regardless of how complicated the original query, the EXISTS subquery is just 'SELECT 1 FROM original_query '.

  Published by: Frank Kulash, December 19, 2011 06:21

• How to build a SQL for this logic.

  Hello
  
  I have a requirement like, I need to derive a column with a calculation.
  
  Here is the psedocode,
  
  number of occurrence (deptno = 10) / count (deptno = 10)
  
  Expected result:
  
  If the deptno = 10 occurs 3 times in the table, then at the time of fist should be the calcuation
  
  second 1/3, 2/3 of the time, the third time 3/3 and so on.
  
  How can I build in a sql query. Help, please.
  
  Any help will be appreciated with points.
  
  Thank you.

  Try this.

      SELECT LEVEL / CNT CALC
        FROM (SELECT COUNT (*) CNT
                FROM EMP
               WHERE DEPTNO = 10)
  CONNECT BY LEVEL <= CNT
  

  G.

• using SQL to find?

  Is it possible to use SQL queries to search for names of entries which are contained in an URL parameter?

  The situation is the following:

  In the #1 database, I have several entries (A, B, C, D, etc.). I want to know if I can use WHERE and LIKE clause to filter the entries that appear in a URL parameter.

  The normal code: WHERE nom_entree AS % whateverTheURLparameterIs % displays only entries that have the URL containsparameter. I need the code to display the entries contained in the URL parameter.

  P.S. does not have the code WHERE the whateverTheURLparameterIs AS argument entryName % .

  Consider using the full text for this research. You could probably achieve what you want to use the like with a predicate subquery, but a full text search will be faster. You can also control the respect of the case.

  > PS another problem that I am having with what corresponds to the URL

  > settings, because they include all of the

  > article ("Hi. My name is... (''), tend to be very long.

  No need to include the item in the query string. The article is stored in the table. Just pass the id of the item in the query string.

• SQL to find the same DATE?

  I wanted to do a check based on a Table of 10g.
  
  customer_id, DATE
  
  Basically, I wanted to do a check, make sure that each customer_id has a SEPARATE DATE, therefore, for the returned data.
  the DATE must be unique and not repeat, I know its probably something super simple, but I wanted to analyze the entire
  table and do a count of these instances:
  
  It would be nice:
  
  12345 20101001
  25487 20101002
  
  This would not be permitted:
  
  12345 20101001
  12345 20101001 - double date
  25487 20101002
  
  a varchar2 column, it is in format YYYYMMDD, not not using type DATE, just FYI. Ago, I know, I have not said that upward.
  
  I would use a SELF JOIN here, not a lot of experience in this.

  Hello

  Here's one way:

  WITH     got_cnt          AS
  (
       SELECT     customer_id
       ,     dt          -- DATE is not a good column name
       ,     COUNT (*) OVER ( PARTITION BY  customer_id
                                  ,              dt
                      )      AS cnt
       FROM    table_x
  )
  SELECT    *
  FROM       cot_cnt
  WHERE       cnt     > 1
  ORDER BY  customer_id
  ,            dt
  ;
  

  A self-join anouther way to find duplicates, but may not be as effective. In addition, what would you like if it was be stored 3 (or more) with the same customer_id and dt?

  Published by: Frank Kulash, October 21, 2010 16:44

  Oh!
  If you want to display the columns are duplicated, you can do something even more fast and simlpler:

  SELECT       customer_id
  ,       dt
  ,       COUNT (*)     AS cnt
  FROM       table_x
  GROUP BY  customer_id
  ,       dt
  HAVING       COUNT (*)     > 1
  ;
  

• SQL to find the grouped rows that have changed their values?

  Hello
  I wonder if it is a pure SQL way do this...?
  
  I have a table that has a number of columns:
  InsertionDate
  IDENTITY
  Col - has to pass - z - some data.
  
  the pair (InsertionDate, identity) is unique.
  
  The lines represent the same values as they change over time, for example:
  
  Select * from < mytable > by its identity, InsertionDate;
  Balance InsertionDate identity
  10 February 01-1001 - 100
  11 February 01-1001-1
  1001 12 February 01 50
  10 February 01-1002-10
  11 February 01-1002-10
  1002 12 February 01 76
  
  
  I want to do the following:
  
  Select < myTable > from where InsertionDate and the next InsertionDate have a different value for the balance "grouped by" identity and InsertionDate = "10 February 01»;»»
  [I use "grouped by" with great caution - I can't explain in 'Nick sql' without using the misleading grouped by term]
  
  To produce the output:
  
  Balance InsertionDate identity
  10 February 01-1001 - 100
  11 February 01-1001-1
  
  Select < myTable > from where InsertionDate and the next InsertionDate have a different value for the balance "grouped by" identity and InsertionDate = ' 11 February 01»;»»
  Balance InsertionDate identity
  11 February 01-1001-1
  1001 12 February 01 50
  11 February 01-1002-10
  1002 12 February 01 76
  
  There may be several columns in addition to the balance that should also be checked for changes.
  
  See you soon,.
  Karl.

  A little misread your reqs:

  with t as (
             select to_date('10-Feb-01','dd-mon-yy') InsertionDate,1001 Identity,-100 Balance from dual union all
             select to_date('11-Feb-01','dd-mon-yy'),1001,1 from dual union all
             select to_date('12-Feb-01','dd-mon-yy'),1001,50 from dual union all
             select to_date('10-Feb-01','dd-mon-yy'),1002,10 from dual union all
             select to_date('11-Feb-01','dd-mon-yy'),1002,10 from dual union all
             select to_date('12-Feb-01','dd-mon-yy'),1002,76 from dual
            )
  select  InsertionDate,
          Identity,
          Balance
    from  (
           select  InsertionDate,
                   Identity,
                   Balance,
                   row_number() over(partition by Identity order by InsertionDate) rn,
                   lead(Balance,1,Balance - 1) over(partition by Identity order by InsertionDate) next_balance
             from  t
          )
    where balance != next_balance
      and rn != 1
    order by Identity,
             InsertionDate
  /
  
  INSERTION   IDENTITY    BALANCE
  --------- ---------- ----------
  11-FEB-01       1001          1
  12-FEB-01       1001         50
  11-FEB-01       1002         10
  12-FEB-01       1002         76
  
  SQL>  
  

  SY.

• SQL to find the counts based on the date

  Hello
  I have a table called APP_TXN and there application_id, application_status, and created_dt columns. My job is to find number of applications created in the last 0-4, 5-9 days and 10 + days, application_status group. Help, please.
  
  Thank you and best regards,
  Christopher.

  Something like that

   select application_status,
       sum(case when created_date between sysdate-4 and sysdate then 1 else 0 end) CNT0TO4DAYS,
       sum(case when created_date between sysdate-9 and sysdate-5 then 1 else 0 end) CNT5TO9DAYS,
       sum(case when created_date <= sysdate-10 then 1 else 0 end) CNT10PLUSDAYS
     from app_txn
    group by application_status
  

• SQL to find identical domains in e-mail addresses

  Hi, guys can anyone help me design a query that will be guve me the names and e-mail addresses of all people who wear the same registered domain name
  
  Published by: user12258774 on November 22, 2009 13:35
  
  Published by: user12258774 on November 28, 2009 13:09
  
  Published by: user12258774 on November 28, 2009 13:11

  Add consultantid column to table T and use < (or=""> ) instead of (! =) when to comparating consultantid:

  WITH T AS (
  select firstname, lastname, email, expertiseid, c.consultantid
    from consultants c, skills s
   where s.consultantid=c.consultantid)
  Select t1.firstname, t1.lastname, t1.email, t2.firstname, t2.lastname, t2.email
    from t t1, t t2
   where t1.consultantid
  

  Max

• Query or logic to find several days through each month.

  Dear friends,
  
  I need your help to solve this problem.
  
  We have a now where we have to pay compensation to the employees based on their number of working days.
  
  Say, for example, if an employee has worked since March 3, 2012-April 5, 2012.
  
  We have a fixed value for a month 300 dirhams. But the number of days on s March 31 and number of days in the month of April are 30.
  
  So by compensation daily for March day would be 300/31 and April would be 300/30.
  
  We are looking for a logical opr query that calcluates first right number of days in each month (per month) and then calculate as below
  
  Number of working days in the month of March is 31-3 + 1 = 29
  
  Compensation of A1 = (300 * 29) / 31
  
  Number of working days in the month of April is 5 (must also find logical I guess)
  Allowance for A2 = (300 * 5) / 30
  
  Then A1 + A2.
  
  (E) would be the total quota when the number of months in all.
  
  Please guys any help would be greatly appricated.
  
  R

  Just a follow-up ;-)

  Note that you can almost get what you want with standard MONTHS_BETWEEN function [url http://docs.oracle.com/cd/E11882_01/server.112/e26088/functions102.htm#i78039].
  But notice this quote from the documentation:

  >
  If date1 and date2 are the same days of the month or the last two days of the month, the result is always an integer. Otherwise the Oracle database calculates the fractional part of the result based on a month of 31 days and consider the time difference components date1 and date2.
  >

  It will always use one even if 31 days a month has fewer days.

  Then you could also implement the logic of my previous answer as your own function months_between implementation:

  create or replace function my_months_between (
     p_todate    date
   , p_fromdate  date
  )
     return number
  is
  begin
     return ((extract(day from last_day(p_fromdate))-extract(day from p_fromdate)+1) / extract(day from last_day(p_fromdate)))
          + (months_between(trunc(p_todate-1,'MM'),trunc(p_fromdate,'MM'))-1)
          + (extract(day from p_todate-1) / extract(day from last_day(p_todate-1)));
  end my_months_between;
  /
  

  I changed it to make it "compatible" with the standard function that it calculates up to but not including the parameter to date (which is correct when you are considering dates with time included, but I guess in your case, you have just date values.)

  Then, you can compare the results of the standard months_between with the new my_months_between:
  (Note that I have call the functions with the d2 + 1 to give the desired result of inclusion and to this day in the calculation).

  SQL> with testdata as (
    2     select date '2012-03-03' as d1, date '2012-04-05' as d2 from dual union all
    3     select date '2012-02-03' as d1, date '2012-05-02' as d2 from dual union all
    4     select date '2012-03-03' as d1, date '2012-03-10' as d2 from dual union all
    5     select date '2012-03-01' as d1, date '2012-07-31' as d2 from dual union all
    6     select date '2012-02-01' as d1, date '2012-03-01' as d2 from dual union all
    7     select date '2012-01-01' as d1, date '2012-03-25' as d2 from dual
    8  )
    9  --
   10  -- end of test data --
   11  --
   12  select months_between(d2+1, d1) std_months
   13       , 300 * months_between(d2+1, d1) std_allowance
   14       , my_months_between(d2+1, d1) my_months
   15       , 300 * my_months_between(d2+1, d1) my_allowance
   16    from testdata
   17  /
  
  STD_MONTHS STD_ALLOWANCE  MY_MONTHS MY_ALLOWANCE
  ---------- ------------- ---------- ------------
  1.09677419    329.032258 1.10215054   330.645161
           3           900 2.99555061   898.665184
  .258064516    77.4193548 .258064516   77.4193548
           5          1500          5         1500
  1.03225806    309.677419 1.03225806   309.677419
  2.80645161    841.935484 2.80645161   841.935484
  
  6 rows selected.
  

  For a large part of the data, both give the same result, especially when the two dates are in month of 31 days.
  To work from ' 2012-03-03' to '' 2012-04-05 standard service gives too little because it uses always 31 days, while my_months_between uses 30 days of April.

  "But note working from '' 2012-02-03 to 2012 - 05 - 02. He jumped 2 days in February and has worked 2 days in May - the standard function concludes he works precisely 3 months.
  But my_months_between computes fraction 27/29 months in February, then March and April like 2 months, and then the fraction 2/31 months in May - which gives a total of 2.99555061 instead of 3 months.

  Just something to be aware of ;-)

• Find missing at time interval in SQL

  All the

  Need help with SQL to find the missing time interval.

  My query returns data as shown below

  Data1

  StartTime EndTime column
  =======   =======   =======

  T2 09:00 18:00

  T3 20:00 23:00

  Data2

  StartTime EndTime column
  =======   =======   =======

  T1 15:00 20:00
  T3 20:00 07:00

  Take above output, I want to find time is not on my data within 24 hours of the first StartTime on each set of data.

  Example: Data1

  First StartTime: 09:00 (registration T2)

  Add 24 hours, which will be updated 21:00.

  Result to get missing scheduled interval for Data1
  18:00 - 20:00

  23:00-09:00 (next day)

  For expected result of data2

  07:00-15:00 the next day

  The basic version: 11g

  Someone at - he met to calculate the missing time interval? Can I use PL/SQL for this as a function of pipeline?

  Any help/directions/references that I greatly appreciate.

  Thanks in advance.

  Edward

  One way to find missing intervals:

  
  alter session set nls_date_format = 'DD-Mon-YYYY HH24:MI:SS';
  with data as
  (
    select to_date('28-Jun-2013 09:00', 'DD-Mon-YYYY HH24:MI') start_time, to_date('28-Jun-2013 18:00', 'DD-Mon-YYYY HH24:MI') end_time from dual union all
    select to_date('28-Jun-2013 20:00', 'DD-Mon-YYYY HH24:MI') start_time, to_date('28-Jun-2013 23:00', 'DD-Mon-YYYY HH24:MI') end_time from dual
  )
  select start_time, end_time,
         case when lead(to_char(start_time, 'HH24'), 1, (select min(to_char(start_time, 'HH24')) from data)) over (order by to_char(start_time, 'HH24')) not between to_char(start_time, 'HH24') and to_char(end_time, 'HH24')
                then to_char(end_time, 'HH24:MI') || ' - ' || lead(to_char(start_time, 'HH24:MI'), 1, (select min(to_char(start_time, 'HH24:MI')) from data)) over (order by to_char(start_time, 'HH24:MI'))
              else
                null
         end period
    from data
  
  START_TIME                END_TIME                  PERIOD
  ------------------------- ------------------------- -------------
  28-Jun-2013 09:00:00      28-Jun-2013 18:00:00      18:00 - 20:00
  28-Jun-2013 20:00:00      28-Jun-2013 23:00:00      23:00 - 09:00
  

  Time information should not be stored in additional fields Varchar, if you have the Date column. You can use Date fields that store the Date and time together.

  Another way to approach this problem is to connect by Clause, or model. Use the search feature to find solutions using these methods too. However, in my opinion, this method is the fastest of all.