Substring of SQL query
HelloIn my table, I have the name used like this
EX:
BOSE, MR. BIRAT
NANDY, MR. AMITABHA
The name before the colon is the name of family and after it's first name
Now, I want to show in the front-end server like this for both above
MR. BOSE BIRAT
MR. AMITABHA NANDY
How to write a Sql query, where you can get the name before the decimal point and place at the end of the name and remove the comma from also for display purpose.
Thank you
Something like that?
WITH t AS
(SELECT 'BOSE, Mr. BIRAT' as n FROM DUAL
UNION ALL
SELECT 'NANDY, Mr. AMITABHA' FROM dual
)
SELECT n,
regexp_replace(n, '([^,]+), (.+)*', '\2 \1')
FROM t;
Tags: Database
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Well, I look forward all the above work well, but I'm having a problem.
If I have more than 1 lines on a modal region and if I change the Start_Time value for a row then MAJ (point) is changing but he effect on all lines.
I want, if I make the changes on the line line # 2 while only 2 # MAJ (point) must be not performed any other lines?
Help, please!
Kind regards
RI
I found the solution me thank you.
I removed all the DA mentioned above and created a new.
1. event: change
Selection type: jQuery Selector
jQuery Selector: .st_tm
Condition: No.
Scope of the event: dynamic and light on page load.
Action (Javascript code)
ROW_ID = $(this.triggeringElement).attr('id').substr (4);
If ($(this.triggeringElement). val() > = 03 &. val() $(this.triggeringElement))<= 11)="">
.Val ('EARLIES') $(«#f11_» + row_id);
}
ElseIf ($(this.triggeringElement). > 11 val() & $(this.triggeringElement). val())<= 18)="">
.Val ('LATES') $(«#f11_» + row_id);
}
ElseIf (. val() > $19 (this.triggeringElement)) {}
.Val ('NIGHTS') $(«#f11_» + row_id);
}
also created another DA because I have a disabled report items.
Event: before the page is sent.
$('_:_disabled').removeAttr ("disabled");
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In the section 'your own Application of 4 Buuilding' https://docs.oracle.com/cd/E37097_01/doc.42/e35122/build_app.htm#TDPAX04000 , they describe the creation of a report
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Use the DECODE and RIGHTEOUS in the sql query
Friends...
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I'm doing below in the SQL query
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DECODE)
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) - 1
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Hi all
I use Oracle database 11g Release 2.
I have the following data set:
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ClassId ClassName ability group
------ ---------------------------------------------- -------------- -----------
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Class 6 1 35 12
7 13 42 1 class
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19 dig & Embd Sys Lab 20 1
20 PSD & Comm 20 1 Lab
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23 gen purpose Lab 40 1
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29 19 42 2 class
30 20 49 2 class
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BatchId BatchName force
--------------- ----------------------- --------------
1 BIT - 11 79
2 BIT - 12 28
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6. BE (SE) 84-2
7 BE (SE) 64-3
8 84 BYTČA-7
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Any response will be appreciated.
The SQL Scripts to generate the required tables and populate data is less to:
CREATE TABLE classrooms (ClassId NUMBER, ClassName VARCHAR2 (50), capacity NUMBER, group NUMBER);
INSERT INTO the classrooms of the VALUES (1, "Babbage/software Engg Lab', 24, 1");
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INSERT INTO the classrooms of the VALUES (3, '1 class room', 56, 1);
INSERT INTO the classrooms of the VALUES (4, '10 class room', 24, 1);
INSERT INTO the classrooms of the VALUES (5, '11 class room', 24, 1);
INSERT INTO the classrooms of the VALUES (6, 'class room 12', 35, 1);
INSERT INTO the classrooms of the VALUES (7, 'class room 13', 42, 1);
INSERT INTO the classrooms of the VALUES (8, 'class room 14', 42, 1);
INSERT INTO the classrooms of the VALUES (9, '15 'class, 42, 1);
INSERT INTO the classrooms of the VALUES (10, 'class 2', 35, 1);
INSERT INTO the classrooms of the VALUES (11, 'class room 3', 35, 1);
INSERT INTO the classrooms of the VALUES (12, 'class room 4', 35, 1);
INSERT INTO the classrooms of the VALUES (13, 'class room 5', 35, 1);
INSERT INTO the classrooms of the VALUES (14, 'class room 6', 25, 1);
INSERT INTO the classrooms of the VALUES (15, '7 class room', 25, 1);
INSERT INTO the classrooms of the VALUES (16, 'class Room 8', 24, 1);
INSERT INTO the classrooms of the VALUES (17, 'class room 9', 24, 1);
INSERT INTO the classrooms of the VALUES (18, 'Control Sys Lab', 24, 1);
INSERT INTO the classrooms of the VALUES (19, 'Dig & Embd Sys Lab', 20, 1);
INSERT INTO the classrooms of the VALUES (20, 'DSP & Comm Lab', 20, 1);
INSERT INTO the classrooms of the VALUES (21, 'system ELECTROMECHANICAL Lab', 28, 1);
INSERT INTO the classrooms of the VALUES (22, ' Farabi/Web Tech Lab', 36, 1);
INSERT INTO the classrooms of the VALUES (23, 'Gen purpose Lab', 40, 1);
INSERT INTO the classrooms of the VALUES (24, ' Shirazi/DB Tech Lab', 36, 1);
INSERT INTO the classrooms of the VALUES (25, 'Elected Adv Lab', 30, 2);
INSERT INTO the classrooms of the VALUES (26, 'class room 16', 42, 2);
INSERT INTO the classrooms of the VALUES (27, 'class room 17', 49, 2);
INSERT INTO the classrooms of the VALUES (28, '18 'class, 56, 2);
INSERT INTO the classrooms of the VALUES (29, '19 'class, 42, 2);
INSERT INTO the classrooms of the VALUES (30, 'class room 20', 49, 2);
INSERT INTO the classrooms of the VALUES (31, 'class room 21', 35, 3);
INSERT INTO the classrooms of the VALUES (32, 'room 22', 35, 3);
INSERT INTO the classrooms of the VALUES (33, 'MDA Lab', 20, 3);
CREATE TABLE DegreeBatches (BatchId NUMBER, BatchName VARCHAR2 (50), membership NUMBER);
INSERT INTO DegreeBatches VALUES(1,'BIT-11',79);
INSERT INTO DegreeBatches VALUES(2,'BIT-12',28);
INSERT INTO DegreeBatches VALUES (3, 'BS (CS) - 1', 35);
INSERT INTO DegreeBatches VALUES (4, 'BS (CS) - 2', 78);
INSERT INTO DegreeBatches VALUES (5,'BE (SE) - 1', 69);
INSERT INTO DegreeBatches VALUES (6,'BE (SE) - 2', 84);
INSERT INTO DegreeBatches VALUES (7,'BE (SE) - 3', 64);
INSERT INTO DegreeBatches VALUES(8,'BICSE-7',84);
INSERT INTO DegreeBatches VALUES(9,'BICSE-8',43);
INSERT INTO DegreeBatches VALUES(10,'BEE-1',112);
INSERT INTO DegreeBatches VALUES(11,'BEE-2',151);
INSERT INTO DegreeBatches VALUES(12,'BEE-3',157);
INSERT INTO DegreeBatches VALUES(13,'BEE-4',157);
Best regards
Bilal
Published by: Bilal on December 27, 2012 09:52
Published by: Bilal on December 27, 2012 10:07Bilal, thanks for the nice problem! Another possibility to double check is to write a small PL/SQL function that returns 1 if a duplicate id is found, then equate to 0: "NUMBER of RETURN of Duplicate_Token_Found (p_str_main in VARCHAR2, p_str_trial VARCHAR2). It should analyze the second string and could use p_str_main LIKE '%', | l_id | ', %' for each id. In any case, the query complete (without that) is given below:
Solution with names SQL> WITH rsf_itm (con_id, max_weight, nxt_id, lev, tot_weight, tot_profit, path, root_id, lev_1_id) AS ( 2 SELECT c.id, 3 c.max_weight, 4 i.id, 5 0, 6 i.item_weight, 7 i.item_profit, 8 ',' || i.id || ',', 9 i.id, 10 0 11 FROM items i 12 CROSS JOIN containers c 13 UNION ALL 14 SELECT r.con_id, 15 r.max_weight, 16 i.id, 17 r.lev + 1, 18 r.tot_weight + i.item_weight, 19 r.tot_profit + i.item_profit, 20 r.path || i.id || ',', 21 r.root_id, 22 CASE WHEN r.lev = 0 THEN i.id ELSE r.nxt_id END 23 FROM rsf_itm r 24 JOIN items i 25 ON i.id > r.nxt_id 26 AND r.tot_weight + i.item_weight <= r.max_weight 27 ORDER BY 1, 2 28 ) SEARCH DEPTH FIRST BY nxt_id SET line_no 29 , rsf_con (nxt_con_id, nxt_line_no, con_path, itm_path, tot_weight, tot_profit, lev) AS ( 30 SELECT con_id, 31 line_no, 32 To_Char(con_id), 33 ':' || con_id || '-' || (lev + 1) || ':' || path, 34 tot_weight, 35 tot_profit, 36 0 37 FROM rsf_itm 38 UNION ALL 39 SELECT r_i.con_id, 40 r_i.line_no, 41 r_c.con_path || ',' || r_i.con_id, 42 r_c.itm_path || ':' || r_i.con_id || '-' || (r_i.lev + 1) || ':' || r_i.path, 43 r_c.tot_weight + r_i.tot_weight, 44 r_c.tot_profit + r_i.tot_profit, 45 r_c.lev + 1 46 FROM rsf_con r_c 47 JOIN rsf_itm r_i 48 ON r_i.con_id > r_c.nxt_con_id 49 WHERE r_c.itm_path NOT LIKE '%,' || r_i.root_id || ',%' 50 AND r_c.itm_path NOT LIKE '%,' || r_i.lev_1_id || ',%' 51 AND r_c.itm_path NOT LIKE '%,' || r_i.nxt_id || ',%' 52 ) 53 , paths_ranked AS ( 54 SELECT itm_path || ':' itm_path, tot_weight, tot_profit, lev + 1 n_cons, 55 Rank () OVER (ORDER BY tot_profit DESC) rnk, 56 Row_Number () OVER (ORDER BY tot_profit DESC) sol_id 57 FROM rsf_con 58 ), best_paths AS ( 59 SELECT itm_path, tot_weight, tot_profit, n_cons, sol_id 60 FROM paths_ranked 61 WHERE rnk = 1 62 ), row_gen AS ( 63 SELECT LEVEL lev 64 FROM DUAL 65 CONNECT BY LEVEL <= (SELECT Count(*) FROM items) 66 ), con_v AS ( 67 SELECT b.itm_path, r.lev con_ind, b.sol_id, b.tot_weight, b.tot_profit, 68 Substr (b.itm_path, Instr (b.itm_path, ':', 1, 2*r.lev - 1) + 1, 69 Instr (b.itm_path, ':', 1, 2*r.lev) - Instr (b.itm_path, ':', 1, 2*r.lev - 1) - 1) 70 con_nit_id, 71 Substr (b.itm_path, Instr (b.itm_path, ':', 1, 2*r.lev) + 1, 72 Instr (b.itm_path, ':', 1, 2*r.lev + 1) - Instr (b.itm_path, ':', 1, 2*r.lev) - 1) 73 itm_str 74 FROM best_paths b 75 JOIN row_gen r 76 ON r.lev <= b.n_cons 77 ), con_split AS ( 78 SELECT itm_path, con_ind, sol_id, tot_weight, tot_profit, 79 Substr (con_nit_id, 1, Instr (con_nit_id, '-', 1) - 1) con_id, 80 Substr (con_nit_id, Instr (con_nit_id, '-', 1) + 1) n_items, 81 itm_str 82 FROM con_v 83 ), itm_v AS ( 84 SELECT c.itm_path, c.con_ind, c.sol_id, c.con_id, c.tot_weight, c.tot_profit, 85 Substr (c.itm_str, Instr (c.itm_str, ',', 1, r.lev) + 1, 86 Instr (c.itm_str, ',', 1, r.lev + 1) - Instr (c.itm_str, ',', 1, r.lev) - 1) 87 itm_id 88 FROM con_split c 89 JOIN row_gen r 90 ON r.lev <= c.n_items 91 ) 92 SELECT v.sol_id, 93 v.tot_weight s_wt, v.tot_profit s_pr, c.id c_id, c.name c_name, c.max_weight m_wt, 94 Sum (i.item_weight) OVER (PARTITION BY v.sol_id, c.id) c_wt, 95 i.id i_id, i.name i_name, i.item_weight i_wt, i.item_profit i_pr 96 FROM itm_v v 97 JOIN containers c 98 ON c.id = To_Number (v.con_id) 99 JOIN items i 100 ON i.id = To_Number (v.itm_id) 101 ORDER BY sol_id, con_id, itm_id 102 / SOL_ID S_WT S_PR C_ID C_NAME M_WT C_WT I_ID I_NAME I_WT I_PR ---------- ---- ---- ----- --------------- ---- ---- ----- ---------- ---- ---- 1 255 255 1 SEECS UG Block 100 100 1 BIT-10 35 35 2 BIT-11 40 40 6 BICSE-7 25 25 2 IAEC Building 70 70 4 BSCS-3 40 40 7 BESE-3 30 30 3 RIMMS Building 90 85 3 BSCS-2 35 35 5 BEE-4 50 50 2 255 255 1 SEECS UG Block 100 95 4 BSCS-3 40 40 6 BICSE-7 25 25 7 BESE-3 30 30 2 IAEC Building 70 70 1 BIT-10 35 35 3 BSCS-2 35 35 3 RIMMS Building 90 90 2 BIT-11 40 40 5 BEE-4 50 50 3 255 255 1 SEECS UG Block 100 100 3 BSCS-2 35 35 4 BSCS-3 40 40 6 BICSE-7 25 25 2 IAEC Building 70 65 1 BIT-10 35 35 7 BESE-3 30 30 3 RIMMS Building 90 90 2 BIT-11 40 40 5 BEE-4 50 50 4 255 255 1 SEECS UG Block 100 100 3 BSCS-2 35 35 4 BSCS-3 40 40 6 BICSE-7 25 25 2 IAEC Building 70 70 2 BIT-11 40 40 7 BESE-3 30 30 3 RIMMS Building 90 85 1 BIT-10 35 35 5 BEE-4 50 50 5 255 255 1 SEECS UG Block 100 95 2 BIT-11 40 40 6 BICSE-7 25 25 7 BESE-3 30 30 2 IAEC Building 70 70 1 BIT-10 35 35 3 BSCS-2 35 35 3 RIMMS Building 90 90 4 BSCS-3 40 40 5 BEE-4 50 50 6 255 255 1 SEECS UG Block 100 100 2 BIT-11 40 40 3 BSCS-2 35 35 6 BICSE-7 25 25 2 IAEC Building 70 65 1 BIT-10 35 35 7 BESE-3 30 30 3 RIMMS Building 90 90 4 BSCS-3 40 40 5 BEE-4 50 50 7 255 255 1 SEECS UG Block 100 100 2 BIT-11 40 40 3 BSCS-2 35 35 6 BICSE-7 25 25 2 IAEC Building 70 70 4 BSCS-3 40 40 7 BESE-3 30 30 3 RIMMS Building 90 85 1 BIT-10 35 35 5 BEE-4 50 50 8 255 255 1 SEECS UG Block 100 100 1 BIT-10 35 35 4 BSCS-3 40 40 6 BICSE-7 25 25 2 IAEC Building 70 70 2 BIT-11 40 40 7 BESE-3 30 30 3 RIMMS Building 90 85 3 BSCS-2 35 35 5 BEE-4 50 50 9 255 255 1 SEECS UG Block 100 100 1 BIT-10 35 35 4 BSCS-3 40 40 6 BICSE-7 25 25 2 IAEC Building 70 65 3 BSCS-2 35 35 7 BESE-3 30 30 3 RIMMS Building 90 90 2 BIT-11 40 40 5 BEE-4 50 50 10 255 255 1 SEECS UG Block 100 100 1 BIT-10 35 35 3 BSCS-2 35 35 7 BESE-3 30 30 2 IAEC Building 70 65 2 BIT-11 40 40 6 BICSE-7 25 25 3 RIMMS Building 90 90 4 BSCS-3 40 40 5 BEE-4 50 50 11 255 255 1 SEECS UG Block 100 100 1 BIT-10 35 35 3 BSCS-2 35 35 7 BESE-3 30 30 2 IAEC Building 70 65 4 BSCS-3 40 40 6 BICSE-7 25 25 3 RIMMS Building 90 90 2 BIT-11 40 40 5 BEE-4 50 50 12 255 255 1 SEECS UG Block 100 95 1 BIT-10 35 35 3 BSCS-2 35 35 6 BICSE-7 25 25 2 IAEC Building 70 70 2 BIT-11 40 40 7 BESE-3 30 30 3 RIMMS Building 90 90 4 BSCS-3 40 40 5 BEE-4 50 50 13 255 255 1 SEECS UG Block 100 95 1 BIT-10 35 35 3 BSCS-2 35 35 6 BICSE-7 25 25 2 IAEC Building 70 70 4 BSCS-3 40 40 7 BESE-3 30 30 3 RIMMS Building 90 90 2 BIT-11 40 40 5 BEE-4 50 50 14 255 255 1 SEECS UG Block 100 100 1 BIT-10 35 35 2 BIT-11 40 40 6 BICSE-7 25 25 2 IAEC Building 70 65 3 BSCS-2 35 35 7 BESE-3 30 30 3 RIMMS Building 90 90 4 BSCS-3 40 40 5 BEE-4 50 50 98 rows selected. Elapsed: 00:00:01.42Published by: BrendanP on January 20, 2013 11:25
I found the need to deduplicate regular expression:AND RegExp_Instr (r_c.itm_path | r_i.path, ',(\d+),.*?,\1,') = 0)
-
Hi all
My version of Oracle: oracle 10G
I got a puzzle and very much if you could help me with the solution (I have it solved, but mine does not seek to be the best solution), if it is here, its got 2 parts:
Part 1:
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AEK MANGO
AEK MANGO
AEK MANGO
AEK MANGO
AEK MANGO
AEK APPLE
AEK ORANGE
AEK LICHI
AEK LICHI
AEK LICHI
AEK LICHI
AEK LICHI
AEK LICHI
AEK LICHI
Abu MANGO
Abu MANGO
Abu APPLE
Abu APPLE
Abu APPLE
Abu ORANGE
Abu LICHI
Abu LICHI
Abu LICHI
Abu LICHI
Abu LICHI
Abu LICHI
Abu LICHI
Abu LICHI
Melanie MANGO
Melanie MANGO
Rémy APPLE
Rémy APPLE
Rémy APPLE
Rémy APPLE
Rémy APPLE
Rémy APPLE
Rémy ORANGE
Rémy ORANGE
Rémy ORANGE
Rémy ORANGE
Rémy ORANGE
Rémy ORANGE
Rémy ORANGE
Rémy ORANGE
Rémy ORANGE
Rémy LICHI
Rémy LICHI
Rémy LICHI
Rémy LICHI
Rémy LICHI
Shakti MANGO
Shakti MANGO
Shakti MANGO
Shakti MANGO
Shakti MANGO
Shakti MANGO
Shakti APPLE
Shakti APPLE
Shakti APPLE
Shakti APPLE
Shakti ORANGE
Shakti ORANGE
Shakti ORANGE
Shakti ORANGE
Shakti ORANGE
Shakti LICHI
power required by my sql query:
Orange mango apple lichi fname
1 7 5 1 AEK
Abu 3 8 2 1
Rémy 6 5 2 9
Shakti 4 1 6 5
-------------------------------------------
part B: is the opposite, my output above is my source and the result should be my source.
Please help me.
Concerning
Rahul
Published by: Mac_Freak_Rahul on January 26, 2012 06:20Hello
This makes for part 1:
Scott@my10g SQL>l 1 with t as ( 2 select 'abhi' c1, 'MANGO' c2 from dual 3 union all select 'abhi', 'MANGO' from dual 4 union all select 'abhi', 'MANGO' from dual 5 union all select 'abhi', 'MANGO' from dual 6 union all select 'abhi', 'MANGO' from dual 7 union all select 'abhi', 'APPLE' from dual 8 union all select 'abhi', 'ORANGE' from dual 9 union all select 'abhi', 'LICHI' from dual 10 union all select 'abhi', 'LICHI' from dual 11 union all select 'abhi', 'LICHI' from dual 12 union all select 'abhi', 'LICHI' from dual 13 union all select 'abhi', 'LICHI' from dual 14 union all select 'abhi', 'LICHI' from dual 15 union all select 'abhi', 'LICHI' from dual 16 union all select 'abu', 'MANGO' from dual 17 union all select 'abu', 'MANGO' from dual 18 union all select 'abu', 'APPLE' from dual 19 union all select 'abu', 'APPLE' from dual 20 union all select 'abu', 'APPLE' from dual 21 union all select 'abu', 'ORANGE' from dual 22 union all select 'abu', 'LICHI' from dual 23 union all select 'abu', 'LICHI' from dual 24 union all select 'abu', 'LICHI' from dual 25 union all select 'abu', 'LICHI' from dual 26 union all select 'abu', 'LICHI' from dual 27 union all select 'abu', 'LICHI' from dual 28 union all select 'abu', 'LICHI' from dual 29 union all select 'abu', 'LICHI' from dual 30 union all select 'anirudh', 'MANGO' from dual 31 union all select 'anirudh', 'MANGO' from dual 32 union all select 'anirudh', 'APPLE' from dual 33 union all select 'anirudh', 'APPLE' from dual 34 union all select 'anirudh', 'APPLE' from dual 35 union all select 'anirudh', 'APPLE' from dual 36 union all select 'anirudh', 'APPLE' from dual 37 union all select 'anirudh', 'APPLE' from dual 38 union all select 'anirudh', 'ORANGE' from dual 39 union all select 'anirudh', 'ORANGE' from dual 40 union all select 'anirudh', 'ORANGE' from dual 41 union all select 'anirudh', 'ORANGE' from dual 42 union all select 'anirudh', 'ORANGE' from dual 43 union all select 'anirudh', 'ORANGE' from dual 44 union all select 'anirudh', 'ORANGE' from dual 45 union all select 'anirudh', 'ORANGE' from dual 46 union all select 'anirudh', 'ORANGE' from dual 47 union all select 'anirudh', 'LICHI' from dual 48 union all select 'anirudh', 'LICHI' from dual 49 union all select 'anirudh', 'LICHI' from dual 50 union all select 'anirudh', 'LICHI' from dual 51 union all select 'anirudh', 'LICHI' from dual 52 union all select 'shakti', 'MANGO' from dual 53 union all select 'shakti', 'MANGO' from dual 54 union all select 'shakti', 'MANGO' from dual 55 union all select 'shakti', 'MANGO' from dual 56 union all select 'shakti', 'MANGO' from dual 57 union all select 'shakti', 'MANGO' from dual 58 union all select 'shakti', 'APPLE' from dual 59 union all select 'shakti', 'APPLE' from dual 60 union all select 'shakti', 'APPLE' from dual 61 union all select 'shakti', 'APPLE' from dual 62 union all select 'shakti', 'ORANGE' from dual 63 union all select 'shakti', 'ORANGE' from dual 64 union all select 'shakti', 'ORANGE' from dual 65 union all select 'shakti', 'ORANGE' from dual 66 union all select 'shakti', 'ORANGE' from dual 67 union all select 'shakti', 'LICHI' from dual 68 ) 69 select 70 c1 71 ,max(decode(rn,1,cnt,null)) l1 72 ,max(decode(rn,2,cnt,null)) l2 73 ,max(decode(rn,3,cnt,null)) l3 74 ,max(decode(rn,4,cnt,null)) l4 75 from ( 76 select c1,cnt,row_number() over (partition by c1 order by substr(c2,1,1)) rn 77 from ( 78 select c1,c2,count(*) cnt 79 from t 80 group by c1,c2 81 ) 82 ) 83 group by c1 84* order by c1 Scott@my10g SQL>/ C1 L1 L2 L3 L4 ------- ---------- ---------- ---------- ---------- abhi 1 7 5 1 abu 3 8 2 1 anirudh 6 5 2 9 shakti 4 1 6 5I decided to not hardcode the four "fruits" inside the query so it would always works with anything else, as long as they do not share the initial letter.
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This should do the part 2:
Scott@my10g SQL>l 1 with t as ( 2 select 'abhi' n, 1 c1, 7 c2, 5 c3, 1 c4 from dual 3 union all select 'abu', 3, 8, 2, 1 from dual 4 union all select 'anirudh', 6, 5, 2, 9 from dual 5 union all select 'shakti', 4, 1, 6, 5 from dual 6 ) 7 select * 8 from ( 9 select t.n, 10 case 11 when m.column_value <= t.c1 then 'APPLE' 12 when m.column_value <= (t.c1+t.c2) then 'LICHI' 13 when m.column_value <= (t.c1+t.c2+t.c3) then 'MANGO' 14 else 'ORANGE' 15 end f 16 from t 17 ,table(cast(multiset(select level n from dual connect by level <= (t.c1+t.c2+t.c3+t.c4)) as sys.OdciNumberList)) m 18 ) 19* order by n, decode(f,'MANGO',1,'APPLE',2,'ORANGE',3,'LICHI',4) Scott@my10g SQL>/ N F ------- ------ abhi MANGO abhi MANGO abhi MANGO abhi MANGO abhi MANGO abhi APPLE abhi ORANGE abhi LICHI abhi LICHI abhi LICHI abhi LICHI abhi LICHI abhi LICHI abhi LICHI abu MANGO abu MANGO abu APPLE abu APPLE abu APPLE abu ORANGE abu LICHI abu LICHI abu LICHI abu LICHI abu LICHI abu LICHI abu LICHI abu LICHI anirudh MANGO anirudh MANGO anirudh APPLE anirudh APPLE anirudh APPLE anirudh APPLE anirudh APPLE anirudh APPLE anirudh ORANGE anirudh ORANGE anirudh ORANGE anirudh ORANGE anirudh ORANGE anirudh ORANGE anirudh ORANGE anirudh ORANGE anirudh ORANGE anirudh LICHI anirudh LICHI anirudh LICHI anirudh LICHI anirudh LICHI shakti MANGO shakti MANGO shakti MANGO shakti MANGO shakti MANGO shakti MANGO shakti APPLE shakti APPLE shakti APPLE shakti APPLE shakti ORANGE shakti ORANGE shakti ORANGE shakti ORANGE shakti ORANGE shakti LICHI 66 rows selected.Published by: on January 26, 2012 Nicosa 15:51
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Dynamic SQL query in the DB adapter
Hello
I want to use the following custom SQL query in the DB adapter:
SELECT EMP_ID, EMP_NAME, EMP_LOCATION FROM EMP WHERE EMP_ID IN (#iNPUT_PARAMETER)
the problem I'm facing is that I don't know at the time of the development that EMP_ID how much will be passed to the process so that I can not use the input parameter specific number. I cannot use it IN the query within which statement I concatenate all the EMP_ID separated by comma and passed under INPUT_PARAMETER, but when running, he read the full concatenated string as a single string rather than identify them as a list of different: with comma separation. could someone help me in this case
Thank you
SunilUse the following query with two parameters. Build the string with delimiter when running and pass this string and delimiter to query... (in this example, the input value would be the same for both Delimiter1 and Delimiter2.)
Select * from EMP WHERE deptno IN (SELECT SUBSTR (STRING_TO_TOKENIZE, DECODE (LEVEL, 1, 1, INSTR (STRING_TO_TOKENIZE, SEPARATOR, 1, LEVEL-1) + 1), INSTR (STRING_TO_TOKENIZE, SEPARATOR, 1, LEVEL)-DECODE (LEVEL, 1, 1, INSTR (STRING_TO_TOKENIZE, SEPARATOR, 1, LEVEL-1) + 1)) FROM (SELECT #StringToTokenizer | #Delimiter1 AS STRING_TO_TOKENIZE, #Delimiter2 AS DELIMITER FROM DUAL) CONNECT BY INSTR (STRING_TO_TOKENIZE SEPARATOR) ((, 1, LEVEL) > 0)
Thank you
-Sreeny -
Hai all,
I want to get the value of decimal as columns of towing column using 'regexp' in the sql query
This means that the value 72.58
as 72 value1, value2 58
need help...Hi Hari,
Make a format decode changes in the use of the query.
SQL> with t 2 as 3 ( 4 select '12.58' str from dual union all 5 select '.72' str from dual 6 ) 7 select regexp_substr(decode(substr(str,1,1),'.',lpad(str,length(str)+1,'0'), 8 str),'[^.]+',1,1) val1, 9 regexp_substr(decode(substr(str,1,1),'.',lpad(str,length(str)+1,'0'), 10 str),'[^.]+',1,2) val2 11 from t 12 / VAL1 VAL2 ---------- ---------- 12 58 0 72 -
Help me with SQL Query to retrieve data from a view
Hello Guru,
I need help in my sql query.
I use SQL TeraData.
I want an Oracle result in the following form-
Open tickets
Open months failure / Repair Service s/o improvement request Total general
2009-01-2 4 4 5 15
2009-02 1 0 2 3 6
2009-03 4 1 2 2 9
Grand Total 7 5 8 10 30
I wrote the query as where - TIME_PERIOD, RQST_TYPE_DM and DEMAND_SUMMARY_FCT are the points of view and I extract the data from the views only.
Select NVL (CA. TIME_PERIOD. PERIOD_CD, 'Total') THAT year.
COUNT (CASE WHEN CA. RQST_TYPE_DM. RQSTTYP_DESC Like '% of Break' THEN 1 END) as BreakFix
COUNT (CASE WHEN CA. RQST_TYPE_DM. RQSTTYP_DESC as 'N/a', 1 END) by n/a
COUNT (CASE WHEN CA. RQST_TYPE_DM. RQSTTYP_DESC as 'Improvement' THEN 1 END) accessories
COUNT (CASE WHEN CA. RQST_TYPE_DM. RQSTTYP_DESC Like '% Service' THEN 1 END) as ServiceRequests
COUNT (CA. RQST_TYPE_DM. RQSTTYP_DESC) AS grand_total
FROM CA. TIME_PERIOD, CA. RQST_TYPE_DM, CA. DEMAND_SUMMARY_FCT
WHERE (CA. DEMAND_SUMMARY_FCT. RQSTTYP_ID = CA. RQST_TYPE_DM. RQSTTYP_ID)
AND (CASE
WHEN CA. DEMAND_SUMMARY_FCT. MONTH_ID = CA. TIME_PERIOD. PERIOD_ID, 1
WHEN {fn concat ({fn concat (SUBSTR (CA. TIME_PERIOD. {(PERIOD_CD, 3, 4),'-')}, SUBSTR (CA. TIME_PERIOD. PERIOD_CD, 7, 2))} BETWEEN ' 2009-01' AND ' 2009-03' THEN 1
WHEN CA. DEMAND_SUMMARY_FCT. RQSTTYP_ID = '1' then 1
END) = 1
GROUP BY ROLLUP (CA. TIME_PERIOD. PERIOD_CD)
After executing the query, I get the following error:
3076: syntax Error: Data Type 'Time' does not match a defined Type name.
:( Kindly help me with this and let me know where I'm wrong... Please.Messages indicates something wrong with your data... It would seem that the data does not match your format mask.
Thus, the data or the format mask.
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Hello
You can see why I get this error message for my SQL query?
Thanks in advance.WITH SKU_DATA AS ( SELECT /*+ MATERIALIZE */ DISTINCT FROM_LOC_ID, SKU_ID, DESCRIPTION, UPDATE_QTY, ORDER_ID, CONSIGNMENT, WEIGHT, PALLET_ID, CASE WHEN Upd_Qty_Ratio < 1 THEN TO_CHAR(UPDATE_QTY) || 'U' WHEN TRUNC(Upd_Qty_Ratio) = Upd_Qty_Ratio THEN TO_CHAR(Upd_Qty_Ratio) || 'C' ELSE TO_CHAR(TRUNC(UPDATE_QTY)) || 'C' || ' ' || TO_CHAR(ROUND(MOD(Upd_Qty_Ratio, 1) * USER_DEF_NUM_3, 6)) || 'U' END CU_Sum FROM ( SELECT DISTINCT FROM_LOC_ID, S.SKU_ID, S.DESCRIPTION, ITL.UPDATE_QTY, S.USER_DEF_NUM_3, OH.ORDER_ID, ITL.CONSIGNMENT, ITL.PALLET_ID, NVL(ITL.UPDATE_QTY,0)*NVL(S.EACH_WEIGHT,0) Weight, ITL.UPDATE_QTY/(CASE S.USER_DEF_NUM_3 WHEN 0 THEN 1 ELSE S.USER_DEF_NUM_3 END) Upd_Qty_Ratio FROM INVENTORY_TRANSACTION ITL, SKU S, LOCATION L, ORDER_HEADER OH WHERE ITL.SKU_ID = S.SKU_ID AND ITL.CODE = 'Pick' AND ITL.CONSIGNMENT = $P{Consignment} AND OH.ORDER_DATE = TO_CHAR($P{Date}, 'DD-Mon-YYYY') AND OH.ORDER_ID = ITL.REFERENCE_ID AND ITL.TO_LOC_ID = 'CONTAINER')) SELECT DISTINCT ORDER_ID, CONSIGNMENT, WEIGHT, PALLET_ID, CU_Sum, (SELECT NVL(TO_CHAR(SUM(CASE WHEN NULLIF(SUBSTR(Cu_Sum, -1), 'U') IS NULL THEN NULL ELSE REPLACE(Cu_Sum,'C',NULL) END)),'0') ||'C' || ' ' || NVL(TO_CHAR(SUM(CASE WHEN NULLIF(SUBSTR(Cu_Sum, -1), 'C') IS NULL THEN NULL ELSE REPLACE(Cu_Sum,'U',NULL) END)),'0') ||'U' FROM SKU_DATA) AS Total_Cu_Sum FROM SKU_DATA
SM.Hello Sam, what is the error, and what has changed since he was executed successfully?
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Œuvres SQL query to MS SQL Server 2008, but not when you use the database kit
I have this SQL query:
DECLARE TABLE (@DataTypeTable)
Name varchar (128).
TypeID INT)-Add comma delimeted type data in the temporary table names
INSERT INTO @DataTypeTable (name)
SELECT * from WhatWeShouldDoRead.func_Split (@DataTypeTrimmed, ',')SELECT the name OF @DataTypeTable
That takes a comma delimited by the string and returns the string as a table. It works correctly in Microsoft SQL Server Management Studio. When I run this as a stored procedure I return nothing. There are no errors, SQL or otherwise. I checked that I am connected to the correct database and the stored procedure is responsible without changing any error chain which is reported of this stored procedure (that code is not shown in the example above). Has anyone seen this problem before, or have experience with SQL/Labview interfaces to tell me what I am doing wrong?
Thanks in advance.
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HI HI... I'm a student doing a project related to labview. My task is to create a vi, type a user name and password to continue the whole VI.
As I am a newbie to SQL query language, can anyone help me this?... This isn't like the VI with password lock
There is a connection of the user called button in my main façade... u by clicking on it, a pop-up window will come out asking you a user name and a password. If the user name and the password is correct, then you can proceed. The problem is that I'm stuck with database...
Help me pls!with respect,
Ray
Hello
You have two cases:
(1) connect to the database with string (link a string of connection information), and then type something like this:
Driver is SQL Native Client;. Server = IP. Add.re.SS; UID = username; PW = *** ; Database = MyDatabase (depends on your database)(2) use a UDL file (you can configure it to connect to your database, with specific format). Remember that the connection is successful with test button.
There is a UDL file that you can edit here: C:\Program NIUninstaller Instruments\LabVIEW 2010\examples\database\Labview.udl
Edit: The connection dropped, you can set the path to an mdb file, and I think you can give the path of your accdb file.
Kind regards
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I am trying to execute the following SQl query, SELECT * failure WHERE ID = '123 ' AND RepairAction =' '; using the DB tools run Query.vi. This query never find record in my database. My database contains a record where the registered ID contains the value '123' and the RepairAction field is an empty string. If I remove the declaration 'AND RepairAction' ';' my query text, the record is found. I think my problem is that I do not use the correct syntax to describe and an empty string. I tried the following: "," ",""," "and NULL as empty and none of these work string arguments.
I was hoping someone might be able to tell me what the correct syntax is an empty string or if there is another approach that I take.
Thanks in advance for your help,
Jim
Jim,
Just to be sure, have you used 'is' instead of '=' in this command?
This makes all the difference in this command.
Cerati
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Support of SQL query: what tasks are Sunday from 07:00 - 12:00
Hello tide Admins.
I need to do a SQL query that can give me a list of jobs that are running on a given (Sunday) day from 07:00 - 12:00. Our environment is not a maintenance window. Therefore, whenever there is application of patches or upgrades, it causes more work and risk of failure of the tide tasks. By moving jobs over the period from 07:00 - 12:00 Sunday, patch can be completed without disrupting the calendar.
Im not the best at the SQL script and can not get my script to work. any help would be great. Here's what I have so far. I get the error ' could not find identifier multi-player jobmst.jobmst_name. IM using Tidal 6.0.3 with SQL for DB Admeral table.
SELECT dbo.jobdtl.jobdtl_id, dbo.jobmst.jobmst_prntname, dbo.jobmst.jobmst_name
FROM dbo.jobdtl INNER JOIN
dbo.jobmst ON dbo.jobdtl.jobdtl_id = dbo.jobmst.jobdtl_id
WHERE (dbo.jobdtl.jobdtl_fromdt > 14 September 2016 06:00 ') AND (dbo.jobdtl.jobdtl_fromdt< '09/11/2016="" 012:00:00="">
GROUP OF dbo.jobdtl.jobdtl_id, dbo.jobmst.jobmst_prntname, dbo.jobmst.jobmst_name
Hi Jeff
The time window from the jobdtl returns only jobs that have an early start time and windows of time from beginning to the end, so there may be some tasks which are not time bound but have dependencies on other jobs, variables, etc.
Here are the 2 SQL queries against the table jobrun and jobmst:
-The list of jobs that took place last Sunday between 07:00 and 12:00
SELECT jobmst.jobmst_prntname, jobmst.jobmst_name, jobrun.jobrun_time FROM jobrun
JOIN jobmst on jobrun.jobmst_id = jobmst.jobmst_id
WHERE jobrun.jobrun_time > = 9/11/2016 07:00 ' and jobrun.jobrun_time<= '9/11/2016="" 12:00="">
ORDER BY jobrun.jobrun_time-For a list of jobs that are scheduled to run on Sunday to come between 07:00 and 12:00
SELECT jobmst.jobmst_prntname, jobmst.jobmst_name, jobrun.jobrun_esttime FROM jobrun
JOIN jobmst on jobrun.jobmst_id = jobmst.jobmst_id
WHERE jobrun.jobrun_esttime > = 9/18/2016 07:00 ' and jobrun.jobrun_esttime<= '9/18/2016="" 12:00="">
ORDER BY jobrun.jobrun_esttimeARO
The Derrick
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How to get the value of a column in sql query?
Hi, anyone knows how to get the value of a column in sql query?
Here is my code, the value must be 1350079224397 in my PB, but I get 0
QString query ("SELECT version FROM db_version");
QVariant result = sda.execute (query);
QVariantMap versionMap = result.toList () such () .toMap ();
If (! versionMap.IsEmpty ())
{
qDebug()<"Version: "=""><>
}OK, I have the solution
QString query ("SELECT version as version FROM db_version");
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