Superior to mixed case in the tree node

Similar Questions

• How to get the value of the tree node without reloading the Page. !

  Hello
  I worked with apex 4.2 and I've created trees and as a table to retrieve the date according to the value of the tree node select the code tree something like that
  
  {
  Select case when connect_by_isleaf = 1 then 0
  When level = 1 then 1
  of another-1
  end the status,
  level,
  'ENAME' as the title,
  NULL as an icon,
  'EMPNO' as value,
  NULL as ToolTip,
  ' f ? p = 36648:34:5234984107903:P40_SELECTED_NODE :'|| EmpNo as link
  "Dept". "" EMP ".
  Start by "MGR" is nothing
  connect prior "EMPNO" = "MGR".
  siblings arrested by 'ENAME '.
  }
  and I put the Page selected node element: P40_SELECTED_NODE. the tree worked well and recover the data in tabular form according to the value of tree node
  
  My Question:
  1. I want to recover the data without submitting the page where whenever I select the value of the tree make page reload to update the tabular presentation with the new value, there is a way to convey the value of the tree node to point P40_SELECTED_NODE and in the form of refreshment without page reload.
  
  2-i want when selected in the page tree run process according to the value of the on-set tree node to create dynamic action with (jquery selector: div.tree li > a) but the value of the incorrect node.
  
  Concerning
  Ahmed;

  Take a look at my sample tree application.
  When you select a node, a details report is updated. That should help you implement for your situation.
  However, one thing to note is the link on each node that you have. Click on a node to redirect to the same page and set the value of P40_SELECTED_NODE. You can keep the element, but the link should go, as it's him "reload" the page whenever you click on a node. Implementation of the action of "onselect" tree and setting the page element to the value of the node that will be in place. Be sure to add the page element in the elements present in the form of tables.
  The reason why your selector didn't return the correct value is that you have a click event bound to the anchor tag in each element of the list. The anchor tag does not hold the real value (usually and id), but holds that the display value. The items list item containing the real value in their attribute "id". Therefore, to get this value you should always inspect the first parent of the clicked anchor tag. (which is another way to solve it, of course)

• make the tree nodes that are engaged in "BOLD"

  Hi friends,
  
  I'm putting a few settings of 'style' as the bold or italics
  for tree nodes that are clicked. For example in the sub tree if you click node a31 , this node is parent node ( a3 ) and the parent node ( a ) A3 will be displayed in bold
  

  *a*..|-a1
     |- a2
     |- *a3*...|- *a31*
     |- a4      |-a32
     |- a5      |-a33
     |- a6
     |- a7

  Any input will be appreciated.
  
  Kind regards
  Jyothi
  
  Published by: Jyothi on January 9, 2011 03:43

  Jyothi,
  You have not used the ID of node item in the code. The element that stores the tree node in your case is P19_EXMPLE and if you need to change the code that is provided in an appropriate way.

  You must change the * $v ('') * to * $v(P19_EXMPLE') * If you use my code
  or * $v ('P19_EXAMPLE') * to * $v(P19_EXMPLE') * If you use Andy.

• make the tree nodes "BOLD"

  Hello
  
  I have a created a structure tree
  -one
  -aa
  -aaa
  -aaa
  b
  -bb
  -bbb
  -cc
  -ccc
  I followed the steps given in the message
  make the tree nodes that are engaged in "BOLD"
  (a)
  Now if I expand the root node, then all of the child nodes automatically become "BOLD", that is if I select 'a '.
  all nodes below becomes "BOLD".
  -a
  -aa *.
  -aaa
  -aaa
  b
  -bb
  -bbb
  -cc
  -ccc
  
  How can I avoid this problem what I want is the selection if 'a' only 'a' should be bold not her children
  now when I select 'aa' or 'bb' only her parents must be "BOLD" not his children.
  
  (b)
  My second problem is that while the page loads for the first time his having the whole tree is in bold how prevent this from happening.

  If the node selected for that tree is P100_SELECTED_NODE_ITEM

  Add the following code to the onload code ("run when the page loads" article on page or dynamic action shot page load)

    selected_node= $('#'+$v('P100_SELECTED_NODE_ITEM')).children('a:first');
    selected_node.parents('li').each( function(){
     $(this).children('a:first').css('font-weight','bold');
     });
  

• Get the value of the tree node

  
  Hello

  I use the hierarchy tree to build a menu (in oracle 11 gform).

  I need to retrieve the value of the selected node (child_id), and when I write what follows, I get an error: frm-47307: could not get the properties of the tree root node .

  the statement is:

  l_node_value: = Ftree.Get_Tree_Node_Property (htree,: SYSTEM.) TRIGGER_NODE, Ftree.NODE_VALUE);

  I use this query to populate the tree (and it works fine...):

  Select the case sensitive option

  When connect_by_isleaf = 1 then

  0

  When level = 1 then

  1

  on the other

  -1

  end as status

  level

  name as title

  null as an icon

  CHAILD_ID as value

  Of

  (

  SELECT TO_CHAR (CUO. OBJECT_ID) CHAILD_ID,.

  PARENT_ID TO_CHAR (NULL).

  CUO. OBJECT_PROMPT NAME,

  OBJECT_TYPE 'G '.

  OF CRDX_USER_OBJECT COU

  WHERE GROUP_ID = - 1

  UNION

  SELECT TO_CHAR (CGO. OBJECT_ID) CHAILD_ID,.

  TO_CHAR (CGO. PARENT_ID FOLDER_ID),

  CGO. OBJECT_PROMPT NAME,

  OBJECT_TYPE

  OF OGS CRDX_GROUP_OBJECT

  )

  Start by parent_id is null

  connect by parent_id = prior CASE OBJECT_TYPE WHEN 'G' THEN CHAILD_ID END

  Can someone help me?

  Thanks in advance,

  Elad

  : SYSTEM. TRIGGER_NODE is valid for one of the WHEN-TREE-NODE-xxx-triggers.

  If you want to get the value of the node selected in any other place, you need the integrated Ftree.GET_TREE_SELECTION

• How to cross the tree node

  Hello
  
  I created the region table advance and I created Hgrid region and I tree region. Now my tree displays perfectly but I want to go to a specific parent node in the tree.
  
  Please help me. How to browse a specific node.
  
  I tried oaweabbean.findChildRecursive ("hGridRN");
  and then I used TreeBean and treebean.findChildRecursive ("TreeRN");
  
  but didn't work at all
  
  Makes me NullPointerException
  
  Please help me someone who has the idea about it.
  
  I'd appreciate your effort.
  
  Thank you

  Muriel

  Crossing hgrid himself will give the required node, no need to get the tree, please see the code below

  OAAdvancedTableBean adTBRN = (OAAdvancedTableBean) webBean.findIndexedChildRecursive ("advanced table id");
  OAHGridBean oahgridbean = (OAHGridBean) adTBRN .findIndexedChildRecursive ("RN HGRID ID");
  OAHGridQueriedRowEnumerator oahgridqueriedrowenumerator = new OAHGridQueriedRowEnumerator (pageContext, oahgridbean);

  for (; oahgridqueriedrowenumerator.hasMoreElements ();)
  {

  Line line (Row) = oahgridqueriedrowenumerator.nextElement ();
  If (line! = null)
  {

  Try
  {
  requiredrowvalue = (Number) row.getAttribute ("the value of required line viewattribute");

  } / / END OF THE try block
  catch (System.Exception e)
  {
  e.printStackTrace ();
  }

  } / / End of control null line

  } / / end of loop for

  Thank you
  Pratap

• #1009-erreur get up by select multi on the tree nodes

  whenever I try to select several nodes in the tree pane, I get this error.

  I want to know what could be the cause of this error.

  Help me friends.

  TypeError: Error #1009: cannot access a property or method of a null object reference.

  at mx.managers::FocusManager/focusInHandler()

  to flash. display::Stage / set focus()

  at mx.core::UIComponent/setFocus()

  at mx.managers::FocusManager/setFocus()

  at mx.managers::FocusManager/mouseDownHandler()

  Thanks in advance.

  1009 error indicates that one of the objects targeted by your code are out of reach.  This may mean that the object...

  n ' is not in the display list
  n ' is not have an instance name (or the name of the instance is misspelled)
  n ' is not in the frame where this code tries to talk to her
  -is animated in place, but is not assigned the name of the instances of each keyframe for her
  -is one of the two or more consecutive keyframes of the same objects without a name assigned in the image previous (s).
   
  If you go to your section to publish the Flash settings and select permit debugging option, your error message should have a suite of line number the number of the frame that will help you to isolate the object that is involved.

• Hide the tree nodes

  I searched for a while, but have yet to find a solution to this:
  
  I want to hide items (associated with each node html help topic) in a tree with xmlListCollection data provider. I found this article:
  http://www.axelscript.com/2008/02/20/using-a-data-manager-and-filtering-data-in-a-Flex-Tre e-same-the-nodes.
  
  but I don't actually want to exclude data from the tree... just hide it... and access to place content elsewhere.
  
  I tried to play with the updateDisplayList function in my custom treeItemRenderer, but I can't completely hide the presence of the list item
  
  Thanks for any help!
  

  Custom data descriptor:
  http://livedocs.Adobe.com/Flex/3/HTML/Help.HTML?content=about_dataproviders_6.html

• can view us the report by using the tree node?

  Hi all
  can view us the report using the tree if node, then please guide me
  
  Sarah

  In the object navigator in the form, there are node named "reports." Create a new entry, and name it "REPORT."

  To call the report use something like the following code:

  DECLARE
    rep REPORT_OBJECT;
    vcServer VARCHAR2(100);
    vcJobId VARCHAR2(100);
    vcUrl VARCHAR2(2000);
    vcServer VARCHAR2(200) := 'PUT_YOUR_REPORTS_SERVERNAME_HERE';
  BEGIN
    rep:=FIND_REPORT_OBJECT('REPORT');
    SET_REPORT_OBJECT_PROPERTY(rep, REPORT_FILENAME, 'put_the_filename_of_your_report_here');
    SET_REPORT_OBJECT_PROPERTY(rep, REPORT_DESTYPE, CACHE);
    SET_REPORT_OBJECT_PROPERTY(rep, REPORT_DESFORMAT, 'PDF');
    SET_REPORT_OBJECT_PROPERTY(rep, REPORT_SERVER,vcServer);
    vcJobId := RUN_REPORT_OBJECT(RO_Report_ID, PL_ID);
    vcJobId := SUBSTR(vcJobId, LENGTH(vcServer) + 2, LENGTH(vcJobId));
    vcUrl:= '/reports/rwservlet/getjobid' || vcJobId || '?server=' || vcServer;
    WEB.SHOW_DOCUMENT(vcUrl, '_blank');
  END;
  

• Double-click event does not tire/triggered by double clicking on the left side of the tree node

  I have the following tree of Flex

  <mx:Tree id="Tree" left="0" right="0" top="0" bottom="0"
         alternatingItemColors="[#EEEEEE, white]" dataProvider="{lsEspecie}"
         dragEnabled="true" dragMoveEnabled="true" dropEnabled="true" labelField="item"
         labelFunction="tree_labelFunc" showRoot="false"
         doubleClickEnabled="true" doubleClick="Tree_DoubleClick(event)">
</mx:Tree> 

  When I double click on the ICON and to the right of the side on any node, double-click event is triggered as expected. But when clicking on any part of the left side of the node double click is not triggered

  

  Is there a way to make the double click event fire when happens on the left side of the node?

  The problem has been resolved with this class of FixedTree

  import flash.display.InteractiveObject;
import flash.events.Event;

  import mx.controls.Tree;
  import mx.core.mx_internal;

  use namespace mx_internal;

  public class FixedTree extends Tree {

  public function FixedTree() {
        super();
     }

  override protected function createChildren():void {
        super.createChildren();

  getListContentHolder().selectionLayer.addEventListener(Event.ADDED, selectionLayerChildAddedHandler);
     }

  private function selectionLayerChildAddedHandler(e:Event):void {
        // ListBase:5790 creates a SpriteAsset for the selectionLayer but does not set mouseEnabled to false

  InteractiveObject(e.target).mouseEnabled = false;
     }

  }

• Operations on the nodes of the tree

  Hi everyone, it's me again, with another question =)
  
  I need to be able to rename any node under a specific node in a hierarchy. Take this table and the following data samples.
  

  CREATE TABLE organisations
  (
    organ_id NUMBER(10) PRIMARY KEY, 
    parent_id NUMBER(10), 
    NAME VARCHAR2(255), 
    CONSTRAINT fk_org_to_parent_org 
       FOREIGN KEY(parent_id) REFERENCES organisations(organ_id)
  );
  
  Insert into ORGANISATIONS (ORGAN_ID,PARENT_ID,NAME) values (1,null,'Organisation 1');
  Insert into ORGANISATIONS (ORGAN_ID,PARENT_ID,NAME) values (2,null,'Organisation 2');
  Insert into ORGANISATIONS (ORGAN_ID,PARENT_ID,NAME) values (21,2,'Organisation 21');
  Insert into ORGANISATIONS (ORGAN_ID,PARENT_ID,NAME) values (22,2,'Organisation 22');
  Insert into ORGANISATIONS (ORGAN_ID,PARENT_ID,NAME) values (221,22,'Organisation 221');
  Insert into ORGANISATIONS (ORGAN_ID,PARENT_ID,NAME) values (2211,221,'Organisation 2211');
  Insert into ORGANISATIONS (ORGAN_ID,PARENT_ID,NAME) values (3,null,'Organisation 3');
  Insert into ORGANISATIONS (ORGAN_ID,PARENT_ID,NAME) values (31,3,'Organisation 31');
  Insert into ORGANISATIONS (ORGAN_ID,PARENT_ID,NAME) values (311,31,'Organisation 311');
  Insert into ORGANISATIONS (ORGAN_ID,PARENT_ID,NAME) values (3111,311,'Organisation 3111');
  Insert into ORGANISATIONS (ORGAN_ID,PARENT_ID,NAME) values (32,3,'Organisation 32');
  Insert into ORGANISATIONS (ORGAN_ID,PARENT_ID,NAME) values (321,32,'Organisatin 321');
  Insert into ORGANISATIONS (ORGAN_ID,PARENT_ID,NAME) values (3211,321,'Organisation 3211');
  Insert into ORGANISATIONS (ORGAN_ID,PARENT_ID,NAME) values (3212,321,'Organisation 3212');
  Insert into ORGANISATIONS (ORGAN_ID,PARENT_ID,NAME) values (313212,3212,'Organisation with an id containing 31.');

  I would rename the tree nodes. For example, for example add the '-renamed "to all nodes under the node with the id of the organ = 31?
  
  I tried the following, but it is not good, because whenever I have another ID containing the number 31, I have an erroneous result.

  SELECT organ_id, lpad(' ', LEVEL * 2) || name, 
         -- sys_connect_by_path(organ_id, ','), 
          case when instr( sys_connect_by_path(organ_id, ','), '31') > 0 then 
             name || '- renamed' 
             else 
             name
          end
    FROM organisations
   START WITH parent_id is null
  CONNECT BY PRIOR organ_id = parent_id;

  The following query performs the work:
  

  select organ_id, lpad(' ', level * 2) || name, 
         -- sys_connect_by_path(organ_id, ','), 
          case when organ_id IN (SELECT organ_id 
                                   from organisations 
                                  start with organ_id = 31
                                CONNECT BY prior organ_id =  parent_id) then 
                name || '- renamed' 
             else 
             name
          end
    from organisations
   start with parent_id is null
  CONNECT BY PRIOR organ_id = parent_id;

  I wanted to know if it was possible without selecting sub?
  
  Thank you

  Hello

  user13117585 wrote:
  ... I tried the following, but it is not good, because whenever I have another ID containing the number 31, I have an erroneous result.

  SELECT organ_id, lpad(' ', LEVEL * 2) || name,
  -- sys_connect_by_path(organ_id, ','),
  case when instr( sys_connect_by_path(organ_id, ','), '31') > 0 then
  name || '- renamed'
  else
  name
  end
  FROM organisations
  START WITH parent_id is null
  CONNECT BY PRIOR organ_id = parent_id;
  

  It is called the problem of 'Mother in chemotherapy', here's a way to solve it:

  SELECT organ_id, lpad(' ', LEVEL * 2) || name,
         -- sys_connect_by_path(organ_id, ','),
          case when instr( sys_connect_by_path(organ_id, ',') || ',', ',31,') > 0 then
             name || '- renamed'
             else
             name
          end
    FROM organisations
   START WITH parent_id is null
  CONNECT BY PRIOR organ_id = parent_id;
  

  In other words, don't look for '31', look at ", 31,

  The following query performs the work:

  select organ_id, lpad(' ', level * 2) || name,
  -- sys_connect_by_path(organ_id, ','),
  case when organ_id IN (SELECT organ_id
  from organisations
  start with organ_id = 31
  CONNECT BY prior organ_id =  parent_id) then
  name || '- renamed'
  else
  name
  end
  from organisations
  start with parent_id is null
  CONNECT BY PRIOR organ_id = parent_id;
  

  I wanted to know if it was possible without selecting sub?

  Thank you

• Expand the node of the tree dynamically

  I have try the XML for the filter and open the tree node.

  var point: XML = xml... node. (@BH is argument); point is not null.

  tree. openItems = item; did not work

  tree. expandItem (point); also not worked

  tree. expandChildrenOf (point); still didn't work

  var p: * = tree.getParentItem (item); p is always null! ~~~

  tree. expandChildrenOf (p);

  The code you posted is slightly different from the one I proposed, after a while range of instruction you must call expandItem for element nodes [0]:

  tree.expandItem (node [0], true)

  So, you should try to replace the two lines that are placed below the one that is placed above.

  tree.expandItem (parentNode.parent (), true);

  tree.expandChildrenOf (PNode [0], true); / / not work

• create new record in the table of the tree

  REFERRED to the ADF Code 83 corner. How-to - create the two-way synchronization between a tree and a form input element

  http://www.Oracle.com/technetwork/developer-tools/ADF/learnmore/83-bidi-synchronization-tree-form-401841.PDF

  Mr.Frank usese (deptId) of allDepartmentsWithEmployeesIterator-> > > iterator

  to insert the new employee in the service selected tree node

  it get the departmentId for the current line of allDepartmentsWithEmployeesIterator

  and set it as the new employee to the new departmentId inserted in the allEmployeesIterator

  This multiy in table tree we have the employees table and departments table

  ------------------------------------

  	public String onCreateEmployee() {}
  	BindingContainer links = getBindings();
  	OperationBinding operationBinding =
  	bindings.getOperationBinding ("Create1");
  	Object result = operationBinding.execute ();
  	If (! operationBinding.getErrors () .isEmpty ()) {}
  	TODO add the error handling
  	Returns a null value.
  	}

  	a department Id the value of the tree node's parent
  	DCIteratorBinding = departmentIter
  	(DCIteratorBinding) bindings.get ("allDepartmentsWithEmployeesIterator");
  	Line currentDepartmentRow = departmentIter.getCurrentRow ();
  	Object deptId = currentDepartmentRow.getAttribute ("DepartmentId");
  	DCIteratorBinding = employeesIter
  	(DCIteratorBinding) bindings.get ("allEmployeesIterator");
  	Line currentEmployeeRow = employeesIter.getCurrentRow ();
  	currentEmployeeRow.setAttribute ("DepartmentId", deptId);

  	Returns a null value.
  	}

  -----------------------------------

  I'm doing the same functionalty

  in the same tree table

  Insert the child registered under the selected parent node

  but it gives me the ID of the employee of topRank

  in which case we use tree one View object

  as long as same as in ADF code corner article

  032. creating a table tree of a single object View and access selected lines

  We thus obtain the topRanked EmployeeID Steven King is 100

  not the employeeId correct if you select low-tier employee

  ------------------------------

  Create Itried to use with the parameter

  He gave me the same result always it create used under top class used 100 steven King

  not covered by the selected Manager

  -----------------------------------------

  in a few words I'm looking for a way to insert a new line under the selected node

  in the case of the component tree is based on the same view object

  is it an idea or a help on this

  Hello

  in your case, the employee Id is what you need to get the tree component itself. In my article, I rely on the synchronization between two iterators, which in your case is not possible. If access you the component of the tree to get the current selected node. This should be an instance of JUCtrlHierNodeBinding that you can call getRow to obtain the selected user. You can query a second View object to show the employee to edit (the current together by key line). Even when you create a new employee. Access you the second VO iterator used after you call Create to create a new line. On the iterator, you call iterator.setAttribute (attribute_name, value_read_from_parent)

  Frank

• Back on the tree Page when click the button cancel on a Page called

  Hello
  
  I develop an application that uses the Application Express 4.1.1.00.23, I developed a tree similar to the APEX tree, Example of Application of database (i.e. reports > shaft of product).
  When I click on a specific node of the tree, it navigates to another page in the existing application (such as tree of the database Application example).
  
  Example of Application of database does not return to the called Page (so called from reports > shaft of product).
  
  I have an obligation to come back on the tree of the Page when I click the button cancel on a Page called.
  
  Please advice. Thanks in advance.

  tnvrahmd wrote:
  Hi Rohit,

  Thanks for the reply. If you look under query (query Sample Application tree), clicking on a tree node, it opens the page 3, 6 or 29 based on link_type = am ", 'C', 'P' or 'o' and the constructed url."

  In this case just a tree node gets selected and should capture the number of the called page.
  As there are 4 urls and 3 pages being called, how do I capture the page given in hidden element or application,

  Thank you.

  I understand the code of the tree. But I'm not clear on what you mean by "How can I capture page reset hidden element or application". Do you mean that you need to store the page in a hidden page element numbers? If so, you can set the value in the URL that you generate in the tree. For example,.

   case when link_type = 'M'
               then 'f?p='||:APP_ID||':3:'||:APP_SESSION||'::NO:RIR:P1_HIDDEN_PAGE_ITEM:'||3
               when link_type = 'C'
               then 'f?p='||:APP_ID||':3:'||:APP_SESSION||'::NO:CIR:IR_CATEGORY,P1_HIDDEN_PAGE_ITEM:'||name||','||3
               when link_type = 'P'
               then 'f?p='||:APP_ID||':6:'||:APP_SESSION||'::NO::P6_PRODUCT_ID,P1_HIDDEN_PAGE_ITEM:'||sub_id||','||6
               when link_type = 'O'
               then 'f?p='||:APP_ID||':29:'||:APP_SESSION||'::NO::P29_ORDER_ID,P1_HIDDEN_PAGE_ITEM:'|| sub_id||','||29
               else null
               end as link 
  

  where P1_HIDDEN_PAGE_ITEM is your element on the page where you have the tree.

  >

  -Application of tree-
  with the data as)
  Select'm ' as link_type,.
  NULL as parent,
  "All categories" as id,.
  'All categories' as the name.
  NULL as sub_id
  of demo_product_info
  Union
  Select distinct('C') as link_type,
  'All categories' as a parent,.
  category such as id,
  category name,
  NULL as sub_id
  of demo_product_info
  Union
  Select 'P' as link_type,
  parent category,
  TO_CHAR (product_id) id,
  product_name as the name,
  product_id as sub_id
  of demo_product_info
  Union
  Select 'o' in the link_type,
  TO_CHAR (product_id) as a parent,
  NULL as id,
  (select c.cust_first_name |) ' ' || c.cust_last_name
  of demo_customers c, demo_orders o
  where c.customer_id = o.customer_id
  and o.order_id = oi.order_id). ', ordered ' | TO_CHAR (OI. Quantity) as the name.
  order_id as sub_id
  of demo_order_items oi
  )
  Select case when connect_by_isleaf = 1 then 0
  When level = 1 then 1
  of another-1
  end the status,
  level,
  name as title,
  NULL as an icon,
  ID as the value,
  'See' as ToolTip,
  -case when link_type = am'
  then ' f? p ='|| : APP_ID | » : 3 :'|| : APP_SESSION. ': NO:RIR '.
  When link_type = 'C '.
  then ' f? p ='|| : APP_ID | » : 3 :'|| : APP_SESSION |':NO:CIR:IR_CATEGORY:'
  || name
  When link_type = 'P '.
  then ' f? p ='|| : APP_ID | » : 6 :'|| : APP_SESSION |': NO::P6_PRODUCT_ID:'
  || sub_id
  When link_type = 'o'
  then ' f? p ='|| : APP_ID | » : 29 :'|| : APP_SESSION |': NO::P29_ORDER_ID:'
  || sub_id
  Another null
  end as link
  from the data
  Start with the parent is set to null
  connect by prior id = parent
  siblings arrested by name

• Casting error trying to access the tree liaison

  JDeveloper version 11.1.2.1.0
  
  java.util.ArrayList cannot be cast to oracle.jbo.uicli.binding.JUCtrlHierBinding
  
  Hi all
  
  I use the ADF Code corner (http://www.oracle.com/technetwork/developer-tools/adf/learnmore/78-man-expanding-trees-treetables-354775.pdf) code to programmatically set the level of disclosure of the tree node when the page is rendered at the beginning. Property DisclosedRowKeys of the tree is #{viewScope.FieldPickerHandler.newDisclosedTreeKeys}. Below is the code for the handler method that is the cause of the problem. First of all, you can see that I commented on the original code of Frank on lines 5, 6 and 8 because for some reason, it did not find the component of the tree (always returned null). To remedy this, I put the tree component binding property to #{viewScope.FieldPickerHandler.jsfTree} so that the instance of the component available in the Manager and it seems to work. However, when typing code line 16 I get the exception of cast of class at the head of this post.
  
  Significant variation of the example Code corner, is my tree is based on a POJO model that is populated by a VO (as shown by Lucas Jellema http://technology.amis.nl/blog/2116/much-faster-adf-faces-tree-using-a-pojo-as-cache-based-on-read-only-view-object-showing-proper-leaf-nodes-again) program where my node set root, and each child node set, is declared as "nodes list < FieldPickerNode > = new ArrayList < FieldPickerNode > ();".
  
  Is the way the POJO tree is built that it is incompatible with the method of development of node Code corner? Can anyone suggest how I can change my bean handler code to work with POJO tree?
  
  Thank you
  
  Adrian
  
  PS the property Value of the tree is set on #{viewScope.FieldPickerHandler.treemodel} where treemodel is a property managed bean - I guess that means that my tree is not related to the ADF?
  
  1 public RowKeySetImpl getNewDisclosedTreeKeys() {}
  2 if (newDisclosedTreeKeys == null) {}
  3 newDisclosedTreeKeys = new RowKeySetImpl();
  4
  5 / / FacesContext fctx = FacesContext.getCurrentInstance ();
  6 / / UIViewRoot root = fctx.getViewRoot ();
  7 //lookup thetree component by its component ID
  8 / / RichTree tree (RichTree) = root.findComponent ('t1');
  9 tree //if is located...
  10 if (jsfTree! = null) {}
  11 //get the model from the collection to access the ADF link layer for
  12 //the binding used tree. Note that for this sample links
  13 //used of the tree is different from the binding used for the tree
  14 //table
  15 model CollectionModel = (CollectionModel) jsfTree.getValue ();
  16 JUCtrlHierBinding treeBinding = (JUCtrlHierBinding) model.getWrappedData ();
  
  Published by: blackadr on November 3, 2011 17:56

  Hello

  java.util.ArrayList cannot be cast to oracle.jbo.uicli.binding.JUCtrlHierBinding

  JUCtrlHierBinding is the model tree binding in the ADF, while if you are not using the ADF for the binding of the tree, its your tree model implementatuon, which in your case seems to be an ArrayList. If the code of the ADF Code corner is sort of by going through your custom implementation. You must cast to an ArrayList and get the data you want to work with out of this list

  We must look on what is the key of the row of each node. Then give you a clue on how to make the angle of ADF Code work for your example of the sample.

  Frank

  PS. : Blog post from Lucas is kind of old and focuses on 10.1.3