Support for mandatory request - insert, select from the same table

Similar Questions

• Insert select on the same table: possible without side effects?

  I have a very large table T1 containing millions of records. I need to treat its lines and create a few new lines based on selection.

  Table T1 contains events and one of them, with the code 100, is created by the further development of other events inside the table.

  My code is as follows:

  insert /*+append */ into T1 (code,...) values (100, c1,c2,...)
  select c1,c2... from T1 where (code=20 or code=10) and <other conditions>...
  
  

  as you can see I'm extract T1 lines to insert again in T1 with a different code and I use the direct path in order to get good performance.

  My fear is: choose is made from the same table I risk data loss? In general it is a good practice? Or is it better to create another table?

  Hello

  No I don't think that there may be loss of data. But that may depend on the behavior of the application and your where clause.

  I will explain how it is treated, so you can see if it's ok:

  1. the table is locked because of the insert add, (as)

  2 lines are read by select and make compatible from the State that was at the beginning of the query - 1.

  3 rows are inserted at the end, after the high-water line

  4 columns for new lines are sorted to be merged in the index

  5. high watermark is adjusted - visible new lines and lock is released

  Note that 2. and 3. occur at the same time: rows are inserted all read.

  Note that anyone can choose in the table during the operation - they see the changes committed only - if the State 1.

  all other DML are waiting for the lock being released, and will see new ranks and then

  If you have things that prevent the direct-path insert, append the hint will be ignored. So, if you must rely on close to 1. then the best lock explicitly with table lock. But I don't think that you need.

  Kind regards

  Franck.

• Update, and select from the same table

  Hello

  I have this selection - I've tested and work

  [code]

  	Select
  	case
  	When DTF_REEW_201301.KTMO = 1 then DTF_REEW_201301.KTBT
  	of other DTF_REEW_201301.KTBT - CTF_REEW_KUM_201301.KTBT
  	end
  	as KTBT_ISO,
  	case
  	When DTF_REEW_201301.KTMO = 1 then DTF_REEW_201301.KTZN
  	of other DTF_REEW_201301.KTZN - CTF_REEW_KUM_201301.KTZN
  	end
  	as KTZN_ISO,
  	case
  	When DTF_REEW_201301.KTMO = 1 then DTF_REEW_201301.KTAB
  	of other DTF_REEW_201301.KTAB - CTF_REEW_KUM_201301.KTAB
  	end as KTAB_ISO,
  	DTF_REEW_201301.brnrn,
  	DTF_REEW_201301.ktat

  Of

  	reewcore. CTF_REEW_KUM_201301 CTF_REEW_KUM_201301,
  	reewdq. DTF_REEW_201301 DTF_REEW_201301

  where

  	(DTF_REEW_201301.BRNRN = CTF_REEW_KUM_201301.BRNRN
  	and DTF_REEW_201301.KTAT = CTF_REEW_KUM_201301.KTAT)
  	and CTF_REEW_KUM_201301.KTMO = (DTF_REEW_201301.KTMO - 1).

  [/ code]

  With the result of KTBT_ISO, KTZN_ISO and KTAB_ISO I want to update the table 'reewdq. DTF_REEW_201301' - and this picture is in the select statement.

  I think I've tried every update statement - but no update does not work.

  I need something like this:

  [code]

  Update reewdq. DTF_REEW_201301 set t1 t1. KTBT_ISO =

  (

  	Select
  	case
  	When DTF_REEW_201301.KTMO = 1 then DTF_REEW_201301.KTBT
  	of other DTF_REEW_201301.KTBT - CTF_REEW_KUM_201301.KTBT
  	end
  	as KTBT_ISO

  Of

  	reewcore. CTF_REEW_KUM_201301 CTF_REEW_KUM_201301,
  	reewdq. DTF_REEW_201301 DTF_REEW_201301

  where

  	(DTF_REEW_201301.BRNRN = CTF_REEW_KUM_201301.BRNRN
  	and DTF_REEW_201301.KTAT = CTF_REEW_KUM_201301.KTAT)
  	and CTF_REEW_KUM_201301.KTMO = (DTF_REEW_201301.KTMO - 1).

  ),

  T1. KTZN_ISO =

  (

  Select

  	case
  	When DTF_REEW_201301.KTMO = 1 then DTF_REEW_201301.KTZN
  	of other DTF_REEW_201301.KTZN - CTF_REEW_KUM_201301.KTZN
  	end
  	as KTZN_ISO

  Of

  	reewcore. CTF_REEW_KUM_201301 CTF_REEW_KUM_201301,
  	reewdq. DTF_REEW_201301 DTF_REEW_201301

  where

  	(DTF_REEW_201301.BRNRN = CTF_REEW_KUM_201301.BRNRN
  	and DTF_REEW_201301.KTAT = CTF_REEW_KUM_201301.KTAT)
  	and CTF_REEW_KUM_201301.KTMO = (DTF_REEW_201301.KTMO - 1).

  ),

  T1. KTAB_ISO =

  (

  	Select
  	case
  	When DTF_REEW_201301.KTMO = 1 then DTF_REEW_201301.KTAB
  	of other DTF_REEW_201301.KTAB - CTF_REEW_KUM_201301.KTAB
  	end as KTAB_ISO

  Of

  	reewcore. CTF_REEW_KUM_201301 CTF_REEW_KUM_201301,
  	reewdq. DTF_REEW_201301 DTF_REEW_201301

  where

  	(DTF_REEW_201301.BRNRN = CTF_REEW_KUM_201301.BRNRN
  	and DTF_REEW_201301.KTAT = CTF_REEW_KUM_201301.KTAT)
  	and CTF_REEW_KUM_201301.KTMO = (DTF_REEW_201301.KTMO - 1).

  )

  [/ code]

  But this isn´t of the labour code. Someone an idea please? Can someone help me please.

  Best regards

  Heidi

  Use MERGE:

  Fusion

  in reewdq. DTF_REEW_201301 t1

  a_l'_aide_de)

  Select the case sensitive option

  When DTF_REEW_201301.KTMO = 1 then DTF_REEW_201301.KTBT

  of other DTF_REEW_201301.KTBT - CTF_REEW_KUM_201301.KTBT

  end as KTBT_ISO,

  case

  When DTF_REEW_201301.KTMO = 1 then DTF_REEW_201301.KTZN

  of other DTF_REEW_201301.KTZN - CTF_REEW_KUM_201301.KTZN

  end as KTZN_ISO,

  case

  When DTF_REEW_201301.KTMO = 1 then DTF_REEW_201301.KTAB

  of other DTF_REEW_201301.KTAB - CTF_REEW_KUM_201301.KTAB

  end as KTAB_ISO,

  reewdq. ROWID that RID

  of reewcore. CTF_REEW_KUM_201301 CTF_REEW_KUM_201301,

  reewdq. DTF_REEW_201301 DTF_REEW_201301

  where DTF_REEW_201301.BRNRN = CTF_REEW_KUM_201301.BRNRN

  and DTF_REEW_201301.KTAT = CTF_REEW_KUM_201301.KTAT

  and CTF_REEW_KUM_201301.KTMO = DTF_REEW_201301.KTMO - 1

  ) t2

  on)

  T1. ROWID = t2.rid

  )

  When Fachhochschule

  then

  Update

  the t1 value. KTBT_ISO = t2. KTBT_ISO,

  T1. KTZN_ISO = t2. KTZN_ISO,

  T1. KTAB_ISO = t2. KTAB_ISO

  /

  SY.

• ORA-22992: cannot use LOB Locators selected from the remote tables...

  Oracle 10.2.1.0.4
  Solaris 10
  
  We try to access a table in another database via a db_link.
  
  The table we are trying to access has a LOB.
  
  We get the following error: ora-22992: cannot use LOB Locators selected from the remote tables.
  
  Is there a way to get around this? We need the data in the BLOB field.
  
  Thank you.

  See on metalink:

  ORA-22992 has a workaround solution in 10 gr 2
  DOC - ID: 436707.1

  Werner

• Insert data into the same table based on certain conditions

  Hello. I'm new to this forum.
  I have to write a stored procedure to insert data in a table MYTABLE say, having a structure like:
  
  Col1 Col2 Col3... TotalInstallments CurrentInstallment PaidAmount MonthYear
  I have to insert all the data that it is in the same table (MYTABLE) except change some fields based on certain conditions:
  
  1. if PaidAmount > 0 & & CurrentInstallment < TotalInstallment then
  
  CurrentInstallment = CurrentInstallment + 1
  
  2. in the field MonthYear I have data ex. 01/2012, 11/2012 formate(month/year)...
  
  So, I have to insert data by incrementing the month and year. for example:
  
  If currentdata is 11/2012 next data will be 12/2012
  
  But following will be 01, 2013
  I have to select all records that belongs to the previous month (across the field MonthYear) and put the audit on each record selected and insert data and then turns them into table (MYTABLE) even.
  
  How to achieve that?
  
  Thank you.

  978184 wrote:
  Hello. I'm new to this forum.
  I have to write a stored procedure to insert data in a table MYTABLE say, having a structure like:

  Col1 Col2 Col3... TotalInstallments CurrentInstallment PaidAmount MonthYear
  I have to insert all the data that it is in the same table (MYTABLE) except change some fields based on certain conditions:

  1. if PaidAmount > 0 & CurrentInstallment

  CurrentInstallment = CurrentInstallment + 1

  2. in the field MonthYear I have data ex. 01/2012, 11/2012 formate(month/year)...

  So, I have to insert data by incrementing the month and year. for example:

  If currentdata is 11/2012 next data will be 12/2012

  But following will be 01, 2013
  I have to select all records that belongs to the previous month (across the field MonthYear) and put the audit & on each of the selected data record and insert then turns them into table (MYTABLE).

  You can do this way:

  This is not tested, but if you can provide the example of table structure and data (IN create table and insert scripts), it can be put to the test.

  insert into your_table
  (col1, col2, col3...current_installment, month_field)
  select col1, col2, col3..,
         current_installment +
         case when paidamount > 0 and current_installment < total_installment then
          row_number() over (
                              partition by column1, column2,.. columnn      -->You may choose partition if you want the
                                                                            --Increment of Current_installment to reset after particular combination ends
                              order by primary_key        -->Order the Increment, you may choose to add more columns to order by
                            )
        else
          0                                               --> if condition is not met, then Add 0
        end curr_installment,
        add_months(to_date(month_field, 'MM/YYYY'), 1) nxt_month
    from your_table;
  

• Create the table in select * from the other table

  DB: 11.2.0.2
  
  How to create a table with structure only not empty the data that we do not generally create table in select * from... But the command will pull the data also. How to create without data?

  create table foo
  in select * bar
  where 1 = 0

• How can I quickly add a stroke color identical to a filled shape for hundreds of items selected at the same time

  I have an illustration with hundreds small Traoré forms are exactly adjacent. But Illustrator seems to show a small seemed however.

  Is there a way to select all objects of my and have a script their race with the same color as their individual filling?

  Albert

  Why don't you just try using object > path > offset path and use a small number (> 0.005 or more).

• Compare the records from the same table

  Hi all

  I have this sample, the data were rendered are group by my_id, the same number of records exist for the two my_ids (2 and 62) as:

  create table myTest as
  (
  my_id number, 
  fieldA varchar2, 
  fieldB number, 
  fieldC number, 
  cost_A number, 
  cost_B number
  )
  
  insert into myTest (my_id, fieldA, fieldB, fieldC, cost_A, cost_B)
  values (2, 'MAINT', 60, 5, 10.3, 15.00);
  insert into myTest (my_id, fieldA, fieldB, fieldC, cost_A, cost_B)
  values (2, 'MAINT', 70, 6, 20.3, 25.00);
  insert into myTest (my_id, fieldA, fieldB, fieldC, cost_A, cost_B)
  values (2, 'MAINT', 80, 7, 30.3, 35.00);
  insert into myTest (my_id, fieldA, fieldB, fieldC, cost_A, cost_B)
  values (62, 'MAINT', 60, 5, 10.3, 5.00);
  insert into myTest (my_id, fieldA, fieldB, fieldC, cost_A, cost_B)
  values (62, 'MAINT', 70, 6, 20.3, 25.00);
  insert into myTest (my_id, fieldA, fieldB, fieldC, cost_A, cost_B)
  values (62, 'MAINT', 80, 7, 10.3, 15.00);
  

  How can display the records with numbers of different costs for the same unique key (fieldA, fieldB and FieldC)?

  With the help of Oracle Database 11 g Enterprise Edition Release 11.2.0.4.0.

  I hope that my message is clear.

  Thank you!

  Hello

  user9542267 wrote:

  ... I need all the exits...

  Me too.  Always show the complete, accurate, results you want from the data provided.  If you want 2 rows at the exit point, don't tell you want 1.

  Here are the results you want?

  MY_ID FIELDA, FIELDB, FIELDC OLD_COST_A COST_A OLD_COST_B COST_B

  ------ ---------- ------ ------ ---------- ------ ---------- ------

  MAINT 62 60 5 10.3 10.3 15 5

  MAINT 62 80 7 30.3 10.3 35 15

  If so, here's a way to get them:

  WITH got_old_costs AS

  (

  SELECT fielda, fieldb, fieldc, cost_a, my_id, cost_b

  , LAG (cost_a) OVER (PARTITION BY fielda, fieldb, fieldc)

  ORDER BY my_id

  ) AS old_cost_a

  , LAG (cost_b) OVER (PARTITION BY fielda, fieldb, fieldc)

  ORDER BY my_id

  ) AS old_cost_b

  OF mytest

  WHERE my_id IN (2, 62)

  )

  SELECT my_id, fielda, fieldb, fieldc

  old_cost_a, cost_a

  old_cost_b, cost_b

  OF got_old_costs

  WHERE my_id = 62

  AND (cost_a <> old_cost_a)

  OR cost_b <> old_cost_b

  )

  ORDER BY fielda, fieldb, fieldc

  ;

• problem of query by comparing records from the same table against each other

  Hi, i'ms truggling to see where I am going wrong here. I have data from cards of following music: -.

  with charts_table as (select 1 id,'oasis' product_name,0801 week, 20 week_chart_position, 20 highest_chart_position from dual
  union select 2,'oasis',0802,14,14 from dual
  union select 3,'oasis',0803,17,14 from dual
  union select 4,'oasis',0804,29,14 from dual
  union select 5,'kings of leon',0801,55,55 from dual
  union select 6,'kings of leon',0802,22,22 from dual
  union select 7,'kings of leon',0803,35,22 from dual
  union select 8,'kings of leon',0804 , 11 , 11  from dual
  union select 9,'bob dylan',0801, 88 , 88  from dual
  union select 10,'bob dylan',0802,79 , 79  from dual
  union select 11,'bob dylan',0803,54,54 from dual
  union select 12,'bob dylan',0804,22,22 from dual
  union select 13,'kid rock',0801,19,19 from dual
  union select 14,'kid rock',0802,24,19 from dual
  union select 15,'kid rock',0803,55,0 from dual
  union select 16,'kid rock',0804,44,0 from dual)

  italic , I need to identify the rogue data where the highest_position is incorrectly registered lower or 0 as there
  position of the highest week was at an earlier date. (stick with me) for example in this kid of rock data initially charted at position 19. What follows
  week (0802) his week_chart_position slipped to 24 and the position the highest card is correctly saved at 19 (ie the week 1). The problem
  is available in week 0803 and 0804 when somehow the data was corrupted and the higest_chart_position is trying to read 0 (instead of 19). How can I write a query to identify this error?
  
  is the best I have at the moment:-

  select * from charts_table ct1 where 
  nvl2(highest_chart_position,0,99999)>
  (select min(week_chart_position) from charts_table ct2
  where ct2.week<ct1.week
  and ct1.product_name=ct2.product_name)

  but it's not working. can someone help and tell where I'm wrong. Thanks a lot for the research/resolve.

  Ahh, I was suggesting using the lag function to ensure that highest chart position is not fall lower than highest prior chart positions. Your concern is he reports a higher chart position that she never had. In this case I use the MIN function as an analytic function rather than as an aggregate function:

  with t1 as (
    select ct.*
         , min(week_chart_position) over( PARTITION by product_name order by week) highest
      from charts_table ct
     order by product_name, week
  )
  select * from t1 where highest != highest_chart_position;
  

  Conversely, you place your order of cards, which is the highest rank is 1, thew me. I saw the high word and the expected value in the highest chartposition column to be on the rise, but has seen examples of it decreases. It was an oversight on my part.

  Published by: Sentinel on October 9, 2008 08:31

• Best practices for retrieving a single value from the Oracle Table

  I'm using Oracle Database 11 g Release 11.2.0.3.0.

  I would like to know the best practice to do something like that in a PL/SQL block:

  DECLARE
    v_student_id    student.student_id%TYPE;
BEGIN
    SELECT  student_id
    INTO    v_student_id
    FROM    student
    WHERE   last_name = 'Smith'
    AND     ROWNUM = 1;
END;

  Of course, the problem here is that when there is no success, the NO_DATA_FOUND exception is thrown, which interrupts the execution.  So, what happens if I want to continue despite the exception?

  Yes, I could create a block nested with EXCEPTION section, etc, but it seems awkward for what seems to be a very simple task.

  I've also seen this handled like this:

  DECLARE
    v_student_id    student.student_id%TYPE;
    CURSOR c_student_id IS
        SELECT  student_id
        FROM    student
        WHERE   last_name = 'Smith'
        AND     ROWNUM = 1;
BEGIN
    OPEN c_student_id;
    FETCH c_student_id INTO v_student_id;
    IF c_student_id%NOTFOUND THEN
        DBMS_OUTPUT.PUT_LINE('not found');
    ELSE
        (do stuff)
    END IF;
    CLOSE c_student_id;   
END;

  But it still seems to kill an Ant with a hammer.

  What is the best way?

  Thanks for any help you can give.

  Wayne

  201cbc0d-57b2-483a-89f5-cd8043d0c04b wrote:

  What happens if I want to continue despite the exception?

  It depends on what you want to do.

  You expect only 0 or 1 rank. SELECT INTO waiting for exactly 1 row. In this case, SELECT INTO may not be the best solution.

  What exactly do you do if you return 0 rows?

  If you want to set a variable with a NULL value and continue the treatment, Frank's response looks good, or else use the modular Billy approach.

  If you want to "do things" when you get a line and 'status quo' when you don't get a line, then you can consider a loop FOR:

  declare
    l_empno scott.emp.empno%type := 7789;
    l_ename scott.emp.ename%type;
  begin
    for rec in (
      select ename from scott.emp
      where empno = l_empno
      and rownum = 1
    ) loop
  l_ename := rec.ename;
      dbms_output.put_line('<' || l_ename || '>');
    end loop;
  end;
  /
  

  Note that when no line is found, there is no output at all.

  Post edited by: StewAshton - Oops! I forgot to put the result in l_ename...

• Comparison of the 2 columns from the same table

  Mr President.
  
  I have a table xyz that has 10 million rows
  
  who has 3 columns
  
  ProfileId personid fpersonid
  
  
  I find on all of the profileids that do not match personid = fpersonid
  
  is there a way better and faster outside self-join?
  
  
  Select a. profileid xyz a, b of xyz where a.personid! = b.fpersonid

  Your SQL is incorrect.

  Just use... . Select xyz profileid where personid! = fpersonid

• Question: Is foreign key references to a different column in the same table

  Hello

  I'm not grasp this concept. Would you be able to provide the logic how and why you need to create a foreign key that references a column of the same table?

  For example, referencing the schema, SupervisorNo @ here is a FOREIGN KEY to the "EmpNo" column in the same table.

  EMPLOYEE (EmpNo, title, Fname, Lname, phone, Email, date of birth, sex, salary, HireDate, OutNo, SupervisorNo @)

  
  

  Why would you want to do this and how can it be used? If you are filling out the data in the table, and this constraint is enabled, you will not be able to load whatever it is because the "EmpNo" column will be empty.

  
  

  Any input you can provide me with this would be greatly appreciated. Thank you!

  
  

  
  

  His name

  Self-referential integrity constraints

  Lets say that we have the table emp with emp_no and mgr_no columns.

  Now all managers should also be an employee too. How can I check this when inserting data into this table? I applied auto integrity constraint. It would help me to make sure no handler (doesn't mean no mgr_no) must be registered if this Manager is not an employee of this organization. Which means, I won't be able to enter any mgr_no in the column until and unless that the same employee also is an employee (emp_no from the same table).

  Check the link as well below.

  Data integrity

  Thank you

  Ishan

• UPDATE on the same table in the sub query

  DB version: 11.2
  
  We have a table called SHP_GC_TRACK, which has about 8 million records with partitions. In the below UPDATE, it updates a column based on the SELECT on the same table in a subquery.
  

  UPDATE shp_gc_track a
     SET f_tran_proc  = 'Y'
   WHERE last_update_date <
            (SELECT MAX (last_update_date)
               FROM shp_gc_track b
              WHERE a.shp_trx_rowid = b.shp_trx_rowid
                AND a.c_shp_inst = b.c_shp_inst
                AND a.f_tran_proc  = b.f_tran_proc 
                AND b.f_ltr_received = 'D'
                AND f_rec_code IN ('G', 'W')
                AND b.f_rec_status = 'B'
                AND b.c_shp_inst = :b1
                )
     AND a.c_shp_inst = :b1
     AND a.f_ltr_received = 'D'             -----------------> part of composite index
     AND a.f_tran_proc  = 'N'              -----------------> part of composite index
     AND a.f_rec_code IN ('G', 'W')      --------------> part of composite index  
     AND a.f_rec_status = 'B';              -----------------> part of composite index  

  This UPDATE takes a long time to run and sometimes get hung up.
  
  We have a composite index on four columns f_ltr_received, f_rec_code, f_rec_status and f_tran_proc. Explain the plan shows that this composite index is used.
  
  
  
  Any way to rewrite this query or suggestion?

  Steve_74 wrote:
  DB version: 11.2

  We have a table called SHP_GC_TRACK, which has about 8 million records with partitions. In the below UPDATE, it updates a column based on the SELECT on the same table in a subquery.

  UPDATE shp_gc_track a
  SET f_tran_proc  = 'Y'
  WHERE last_update_date <
  (SELECT MAX (last_update_date)
  FROM shp_gc_track b
  WHERE a.shp_trx_rowid = b.shp_trx_rowid
  AND a.c_shp_inst = b.c_shp_inst
  AND a.f_tran_proc  = b.f_tran_proc
  AND b.f_ltr_received = 'D'
  AND f_rec_code IN ('G', 'W')
  AND b.f_rec_status = 'B'
  AND b.c_shp_inst = :b1
  )
  AND a.c_shp_inst = :b1
  AND a.f_ltr_received = 'D'             -----------------> part of composite index
  AND a.f_tran_proc  = 'N'              -----------------> part of composite index
  AND a.f_rec_code IN ('G', 'W')      --------------> part of composite index
  AND a.f_rec_status = 'B';              -----------------> part of composite index  
  

  This UPDATE takes a long time to run and sometimes get hung up.

  We have a composite index on four columns f_ltr_received, f_rec_code, f_rec_status and f_tran_proc. Explain the plan shows that this composite index is used.

  Any way to rewrite this query or suggestion?

  Setting updates with subqueries may be difficult: (.) Unfortunately my suggestions below are of the try-it-and-see-what-happens variety - nothing of certain

  First of all, check the index. Is it bitmap or tree? If the tree to see if the more restrictive columns are listed first - this can help with effectiveness of b-tree indexes. Also if the tree a composite bitmap for columns with lots of repeat values instead could help

  Its a correlated subquery so that you cannot run just the subquery first put the result in a scalar varaiable and using the variable in the SQL instead. You can try putting the keys w/join subuqery results in a TWG first to use TWG in SQL to see if I/O is reduced together during these two operations.

  You have the license for the parallel query option? Using parallel DML (this must be activated manually) can help. Check the documentation of the ALTER SESSION command to do so. In addition, the PARALLEL_INDEX() indicator could help

  Display the SQL execution plan

• Report with multiple columns NUMBER of counts of the same table

  I am new to discoverer, so I'm a little lost.
  
  I work to create a report to show usage data and Knowledge Base of e-business. I have written using subqueries in SQL query that is in the format:
  
  Solution number | Soultion title | Solution views. Positive feedback | Negative feedback
  Title of 12345 _ 345 _ 98 34
  
  
  The entries 'Views', 'Positive' and 'Negative' are stored in the same table, so I do a count where setid = setid and usedtype = VS, then count where usedtype = usedtype and PF = NF
  
  Discoverer, I can get the number of solution, the title and THE totals but I can't seem to understand how to get an ACCOUNT for three different things from the same table in the columns on the same line.
  
  When I go on change map-> select the items once I select the option NUMBER of the UsedType column in the CS_KB_SET_USED_HISTS table, I can't select it again. I also found way now to add a column based on a query entered.
  
  If someone could help it would be much appreciated.
  
  Thank you
  
  Published by: Toolman21 on December 2, 2010 14:17
  _ to correct spacing added.

  Hello
  You can separate the column with a case or decode.
  for example to create 2 calculations:

  case
  When usedtype = "PF".
  then - that contain both
  0 otherwise
  end

  case
  When usedtype = 'NF '.
  then - that contain both
  0 otherwise
  end

  After that, you can create the aggregation count on those.

  Tamir

• FRM - 40202:Field must be entered on two blocks with the same table

  I have two blocks, blockA and blockB, both from the same table that is tableX.
  
  When I ask of blockA and it worked, then I go to blockB and modify data, and save, there is no problem. But when I do not run the query of blockA or if the query did not return any results, I go to blockB and change some data then save, I got this error. The cursor then go to first blockA point. So now, I have to delete this empty line before the Save.
  
  
  Any suggestion?

  you set a few initial values programmatically for a block?
  in this case, the status changes to INSERT and you will get this message.
  You can check the staus with GET_RECORD_PROPERTY (1, "A BLOCK", STATUS), e.g. with the trigger KEY-COMMIT.