Suppression of zeros of column
How can I remove the zeros of a column?The data looks like to * 00-04-071 *.
The output should display 4071
SQL> select ltrim(replace('00-04-071','-'),'0') from dual
2 /
LTRI
----
4071
SQL>
SY.
Tags: Database
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Suppression of zeros of a column
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I want to remove the zeros of a column of varchar type that allows to store alpha numeric characters.
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0-> 0
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If I use ltrim(column,'0') it returns null
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Published by: user518071 on February 22, 2010 12:00Or
SQL> with t as ( select '0' str from dual union all select '00x42' from dual union all select '000AB' from dual union all select null from dual ) -- -- select str, regexp_replace(str, '^0+', '0') str2 from t / STR STR2 ----- ------------------------------ 0 0 00x42 0x42 000AB 0AB 4 rows selected. -
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How to get no value zero to a data set
Here is my SQL statements:
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Current output
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for example,.
For i1 and Loc l1 point, we have 6 entries and Jan 07, Jan 21st and Feb 11 we have zero quantities and Jan 14th, 28 Jan and Feb 04 have non - zero quantities, when all of this is stopped by date, amount of 14 Jan must stem from Jan 07, Jan 28 should be established on 21st January and Feb 11 is to have zero quantity but there is no record found after that if she should remain such what.
Similar logic for all other combinations
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Select only records where the column values are not all equal to zero
Hi everyone, it seems so easy, but it has left me speechless on the research in a way that is clean, easy to achieve. I know when someone replies, I'm going to kick me. So, let's assume this is what I have:
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Thanks in advance!
Mark
Edit... I know not what follows will work using the MINUS operator, but my actual query is really huge, and I don't want to have to write it twice...
{code}
Select
ItemType,
sum (case monthname when "JAN" then Val else 0 end) such as JAN,.
sum (case when monthname 'FEB', then Val 0 otherwise end) by Feb.
sum (case when monthname 'MAR', then Val 0 otherwise end) like MARS,
sum (case monthname when "APR" then Val else 0 end) as APR.
sum (case when monthname 'MAY', then Val else 0 end) either.
sum (case when monthname "JUN", then Val 0 otherwise end) as JUN.
sum (case monthname when "JUL" then Val else 0 end) as JUL,.
sum (case monthname when "AUG" then Val else 0 end) as AUG.
sum (case monthname when "MS" then Val else 0 end) as MS.
sum (case monthname when "OCTS" then Val else 0 end) OCT.
sum (case monthname when "NOV" then Val else 0 end) as NOV.
sum (case monthname when 'DEC' then Val else 0 end) as DEC
FROM MyTable
Group of itemtype
less
Select
ItemType,
Jan, Feb, mar, Apr, may, June, July, August, Sept, oct, nov, dec
de)
Select
ItemType,
sum (case monthname when "JAN" then Val else 0 end) such as JAN,.
sum (case when monthname 'FEB', then Val 0 otherwise end) by Feb.
sum (case when monthname 'MAR', then Val 0 otherwise end) like MARS,
sum (case monthname when "APR" then Val else 0 end) as APR.
sum (case when monthname 'MAY', then Val else 0 end) either.
sum (case when monthname "JUN", then Val 0 otherwise end) as JUN.
sum (case monthname when "JUL" then Val else 0 end) as JUL,.
sum (case monthname when "AUG" then Val else 0 end) as AUG.
sum (case monthname when "MS" then Val else 0 end) as MS.
sum (case monthname when "OCTS" then Val else 0 end) OCT.
sum (case monthname when "NOV" then Val else 0 end) as NOV.
sum (case monthname when 'DEC' then Val else 0 end) as DEC
FROM MyTable
Group of itemtype
)
where (oct = 0 & nov = 0 and dec = 0 and jan = 0 and 0 = Feb and mar = 0
apr = 0 and may = 0 and = 0 jun and Jul = 0 and aug = 0 and Ms = 0
)
order of itemtype
{code}
Change again... OK, I guess that I am answering my own question here, but I think that by using a WITH to write the main request once clause and then selecting * twice using the MINUS operator between where the second query is where (oct = 0, etc.) is what I need. If anyone has better suggestions, please let me know! Here's the logic of nickname for what I come up with to date...
{code}
WITH mainquery as (select all)
Select * from mainquery
less
Select * from mainquery where (oct = 0, nov = 0, etc...)
{code}
Thanks again!
Mark
Published by: user455268 on March 1, 2012 19:13
Published by: user455268 on March 1, 2012 19:16Hello
You can do it with a HAVING clause:
select itemtype, sum (case monthname when 'JAN' then theval else 0 end) as JAN, sum (case monthname when 'FEB' then theval else 0 end) as FEB, sum (case monthname when 'MAR' then theval else 0 end) as MAR, sum (case monthname when 'APR' then theval else 0 end) as APR, sum (case monthname when 'MAY' then theval else 0 end) as MAY, sum (case monthname when 'JUN' then theval else 0 end) as JUN, sum (case monthname when 'JUL' then theval else 0 end) as JUL, sum (case monthname when 'AUG' then theval else 0 end) as AUG, sum (case monthname when 'SEP' then theval else 0 end) as SEP, sum (case monthname when 'OCT' then theval else 0 end) as OCT, sum (case monthname when 'NOV' then theval else 0 end) as NOV, sum (case monthname when 'DEC' then theval else 0 end) as DEC from mytable group by itemtype HAVING MIN (theval) != 0 OR MAX (theval) != 0 order by itemtype ;If the values are all 0, then the MIN and MAX will be 0.
If the MIN or MAX is not 0, the values are all 0.This assumes that the combination (itemtype, monthname) is unique, because it is in your sample data.
If this is not the case, start with a subquery that GROUPs BY itemtype, monthname, so that when you get to the main request, this combination will be unique.
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