Suspend the data string decoder

Similar Questions

• conversion of the date string

  Hello
  
  I've recently become involved with databases, and I hit a little snag.
  I have strings that represent a date, they are very oddly formatted and need to store them as dates. the format string looks like this:
  
  "Monday, May 13, 2001"
  
  How can I effectively convert DATE type?
  I hope it's more simple I think.
  Thanks in advance

  /* Formatted on 2012/06/26 04:31 (Formatter Plus v4.8.8) */
  SELECT TO_DATE (REGEXP_REPLACE ('SUNDAY,May the 13th of 2001', 'the|th|of',
                                  ''),
                  'DAY,MONTH DD RRRR'
                 )
    FROM DUAL;
  

• Date string

  Hello world

  Is there anything to get the date string that is actually a day late from the effective date of the PC. I am using format string minus 1 away from the day and time. But the problem occurs when the real is '1 '. My program will not be able to decide if the watch is "30,31,28 or 29.Etc.."

  Please help me

  

  Concerning

  Ray.

  

• TCP IP to receive and divide the data in real time

  I'm using labview 11 and I have a computer send data via tcp ip. The data string is like this P 22 33 44 P 22 44 66 P 22 33 11 P and so on are numbers between P x y and z co - ord, I need labview to receive this and separate each x y and z as separate outputs

  Two examples of analysis of some basic:

  

  The upper part is by using a regular expression, which is a lot more forgving the lower part that uses parsing the string. The analysis of the chain will work only if there is a space between the elements. The regular expression will work will allow multiple spaces.

• Can I use data string Web App (image) in a CSS hover function?

  I'm developing a profile of employee of company "show and tell" using the Web application. I built my item in the list and details. Works very well. However, I have no hover function. So, I created a few css - one div id and added a background image then hover div with another image to hover. It worked. I moved the code of Dreamweaver in British Colombia - inside (the list template) Web application. I replaced the paths of the image with the data string Web App - image (e.g. {tag_employee photo}). Then I did the same thing to hover - I changed the image of the data string (e.g. {tag_employee photo2}). It does not work now.

  All CSS is written inside the body, so it's not pulling to the outside path. I thought that a path from the outside may not understand the data string.

  How can I get this to post a link with the chain of image data? Am I missing something?

  How can I create an image using CSS switch and function WITH the BC Web App data strings hover?

  Here's how I wrote the id of the DIV:

  
  

  # {List_photo

  height: 200px;

  Width: 200px;

  background-image: url("{tag_employee photo (200px)}" ");

  position: relative;

  margin-bottom: 10px;

  Display: block;

  }

  # {List_photo:hover

  height: 200px;

  Width: 200px;

  background-image: url("{tag_employee photo (hover)}" ");

  position: relative;

  margin-bottom: 10px;

  Display: block;

  }

  Thank you!

  Robert

  Hi Robert,.

  The concept of what you're doing works (as long as the)

• Play with the date format TO_CHAR

  Hi all
  I'm learning how function TO_CHAR date format and code using the table double, but I had a few difficulties:

  SQL> select to_char(sysdate,'dl') test from dual;
  
  TEST
  -----------------------------
  Monday, December 20, 2010
  
  SQL> select to_char(sysdate) test from dual;
  
  TEST
  ---------
  20-DEC-10
  
  SQL> select sysdate test from dual;
  
  TEST
  ---------
  20-DEC-10
  
  SQL> select to_char('20-DEC-10','dl') test from dual;
  select to_char('20-DEC-10','dl') test from dual
                 *
  ERROR at line 1:
  ORA-01722: invalid number

  How can I place an explicit function TO_CHAR date?
  
  Best regards
  Valerie

  Valerie Debonair wrote:
  Hi all
  I'm learning how function TO_CHAR date format and code using the table double, but I had a few difficulties:

  SQL> select to_char('20-DEC-10','dl') test from dual;
  select to_char('20-DEC-10','dl') test from dual
  *
  ERROR at line 1:
  ORA-01722: invalid number
  

  How can I place an explicit function TO_CHAR date?

  Oracle converts implicitly your string to a date so that it can convert it to a string using your to_char function. Implicit conversion is based on your NLS_DATE_FORMAT settings, but you can never count on these implicit conversions.

  You can be...

  SQL> select to_char(to_date('20-DEC-10','DD-MON-RR'),'dl') from dual;
  
  TO_CHAR(TO_DATE('20-DEC-10'
  ---------------------------
  Monday 20 December 2010
  

  or

  SQL> select to_char(date '2010-12-20','dl') from dual;
  
  TO_CHAR(DATE'2010-12-20
  -----------------------
  Monday 20 December 2010
  

  Note that this one used Oracle fixed-date internal format YYYY-MM-DD, so if ever you use this method, you must specify the date string in this format. It also only deals with dates, not the component "hour".

• Channel of String conversion to the data channel

  I have a problem I tried to accomplish through a. The URI of the file but can seem to make it work good for me.  I have an original data channel are in TEXT format and the data in the channel are the phone number in the format 6667779999 or 4343. Can someone help me with a suggestion of script to convert this. Most of my ATTEMPTS end with a 66.67779e5.  Can be simple but I can just figure it out.

  Thank you J

  Hello J,

  A number such as 66.6778888e5 can be shown as 6667778888 in a DISPLAY box or table or text REPORT or a axis of REPORT graph by using the display correct format string - in this case "d".  Where do you 6667778888 number appears like this in DIAdem, exactly?  If you want to see in a BULLETIN Board, you will need to choose the option button 'Selected channels' first in the configuration dialog box, and only then will you be able to choose a format string to display such as "d" for this column.

  Brad Turpin

  Tiara Product Support Engineer

  National Instruments

• concatenate the data in 2 tables in a third table as well as in CONCATENATE strings

  Hello. as the title says, I wish to only concatenate the data in 2 tables in a similar third table that concatenate strings don't. All tables should be 1 d. For example, suppose that there is 1 table with the following: 1. 2; 3; 4 and table 2 with:; b; c; d. I would like a table 3 either 1 a, 2 b, 3 c, 4 d. Now this could be done easily with above mentioned concatenate strings, then table construction. but table 1 and 2 have something like 150 items. Rather painful. Any ideas?

  Hold arrays of two strings in a loop for example, concatentate the strings inside the loop and run the result réécrirait array3.

  Autoindexing manages table manipulations.

  MIke...

• The analysis of the data of a string of series

  Alert LabVIEW Express 7

  Sorry, all I have to work with and there is no budget at the moment to upgrade.

  Hello, I am in phase 1 (data transfer reliable to labview) 24/7 of my small Miettinen, who is to display and record data environmental Lab 24/7 our Fisher 02-403 digital barometer that has a serial port. In fact, it came with the software, but no one here seems to like use it so I'll try to find something more intuitive. I can't find any info at all about I/O with this device, so I'm reverse engineering. I'm sure that you cannot write anything to this device only read.

  I started with the connection of the device and the interface with NOR measure and automation and received the following string: P,43,1019,44,31,01,0023.0\r\n.

  I tried to use the Labview 7 Express e/s Companion Instrument, selected 1 COMM, changed the timeout to 5000 (trial and error), added a step reading and analysis, ran and received the following string: P, 43,0999, 44,41, 01,0018.0, XX. After well guess, I determined that the values I have in bold change with the environment and the other 3 are always the same idea 9no what they represent). Alphabetical 1 in bold represents the tendency of climate S sunny = P = C sunny cloudy = etc., the value 2 is the atmospheric pressure in hPa, the 3rd is % relative humidity and the last is the temperature in Deg. C.

  At first, I tried to create simply chips for data I want and operation loop the wizard of e/s in awhile, but often error messages obtained suggesting that I need to define all the tokens in the string. I did it and it worked, then I opened the front panel to access the underlying schemas whence I came with the attached VI. I left this race for more than 24 hours, no error, seems good.

  My question on this forum is, can I simplify this VI losing a part of the analysis of the data that I don't need at this point?

  Please let me know if you can not access this VI maybe I can do a screenshot or something.

  Thank you

  Doug

  Yes, it can be simplified to just a bit.

  

  Since you are new to LabVIEW, you can start with the basic tutorial.

• A string that can be displayed as ASCII and hex in an indicator will allow not to store the data in a file in ASCII format

  You can see the data in an indicator very well, but when we try to write this string of hexadecimal data in a file, it will only save the data in ASCII format.

  This seems simple enough, as the indicator can be selected to display the data in different formats (VI > properties > appearance > display Style: Normal, backslash, hexadecimal).  However, I could not, for the moment save data in different formats.

  Altenbach says:

  ... or you can just read the string: text.text property to get everything that is actually displayed.

  Like this...

  

• The analysis of the data of a string in an array

  I'm trying to analyze data from this series, which are continually being added to a string. How can I do this in a table that is added to each pass through the loop? The data looks like this:

  20/08/2015-04:31:39, 0,242 4.382 0.219, 22.97, 8.211, 381,.

  20/08/2015 04:31:43, 0,241, 4380, 0,220, 22.78, 8.202, 463,

  20/08/2015 04:31:48, 0,242, 4380, 0.219, 23.06, 8.196, 543,

  I tried to use the block 'string function analysis' with my 'chain' as

  %f/%f/%f % f % f: %f %f %f, %f, %f, %f and %f,

  mikeporter wrote:
  Personally I have never had much luck with how long scan chains. I think that I divide the inflow on the date and then put the rest of the sample in a table 1 d of tanks using the spreadsheet string table. You convert the timestamp separately.

  In fact, converting the first timestamp.

  

• Avoid writing empty lines or remove the empty string between data lines

  Hello

  I have this problem...  I write as a 4 x 4 witch table comes from a graph of intensity in a file. But when I write, regardless of the method that I use out it somehow unusable when I try to read more later.

  Right now I got change for a 1 x 16 table witch I later convert back to 4 x 4 again shown in the graph of the intensity.

  The problem is that I have empty lines between the data I want to remove to display correctly.

  Maybe to be clear in my explanation I will post screenshots of how I write and how I like to read...

  

  Can someone help me?

  Thank you!

  Antonio

  Why do you use a loop to create a string to write to the file? In LabVIEW 8.x writing on a spreadsheet file is polymorphic, so you can select the instance of 'Double' and simply connect your table 2D directly to it, without a loop or anything like that. On playback, even select the instance 'Double' for your return values exactly as you wrote them.

• the analysis of the data of type string mid

  I'm pretty new to LV and I'm trying to find a way to analyze the data in the middle of a set of string. an example of the data : 854560@67042850@600,000@151168390748@1000477480@00000000000000000

  Here I am trying to extract the first 6 digits (854560) and the 10 digits (1000477480). The length of the other numbers go from DataSet to the dataset that I work with but the '@' symbols are always involved. So, I wonder if there is a method to extract the left 6 and between the 4th and the 5th symbol @.

  Thank you.

  If you still have @ symbols as a delimiter and it will always be the same number of elements, you can convert only one table using '@' as separator and shoot the first and the 5th element.

  

• Display the name of the tag as the column name and the value in the tag as a row of data from the input string.

  Hi Forum members,

  I am looking for a query display the name of the tag as the column name and the value in the tag as a row of data.

  I have to print the values within the tag to a file by choosing the value of the flags. the sequence of the tags will vary each time, as the tag name will change dynamically.

  So here is the example of input data and the expected output. The string in the text column must be separated as the column names and values.

  Input data
  Select 1 as seqno,' < > 0210A 50 4f < / 4f > < 5f20 > TEST CARD 16 < / 5f20 > < 5f2a > < / 5f2a > < 82 > 1 c 00 < / 82 > ' double text

  
  Output:

  Seqno 4f 5f20 5f2a 82
  0210A 50 16 1 00 TEST CARD 1

  Please help me by providing your entries on this.

  We use the version of Oracle 11.2.

  Note: This is not the XML string

  Thank you

  Shree

  with

  data in the form of

  (select 1 as seqno,'<4f>0210 A 50<5f20>TEST CARD 16<5F2a><82>00 1' text of all the double union)

  Select 2 as seqno,'XYZ<4F>0210 A 50<5f20>TEST CARD 16<5f2a><82>00 1' text of all the double union

  Select 3 as seqno,'<4f>0210 A 50<5f20>TEST CARD 16<5F2A><82>1 00XYZ ' text of all the double union

  Select option 4 as seqno,'<4F>0210 A 50<5F20>TEST CARD 16<5f2A><82>1 00XYZ' double text

  )

  Select d.seqno, x.*

  d the data,

  XMLTable ('/ root')

  by the way xmltransform (xmltype ('': replace (replace (text,'<><>'),)))

  XmlType (q'~http://www.w3.org/1999/XSL/Transform "version ="1.0"> ")

                                                   

                                                     

                                                       

                                                     

                                                   

                                                   

                                                     

                                                       

                                                     

                                                   

  ~'

  )

  )

  path of columns '4f' varchar2 (10) "tag4f."

  path of "5f20' varchar2 (30)"tag5f20. "

  path of '5f2a' varchar2 (10) "tag5f2a."

  path of varchar2 (10) "82" "tag82.

  ) x

  
  

  SEQNO	4f	5f20	5f2a	82
  1	0210A 50	16 TEST CARD	-	1 00
  2	0210A 50	16 TEST CARD	-	1 00
  3	0210A 50	16 TEST CARD	-	1 00
  4	0210A 50	16 TEST CARD	-	1 00

  with

  data in the form of

  (select 1 as seqno,'<4f>0210 A 50<5f20>TEST CARD 16<5F2a><82>00 1' text of all the double union)

  Select 2 as seqno,'XYZ<4F>0210 A 50<5f20>TEST CARD 16<5f2a><82>00 1' text of all the double union

  Select 3 as seqno,'<4f>0210 A 50<5f20>TEST CARD 16<5F2A><82>1 00XYZ ' text of all the double union

  Select option 4 as seqno,'<4F>0210 A 50<5F20>TEST CARD 16<5f2A><82>1 00XYZ' double text

  ),

  Chopper (seqno, Key, value, String) as

  (select seqno,

  regexp_substr (text,'<(.+?)>', 1, 1, null, 1),

  regexp_substr (Text,'>(.*?))

  regexp_substr (text,'<.+?>. *? ) (.*) $', 1, 1, null, 1). » <>'

  from the data

  Union of all the

  Select seqno,

  regexp_substr (String,'<(.+?)>', 1, 1, null, 1),

  regexp_substr (String,'>(.*?))

  regexp_substr (String,'<.+?>. *? ) (.*) $', 1, 1, null, 1)

  Chopper

  where regexp_substr (string,'<(.*?)>', 1, 1, null, 1) is not null

  )

  Select '4f', seqno, '5f2a', '82', '5f20.

  of (seqno, lower (key) select key, value)

  Chopper

  )

  Pivot (max (value) for key in ('4f' as '4f', '5f20' as '5f20', '5f2a' as '5f2a', "82" as "82"))

  Concerning

  Etbin
  

• ORA-01436: CONNECT loop in the user data when the delimited string splitting by the

  I'm trying to split a string into records. The values are three characters more '-' with a limit of 12 values. The values themselves are a combination of two data, the first being two characters, a.

  The following example translates: ORA-01436: CONNECT BY a loop in the user data

  WITH
      Data(Code, Datum)
  AS
      (
       SELECT 'VGCU3VM', '00V-YYG-BVC-PIU-DV3-EVV-TVM-' FROM Dual UNION ALL
       SELECT 'VGAU3VM', '00V-YYG-BVA-PIU-DV3-EVV-TVM-' FROM Dual UNION ALL
       SELECT 'VGLN3CM', '00V-YYG-BVL-PIN-DV3-EVC-TVM-' FROM Dual UNION ALL
       SELECT 'VGLT3PM', '00V-YYG-BVL-PIT-DV3-EVP-TVM-' FROM Dual UNION ALL
       SELECT 'VGAT3RA', '00V-YYG-BVA-PIT-DV3-EVR-TVA-' FROM Dual
      )
  SELECT
      Datum,
      LEVEL,
      SUBSTR(Datum, ((LEVEL - 1) * 4) + 1, 2),
      SUBSTR(Datum, ((LEVEL - 1) * 4) + 3, 1)
  FROM
      Data
  CONNECT BY
      Code    = PRIOR Code
      AND    LEVEL    <= LENGTH(Datum) / 4;
  
  

  Remove the 'Code = Code PREREQUISITE"clause, to avoid the error, but too many records are returned, because nothing is to limit the records in their own groups.

  The following works:

  WITH
      Data(Code, Datum)
  AS
      (
       SELECT 'VGCU3VM', '00V-YYG-BVC-PIU-DV3-EVV-TVM-' FROM Dual UNION ALL
       SELECT 'VGAU3VM', '00V-YYG-BVA-PIU-DV3-EVV-TVM-' FROM Dual UNION ALL
       SELECT 'VGLN3CM', '00V-YYG-BVL-PIN-DV3-EVC-TVM-' FROM Dual UNION ALL
       SELECT 'VGLT3PM', '00V-YYG-BVL-PIT-DV3-EVP-TVM-' FROM Dual UNION ALL
       SELECT 'VGAT3RA', '00V-YYG-BVA-PIT-DV3-EVR-TVA-' FROM Dual
      )
  SELECT
      Datum,
      SUBSTR(Datum, ((Some.Num - 1) * 4) + 1, 2) A,
      SUBSTR(Datum, ((Some.Num - 1) * 4) + 3, 1) B
  FROM
      Data,
      (SELECT LEVEL Num FROM Dual CONNECT BY LEVEL <= 12) Some
  WHERE
      SUBSTR(Datum, ((Some.Num - 1) * 4) + 1, 2) IS NOT NULL;
  
  

  What causes ORA-01436?

  Hello

  Depending on your version, you can add another condition to your CONNECT BY clause.

  It works in Oracle 11.2.0.3.0:

  SELECT

  Point of reference,

  LEVEL,

  SUBSTR (Datum, ((LEVEL-1) * 4) + 1, 2),

  SUBSTR (Datum, ((LEVEL-1) * 4) + 3, 1)

  Of

  Data

  CONNECT

  Code = Code PRIOR

  AND LEVEL<= length(datum)="">

  AND PRIOR SYS_GUID () IS NOT NULL-* ADDED *.

  ;

  Thanks for the display of the data of the sample; This is really useful!

  In addition, relational databases are designed to have 1 piece of information in each column of each row, not a list delimited by up to 12 points.  It is so basic to the design of database he called the first normal form.  You're going to solve a lot of problems even before they occur if you paste to first normal form and change the table structure to resemble the result set of this query.  (Maybe that's exactly why you're doing this query.)