SYSDATE + 1 day
I have this statement was updated as follows:update customer set date = sysdate + 1 day where customer_id = 12345;Set date = sysdate + 1
I doubt you have a column called"date"unless you used quotes during the definition of the column that would be a very bad idea... ;)
Tags: Database
Similar Questions
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Restrict the datePicker to sysdate + 2 days
Hello
I am trying to achieve in a date picker sysdate + 2 days in apex 4.2.6 where sysdate format willl be DD-MON-YYYY HH:MIPM. Ideally speaking, I have to add 48 hours to the current date and the user should not be able to select before this date and time. TKS
Hi hayatms,
hayatms wrote:
Hello
I am trying to achieve in a date picker sysdate + 2 days in apex 4.2.6 where sysdate format willl be DD-MON-YYYY HH:MIPM. Ideally speaking, I have to add 48 hours to the current date and the user should not be able to select before this date and time. TKS
Hereby you mean this:
https://Apex.Oracle.com/pls/Apex/f?p=52380:1:100094430581177:
See the region "Datepicker with dates.< sysdate="" +="" 2="">
To do this, I changed the Datepicker element-> settings-> Minimum Date to '+ 2d' as follows:
I hope this helps!
Kind regards
Kiran
-
How to generate date thru sysdate and day of the week
Hello world!
Please give me a hand with this:
I need calculate a date thru sysdate and day of the week.
For example:
SYSDATE: 22/08/2013
DAY: TUESDAY
Result: 27/08/2013 (the date for Tuesday next from today ' hui).
Another example:
SYSDATE: 22/08/2013
DAY: FRIDAY
Result: 23/08/2013 (the date for Friday next today).
My version of oracle's 8i (I work with a legacy database).
Thanks in advance! ... and sorry for my English
Search the NEXT_DAY function it does exactly what you want
-
Hello
It's probably very basic, but I'm super new to SQL and I'm trying to understand this.
I have a table that has a bunch of files each with a column 'DAY' that has a date in the format DD/MM/YYYY.
What I want to be able to do, it of saying something to the effect of today + 1 is a Wednesday, show me every Wednesday. I intend to create a loop for it going then today + 2, 3 etc. today. The loop is not a problem, but convert the date day and then find all the corresponding days gives me a headache.
Hello
Roger has shown how to find the same day of the week as today:
WHERE TO_CHAR(DAY,'D') = TO_CHAR(SYSDATE,'D')
You asked the same day-of-the-week in the future, that would be
WHERE TO_CHAR (DAY, 'Day') = TO_CHAR (SYSDATE+ 1, 'Day')
No matter if the 2nd argument TO_CHAR is ', 'DY' or 'DAY', or how it is capitalized, but it must be exactly the same in the two calls to TO_CHAR.
For more information, search for TO_CHAR (datetime) in the manual of the SQL language.
4057bc8b-7016-4CBD-A9ac-3b98ed6b47be wrote:
Hello
It's probably very basic, but I'm super new to SQL and I'm trying to understand this.
I have a table that has a bunch of files each with a column 'DAY' that has a date in the format DD/MM/YYYY.
...
If you have a DATE column (which is the only reasonable way to store the date information), then it is not in a particular format, such as "JJ/MMYYYY. Maybe it's the format by default on your system, then what you're saying
SELECT issue_date FROM my_table;
It may appear automatically in August 4, 2014 ", but it is wrong to think that the data is in the format of table to which (or other)."
-
I want to know the difference between columns days and day 1
Hi all
I used this query:
SELECT to_char (return_date_time, ' DD/month/yyyy hh24:mi:ss') Test,
DECODE ('I', 'I', DECODE (1, NULL, NULL, 0, NULL, SYSDATE + 1)) days.
DECODE ('I', 'I', SYSDATE + 1) day 1
OF fm_curr_locn
WHERE patient_id = 'DU00002765. '
output:
Test Days Day 1 October 26, 2013 00:00:00 26 OCTOBER 13 26/10/2013-15:06:59 I want to know the difference between days and day column 1 column and why the days column did not show both
Please someone help...
Concerning
Nassik M
In which client tool (such as SQL * Plus, TOAD, SQL Developer, etc...) you run the query?
Could you please run the query in SQL * more and show us the exact result?
In some Client Tools, you have the privilege to set the DATE format, but should not be different level columnar.
I was wondering, how NLS_DATE format parameter can show different formats for different columns?
-
How to find the next date of the year and day as of today's date and the day
I have a question about date functions, that is to say: how to get one next year (date and day) like today are the date and the day this year?
You mean like this?
SQL > select to_char (add_months (sysdate, 12),' day DD/MM/YYYY ') twice;
TO_CHAR (ADD_MONTHS (S
--------------------
Friday, August 22, 2014 -
How to get the 'DAY' based on the territory of current account held a number between
Hi all
Looks like I'm at the end of my intelligence here but how to get the 'DAY' based on the territory of current account with a number between 1 and 7? Oracle has functions to extract the day of the week, but I can't find the other way around.
I need a way to know that the number '3' on the database with NLS_TERRITORY = AMERICA means a 'Tuesday' or the number '2' on a database with NLS_TERRITORY = GERMANY means "Tuesday" as well.SQL> select * from v$version; BANNER -------------------------------------------------------------------------------- Oracle Database 11g Release 11.2.0.3.0 - 64bit Production PL/SQL Release 11.2.0.3.0 - Production CORE 11.2.0.3.0 Production TNS for Linux: Version 11.2.0.3.0 - Production NLSRTL Version 11.2.0.3.0 - Production SQL> alter session set nls_territory=AMERICA; Session altered. SQL> select to_char (sysdate, 'D') from dual; T - 3 SQL> alter session set nls_territory=GERMANY; Session altered. SQL> select to_char (sysdate, 'D') from dual; T - 2
Hope I am clear enough.
And wish you all a happy new year :)
Kind regards
SmailUse the format "IW" to get the date of Monday and the format "DAY" to get the "first day of the week. Then compare dates to see if they are identical.
ALTER SESSION SET NLS_TERRITORY = 'AMERICA'; SELECT TRUNC(SYSDATE-LEVEL, 'IW') "Monday", TRUNC(SYSDATE-LEVEL, 'DAY') "NLS First day of week", MOD(TRUNC(SYSDATE-LEVEL, 'IW') - TRUNC(SYSDATE-LEVEL, 'DAY') + 7, 7) "1 if day 1 = SUN, 0 if MON" FROM DUAL CONNECT BY LEVEL <= 7; Monday NLS First day of week 1 if day 1 = SUN, 0 if MON --------- --------------------- -------------------------- 31-DEC-12 30-DEC-12 1 24-DEC-12 30-DEC-12 1 24-DEC-12 23-DEC-12 1 24-DEC-12 23-DEC-12 1 24-DEC-12 23-DEC-12 1 24-DEC-12 23-DEC-12 1 24-DEC-12 23-DEC-12 1 alter session set nls_territory = 'FRANCE'; SELECT TRUNC(SYSDATE-LEVEL, 'IW') "Monday", TRUNC(SYSDATE-LEVEL, 'DAY') "NLS First day of week", MOD(TRUNC(SYSDATE-LEVEL, 'IW') - TRUNC(SYSDATE-LEVEL, 'DAY') + 7, 7) "1 if day 1 = SUN, 0 if MON" FROM DUAL CONNECT BY LEVEL <= 7; Monday NLS First day of week 1 if day 1 = SUN, 0 if MON -------- --------------------- -------------------------- 31/12/12 31/12/12 0 24/12/12 24/12/12 0 24/12/12 24/12/12 0 24/12/12 24/12/12 0 24/12/12 24/12/12 0 24/12/12 24/12/12 0 24/12/12 24/12/12 0Or it could be simpler:
ALTER SESSION SET NLS_TERRITORY = 'AMERICA'; WITH DATA AS (SELECT LEVEL INPUT_DAY FROM DUAL CONNECT BY LEVEL <= 7) SELECT INPUT_DAY, TO_CHAR(TRUNC(SYSDATE, 'Day')+INPUT_DAY-1, 'DAY') "Day label" from data; INPUT_DAY Day label --------- ------------------------------------ 1 SUNDAY 2 MONDAY 3 TUESDAY 4 WEDNESDAY 5 THURSDAY 6 FRIDAY 7 SATURDAY alter session set nls_territory = 'FRANCE'; WITH DATA AS (SELECT LEVEL INPUT_DAY FROM DUAL CONNECT BY LEVEL <= 7) SELECT INPUT_DAY, TO_CHAR(TRUNC(SYSDATE, 'Day')+INPUT_DAY-1, 'DAY') "Day label" from data; INPUT_DAY Day label --------- ------------------------------------ 1 MONDAY 2 TUESDAY 3 WEDNESDAY 4 THURSDAY 5 FRIDAY 6 SATURDAY 7 SUNDAY -
Dear all seniors
Please help me in the following sql script
Select round ((sysdate-joining_date)/365,2)
of the members of
where emp_code = '470';
Result:
ROUND ((SYSDATE-JOINING_DATE)/365,2)
-----------------------------------
4.79
1 selected lines
--------------------------------------------------------------------
I want to divide only 79/7.
Please tell me how it will be resolved.Ghulam Yassen wrote:
Dear all seniors
Please help me in the following sql scriptSelect round ((sysdate-joining_date)/365,2)
of the members of
where emp_code = '470';Result:
ROUND ((SYSDATE-JOINING_DATE)/365,2)
-----------------------------------
4.791 selected lines
--------------------------------------------------------------------
I want to divide only 79/7.
Please tell me how it will be resolved.If you want only the calculation of the days
Try this,select TO_DATE (SYSDATE)- ADD_MONTHS (joining_date,TRUNC (MONTHS_BETWEEN (SYSDATE, joining_date)) ) DAYS from personnel where emp_code='470';also check How to get year, month, and date from the two date?
Hope this helps
-
Need to get Max Value day in a table with hourly data of SQL
I have a table "tmp" with these columns:
ID, date, time, value
I want to get the 'time' when 'value' max is reached in each 'day '.
the query:
"SELECT id, day, hour, max (value) from group tmp by id, date, time"
does not return the desired lines.
You have an idea to get what I want?Maybe this:
with tmp as ( select 1 id, trunc(sysdate) day, 10 hour, 100 value from dual union all select 2 id, trunc(sysdate) day, 11 hour, 110 value from dual union all select 3 id, trunc(sysdate) day, 12 hour, 120 value from dual union all select 4 id, trunc(sysdate) day, 13 hour, 130 value from dual union all select 5 id, trunc(sysdate-1) day, 10 hour, 100 value from dual union all select 6 id, trunc(sysdate-1) day, 11 hour, 90 value from dual union all select 7 id, trunc(sysdate-1) day, 12 hour, 150 value from dual union all select 8 id, trunc(sysdate-1) day, 13 hour, 100 value from dual ) Select ID, Day, Hour, Value From Tmp Where (Day, Value) IN ( Select Day, Max(Value) From Tmp Group by Day)Results:
ID DAY HOUR VALUE ---------- --------- ---------- ---------- 7 08-DEC-08 12 150 4 09-DEC-08 13 130 2 rows selected.Kind regards
Miguel -
function with dates to compare?
Hi all
in my test examples, which must extend, problem start by employees who start working
previous year (2014, 2013...) more months then sys - 10 month and day to start working more then 28 large
all other dates are working fine.
At this point I've seen like this:
SELECT SUM ((extrait (an (SYSDATE))-extract (year DATE_OF_BEGIN_WORK))) as the year.
SUM (abs (extract(month from SYSDATE)-extract(month from DATE_OF_BEGIN_WORK))) as month,
SUM (abs (extract(day from SYSDATE)-extract(day from DATE_OF_BEGIN_WORK))) as day, group employ_id employ_id table_a where active = 1
are there solutions for creating features that compare the dates in the table:
table_a have colum DATE_OF_BEGIN_WORK compare with sysdate
case 1:
months from the date of start to work > sysdate current months and days of the date to start work > current sysdate day and date of start working < sysdate year then
(extract (YEAR sysdate)-extract (YEAR DATE_OF_BEGIN_WORK));
(Excerpt extracted from (DATE_OF_BEGIN_WORK months) - (sysdate month));
(extract (DATE_OF_BEGIN_WORK days) - excerpt (sysdate days));
case 2:
months from the date of starting work < sysdate current months and the days of the date to start work < current sysdate day and date of start working < sysdate year then
(extract (YEAR sysdate)-extract (YEAR DATE_OF_BEGIN_WORK));
((sysdate sysdate months) extract - extract (DATE_OF_BEGIN_WORK month));
((sysdate day) extract - extract (DATE_OF_BEGIN_WORK days)) + 1;
case 3:
months from the date of start to work > sysdate current months and days of the date to start work > current sysdate day and date of start working < sysdate year then
(extract (YEAR sysdate)-extract (YEAR DATE_OF_BEGIN_WORK))-1;
((extract(month from DATE_OF_BEGIN_WORK)-12) - extract (DATE_OF_BEGIN_WORK month));
(extract (DATE_OF_BEGIN_WORK days) - EXTRACTED (LAST_DAY DATE (DATE_OF_BEGIN_WORK)) + extract (sysdate days)) + 1;
no idea how to solve this problem with the functions will be very useful
concerning
Gordan
It seems you are trying to re - invent most of date mathematics that Oracle has obtained already integrated into it. You'll just put in trouble, especially when there are leap years etc.
How about something like this?
SQL > with (id, dt) t (select 1, to_date('02/06/2010','MM/DD/YYYY') of all the double union)
2 Select 2, to_date('11/29/2001','MM/DD/YYYY') of all the double union
3 select 3, to_date('02/06/2011','MM/DD/YYYY') of all the double union
4. Select option 4, double to_date('10/10/2011','MM/DD/YYYY')
5 )
6 --
7. end of test data
8 --
9 select id, dt
10, floor (months_between(sysdate,dt)/12) years
11, floor (mod (months_between (sysdate, dt), 12)) months
12 - day be ambiguous because of the number of days in a different month
13. you could design your own algorithm to give the desired results, but it is a good approximation
14, floor (sysdate-(add_months (dt, floor (months_between (sysdate, dt))) as dys
15 t
16.
ID DT YEARS MONTHS DYS
---------- ----------- ---------- ---------- ----------
1-6 FEBRUARY 2010 5 8 22
2 29 NOVEMBER 2001 13 10 29
3-6 FEBRUARY 2011 4 8 22
4-10 OCTOBER 2011 4 0 184 selected lines.
-
Hello
I use Oracle 12 c, and I see in the dba_segments, somone using 9 GB of UNDO - TS. How can I check which user use this 9 GB or what process?
For the moment, I have no entry in the table of transactions $ v - so that the transaction is complete or crashed. I only see the usn number in the v$ rollname.
Thank you.
Rogeror TRY this one
SELECT 'Undo Segment name' r.NAME, dba_seg.size_mb,.
DECODE (TRUNC (SYSDATE - LOGON_TIME), 0, NULL, TRUNC (SYSDATE - LOGON_TIME) |) "Days" | ' + ') ||
TO_CHAR (TO_DATE (TRUNC (MOD(SYSDATE-LOGON_TIME,1) * 86400), 'SSSSS'), 'HH24:MI:SS') OPENING SESSION.
session v$. SID, v$ session. N ° of SERIES, p.SPID, v$ session.process.
session v$. USER name, v$ session. STATUS, v$ session. OSUSER, v$ session. MACHINE, session v$. PROGRAM, v$ session.module, action
V $ lock l, v$ process p, v$ rollname r, v$ session.
(SELECT nom_segment, ROUND (/(1024*1024) bytes, 2) size_mb FROM dba_segments WHERE segment_type = 'TYPE2 UNDO' ORDER BY DESC bytes) dba_seg
WHERE l.SID = p.pid (+) AND
session v$. SID = l.SID AND
TRUNC (l.id1 (+) / 65536) = r.usn AND
l.TYPE (+) = "TX" AND
l.lMode (+) = 6
AND r.NAME = dba_seg.segment_name
ORDER BY size_mb DESC;
-
Necessary emergency with a request: fill date of prior art on the column name
Hello
Can you please help me with the query. I would be grateful for your time and your help.
I have the query and the following output. Basically, the query selects a date, a table and counties received documents based on the current date, day-1, - 2 days-, 3 days-4 days-5 days and especially 5 days. It's the query I wrote. Now the requirement has slightly changed and described below.
Current query:
SELECT SUM (CASE WHEN TRUNC (SYSDATE) TRUNC ( )File_Date() = 0 PUIS 1 AUTRE 0 FIN) Zéro ,
SUM (CASE WHEN TRUNC (SYSDATE) TRUNC ( )File_Date() = 1 PUIS 1 AUTRE 0 FIN) One ,
SUM (CASE WHEN TRUNC (SYSDATE) TRUNC ( )File_Date() = 2 PUIS 1 AUTRE 0 FIN) Two ,
SUM (CASE WHEN TRUNC (SYSDATE) TRUNC ( )File_Date() = 3 ALORS 1 SINON 0 FIN) Trois ,
SUM (CASE WHEN TRUNC (SYSDATE) TRUNC ( )File_Date() = 4 PUIS 1 AUTRE 0 FIN) Quatre ,
SUM (BOX WHEN TRUNC (SYSDATE) TRUNC (File_Date) = 5 THEN 1 ELSE 0 END) Five ,
SUM (CASE WHEN TRUNC (SYSDATE) TRUNC ( )File_Date() > 5 PUIS 1 AUTRE 0 FIN) OverFive ,
COUNTY (*) Total
DE DOCUMENT_TABLE
OUTPUT:
Zero
One
Two
Three
Four
Five
More than five
Total
3
6
3
6
10
50
100
178
Now the desired output:
The column name must be the date, for example the column name, we're Sysdate, two column name is Sysdate-1 day and the result would look like:
OUTPUT:
17/12/2014
16/12/2014
15/12/2014
14/12/2014
13/12/2014
12/12/2014
More than five
Total
3
6
3
6
10
50
100
178
Hi, just try below as you say it's urgent
Select sysdate, sysdate-1, sysdate-2, sysdate-3,-4, etc of daul sysdate
Union
your query
(you must ensure for the same type of data)
are you using oracle report or just in the sql query. If the reports, then you can manage very easily with the introduction of a formula column.
-
Hello all;
I have a date picker I want to limit: of sysdate sysdate + 10 days. I tried to use this solution: Oracle & Apex Geekery: Dynamic Date Range in APEX Datepicker - no need to Plugin
but it did not work for me. I created two hidden and picker dates min max and created dynamic actions, but it does nothing. I don't know if I'm away from the steps. Please notify.
Thank you
Hi Haisai,.
If you try the following:
in your article in date picker under the section 'Settings' for 'Minimum Date' add + 0 d and for 'Maximum Date' add + 10 d
Hope this helps
Paul
-
problem with INTERVAL using the dynamic variable
Hi gurus
SQL > SELECT INTERVAL '1' DAY OF DOUBLE;
'1'-DAY INTERVAL
---------------------------------------------------------------------------
+ 01 00:00:00
SQL > SELECT INTERVAL '1' HOUR OF the DOUBLE;
'1' TIME INTERVAL
---------------------------------------------------------------------------
+ 00 01:00
JavaScript:void (0);
SQL > SELECT INTERVAL '1' MINUTE FROM DUAL;
'1' MINUTE INTERVAL
---------------------------------------------------------------------------
+ 00 00:01:00
I want to design an Interior that will contain three input parameters to make the above statement sql dynamic
can you please help with error code below.
QL > CREATE OR REPLACE PROCEDURE SP_INTERVAL (DAT TIMESTAMP, INTRVL VARCHAR2, VARCHAR2)
2 AS
3 TIMESTAMP V_OUT;
4 BEGIN
5
6
7 EXECUTE IMMEDIATELY "SELECT: 1 + INTERVAL"2"DOUBLE DAY ' IN V_OUT to the AID of DAT; "
DBMS_OUTPUT. Put_line (' Hi ' |) (DAT);
DBMS_OUTPUT. Put_line (' Hi ' |) (DAT);
END;
/ 8 9 10 11 12 13
Created procedure.
SQL > EXECUTE SP_INTERVAL(SYSDATE,'1','DAY');
Hi July 14, 14 01.15.21.000000 PM
Hi July 16, 14 01.15.21.000000 PM
PL/SQL procedure successfully completed.
SQL > CREATE OR REPLACE PROCEDURE SP_INTERVAL (DAT TIMESTAMP, INTRVL VARCHAR2, VARCHAR2)
AS
V_OUT TIMESTAMP;
BEGIN
EXECUTE IMMEDIATELY "SELECT: 1 + INTERVAL": 2 "DOUBLE DAY ' IN V_OUT to the AID of DAT, INTRVL;"
DBMS_OUTPUT. Put_line (' Hi ' |) (DAT);
DBMS_OUTPUT. Put_line (' Hi ' |) V_OUT);
END;
/ 2 3 4 5 6 7 8 9 10 11 12 13
Created procedure.
SQL > EXECUTE SP_INTERVAL(SYSDATE,'1','DAY');
BEGIN SP_INTERVAL(SYSDATE,'1','DAY'); END;
*
ERROR on line 1:
ORA-01867: the interval is invalid
ORA-06512: at "SP_INTERVAL", line 7
ORA-06512: at line 1
SQL >
Thank you
Hello
Maybe this can help you:
CREATE OR REPLACE PROCEDURE SP_INTERVAL (TIMESTAMP, INTRVL VARCHAR2, TERM DAT VARCHAR2)
AS
V_OUT TIMESTAMP;
BEGIN
RUN IMMEDIATELY "SELECT: 1 + INTERVAL"'| " INTRVL | " ' || TERM | 'FROM DUAL' IN V_OUT WITH THE HELP OF DAT;
DBMS_OUTPUT. Put_line ('Hi' |) (DAT);
DBMS_OUTPUT. Put_line ('Hi' |) V_OUT);
END;
/
concerning
Kay -
Up to THAT TIME in RMAN clause
DB version: 11.2
Quick question on up to THAT TIME in RMAN clause. The following command removes archivelogs over 2 days or archivelogs generated between now (Sydate) and the last 2 days?
delete noprompt archivelog until ' SYSDATE-2';
Hello
It will remove more than archiving logs sysdate-2 days.
UNTIL_TIME specifies a time as a limit superior, noninclusive
Ivica
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