Tabular form - stop some lines from being modified according to user

Similar Questions

• Adding line by submitting the manual tabular form while adding lines

  Hi all

  I'm a newbie in the Apex.

  I created a manual tabular form based on Apex_Collection. In addition, created the buttons ADD, DELETE and APPLY the CHANGES .

  The data below are the steps that I did.

  1 initialize the Collections

  Process: When loading - before header

  Enforcement process: once a Page visit

  Source:

  DECLARE
    l_collection_name APEX_COLLECTIONS.COLLECTION_NAME%TYPE;
    l_bind_names      APEX_APPLICATION_GLOBAL.VC_ARR2;
    l_bind_values     APEX_APPLICATION_GLOBAL.VC_ARR2;
    l_query           VARCHAR2(32767);
  BEGIN
    l_collection_name := 'EMAILDETAILS';
  
    IF apex_collection.collection_exists(l_collection_name)
    THEN
    apex_collection.delete_collection(p_collection_name => l_collection_name);
    END IF;
  
    l_query := '   SELECT cmp_cd, ' --c001 => f01
    || '   email, ' --c002 => f02
    || '   tab_seq_id, '  --c003 => f03
    || '   NULL, ' --c004 => f04
    || '   NULL, ' --c005 => f05
    || '   NULL, ' --c006 => f06
    || '   NULL, ' --c007 => f07
    || '   NULL, ' --c008 => f08
    || '   NULL, ' --c009 => f09
    || '   NULL, ' --c010 => f10
    || '   NULL, ' --c011 => f11
    || '   NULL, ' --c012 => f12
    || '   NULL, ' --c013 => f13
    || '   NULL, ' --c014 => f14
    || '   NULL, ' --c015 => f15
    || '   NULL, ' --c016 => f16
    || '   NULL, ' --c017 => f17
    || '   NULL, ' --c018 => f18
    || '   NULL, ' --c019 => f19
    || '   NULL, ' --c020 => f20
    || '   NULL, ' --c021 => f21
    || '   NULL, ' --c022 => f22
    || '   NULL, ' --c023 => f23
    || '   NULL, ' --c024 => f24
    || '   NULL, ' --c025 => f25
    || '   NULL, ' --c026 => f26
    || '   NULL, ' --c027 => f27
    || '   NULL, ' --c028 => f28
    || '   NULL, ' --c029 => f29
    || '   NULL, ' --c030 => f30
    || '   NULL, ' --c031 => f31
    || '   NULL, ' --c032 => f32
    || '   NULL, ' --c033 => f33
    || '   NULL, ' --c034 => f34
    || '   NULL, ' --c035 => f35
    || '   NULL, ' --c036 => f36
    || '   NULL, ' --c037 => f37
    || '   NULL, ' --c038 => f38
    || '   NULL, ' --c039 => f39
    || '   NULL, ' --c040 => f40
    || '   NULL, ' --c041 => f41
    || '   NULL, ' --c042 => f42
    || '   NULL, ' --c043 => f43
    || '   NULL, ' --c044 => f44
    || '   NULL, ' --c045 => f45
    || '   NULL, ' --c046 => f46
    || '   ''O'', ' --c047 (for record status)
    || '   wwv_flow_item.md5(cmp_cd, email, tab_seq_id) ' --c048 (for optimistic locking)
    --c049 for (not used in collection/reserevered for seq_id array)
    --c050 (not used in collection/reservered for delete checkbox array)
    || ' FROM Cmp_Email '
    || ' WHERE cmp_cd= v(''P9_CMP_CD'') ';
  
    apex_collection.create_collection_from_query_b (
    p_collection_name => l_collection_name,
    p_query           => l_query
    );
  
  
    IF :REQUEST = 'ADD'
    THEN
    APEX_COLLECTION.ADD_MEMBER(p_collection_name => l_collection_name);
    END IF;
  
  END;
  

  2. tabular Guide

  Type: SQL query

  Source:

  SELECT apex_item.hidden(4,c047,NULL,'f04_'|| '#ROWNUM#')
    || apex_item.hidden(5,c048,NULL,'f05_'|| '#ROWNUM#')
    || apex_item.hidden(6,seq_id,NULL,'f06_'|| '#ROWNUM#')
    || apex_item.hidden(3,c003,NULL,'f03_'|| '#ROWNUM#')
    || apex_item.hidden(1,c001,NULL,'f01_'|| '#ROWNUM#')
    || apex_item.checkbox(
    7, 
    seq_id,
    NULL,
    CASE 
    WHEN c047 = 'D' THEN seq_id
    END,
    ':',
    'f07_' || '#ROWNUM#'
    ) AS delete_checkbox,
    apex_item.text(
    2,
    c002,
    20,
    50,
    NULL,
    'f02_' || '#ROWNUM#'
    ) AS email_id
  FROM apex_collections
  WHERE collection_name ='EMAILDETAILS'
  ORDER BY c002
  

  The buttons used:

  1. name button: ADD

  Action: send the Page

  2 button name: DELETE

  Action: send the Page

  3 Collection page

  Point process: present now - before the calculations and Validations

  Enforcement process: once a Page visit

  Source:

  DECLARE
  
  
    l_collection_name APEX_COLLECTIONS.COLLECTION_NAME%TYPE;
    l_original_md5    VARCHAR2(32);
    l_latest_md5      VARCHAR2(32);
  
  BEGIN
  
    l_collection_name := 'EMAILDETAILS';
  
    FOR x IN 1 .. apex_application.g_f06.count 
    LOOP         
    IF apex_application.g_f01(x) IS NOT NULL --ID exists, check to see if record was updated
    THEN
    SELECT c048 INTO l_original_md5
    FROM apex_collections
    WHERE collection_name = l_collection_name
    AND seq_id = apex_application.g_f06(x);
  
    l_latest_md5 := wwv_flow_item.md5(
    apex_application.g_f01(x),
    apex_application.g_f02(x),
    apex_application.g_f03(x)
    );
  
    IF l_original_md5 != l_latest_md5 
    THEN
    apex_collection.update_member(
    p_collection_name => l_collection_name,
    p_seq             => apex_application.g_f06(x),
    p_c001            => apex_application.g_f01(x),
    p_c002            => apex_application.g_f02(x),
    p_c003            => apex_application.g_f03(x),
    p_c047            => 'U',
    p_c048            => apex_application.g_f05(x)
    );
    END IF;
    ELSE --ID does not exist, must be new record
    apex_collection.update_member(
    p_collection_name => l_collection_name,
    p_seq             => apex_application.g_f06(x),
    p_c001            => apex_application.g_f01(x),
    p_c002            => apex_application.g_f02(x),
    p_c003            => apex_application.g_f03(x),
    p_c047            => 'N',
    p_c048            => apex_application.g_f05(x)
    );
    END IF;
    END LOOP;
  
    IF :REQUEST = 'DELETE' 
    THEN
    FOR x IN 1 .. apex_application.g_f07.count 
    LOOP
    apex_collection.update_member_attribute(
    p_collection_name => l_collection_name, 
    p_seq             => apex_application.g_f07(x), 
    p_attr_number     => '47', 
    p_attr_value      => 'D'
    );
    END LOOP;
    END IF;
     
  END;
  

  4. table collection

  Point process: submit now - after calculations and Validations

  Enforcement process: once a Page visit

  Source:

  DECLARE
    l_table_md5       VARCHAR2(32);
    l_collection_name APEX_COLLECTIONS.COLLECTION_NAME%TYPE;
    l_del_count       PLS_INTEGER := 0;
    l_upd_count       PLS_INTEGER := 0;
    l_ins_count       PLS_INTEGER := 0;
    l_success_message VARCHAR2(32767);
     
    CURSOR op_lock_check_cur (p_id IN NUMBER)
    IS
    SELECT wwv_flow_item.md5(cmp_cd, email, tab_seq_id)
    FROM Cmp_Email
    WHERE tab_seq_id = op_lock_check_cur.p_id
    FOR UPDATE;
  BEGIN
    l_collection_name := 'EMAILDETAILS';
  
  
    FOR x IN (
    SELECT *
    FROM apex_collections
    WHERE collection_name = l_collection_name
    AND c047 IN ('N','U','D')) 
    LOOP
    IF x.c047 = 'N'
    THEN
    INSERT INTO Cmp_Email(tab_seq_id,cmp_cd,email) 
    VALUES (cmp_email_seq.nextval,
    :P5_CMP_CD_HIDN, 
    x.c002
    );
  
    l_ins_count := l_ins_count + 1;
    ELSIF x.c047 = 'U'
    THEN
    OPEN op_lock_check_cur(x.c003);
    FETCH op_lock_check_cur INTO l_table_md5;
  
  
    IF l_table_md5 != x.c048 
    THEN
    raise_application_error(-20001,'Current version of data in database has changed since user initiated update process.');
    END IF;
  
    UPDATE Cmp_Email
    SET cmp_cd=:P5_CMP_CD_HIDN
    ,email = x.c002
    WHERE CURRENT OF op_lock_check_cur;
  
    CLOSE op_lock_check_cur;
  
    l_upd_count := l_upd_count + 1;
    ELSIF x.c047 = 'D'
    THEN
    DELETE FROM Cmp_Email
    WHERE tab_seq_id = x.c003;
  
    l_del_count := l_del_count + 1;
    END IF;
    END LOOP;
     
    apex_collection.delete_collection(p_collection_name => l_collection_name);
     
    l_success_message :=  
    l_ins_count || ' rows inserted, ' ||
    l_upd_count || ' rows updated, ' ||
    l_del_count || ' rows deleted';
  
    :P5_SUCCESS_MESSAGE:= l_success_message;
     
  END;
  

  When I press the ADD button, a new line must be added to the shape of the table and the data should be saved to the collection. , But currently, the page is being submitted to the database table when adding new lines in the form of tables. The data should only be saved in the database when the user clicks on the APPLY CHANGES button

  I searched the Forum about this issue and have found many discussions which suggested to use JavaScript to add new lines. As I have no knowledge of JavaScript, these solutions have been strange for me.

  Please help me solve this problem.

  Thanks in advance.

  Kind regards

  Aravind

  Hi Christophe,

  Follow the changes mentioned below

  1. remove this your Collections initialize

  IF :REQUEST = 'ADD'
  THEN
    APEX_COLLECTION.ADD_MEMBER(p_collection_name => l_collection_name);
  END IF;  
  

  2 condition your collection process initialize

  Modify your process-> conditions-> PLSQL Expressions->: REQUEST IS NULL

  3. create a process more onload I say Add new line to the collection

  DECLARE
      l_collection_name APEX_COLLECTIONS.COLLECTION_NAME%TYPE;
     BEGIN
        l_collection_name := 'EMAILDETAILS';
       IF apex_collection.collection_exists(l_collection_name)
        THEN
            APEX_COLLECTION.ADD_MEMBER(p_collection_name => l_collection_name);
            END IF;
     END;
  

  4 condition your Add new line to the collection

  Modify your process-> conditions-> request = Expression1-> ADD (this should be request ADD button)

  5. change your button-> Action addition-> redirect to this application page :-> page no (same page)->-> ADD APPLICATION

  6. check your through the process conditional Page collection

  Modify your process-> conditions-> PLSQL Expressions->: ASK IN ('ADD', 'APPLY_CHANGES', 'DELETE')

  7. check your subject to the process of Collection to Table under condition

  Modify your process-> conditions-> PLSQL Expressions->: ASK IN ('APPLY_CHANGES')

  8. for the whole process to remove the conditions when the button is pressed.

  If the problems persists, create a sample on apex.oracle.com and share the connection information with the name of workspace.

  Hope this helps you,

  Kind regards

  Jitendra

• Request Express 5.0.0.00.31/Tabular form/number of lines

  Hello

  I would like to ask how to configure the number of lines displayed per page.

  I did the below and also I tried to re-charge/reload, but impossible to get what I want.

  Implement a tabular form

  Set the presentation attributes of the State and the paging number of rows 50

  Registered and run this page, it shows still 15 ranks in this page.

  A I missed something? Or as a table don't allow no more than 15 lines be shown on 1 page?

  Thank you.

  Hello

  Pagination settings are cached for the duration of the session. This change is visible immediately, close the session, restart the brower and connect again or manually re - request the page from the browser's address bar, adding the ClearCache position 'RP' in the URL.

  Do not set anything in number of lines (point). This is used to identify an element of the page containing the number of lines to allow users to control this

  (Note: If you think it answers your question, please mark it as correct answer.) This will help other users in the community)

  Thank you

  Benhamdia

• Tabular form when adding line error

  I click on the 'Add' button to add a row to the table OCA_OTHER_AGENCIES, I get the following error:
  
  Internal error in the routine mru: ORA-20001: error in MRU: line = 1, ORA-01400: cannot insert NULL into ('CONFIRM'. "" "" OCA_OTHER_AGENCIES '. "" OA_ID"), insert"CONFIRM ". "" OCA_OTHER_AGENCIES values ' ('OA_FIRM_ID', 'OA_ID', 'The AGENCY', 'PROGRAM', 'STATUS', 'AGENCY_DATE', 'DBE_ON_SITE_VISIT', 'DBE_ON_SITE_VISIT_DATE', "DBE_ON_SITE_VISIT_STATE") (: b1,: b2,: b3: b4,: b5,: b6,: b7,: b8,: b9)
  
  OA_ID is the primary key and is defined in the table as presentation:
  display as: HIDDEN
  default type: PL/SQL Expression or a function
  default: oca_pkg.get_next_key ('OA')
  
  the get_next_key function returns the following sequence as follows:
  Function get_next_key (p_key in varchar2) return number is
  number of v_seq_no;
  Start
  If (p_key)
  When ("OA") and then select OCA_OA_SEQ.nextval in the double v_seq_no;
  When ('FARM') and then select OCA_FIRMS_SEQ.nextval in the double v_seq_no;
  Another null.
  end case;
  return (v_seq_no);
  end;
  
  In debug mode: append query appears as:
  0.08: Add line query: select 'FIND$ 01' "CHECK$ 01", 'OA_FIRM_ID' 'OA_FIRM_ID' 'OA_ID' 'OA_ID' 'OA_FIRM_ID_DISPLAY' 'OA_FIRM_ID_DISPLAY', 'OA_ID_DISPLAY', 'OA_ID_DISPLAY', 'AGENCY' "', 'PROGRAMME', 'PROGRAMME', 'STATUS', 'STATUS', 'AGENCY_DATE' 'AGENCY_DATE' 'DBE_ON_SITE_VISIT' 'DBE_ON_SITE_VISIT' 'DBE_ON_SITE_VISIT_DATE' 'DBE_ON_SITE_VISIT_DATE' 'DBE_ON_SITE_VISIT_STATE' 'DBE_ON_SITE_VISIT_STATE' of (select NULL" RECORD$ 01 "'). , 'OA_FIRM_ID' 'OA_FIRM_ID' 'OA_ID' 'OA_ID' 'OA_FIRM_ID_DISPLAY' 'OA_FIRM_ID_DISPLAY', 'OA_ID_DISPLAY', 'OA_ID_DISPLAY', 'AGENCY' "', 'PROGRAMME', 'PROGRAMME', 'STATUS', 'STATUS', 'AGENCY_DATE' 'AGENCY_DATE' 'DBE_ON_SITE_VISIT' 'DBE_ON_SITE_VISIT' 'DBE_ON_SITE_VISIT_DATE' 'DBE_ON_SITE_VISIT_DATE' 'DBE_ON_SITE_VISIT_STATE' 'DBE_ON_SITE_VISIT_STATE' from (select 'OA_FIRM_ID' , 'OA_ID', 'OA_FIRM_ID' OA_FIRM_ID_DISPLAY, OA_ID_DISPLAY 'OA_ID', 'AGENCY', 'PROGRAM', 'STATUS', 'AGENCY_DATE', 'DBE_ON_SITE_VISIT', 'DBE_ON_SITE_VISIT_DATE', ' DBE_ON_SITE_VISIT_STATE ' to "CONFIRM'." " ((OCA_OTHER_AGENCIES' where oa_firm_id =: F103_FIRM_ID UNION ALL SELECT NULL, NULL, NULL, NULL, NULL, NULL, NULL, NULL, NULL, NULL, NULL FROM DUAL WHERE: request = 'ADD_ROWS' or: application is NULL to CONNECT BY LEVEL < = 1)) Union all select NULL 'CHECK' $ 01, NULL, 'OA_FIRM_ID', oca_pkg.get_next_key ('OA') 'OA_ID', NULL, 'OA_FIRM_ID_DISPLAY '. NULL, NULL, 'OA_ID_DISPLAY', NULL, 'AGENCY', 'PROGRAM', NULL, 'STATUS', NULL, 'AGENCY_DATE', NULL, 'DBE_ON_SITE_VISIT', 'DBE_ON_SITE_VISIT_DATE', 'DBE_ON_SITE_VISIT_STATE' of the double NULL NULL
  
  
  Can someone please.

  Why you doing this in the form and not by a trigger?

  Denes Kubicek
  ------------------------------------------------------------------------------
  http://deneskubicek.blogspot.com/
  http://www.Opal-consulting.de/training
  http://Apex.Oracle.com/pls/OTN/f?p=31517:1
  ------------------------------------------------------------------------------

• A .as file will stop a .swf from being linked?

  I have a simple movie that has essentially the AS3 code for the two buttons.
  
  A single button (named videopage_btn) links to another file .swf perfectly.
  
  The other button (named thumbnailgallery1_btn) is not related to another .swf file. It gives me an error (TypeError: Error #1009: null) when you use the same code (attached).
  
  In the folder of my project, I have this .swf file and the other .swf file, which has a .as file to go with it.
  
  When I opened the other single thumbnailgallery1.swf file (without the other file simple.swf button), it compiles properly. However, when I try to use the button, I get the error 1009.
  
  Can I use a different code to open the thumbnailgallery1.swf of the thumbnailgallery1_btn?
  
  Yours Sincerely,
  
  Jntspecialty
  
  
  

  that must be something lost in translation because I do not understand this error message. in all cases, you will need to debug this class file.

• How to prevent from being changed by the user or: SliderDouble ranges

  Hello

  I have a slider in WPF / c#

  <>liderDouble height = "60" Name = 'updateRate"ValueChanged ="OnUpdateRateValueChanged"range ="0.05,1"Value ="0.05"/ >

  When the application runs in user can change min or max value of the range by clicking on the lable of ticks and changing the value.

  Need a way to prevent/protect, make unmodifiable.

  Thank you

  Yuri

  Range scale of editing is controlled by the InteractionMode property to the cursor. To turn off the EditRange , you can assign a different set of indicator values, such as InteractionMode="ArrowKeys,Drag,Snap,ScrollWheel" .

• Insert/update of the lines in tabular form from one table to another table

  Hello
  
  I'm having a tabular presentation for a table (equip_test) with 2 columns (equip_id, equip_name). I create a new
  
  Button (submit_alt) in this tabular form. I need to insert or update lines that are changed in this table to form
  
  another table (equip_staging) when you press the submit_alt button. How can I do this? How can I identify which lines are
  
  Insert or update? The process of the page I am trying since this button is
  

  begin
  
  FOR i in 1..APEX_APPLICATION.G_F01.count
  
  LOOP
  insert into equip_staging values(APEX_APPLICATION.G_F02(i),APEX_APPLICATION.G_F03(i));
  END LOOP;
  
  end;

  But it does not work. Help, please
  
  Thank you
  
  TJ

  Unchecking (does not) the column is a problem. Use this SQL instead (which is included in my examples):

  SELECT empno,
            empno
         || apex_item.hidden (33, wwv_flow_item.md5 (ename, sal, job))
                                                                  empno_display,
         ename, sal, job
    FROM emp
  

  and join this column hidden from your display column. In this way, it should work. When you feel there is no data found message in the treatment in a table, it will mean that the id does not exist.

  Denes Kubicek
  ------------------------------------------------------------------------------
  http://deneskubicek.blogspot.com/
  http://www.Opal-consulting.de/training
  http://Apex.Oracle.com/pls/OTN/f?p=31517:1
  ------------------------------------------------------------------------------

• Added new line at the top of tabular form in APEX 5.0 and universal theme (topic 42)

  Hello Apex Experts,

  When the user clicks on the button 'Add Row' a tabular presentation, I would like the new line to be at the top of the report rather than the bottom.

  
  

  I followed the instructions from Added new line at the top of table in APEX 4.0 form and Denes Kubicek demo application. But it does nothing, always create new bottom line.

  
  

  Anyone have an idea or an idea?

  
  

  Your help would be appreciated.

  
  

  Kind regards

  Blabla
  

  Hi all

  This problem is now solved by following the new blogpost of Dene:

  http://www.deneskubicek.blogspot.de/2015/05/tabular-form-add-rows-top-universal.html

  Kind regards

  Blabla

• Add several lines in tabular form which object to list different shows to all rows

  Hello

  Apex 4.2, oracle 11 g 2

  I have a table on the emp table where when I click on Add button line

  then I get no lines that are stored in the string.

  for this element of the page creation PX_job that return the value of separate employment with two points separate values by the

  for example seller: Analyst: Clerk: Manager: President

  to add several lines to add lines.

  by using the dynamic action

  event: click on

  selection type: button

  Action: run javascript code

  as follows

  var a = $v("PX_job").split(":") // Delimiter is a string
  for (var i = 0; i < a.length; i++)
  {
  
  apex.widget.tabular.addRow();
  
  }
  
  

  This work that well it adds the number ranks equal to 5

  now I'm post job as select list

  now I want to display the list of work in form of tables as row 1 poster list entry, second row entry list second poster... last line shows last entry from list

  but working this column in all the rows by first writing list of projects in the work list

  How to solve this problem.

  Leave.

  Hi, go,

  Yes, you need to replace "myvalue" with the return value of the select list. But even in this case it would be a problem because it would change all the lines.

  In any case, I changed the code to do this:

  apex.widget.tabular.addRow (); Add the line

  var checkboxIndex is apex.jQuery('input[name=f01][value=0]').eq (i) .parent () .parent () .index ();. get the number of the line that was added

  var SelectItem = apex.jQuery('select[name=f04]').eq (checkboxIndex); Use this number to get the selection list

  iOption var = apex.jQuery (SelectItem) .children () .eq (i) .val (); Get the i option value

  apex.jQuery (SelectItem) .val (iOption); Set the value of the option

  I hope it's clear.

  Kind regards

  Joni

• Adding empty lines to tabular form on page load

  Hello
  I use APEX 4.1.1 on 11gXE and Windows Vista.
  
  I created a tabular form on a page. When the page loads I want the::AddRow() to call x number of times where x is the value returned by a list of selection (from 1 to 10) on another page. If the value 3 is selected::AddRow() is called 3 times. This is similar to the example of Denes Kubicek, but I am interested in the use of a dynamic action instead. Here is the link to Dene
  
  http://Apex.Oracle.com/pls/OTN/f?p=31517:209
  
  I created a dynamic action that fires when the page loads and runs the following code:
  
  var i = 0, z = $v ('P1_NO_ITEMS');
  
  While (I < z)
  {
  ::AddRow();
  i ++ ;
  }
  
  When I put P1_NO_ITEMS 3 and go to the tabular presentation page, it loads but does not add 3 empty lines in the form. I tried hard coding a value into the javascript code and that works very well. for example
  
  var i = 0, z = 3;
  
  When I add an alert in the code the value of P1_NO_ITEMS seems to be undefined, and I get a white for its value. If I check the session state P1_NO_ITEMS has the value 3.
  
  Any ideas where I'm wrong? I have a feeling that it is something simple...
  Thank you very much
  Helen

  Hi Helen
  >
  I use APEX 4.1.1 on 11gXE and Windows Vista.

  I created a tabular form on a page. When the page loads I want the::AddRow() to call x number of times where x is the value returned by a list of selection (from 1 to 10) on another page. If the value 3 is selected::AddRow() is called 3 times. This is similar to the example of Denes Kubicek, but I am interested in the use of a dynamic action instead. Here is the link to Dene

  http://Apex.Oracle.com/pls/OTN/f?p=31517:209

  I created a dynamic action that fires when the page loads and runs the following code:

  var i = 0, z = $v ('P1_NO_ITEMS');
  >
  JavaScript works only on elements in the HTML DOM. Once you have navigated away Page 1 the P1_NO_ITEMS not available in JavaScript.
  >
  While (i<>
  {
  ::AddRow();
  i ++ ;
  }

  When I put P1_NO_ITEMS 3 and go to the tabular presentation page, it loads but does not add 3 empty lines in the form. I tried hard coding a value into the javascript code and that works very well. for example

  var i = 0, z = 3;

  When I add an alert in the code the value of P1_NO_ITEMS seems to be undefined, and I get a white for its value. If I check the session state P1_NO_ITEMS has the value 3.

  Any ideas where I'm wrong? I have a feeling that it is something simple... >

  Change

  z=$v('P1_NO_ITEMS');
  

  TO

  z='&P1_NO_ITEMS.';
  

  See you soon,.

• How to add a new line at the top of manual tabular form

  I have a manual tabular form. I am trying to add a line at the top of the form, instead of the new line of being displayed at the bottom. any ideas are appreciated.
  
  Thank you
  Surya

  If you did a manual tabular presentation using a select statement as follows:
  Choose option...

  
  Union of all the
  Select... of double

  Try to simply reverse the two select:
  Select... of double
  Union of all the
  Choose option...

  I did this in an application, and it works.
  (I've never tried with sorting...)
  Concerning
  Stefano Corradi

• I deleted some photos from my iPhone 6 but I noticed that it was also deleted out of my IMac. How can I stop this

  I deleted some photos from my iPhone 6 but I noticed that it was also deleted out of my IMac. How can I stop this

  If you use iCloud photo library all the photos you delete a device will be deleted to iCloud and all other devices that are connected to this library to iCloud. The iCloud design library should synchronize all changes, including deletions, to all devices. You can reduce the storage space required on your phone by selecting settings > iCloud > Photos > optimize iPhone storage.

• line tabular form selector ignores the Tab key, how?

  Hello world

  We have Oracle 11.2 and Apex 4.2.6.

  Tabular form a selector of line, trying to prevent cleat key home, for item in normal form, I would use just something like tabindex =-1, but I don't know how I can add this tab index for the line selector, whose property is 'Download' BLOB. If I inspect element, it is a checkbox:

  < input type = "checkbox" name = "f01" value = "1" class = 'row selector' id = 'f01_0001' entered AutoComplete = "off" >

  How can I add tabindex = "-1" inside this entry line selector type?

  Any suggestions are greatly appreciated.

  $(':checkbox').attr ("tabindex", - 1).

  However, it would be preferable to add a static region id to your region and your prefix selector

  $('#p1_my_region_:checkbox').attr ("tabindex", - 1).

• How to stop records in doubles before the Save as tabular form Oracle/Developer

  Dear friends

  I want to stop duplicate records to save in tabular form of oracle developer.

  For example

  I have a tabular form and there are three fields.

  Vendor_id Item_id Qty.

  1                  37630         1

  1                  37630         4

  Above in double item_id should not be saved.

  Help, please

  Concerning

  Why not make a unique constraint on the database?

  Kind regards

  Zlatko

• Add button of tabular form a line can open several rows?

  Hello

  I use apex 4.2

  I create tree on page when when I click on any node tabular presentation open and display reports record.

  Now, I want, in my article a tabular presentation contain a selection list

  My requirement is when I click on any node tabular form open the no. lines on the no equals. entries in the respective selection of each tree node list.

  Is it possible?

  Help appretiate.

  Thank you

  GO

  Go

  I've created a demo by adding several lines slot table using dynamic action form.

  Select the number of rows in the selection list and click the button "Add line".

  See the information on the page for what I've done.

  Nicolette