The search sort the list

I'm writing a method that searches a list sorted using compareTo() instead of equals(), as follows:
public static <T extends Comparable<T>> T find(final T instance, final List<T> list) {

   T result = null;
   for (final T entry : list) {
      final int comparison = entry.compareTo(instance);
     if (comparison < 0) {
        continue;
        }
        if (comparison > 0) {
           break;
        }
     result = entry;
     break;
   }
   return result;
}
I have two classes, A & B:
Class A implements Comparable<A>
...
Class B extends A
I don't understand why it does not compile:
List<B> list;
B item;
...
final B result = find(item, list);
The error message reads as follows:
Bound mismatch: The generic method find(T, List<T>) ... is not applicable for the arguments (B, List<B>).
The inferred type B is not a valid substitute for the bounded parameter <T extends Comparable<T>>
Is this just a mistake of syntax on my part, or is not possible to do what I'm looking for? Or is there a standard collection class that is already? I watched Collections.binarySearch (), but I need to use compareTo() instead of equals() to determine a match.

Looks like you write a linear search of the Collections.binarySearch version.
[HTTP://DOWNLOAD.ORACLE.COM/JAVASE/6/DOCS/API/JAVA/UTIL/COLLECTIONS.HTML#BINARYSEARCH%28JAVA.UTIL.LIST, 20 T 29%]
You will notice that it has been declared

public static  int binarySearch(List> list, T key)

Tags: Java

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