The secondary price list price list

Hello

I have the following query returns the order customer, transaction quantity, part number, number of sales, and RMA number we had.

I'm also trying to get the sale price of the ordering customer.  I can return the price list that shows as a price to zero.  After investigation, I found that the price of the item is in the list of secondary prize for the price list that I managed to return.

Please can someone explain how I can show all lists of secondary prize under a primary price list?

SELECT oha.order_number

ol.line_number

msib.segment1

sum (mtt.transaction_quantity) AS TXN_QTY

mtt.transaction_date

TT. DESCRIPTION

oha.sold_to_org_id

csua.location AS SHIP_TO

hp.party_name AS CUSTOMER

htl.name AS PRICE_LIST

Of oe_order_headers_all Aho

oe_order_lines_all ol

mtl_material_transactions mtt

mtl_transaction_types tt

mtl_system_items_b msib

hz_cust_site_uses_all ACUS

ca hz_cust_accounts

hz_parties hp

qp. QP_LIST_HEADERS_TL htl

WHERE 1 = 1

AND htl.list_header_id = oha.price_list_id

AND hp.party_id = ca.party_id

AND ca.cust_account_id = oha.sold_to_org_id

AND csua.site_use_id = oha.ship_to_org_id

AND oha.header_id = ol.header_id

AND ol.line_id = mtt.trx_source_line_id

AND mtt.transaction_type_id = tt.transaction_type_id

AND mtt.transaction_type_id IN (33,15)

AND msib.inventory_item_id = mtt.inventory_item_id

and msib.organization_id = mtt.organization_id

and mtt.transaction_date > (sysdate - 36)

and msib.organization_id = 26

and msib.segment1 = 'C57M70N3GB. '

Oha.order_number group

ol.line_number

msib.segment1

mtt.transaction_date

TT. DESCRIPTION

oha.sold_to_org_id

csua.location

hp.party_name

htl.name

Any help would be great.

Thank you

Chris

SELECT distinct htl1.name, htl2.name

-QP_LIST_HEADERS_B hb

He's QP_LIST_LINES

QP_LIST_HEADERS_TL htl1

QP_LIST_HEADERS_TL htl2

QP_SECONDARY_PRICE_LISTS_V lv

WHERE 1 = 1

- AND HB. LIST_HEADER_ID = HE'S. LIST_HEADER_ID

- and HB. LIST_HEADER_ID = HTL. LIST_HEADER_ID

and HTL1. LIST_HEADER_ID = HE'S. LIST_HEADER_ID

- and htl.name = "price list of NEFFUK.

AND htl1.list_header_id = 6133

AND lv.parent_price_list_id = htl1.list_header_id

and htl2.list_header_id = lv.list_header_id

Tags: Oracle Applications

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