Time of start and end elements
Hey there,I have an application where I need two elements of time. I can hard code the data once and use a Select list, but this link below by Daniel McGhan is the way to go. Does anyone know how to access this code for the start and end time the elements? The article does not list how this is possible, but I can have over looked something... not sure. Thank you for reading this Thread.
http://apex.shellprompt.net/pls/apex/f?p=566:4:198609458994020::NO:::
Hello:
Now sure to know how this was done, but it seems as likely javascript.
There is a very cool JQuery Timepicker that I really like and in fact for a really nice interface:
http://Haineault.com/Media/jQuery/UI-timepickr/page/
Kind regards
Bruce
Tags: Database
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==============================================================
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Thread: 3
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Complete thread: main thread.
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Wire termination: 3
Complete thread: 2
BUILD successful (total time: 2 seconds)
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Thread: 2
Thread: 3
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Thread: 2
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Wire termination: 3
Wire termination: 4
Complete thread: 2
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BUILD successful (total time: 2 seconds)user13476736 wrote:
You can specify the reason please? See you soon.It's pretty simple. Start-up and execution of threads are not an operation of determenistic on operating systems that do not support hard real-time requirements. (Most operating systems do not support hard real-time requirements)
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Need your help to solve a SQL query
My data like this look
year of CID rid
52 1000 2001 1
52 1000 2002 1
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52 1000 2004 6
52 1000 2005 6
52 1000 2007 1
52 1001 2003 1
52 1001 2004 1
52 1001 2005 1
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52 1000 2001 - 2002 1
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-----------
Here's the script for the table and data
create table T)
CID NUMBER,
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Insert into t (cid, RID, start_year, title) values (52, 1000, 2002, 1).
Insert into t (cid, RID, start_year, title) values (52, 1001, 2003, 1);
Insert into t (cid, RID, start_year, title) values (52, 1000, 2003, 6);
Insert into t (cid, RID, start_year, title) values (52, 1001, 2004, 1);
Insert into t (cid, RID, start_year, title) values (52, 1000, 2004, 6);
Insert into t (cid, RID, start_year, title) values (52, 1001, 2005, 1).
Insert into t (cid, RID, start_year, title) values (52, 1000, 2005, 6);
Insert into t (cid, RID, start_year, title) values (52, 1001, 2006, 3);
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commit;
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Select the title, max (year1), min (year2), cid, RID
de)
Select tc.cid, tc.rid, tc.title, tc.start_year year1, year2, tp.start_year, decode (tc.title, tp.title, 'n', 'Y') gap
t tc,.
t tp
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and tc.rid = tp.rid
)
Cid group, RID, title, gap
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Ngoyi,
Houston-TexasHi, Ngoyi,
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Thanks for posting the CREATE TABLE and INSERT statements; It is very useful.
Still, it would be more useful if the sample data and the results don't always have the same value in a column. I'm just guessing at what cid and get rid of play in this problem.
Also, thanks for posting your request. It helps to understand the problem.For an explanation of the technique of Difference sets used in the above query, see {message: id = 9953384} and/or {message: id = 9956917}
Published by: Frank Kulash, March 23, 2012 13:34
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Table: MG_AUTH_AGNT
-----
ID
MGATH_clnt
MGATH_beg_DT
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MGATH_STAT
MGATH_TYP
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-----
I need to find records containing dates that overlap.
Examples of data
-----
If the customer has two records with the same MGATH_SERV_GRP, MGATH_STAT, MGATH_TYP and start and end dates of the first disc are 01/JAN/2009 AND 01 / JAN / 2009.
start and end dates of second record are 15/JAN/2009 and 15/FEB/2009.
Here are the dates overlap. with my select query, I should get these two recordings.
I am using the following query. But it is too slow. Could you please suggest a better sql?
----------------------------------------------------------------------------------------------------------------------------------------------------------------------------
Select MG_AUTH_AGNT m, MGATH_clnt, MGATH_beg_DT, MGATH_END_DT, MGATH_NHIC_ERR_CD, id where m.MGATH_SERV_GRP = '1' and m.MGATH_STAT = 'A' and MGATH_clnt = (select distinct MGATH_clnt of MG_AUTH_AGNT d where d.MGATH_SERV_GRP = m.MGATH_SERV_GRP and d.MGATH_TYP = m.MGATH_TYP and m.MGATH_CLNT = d.MGATH_CLNT and d.MGATH_STAT = m.MGATH_STAT and m.idd.id ((trunc (m.MGATH_beg_DT) & gt; = trunc (d.MGATH_beg_DT) and trunc (m.MGATH_beg_DT) & lt;=trunc(d.MGATH_END_DT)) or (trunc (m.MGATH_END_DT) & gt; = trunc (d.MGATH_beg_DT) and trunc (m.MGATH_END_DT) & lt; = trunc (d.MGATH_END_DT)) or (trunc (m.MGATH_beg_DT) & lt; = trunc (d.MGATH_beg_DT) and trunc (m.MGATH_END_DT) & gt; = trunc (d.MGATH_END_DT))) MGATH_clnt order MGATH_beg_DT
Published by: user10727414 on March 17, 2009 01:36user10727414 wrote:
My data is correctMGSRV_CLNT = MGSRV_BEG_DT = MGSRV_END_DT
501184242 = 28-AUG-07 = 31-DEC-9999
501184242 = 28-AUG-07 = 31-DEC-9999
501184242 = 20-DEC-07 = 31-DEC-9999
501184242 = 20-DEC-07 = 31-DEC-9999And we had to guess that a year of "99" was in fact "9999" were we? Hang on I'll go and dust off my crystal ball.
Well, now we know the correct dates (?), we'll put that in the original request...
SQL> ed Wrote file afiedt.buf 1 with mypeople as 2 (select 501184242 as id, to_date('28-AUG-2007','DD-MON-YYYY') as stdt, to_date('31-DEC-9999','DD-MON-YYYY') as endt from dual union all 3 select 501184242, to_date('28-AUG-2007','DD-MON-YYYY'), to_date('31-DEC-9999','DD-MON-YYYY') from dual union all 4 select 501184242, to_date('20-DEC-2007','DD-MON-YYYY'), to_date('31-DEC-9999','DD-MON-YYYY') from dual union all 5 select 501184242, to_date('20-DEC-2007','DD-MON-YYYY'), to_date('31-DEC-9999','DD-MON-YYYY') from dual union all 6 select 2, to_date('19/01/2009','DD/MM/YYYY'), to_date('24/01/2009','DD/MM/YYYY') from dual) 7 -- END OF TEST DATA 8 select id, stdt, endt 9 ,case when lead(stdt) over (partition by id order by stdt,endt) <= endt 10 or lag(endt) over (partition by id order by stdt,endt) >= stdt then 'Overlap' 11 else 'Ok' 12 end as status 13 from mypeople 14* order by id, stdt, endt SQL> / ID STDT ENDT STATUS ---------- --------- --------- ------- 2 19-JAN-09 24-JAN-09 Ok 501184242 28-AUG-07 31-DEC-99 Overlap 501184242 28-AUG-07 31-DEC-99 Overlap 501184242 20-DEC-07 31-DEC-99 Overlap 501184242 20-DEC-07 31-DEC-99 Overlap SQL>
Looks like it works for me.
If it does not work for you then maybe had better give us a statement of create table and insert to your data in the example statements then we can see what you're trying to do.
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Start and End DateTime calculations
Dear all
I have 3 fields start time, end time and hours. I want that if I give hours then the start time should be filled in with the current date and time and end time must be calculated accordingly. Suppose I have hours = 1 then start time should be May 17, 2015 11:25:30 and end time should already be filled in 17 may 2015 12:25:30
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See you soon
AJ
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