Trunc (sysdate) question

Similar Questions

• With the help of trunc (sysdate) between

  Hello - I have a question about when to use trunc (sysdate).
  
  In particular, I wonder whether or not there are no reason to use trunc (sysdate) in the following statement:
  

  select app_id from app where sysdate between start_date and stop_date

  .. .or start_date and stop_date are stored truncated (not stored in the column time info).
  
  Thank you!

  To some extent, it depends on you want to return. If you ran the query today, and the date of the judgment was 21-sep-2011, would you record back or not? If Yes, then you need to trunc sysdate, given that the component "hour" of stop_date's midnight, and it's almost always after midnight for sysdate (86 399 seconds per day). If this isn't the case, then it is not serious.

  John

• trunc sysdate returns 12:08 AM

  SELECT TO_CHAR (TRUNC (SYSDATE), ' MM/DD/YYYY hh: mm AM ")"Current Date and time"from DUAL;

  ----------

  21/08/2015-12:08 AM

  If this should not return 12:00 AM... ?

  I see the example, with the same output (where I got of) mentioned in this oradoc:

  http://docs.Oracle.com/CD/B19306_01/server.102/b14200/functions201.htm

  However, the textbooks I use show 12:00 as output. Maybe something's different in my initialization?

  MM is the month, not minutes

• Difference between Sysdate and trunc (sysdate)?

  SYSDATE and trunc (sysdate) both return the current date.

  So I would like to know is there a difference between them?

  Thank you

  DATEs in Oracle ALWAYS have a portion of time (what you call a timestamp). Using tronque() on a DATE fixed the part time at midnight that day there

• trunc (transaction_date) = trunc (sysdate) is there a performance issue?

  Hi gurus,
  
  I wrote a code that summarize the records for a day.
  I need to put it as a daily_summary_job.
  
  I used expression such as:
  
  trunc (transaction_date) = trunc (sysdate)
  
  Is it a good idea to truncate the dates on both sides?
  I need to summarize the data for a day.
  
  Thank you

  Hi Tina,

  as others already said, using a function on a column WHERE clause prevents the use of an index on that column. Another important issue for the performance, it's that the cardinality estimates are likely to be less accurate in this case.

  You can avoid these problems by creating an index based on a function on trunc (transaction_date). In addition to creating a usable index, it will also create a virtual column for which optimizer will collect stats.

  Best regards
  Nikolai

• What is the difference between TRUNC (SYSDATE + 1) and trunc (sysdate) + 1?

  Hello
  The two functions are truncated anyway. Is there a difference between the two, in this scenario?

  trunc(sysdate + 1) add 1 day to the sysdate and then truncating

  trunc (sysdate) + 1 truncating sysdate and then adds 1 day

  output will be the same.

• Error that using TO_CHAR (TRUNC (SYSDATE), 'DAY') FROM DUAL

  Hello everyone.
  
  I have a pl/sql procedure that contains TO_CHAR (TRUNC (SYSDATE), 'DAY') FROM DUAL to capture the DAY in a variable. Now when I access this procedure of someother application (Workflow), I get the error ORA-01841: (full) year must be understood between-4713 and 9999 and not be 0.
  
  If I do not use TO_CHAR (TRUNC (SYSDATE), 'DAY') and hardcode the value, it throws no error.
  
  Any ideas on this error?
  
  Is this something to do with the NLS_DATE?
  
  Thank you
  
  Kind regards
  
  Pavan K

  >
  ...

  IF (TRIM (SAT_DAY) = 'SATURDAY')
  THEN
  L_DAYS: = L_DAYS + 2;
  ELSIF (TRIM (SAT_DAY) = "SUNDAY")
  THEN
  L_DAYS: = L_DAYS + 1;
  ON THE OTHER
  L_DAYS: = 1; - FND_PROFILE. VALUE ('DSD_PAF_TIMEOUT'); -Getting the value of timeouit in days
  END IF;
  L_DAYS: = L_DAYS * 24 * 60;

  First, you add two days if it's a Sunday.
  Then you multiply by 24 * 60.
  Are you sure that this logic is ok?

  I guess you just use bad values for the L_days parameter.

  The difference between last Friday and today, without doubt is:

  last Friday, the variable L_days has been VERY VERY VERY big, for example 20000000 = (x + 2) * 24 * 60)

  Today, it's only 1 * 24 * 60 = 1440.

  Published by: W. Sven on September 21, 2009 18:01

  Looking at the error message...

  ORA-01841: (full) year must be between-4713 and 9999

  My current guess is that you have created a date that goes beyond the year 9999.

  Published by: W. Sven on September 21, 2009 18:05

• To_date (sysdate) question

  Hi all
  
  I have a small question... but first, I'll post the code
  

  CREATE TABLE TBL_HEADER (RECORD_ID          VARCHAR2(1 CHAR),
                           DATA_DEFINITION    VARCHAR2(2 CHAR),
                           CREATION_DT_TM     TIMESTAMP);
  
  INSERT INTO TBL_HEADER VALUES ('#',
                                 '1',
                                 TO_DATE(SYSDATE, 'YYYY-MM-DD HH24:MI:SS'));

  I get the result date saying 12:00:00.000000 13/05/13 h
  
  I would like to that the release date of say 13/05/2013 12:30:23, and that's it. Is there something wrong I do in my orders to date?
  
  I have Oracle 11g 64 bit.
  
  Thanks advance.

  Hello

  991769 wrote:
  Hi all

  I have a small question... but first, I'll post the code

  CREATE TABLE TBL_HEADER (RECORD_ID          VARCHAR2(1 CHAR),
  DATA_DEFINITION    VARCHAR2(2 CHAR),
  CREATION_DT_TM     TIMESTAMP);
  
  INSERT INTO TBL_HEADER VALUES ('#',
  '1',
  TO_DATE(SYSDATE, 'YYYY-MM-DD HH24:MI:SS'));
  

  I get the result date saying 12:00:00.000000 13/05/13 h

  I would like to that the release date of say 13/05/2013 12:30:23, and that's it. Is there something wrong I do in my orders to date?

  The TO_DATE name actually tells what the function: it converts something (a VARCHAR2, to be exact) to a DATE . The function SYSDATE returns a DATE, so there is not need to convert. INSERT some values like this:

  INSERT INTO TBL_HEADER VALUES ('#',
                                  '1',
                                  SYSDATE
                                  );
  

  Published by: Frank Kulash, May 13, 2013 13:37
  I just noticed that creation_dt_tm is a TIMESTAMP, not a DATE. In this case, DATE functions can still basically do what you want, but it is better to use the time STAMP functions when possible, like this:

  INSERT INTO TBL_HEADER
         (record_id,  data_definition,  creation_dt_tm)
  VALUES ('#',        '1',              SYSTIMESTAMP);
  

  The only difference between the DATEs and timestamps is that DATEs can not handle fractions of a second, but horodateurs can. If you do not need fractions of a second, I suggest that you use DATE instead of the TIMESTAMP. It will be simpler and more effective.

• using trunc ((sysdate-1 * 12) add_months get Monday on this wk

  Hello all;
  
  I use trunc (add_months (sysdate-1 * 12)), which get me on 18/05/2010 but what I would do is bascially, if this date falls on a Monday, then getting Monday involved in this period, in this case Monday that is associated with is therefore 17/05/2010. How to get what I want to change.
  
  Edited by: user13328581 may 18, 2011 08:36

  SQL> select trunc(add_months(sysdate, 1 * -12),'IW') from dual
    2  /
  
  TRUNC(ADD
  ---------
  17-MAY-10
  
  SQL> 
  

  GOLD:

  SQL> select next_day(trunc(add_months(sysdate, 1 * -12)) - 7,'monday') from dual
    2  /
  
  NEXT_DAY(
  ---------
  17-MAY-10
  
  SQL> 
  

  SY.

• Framing OBIEE-implementation of responses with the sysdate and trunc keywords?

  How can apply us this condition in the Oracle replies:
  
  trunc (dim1.start_date) between trunc(sysdate-1) and trunc (sysdate + 4)
  
  Thank you!

  Try this criteria tab

  dim1.start_date-> filter-> Advanced-> convert this filter in SQL
  Cast (dim1.start_date as date) > = current_date and
  Cast (dim1.start_date as date)<=timestampadd(sql_tsi_day,4,cast(current_date as="">

• Question about SYSDATE

  This information below is a line from my database.
  
  GK_ID GK_SR GK_AGENT GK_DATE GK_SHIFT
  361 12345678 ALEJANDRO DAY 25/05/2011
  
  I've run this query SELECT COUNT (*) FROM GK_LOG WHERE GK_DATE = SYSDATE
  
  The request should show me 9, because there are 9 lines with the current date (sysdate). I tried to put WHERE GK_DATE > = SYSDATE and nothing. I tried to put WHERE GK_DATE < SYSDATE
  and he showed me 9, but it does not help. I need that this query WHERE GK_DATE = SYSDATE show me 9. I actually insert the data in the column GK_DATE with the SYSDATE.
  
  Could you help me with this please. I understand you. Thank you

  Hello

  SYSDATE is a time component, including seconds.

  You can use such AS sysdate. Or insert and query with trunc (sysdate).

  Concerning
  Peter

• 2 questions about Calendar implementations (APEX 5.0)

  Hello

  I use 5 APEX on Oracle Express Edition.

  I created a calendar that displays data in multiple tables.

  Here is the query to simplify:

  Select an evt, b datevt

  FROM table1

  Union

  Select evt c, datevt d

  from table2

  Union

  Select e TTE, f datevt

  table 3;

  I need to put up a link in the calendar on these data that display a modal page where users can see the details and update the data.

  I have seen that it is possible to create a link on the calendar, but this link is considered to be a single page. In my case, I need to 3 different links, one per page.

  Another question: I want to display these data on the calendar with a color that depends on the table. For example, blue for the first table, the Red during the second and the Orange for the third.

  You have a solution that helps me implement those needs?

  You will appreciate any help, and sorry if these questions have already addressed the Forum.

  Thanks in advance

  Vincent

  2979122 wrote:

  Please update your forum profile with a recognizable username instead of "2979122": Video tutorial how to change username available

  Always include the information described in these guidelines when you post a question: How to get the answers from the forum

  I use 5 APEX on Oracle Express Edition.

  I created a calendar that displays data in multiple tables.

  Here is the query to simplify:

  Select an evt, b datevt

  FROM table1

  Union

  Select evt c, datevt d

  from table2

  Union

  Select e TTE, f datevt

  table 3;

  I need to put up a link in the calendar on these data that display a modal page where users can see the details and update the data.

  I have seen that it is possible to create a link on the calendar, but this link is considered to be a single page. In my case, I need to 3 different links, one per page.

  Another question: I want to display these data on the calendar with a color that depends on the table. For example, blue for the first table, the Red during the second and the Orange for the third.

  You have a solution that helps me implement those needs?

  An explanation of how to display events in different colors using CSS classes is given in the online help for the region calendar Class CSS attribute:

  select ID,
    START_DATE,
    END_DATE,
    TASK_NAME,
    case STATUS
      when 'Open' then 'apex-cal-green'
      when 'Pending' then 'apex-cal-yellow'
      when 'Closed' then 'apex-cal-red'
      when 'On-Hold' then 'apex-cal-black'
    end as css_class,
    ASSIGNED_TO as supplemental_info
    from PROJECTS
  

  The column specifying the apex - cal-* color class is then selected in the attribute of Class CSS region.

  Link target URL can be built dynamically in the region of link attributes using chains of substitution that reference columns in the query. Again, see the online help for the link attributes. In a UNION like yours, a different target page can be specified in each request, and referenced in the link attribute display/change page numbers to specify the page number and set the values of the elements of the requested page:

  Source of the region

  select
      10 x
    , trunc(sysdate) - 9 d
    , 'Foo' s
    , 'apex-cal-green' css_class
    , '10' link_page
  from
      dual
  union all
  select
      20
    , trunc(sysdate) - 6
    , 'Bar'
    , 'apex-cal-yellow'
    , '11'
  from
      dual
  union all
  select
      30
    , trunc(sysdate)
    , 'Baz'
    , 'apex-cal-red'
    , '12'
  from
      dual
  

  
  

  View/Edit link

  f?p=&APP_ID.:&LINK_PAGE.:&SESSION.::&DEBUG.:10:P&LINK_PAGE._X:&X.
  

• XML PIVOT QUERY QUESTIONS

  I'm new to PIVOT queries.  I was making reference to the discussion that follows, but ran into a problem.  https://forums.Oracle.com/message/9393302

  When I added the XML to format data, I started to have NULL values rather than what I was looking for.

  WITH (AS PIVOT_DATA)

  SELECT * FROM)

  SELECT THE REGION, FCST_PERIOD, PRIME_PART, FINAL_FORECAST

  OF XYZ WHERE FCST_PERIOD > = last_day (trunc (sysdate)) + 1 and FCST_PERIOD < = last_day (add_months(sysdate,12)) AND PRIME_PART IN ('BLAH')

  )

  PIVOT XML (SUM (FINAL_FORECAST) FOR FCST_PERIOD IN (SELECT DISTINCT FCST_PERIOD OF XYZ))

  )

  SELECT PRIME_PART, REGION,

  EXTRACTVALUE(FCST_PERIOD_XML,'/PIVOTSET/ITEM[1]/COLUMN[2]') FCST_PERIOD1,

  EXTRACTVALUE(FCST_PERIOD_XML,'/PIVOTSET/ITEM[2]/COLUMN[2]') FCST_PERIOD2,

  EXTRACTVALUE(FCST_PERIOD_XML,'/PIVOTSET/ITEM[3]/COLUMN[2]') FCST_PERIOD3

  OF PIVOT_DATA;

  RESULTS IN:

  PRIME_PART	REGION	FCST_PERIOD1	FCST_PERIOD2	FCST_PERIOD3
  BLA	MIDWEST	(NULL)	(NULL)	(NULL)
  BLA	WEST-NV	(NULL)	(NULL)	(NULL)
  BLA	SOUTH-EAST	(NULL)	(NULL)	(NULL)
  BLA	WEST-CA	(NULL)	(NULL)	(NULL)
  BLA	SOUTHWEST	(NULL)	(NULL)	(NULL)
  BLA	EAST	(NULL)	(NULL)	(NULL)

  The second part of my question is how would I do a group when you use a pivot query.  When I finished, I've has several parts and would like to group by REGION.

  Thank you!

  Names of elements and attributes in XML are case-sensitive.

  Try with:

  EXTRACTVALUE (FCST_PERIOD_XML, ' / PivotSet/item [1] /column [2]') FCST_PERIOD1

  There is also a good chance that EXTRACTVALUE is frowned upon in your version. Instead, use XMLQuery or XMLTable.

  That being said, using XML PIVOT just to grind it later into a number known columns is pretty useless.

  The same can be achieved much more efficiently with regular PIVOT operator (and if necessary analytical function).

  Post some examples of data in the table of your database and your final result expected to get useful assistance.

• dbms_job questions

  Hi all..
  
  Please help with dbms_job questions.
  
  Oracle version: 9i
  
  say, if I get a job with the following times
  next_date = trunc (sysdate) + 1/24-> saying that it starts at 01:00
  range = trunc (sysdate) + 1/24-> saying that it runs every day at 01:00
  
  (1) what happens if the job takes more than 24 hours to complete?
  When it start again? According to the schedule, we say that it starts at 01:00
  but the current run up to the race?
  
  
  (2) if my job_queue_process = 10 (means run only 10 jobs at a time).
  In this scenario, if there are already 10 jobs at 01:00.
  my work took me from 01:00 be taken up.
  When it starts to this scenario? What happened to 'run '?
  
  (3) other use of dbms_schduler (using channels in the Task Scheduler), is possible to
  do the following?
  If I have 4 jobs 1,2,3,4. I would like to run Task 4 only after job 1,2,3 had finished.
  using any dbms_alert or dbms_ * etc.?
  
  Please help me.
  
  Thanks in advance

  First, I am assuming that you intend INTERVAL trunc (sysdate + 1) + 1/24. Otherwise, the INTERVAL did not assess for tomorrow at 01:00.

  (1) the INTERVAL is evaluated once the work is completed. So if work begins at 01:00 on 1 January and ends at 02:00 on Jan 2, the INTERVAL would be assessed at 02:00 on Jan 2 and go back to 01:00 on 3 Jan. The work would go to 01:00 Jan 3, so 2 Jan run might be ignored.

  (2) the task will run as soon as one of the 10 jobs running ends (assuming that there is no other jobs are put on hold and waiting to run upward).

  (3) is it possible? Sure. You must write custom code. The simplest approach would be to create a table of simple state with 4 rows, one by mail. Jobs 1-3 update the state table when they are complete and 4 job is configured to run every few minutes, query the data in the table and only work if she sees that 1-3 posts were all successful. When work 4, he then clears the data in the status table.

  Justin

• Question about Group by

  Hello friends,
  
  I have a table called APPLICATIONS (INQUIRY_ID, CALLING_DATE, ASSIGN_TO_AGENT)
  
  I need to create a report to show the number of requests received by Agent as follows:
  

  Assign_to_agent , number_of_daily_inquiries, total_inquiries_number
  
  X               ,         4                 , 150
  Y               ,         8                 , 200
  ..........
  ....

  I used this query that does not work:
  

  select assign_to_agent   ,
   count (inquiry_id) , 
   (select count ( inquiry_id)   as "total_inquiries_number"
   from inquiries   where trunc ( calling_date,'DD' )= trunc ( sysdate, 'DD')  ) as "number_of_daily_inquiries"
  from inquiries  group by assign_to_agent

  I hope that my question was clear.
  
  Kind regards
  Water
  
  Published by: cold_water on 25 Sep 2012 10:23

  Hi cold_water,

  Maybe it is not necessary to query two times table. Something like

  select   i.assign_to_agent,
           count (
             case
               when trunc ( i.calling_date, 'DD') = trunc ( sysdate, 'DD') then
                 i.inquiry_id
             end ) as "number_of_daily_inquiries",
           count (i.inquiry_id) as "total_inquiries_number"
  from     inquiries i
  group by i.assign_to_agent;
  

  Concerning
  Peter