Updated with the hash values column

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• Bug in reporter Panel updated with the property Value Chart

  Hi guys,.

  Defer to what the Panel update property is set to true and chart is updated with the help of node "Property value", data are not updated graphics. Capture of the block diagram and VI (2014) screen gasket.

  Is this a known bug, and is there any fix for it?

  

  Thank you

  Knockaert

  I have not tried running your code, but here are some possible solutions:

  1. There is a primitive to write the value of a control by index (added in ~ 2013). This is designed to be used others live too and should work like a local.
  2. You can send data using another way (like a queue, etc.).
  3. Use the Ctl Val.Set method.
  4. Do not use a chart. Use a chart and manage the buffer yourself. You can find some examples if you're looking for graph XY.

• Update with the Lead feature and several lines

  I have a table such as:

  Table1:

  OrderNumber EFFECTIVE_DATE EFFECTIVE_END_DATE FileName

  123 11/5/2015-12/31/2099 File5.txt

  123, 7/11/2015-12/31/2099 File7.txt

  or it can look like:

  Table2

  OrderNumber EFFECTIVE_DATE EFFECTIVE_END_DATE FileName

  123 11/5/2015-11/7/2015 File5.txt

  123, 7/11/2015-11/9/2015 File7.txt

  123 11/9/2015-12/31/2099 File9.txt

  123 11/15/2015-12/31/2099 File15.txt

  I want to take the 2nd to the last EndDate and update with the previous value.

  So in fact, it would look like this.

  Table1:

  OrderNumber EFFECTIVE_DATE EFFECTIVE_END_DATE FileName

  123 11/5/2015-11/7/2015 File5.txt

  123, 7/11/2015-12/31/2099 File7.txt

  or

  Table2

  OrderNumber EFFECTIVE_DATE EndDate FileName

  123 11/5/2015-11/7/2015 File5.txt

  123, 7/11/2015-11/9/2015 File7.txt

  123-11/9/11/15 to 2015/2015 File9.txt

  123 11/15/2015-12/31/2099 File15.txt

  I got it work in a select statement to a single value. now I just need help it enter an UPDATE statement and update all records.

  SELECT W.EFFECTIVE_DATE, W.EFFECTIVE_END_DATE,

  NVL (LEAD (W.EFFECTIVE_DATE, 1) (ORDER implementation W.EFFECTIVE_DATE), December 31, 99 ') AS 'EFFECTIVE_DATE_NEW '.

  OF WH_ORDERS_REPORT W

  WHERE ORDERNUMBER = '10460992';

  It did not work:

  UPDATE WH_ORDERS_REPORT WH

  SET EFFECTIVE_END_DATE = (SELECT NVL (LEAD (WH2. EFFECTIVE_DATE, 1) (ORDER of WH2. (EFFECTIVE_DATE), DECEMBER 31, 99 ')

  OF WH_ORDERS_REPORT WH2

  WHERE WH. ORDERNUMBER = WH2. ORDERNUMBER)

  I appreciate your help in the creation of an update statement to do this.

  Rap, but it's working now.  I'll confirm with a few other records before I mark as correct, but what I see so far, it is beautiful, thank you!

  merge into WH_LIFELINE_ORDERS_REPORT D

  a_l'_aide_de)

  Select

  DISTINCT ORDERNUMBER,

  CURRENTSTATUSDATETIME,

  NVL (LEAD(EFFECTIVE_DATE, 1) ON (ORDERNUMBER partition

  (EFFECTIVE_DATE order), December 31, 99 ') as EFFECTIVE_END_DATE

  of WH_LIFELINE_ORDERS_REPORT

  ) S

  WE (D.ORDERNUMBER = S.ORDERNUMBER

  AND D.CURRENTSTATUSDATETIME = S.CURRENTSTATUSDATETIME

  )

  When matched then

  setting a day of set D.EFFECTIVE_END_DATE = S.EFFECTIVE_END_DATE;

• update to column values (false) in a copy of the same table with the correct values

  Database is 10gr 2 - had a situation last night where someone changed inadvertently values of column on a couple of hundred thousand records with an incorrect value first thing in the morning and never let me know later in the day. My undo retention was not large enough to create a copy of the table as it was 7 hours comes back with a "insert in table_2 select * from table_1 to timestamp...» "query, so I restored the backup previous nights to another machine and it picked up at 07:00 (just before the hour, he made the change), created a dblink since the production database and created a copy of the table of the restored database.
  
  My first thought was to simply update the table of production with the correct values of the correct copy, using something like this:
  
  
  Update mnt.workorders
  Set approvalstat = (select b.approvalstat
  mnt.workorders a, mnt.workorders_copy b
  where a.workordersoi = b.workordersoi)
  where exists (select *)
  mnt.workorders a, mnt.workorders_copy b
  where a.workordersoi = b.workordersoi)
  
  It wasn't the exact syntax, but you get the idea, I wanted to put the incorrect values in x columns in the tables of production with the correct values of the copy of the table of the restored backup. Anyway, it was (or seem to) works, but I look at the process through OEM it was estimated 100 + hours with full table scans, so I killed him. I found myself just inserting (copy) the lines added to the production since the table copy by doing a select statement of the production table where < col_with_datestamp > is > = 07:00, truncate the table of production, then re insert the rows from now to correct the copy.
  
  Do a post-mortem today, I replay the scenario on the copy that I restored, trying to figure out a cleaner, a quicker way to do it, if the need arise again. I went and randomly changed some values in a column number (called "comappstat") in a copy of the table of production, and then thought that I would try the following resets the values of the correct table:
  
  Update (select a.comappstat, b.comappstat
  mnt.workorders a, mnt.workorders_copy b
  where a.workordersoi = b.workordersoi - this is a PK column
  and a.comappstat! = b.comappstat)
  Set b.comappstat = a.comappstat
  
  Although I thought that the syntax is correct, I get an "ORA-00904: 'A'. '. ' COMAPPSTAT': invalid identifier ' to run this, I was trying to guess where the syntax was wrong here, then thought that perhaps having the subquery returns a single line would be cleaner and faster anyway, so I gave up on that and instead tried this:
  
  Update mnt.workorders_copy
  Set comappstat = (select distinct)
  a.comappstat
  mnt.workorders a, mnt.workorders_copy b
  where a.workordersoi = b.workordersoi
  and a.comappstat! = b.comappstat)
  where a.comappstat! = b.comappstat
  and a.workordersoi = b.workordersoi
  
  The subquery executed on its own returns a single value 9, which is the correct value of the column in the table of the prod, and I want to replace the incorrect a '12' (I've updated the copy to change the value of the column comappstat to 12 everywhere where it was 9) However when I run the query again I get this error :
  
  ERROR on line 8:
  ORA-00904: "B". "" WORKORDERSOI ": invalid identifier
  
  First of all, I don't see why the update statement does not work (it's probably obvious, but I'm not)
  
  Secondly, it is the best approach for updating a column (or columns) that are incorrect, with the columns in the same table which are correct, or is there a better way?
  
  I would sooner update the table rather than delete or truncate then re insert, as it was a trigger for insert/update I had to disable it on the notice re and truncate the table unusable a demand so I was re insert.
  
  Thank you

  Hello

  First of all, after post 79, you need to know how to format your code.

  Your last request reads as follows:

  UPDATE
    mnt.workorders_copy
  SET
    comappstat =
    (
      SELECT DISTINCT
        a.comappstat
      FROM
        mnt.workorders a
      , mnt.workorders_copy b
      WHERE
        a.workordersoi    = b.workordersoi
        AND a.comappstat != b.comappstat
    )
  WHERE
    a.comappstat      != b.comappstat
    AND a.workordersoi = b.workordersoi
  

  This will not work for several reasons:
  The sub query allows you to define a and b and outside the breakets you can't refer to a or b.
  There is no link between the mnt.workorders_copy and the the update and the request of void.

  If you do this you should have something like this:

  UPDATE
    mnt.workorders     A      -- THIS IS THE TABLE YOU WANT TO UPDATE
  SET
    A.comappstat =
    (
      SELECT
        B.comappstat
      FROM
        mnt.workorders_copy B   -- THIS IS THE TABLE WITH THE CORRECT (OLD) VALUES
      WHERE
        a.workordersoi    = b.workordersoi      -- THIS MUST BE THE KEY
        AND a.comappstat != b.comappstat
    )
  WHERE
    EXISTS
    (
      SELECT
        B.comappstat
      FROM
        mnt.workorders_copy B
      WHERE
        a.workordersoi    = b.workordersoi      -- THIS MUST BE THE KEY
        AND a.comappstat != b.comappstat
    )
  

  Speed is not so good that you run the query to sub for each row in mnt.workorders
  Note it is condition in where. You need other wise, you will update the unchanged to null values.

  I wouold do it like this:

  UPDATE
    (
      SELECT
        A.workordersoi
        ,A.comappstat
        ,B.comappstat           comappstat_OLD
  
      FROM
        mnt.workorders        A      -- THIS IS THE TABLE YOU WANT TO UPDATE
        ,mnt.workorders_copy  B      -- THIS IS THE TABLE WITH THE CORRECT (OLD) VALUES
  
      WHERE
        a.workordersoi    = b.workordersoi      -- THIS MUST BE THE KEY
        AND a.comappstat != b.comappstat
    ) C
  
  SET
    C.comappstat = comappstat_OLD
  ;
  

  This way you can test the subquery first and know exectly what will be updated.
  This was not a sub query that is executed for each line preformance should be better.

  Kind regards

  Peter

• An update on an index column with the same value generates an index to the top

  An update on an index column with the same value generates an update of the index?
  
  
  Thank you

  In addition to my previous answer, see also

  http://orainternals.WordPress.com/2010/11/04/does-an-update-statement-modify-the-row-if-the-update-modifies-the-column-to-same-value/

  Riyaj Shamsudeen has this to say:
  "+ We have an index on this column v1 and we update this column indexed too." Oracle was updating the indexed column? N ° if the values match the level of the indexed column, then the code of RDBMS isn't up-to-date index, a feature for optimization again. Only the row of table is updated, and the index is not updated. + "

  Hemant K Collette

• Documentation about adding column with the DEFAULT value.

  Hello
  
  http://download.Oracle.com/docs/CD/B19306_01/server.102/b14200/statements_3001.htm#i2198241
  
  < quote >
  If you add a column, then the initial value of each row in the new column is NULL unless you specify the DEFAULT clause. In this case, Oracle database updates each row in the new column with the value specified for the DEFAULT value. This update operation, in turn, triggers AFTER UPDATE triggers defined on the table.
  < quote >
  
  I am not able to understand the emphasis on the part AFTER UPDATE while the column with DEFAULT values addition triggers both BEFORE and AFTER triggers defined on UPDATE.
  
  According to the documents of 11 g
  
  http://download.Oracle.com/docs/CD/B28359_01/server.111/b28286/statements_3001.htm#i2133105
  
  n.m. (u) r only changes with the NON NULL columns, but focus on AFTER UPDATE is still there. No trigger defined on the fire of the update in this case.
  
  This insistence is intended? If not, IMO, it should be changed.
  
  Kind regards

  Hi Sissi. After further discussion, we have added some information about a change in behavior. Here is what says the next version of the doc:

  When you add a column, the initial value of each row in the new column is null.

  * If you specify the DEFAULT clause for a column NOT NULL, then the default value is stored as metadata, but the column itself is not populated with data. However, the following queries that specify the new column are rewritten so that the default value is returned in the result set.

  This optimized behavior differs from earlier versions, when as part of operation ALTER TABLE Oracle database updated every line in the newly created with the default column and then fired defined update triggers on the table. In this release, no trigger is triggered because the default value is stored only in the form of metadata.

  * If you specify the DEFAULT for a nullable column clause, then the default value is added to existing lines under this ALTER TABLE statement, and any update triggers defined on the table are activated. This behavior also means if you change a NOT NULL column with a default value to be nullable.

  Hope that helps to clarify the matter further.

  Kind regards
  Diana

• I have a column with two values, separated by a space, in each line. How to create 2 new columns with the first value in a column, and the second value in another column?

  I have a column with two values, separated by a space, in each line. How do I create 2 new columns with the first value in one column and the second value in another column?

  Add two new columns after than the original with space separated values column.

  

  Select cell B1 and type (or copy and paste it here) the formula:

  = IF (Len (a1) > 0, LEFT (A1, FIND ("", A1) −1), ' ')

  shortcut for this is:

  B1 = if (Len (a1) > 0, LEFT (A1, FIND ("", A1) −1), ' ')

  C1 = if (Len (a1) > 0, Member SUBSTITUTE (A1, B1 & "", ""), "")

  or

  the formula of the C1 could also be:

  = IF (Len (a1) > 0, RIGHT (A1, LEN (A1) −FIND ("", A1)), "")

  Select cells B1 and C1, copy

  Select cells B1 at the end of the C column, paste

• How to compare the new values with the old values in triggers.

  Dear all,
  
  Please tell me how to compare the new values with the old values in triggers.

  Hi, the employee example is in the document. You'd better read yourself.

  CREATE OR REPLACE TRIGGER Print_salary_changes
    BEFORE DELETE OR INSERT OR UPDATE ON Emp_tab
    FOR EACH ROW
  WHEN (new.Empno > 0)
  DECLARE
      sal_diff number;
  BEGIN
      sal_diff  := :new.sal  - :old.sal;
      dbms_output.put('Old salary: ' || :old.sal);
      dbms_output.put('  New salary: ' || :new.sal);
      dbms_output.put_line('  Difference ' || sal_diff);
  END;
  /
  

• Plan of the hash value for two queries!

  Hello
  DB: Oracle 11g (11.2.0.3.0)
  OS: RHEL 5
  
  I have two question:
  
  1. can two queries have the same hash value of the plan? I mean I have here are two queries:
  
  SELECT /+ NO_MERGE * / MIN (payor.next_review_date). *
  * Payer from *.
  * WHERE payor.review_complete = 0 *.
  * AND payor.closing_date IS NULL *.
  * AND payor.patient_key = 10; *
  
  and
  
  SELECT MIN (payor.next_review_date)
  * Payer from *.
  * WHERE payor.review_complete = 0 *.
  * AND payor.closing_date IS NULL *.
  * AND payor.patient_key = 10; *
  
  When I tried to examine the execution plan for the two motions, the hash value of the plan remains the same. This means that implementation plan for both queries are same? If so, then how Oracle includes or changes to the execution plan based on hint. If not, then what hash value of the plan represents?
  
  2. If the plan with suspicion, and without suspicion is identical except for a given query except the number of lines and bytes. Do you mean this query with fewer lines and scanned bytes is better?
  
  Thanks in advance
  -Onkar

  >
  1. can two queries have the same hash value of the plan?
  >
  Yes - as already said - but it's not just because of tips.

  Here is the example code that I use to show that Oracle does NOT simply use a text version of the query that you propose and compute a hash of it.
  These two queries are radically different but have the same hash value; Oracle are not different at all.

  set serveroutput on
  set autotrace traceonly
  select * from DEPT A, EMP B
  where A.DEPTNO=B.DEPTNO
  
  SQL> select * from DEPT A, EMP B
    2  where A.DEPTNO=B.DEPTNO
    3  / 
  
  14 rows selected.
  
  Execution Plan
  ----------------------------------------------------------
  Plan hash value: 844388907
  
  select * from
  (select * from DEPT) A, (select * from EMP) B
  WHERE A.DEPTNO = B.DEPTNO
  
  SQL> select * from
    2  (select * from DEPT) A, (select * from EMP) B
    3  WHERE A.DEPTNO = B.DEPTNO
    4  / 
  
  14 rows selected.
  
  Execution Plan
  ----------------------------------------------------------
  Plan hash value: 844388907
  

• Creating a trigger to insert delete update with the sequence number

  Hey all,.
  I have two tables. tbl_main, tbl_temp. Whenever a record is inserted, deleted, updated in tbl_main, I need to insert the records in tbl_temp. All field/column names are exactly the same, except that in tbl_temp, I now have a single column by using a sequence number, a column to determine if the record has been updated, remove, modified(hence the codes) and the date when a record has been added to the table.
  So far, that's what I have:
  
  create or replace
  audit_trg relaxation
  after update or insert or delete ON tbl_main
  for each line
  Start
  If the update can
  insert into tbl_temp (seq_id, idx, ctl, action_taken, date_added)
  VALUES
  (temp_seq.nextval, idx, mke, ctl, sysdate, 'U');
  ELSif INSERTION then
  insert into tbl_temp (seq_id, idx, ctl, action_taken, date_added)
  VALUES (temp_seq.nextval, idx, mke, ctl, 'n', sysdate);
  ELSIF deletion then
  insert into tbl_temp (seq_id, idx, ctl, action_taken, date_added)
  VALUES (temp_seq.nextval, idx, mke, ctl, would be ', sysdate);
  END IF;
  END audit_trg;
  
  I tried several combinations, but I get many compilation errors. This code looks good or I am the way of track? Thanks in advance.

  Who looks fine for me. What are the mistakes are you?

  Assuming that MKE and CTL are columns in the base table, your INSERT statements will insert either the: new.mke and: new.ctl values or the: old.mke and: old.ctl values in the table. Presumably, you could insert the: new values for inserts and updates, and the: old values for deletions.

  Justin

  Published by: Justin Cave 27 February 2009 16:08

  DOH! Just noticed the error...

• Restrictions does not not after ISO put 10.0.1 update with the new iPhone 7

  Restrictions does not after ISO put 10.0.1 update with the new iPhone 7 any which option of ranking app I don't choose no changes are made.  All the patches?

  Thank you

  Hello Launcher,

  Thank you for bringing your question about Restrictions here in Apple Support communities. My understanding of your question is that you change the Restrictions, but no change is noticed. I tried the same on my iPhone 6 Plus running iOS 10 and noticed a similar situation. Please allow me the opportunity to explain how the Restrictions is designed to work. First, I put my limitations for applications, do not allow Apps and together 4 +, which basically means everything beyond 4 + will be blocked from buying. Then I went to the App Store and the first app that caught my attention was NCIS: hidden crimes. This app is rated 12 + and is definitely an application I would not want my toddler to help. It is that Restrictions come into play. When I type on NCIS: hidden Crimes, the Get option is grayed out. Restrictions does remove all apps, songs, books, etc. from view, but it will prevent the purchase, download, and install all applications rated above the setting you choose when you set up restrictions. It's the help article that discusses the Restrictions and prevent purchases: Use Restrictions in order to avoid buying on iPhone, iPad, or iPod touch.

  I checked on the restrictions help articles, and I understand where it can be a bit confusing. In the help article Use Restrictions on iPhone, iPad and iPod touch, it says "You can use Restrictions, also known as parental control, to block or limit specific applications and features on your iPhone, iPad or iPod touch." This means in fact that apps, features or services (rated above that helped you, or if you have turned off completely) can he no longer appears on the device if the restriction is activated and starts blocking them. I also tested this by activating Restrictions and turned the cursor for Safari to off. When I went back to the home screen, Safari doesn't show any more and I could no longer use it.

  I hope this helps to clarify how the Restrictions. If my understanding of the issue was not accurate to the issue that you are experiencing, I will be happy to pursue this issue with you. Please indicate exactly what you took measures, and what expectations you had or the some restrictions, applications, features, or services you are restricted. Thanks again and have a great rest of your day!

• I bought an iphone used several years ago... hen his recently updated with the new iOS 7.1.2 it was locked with the previous owners account.how can I use my iphone is back with my apple and pass

  I bought an iphone used several years ago... When updating with the new iOS 7.1.2 recently, he was locked with previous apple owners account.

  its now useless. I didn't know all these crappy activation locks and all.now I have no idea

  How can I find my iphone is off and use my phone back

  iphone 4 32 gb

• Please help me understand how to install updates with the following error updated Message__The following have not been installed: __Security update for Microsoft XP KB 2289162

  Please help me understand how to install updates with the following error Message

  The following updates were not installed:

  Security for Microsoft XP KB 2289162 update

  See the section "How to get help" of http://support.microsoft.com/kb/2289162

  For individuals, please visit the Microsoft Solution Center and antivirus security for resources and tools to keep your PC safe and healthy.  If you have problems with the installation of the update itself, visit the Microsoft Update Support for resources and tools to keep your PC updated with the latest updates.

  Buying to meet problems installing Microsoft security updates also can visit the following page for assistance: https://consumersecuritysupport.microsoft.com/

  ~ Robear Dyer (PA Bear) ~ MS MVP (that is to say, mail, security, Windows & Update Services) since 2002 ~ WARNING: MS MVPs represent or work for Microsoft

• I am also having the same problem with the same updates. I have Windows XP SP3 and it's updates with the problem.

  I am also having the same problem with the same updates. I have Windows XP SP3 and it's updates with the problem.

  Security Update for Microsoft .NET Framework 2.0 SP2 on Windows Server 2003 and Windows XP x 86 (KB2572073)
  A security update for .NET Framework 2.0 SP2 and 3.5 SP1 on Windows Server 2003 and Windows XP x 86 (KB2518864)
  Security Update for Microsoft .NET Framework 2.0 SP2 on Windows Server 2003 and Windows XP x 86 (KB2633880)

  They all install properly but switches back to windows update to install. It's some kind of loop.

  Hi billy73,

  In addition, if you still have questions, please take a look at the thread similar here with a solution as possible.

  I hope this helps!

• When I delete the "screensaverissecure" with the registry value, it reappears again in the registry after I stop and start the system the next day. Help, please

  When I delete the "screensaverissecure" with the registry value, it reappears again in the registry after I stop and start the system the next day. Help, please
  use widows xp

  Hello

   
  1. Have you tried to Hibernate for ever in the power settings option?
   
  To resolve this problem, you can follow the steps below.
   
  (a) click and start
  (b) type power Option in the start search bar.
  (c) now select click Change plan for the current plan of the selected power.
  (d) now click on advanced power settings.
  (e) scroll down and click on the sign more next to sleep.
  (f) now click on allow the eve hybrid and turn it off.
  (g) click on the option put into hibernation after and set it to never.