Using the HAVING clause
I have trouble understanding the following query:
SELECT cust_city, COUNT (cust_last_name)
Customers
WHERE cust_credit_limit > 1000
GROUP BY cust_city
HAVING AVG (cust_credit_limit) BETWEEN 5000 AND 6000
According to my preparation for the review, it will work successfully without errors, although I don't understand why.
The AVG (cust_credit_limit) should also be included in with the rest of the fields to make it work correctly?
It would be greatly appreciated if someone could explain it to me better.
Thank you
Sean
5285cd35-2ff3-432e-B2FD-19285481be60 wrote:
I have trouble understanding the following query:
SELECT cust_city, COUNT (cust_last_name)
Customers
WHERE cust_credit_limit > 1000
GROUP BY cust_city
HAVING AVG (cust_credit_limit) BETWEEN 5000 AND 6000
According to my preparation for the review, it will work successfully without errors, although I don't understand why.
The AVG (cust_credit_limit) should also be included in with the rest of the fields to make it work correctly?
It would be greatly appreciated if someone could explain it to me better.
Thank you
Sean
No - the AVG function doesn't have to be in the select list. Explain why you think it should be.
How would it make a difference if you added to the SELECTION list and ignored, then?
When you have questions DOC the first thing you need to do is RTFM. See the HAVING clause in the RFSO of the SQL language
http://docs.Oracle.com/CD/B28359_01/server.111/b28286/statements_10002.htm
>
HAVING clause
Use of the HAVING
clause to restrict groups of returns of the lines to these groups for which the specified condition
is TRUE
.
>
As the doc t says
He HAVING condition applies to the 'groups '.
If you use the HR. EMPLOYEES table you can see the effect of the HAVING clause. This query is similar to yours but with none HAVING clause, and the AVG (salary) added to the selection list to see which groups will have
>
Select department_id, count (last_name), avg (salary)
employees
where salary > 500
Group by department_id
- DEPARTMENT_ID, COUNT (LAST_NAME), AVG (SALARY)
- 10,1,4400
- 20,2,9500
- 30,6,4150
- 40,1,6500
- 50,45,3475.55555555556
- 60,5,5760
- 70,1,10000
- 80,34,8955.88235294118
- 90,3,19333.3333333333
- 100,6,8601.33333333333
- 110,2,10154
- 1,7000
>
Note that 60 is the ONLY group with AVG (salary) between 5000 and 6000
Now, try the query using the HAVING clause
>
Select department_id, count (last_name)
employees
where salary > 500
Group by department_id
having avg (salary) between 5000 and 6000
DEPARTMENT_ID, COUNT (LAST_NAME)
60.5
>
Only group 60 has been selected - the HAVING condition has been applied to the first query GROUPS, not the lines.
Tags: Database
Similar Questions
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How to generate the HAVING clause?
Hi all
When I add a function like the SUM, the code generates the "group by" clause by default. I also want to generate the clause "have" about it, how to do this in ODI?
-Ian.Hello
In your interface drag and drop the source column in the Web for which you want to generate the HAVING clause.
It will create filters for columns. Now use the aggregation works like SUM, MIN, MAX, AVG etc. in this filter query.The generated code will now contain the inside HAVING clause.
Thank you
Fati -
Hi all
I have this select statement to help to filter different from zero records.
Select GroupName, Nom_liste,
Sum ((a_cost/1000) * degradation * quantity * total_count * index) such as total_cost,.
FROM MyTable
having sum ((a_cost/1000) * degradation * quantity * total_count * index) <>0
Group GroupName, Nom_liste
Having done so the query to run more slowly.
How can I filter records with zero total_cost (they can be negative or greater than zero).
Thank you!
Hello
user9542267 wrote:
Hi all
I have this select statement to help to filter different from zero records.
Select GroupName, Nom_liste,
Sum ((a_cost/1000) * degradation * quantity * total_count * index) such as total_cost,.
FROM MyTable
having sum ((a_cost/1000) * degradation * quantity * total_count * index) <> 0
Group GroupName, Nom_liste
Having done so the query to run more slowly.
How can I filter records with zero total_cost (they can be negative or greater than zero).
Thank you!
The query you posted should not take more time with or without the HAVING clause. The right of the comma before 'from' causes a compilation error very quickly anyway.
If you get no result other than an error message, then this is not the code you are running. Show the code you actually run, or a simplified version that has the same problem.
For all performance issues, see the FAQ forum:
https://community.Oracle.com/message/9362003#9362003
If the problem was really in the HAVING clause, then you can try something like this:
WITH got_total_cost AS
(
SELECT GroupName, Nom_liste
, SUM ((a_cost/1000) * degradation * quantity * total_count * index) SUCH as total_cost
FROM MyTable
GROUP BY GroupName, Nom_liste
)
SELECT *.
OF got_total_cost
WHERE as total_cost <> 0
;but it would be very surprising he made all the difference. I suspect that the problem is not really in the HAVING clause.
-
The sql statement is
Select ename, job
from emp, dept
where emp.deptno = dep.deptno
and emp.deptno = 10
Union
Select ename, job
from emp, dept
where emp.deptno = dep.deptno
and emp.deptno = 20
the statement above using the WITH Clause
WITH dept10 AS
(select ename, job, hiredate, sal, comm, dname, emp.deptno
from emp, dept
where emp.deptno = dept.deptno
and emp.deptno = 10)
dept20 AS
(select ename, job, hiredate, sal, comm, dname, emp.deptno
from emp, dept
where emp.deptno = dept.deptno
and emp.deptno = 20)
SELECT *.
OF dept10
UNION
SELECT *.
OF dept20
Correct me if I'm wrong...
Thank youHello
SeenuGuddu wrote:
the Question is how u would provide the statement above by using the ClauseThe answer is that the question is meaningless. You will not use a WITH clause for this work.
Because you must use a WITH clause to get the same results as the first query, I think the best way would be:
WITH unnecessary_sub_query AS ( select DISTINCT ename, job -- , hiredate, sal, comm, dname,emp.deptno -- these columns are not in the original query from emp , dept where emp.deptno = dept.deptno and emp.deptno IN (10, 20) ) SELECT * FROM unnecessary_sub_query;
is this correct using Clause WITH or correct me
No, it's not ok to make queries more complex or slow they need to do.
In addition to the extra columns, it seems that the second query that you posted (the one who has a WITH clause) produces the same results as the first request. -
Hi, I tried to use the nologging clause to improve the performance of DML on one of the table. However I have observed this table with nologging option actually decreases performance :(
Please see the next newspaper.
SQL > create table test_log (int id, name char (40))
2.
Table created.
Elapsed time: 00:00:00.03
SQL > create table test_nolog (int id, name char (40)) nologging
2.
Table created.
Elapsed time: 00:00:00.00
SQL > insert into test_log select ROWNUM *-1, DBMS_RANDOM. String('A',1) FROM DUAL CONNECT BY LEVEL < = 1000000
2.
1000000 rows created.
Elapsed time: 00:00:13.46
SQL > insert into test_nolog select ROWNUM *-1, DBMS_RANDOM. String('A',1) FROM DUAL CONNECT BY LEVEL < = 1000000
2.
1000000 rows created.
Elapsed time: 00:00:16.95
SQL > update test_log set id = 100
2.
1000000 lines to date.
Elapsed time: 00:00:46.35
SQL > update test_nolog set id = 100
2.
1000000 lines to date.
Elapsed time: 00:00:49.43Insert and update have no impact if the tables are created with the NOLOGGING clause or logging
It generates the same amount of redo for insert and UPDATE stmts stmts
NOLOGGING can help for the following things
1 CTAS
2.SQL * loader in direct mode
3. INSERT / * + APPEND * /...SYSTEM@rman 15/12/2008> truncate table test_log; Table truncated. Elapsed: 00:00:01.49 SYSTEM@rman 15/12/2008> truncate table test_nolog; Table truncated. Elapsed: 00:00:00.67 SYSTEM@rman 15/12/2008> insert into test_nolog select ROWNUM*-1,DBMS_RANDOM.STRING('A',1) FROM DUAL CONNECT BY LEVEL <=1000000; 1000000 rows created. Elapsed: 00:00:39.80 Execution Plan ---------------------------------------------------------- Plan hash value: 1731520519 ------------------------------------------------------------------------------ | Id | Operation | Name | Rows | Cost (%CPU)| Time | ------------------------------------------------------------------------------ | 0 | INSERT STATEMENT | | 1 | 2 (0)| 00:00:01 | | 1 | COUNT | | | | | |* 2 | CONNECT BY WITHOUT FILTERING| | | | | | 3 | FAST DUAL | | 1 | 2 (0)| 00:00:01 | ------------------------------------------------------------------------------ Predicate Information (identified by operation id): --------------------------------------------------- 2 - filter(LEVEL<=1000000) Statistics ---------------------------------------------------------- 3081 recursive calls 41111 db block gets 8182 consistent gets 0 physical reads 60983504 _redo size_ 674 bytes sent via SQL*Net to client 638 bytes received via SQL*Net from client 3 SQL*Net roundtrips to/from client 2 sorts (memory) 0 sorts (disk) 1000000 rows processed SYSTEM@rman 15/12/2008> commit; Commit complete. Elapsed: 00:00:00.03 SYSTEM@rman 15/12/2008> insert into test_log select ROWNUM*-1,DBMS_RANDOM.STRING('A',1) FROM DUAL CONNECT BY LEVEL <=1000000; 1000000 rows created. Elapsed: 00:00:38.79 Execution Plan ---------------------------------------------------------- Plan hash value: 1731520519 ------------------------------------------------------------------------------ | Id | Operation | Name | Rows | Cost (%CPU)| Time | ------------------------------------------------------------------------------ | 0 | INSERT STATEMENT | | 1 | 2 (0)| 00:00:01 | | 1 | COUNT | | | | | |* 2 | CONNECT BY WITHOUT FILTERING| | | | | | 3 | FAST DUAL | | 1 | 2 (0)| 00:00:01 | ------------------------------------------------------------------------------ Predicate Information (identified by operation id): --------------------------------------------------- 2 - filter(LEVEL<=1000000) Statistics ---------------------------------------------------------- 3213 recursive calls 41323 db block gets 8261 consistent gets 2 physical reads 60993120 _redo_ size 674 bytes sent via SQL*Net to client 636 bytes received via SQL*Net from client 3 SQL*Net roundtrips to/from client 2 sorts (memory) 0 sorts (disk) 1000000 rows processed SYSTEM@rman 15/12/2008> commit;
They simply generate the same anount of redo
If you use hint APPEND, you can reduce the timings of INSERT stmt
SYSTEM@rman 15/12/2008> truncate table test_nolog; Table truncated. Elapsed: 00:00:00.28 SYSTEM@rman 15/12/2008> INSERT /*+ APPEND */ into test_nolog select ROWNUM*-1,DBMS_RANDOM.STRING('A',1) FROM DUAL CONNECT BY LEVEL <=100 1000000 rows created. Elapsed: 00:00:28.19 Execution Plan ---------------------------------------------------------- ERROR: ORA-12838: cannot read/modify an object after modifying it in parallel SP2-0612: Error generating AUTOTRACE EXPLAIN report Statistics ---------------------------------------------------------- 3125 recursive calls 8198 db block gets 929 consistent gets 0 physical reads 161400 redo size 660 bytes sent via SQL*Net to client 652 bytes received via SQL*Net from client 3 SQL*Net roundtrips to/from client 2 sorts (memory) 0 sorts (disk) 1000000 rows processed SYSTEM@rman 15/12/2008>
You can also view time significant difference/redo generated between INSERT and INSERT with append on a table NOLOGGING
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Cannot use the command clause contained in the posting online of a cursor
Dear people,
I use Oracle 10 g with forms 6i. I had a requirement where I gotto choose the latest ten records and view the sorting in the opposite order.say for ex.
But my problem is all the time that I came to know that we cannot use the order by clause in the view of a cursor line in forms 6i. Think it's one of the limitations of forms 6i.so u can suggest me what I can do to get the expected results? do we not have any alternative?Cursor C is select * from (select ename,sal from emp order by sal desc) where rownum<=10;
Thanking you,
Concerning
Vids
Published by: vidusnat on July 4, 2012 03:38Hello
Please specify!
Forms 6i must be with an older version of SQL and PL/SQL (8.x).To keep it simple create a VIEW in the comics with your as its source and the use of the VIEW in the form. As you noted, it works in 10g and exploit it.
See you soon,.
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try to get the SUM of all of the charges with the having clause
Hi Oracle users.
I'm trying to accomplish to get a sum of a series of charges and it should be easy, but I can't get it.
For example, I have the following.
Select ACCTLOC, count(ACCTLOC) AS TOTALP FROM BOX_ACCTS_TBL WHERE TIME_REQ > SYSDATE-120 Group By ACCTLOC having (count(ACCTLOC) > 1) the results are ACCTLOC TOTALP Philly 15970 NY 8623 Tacoma 3 SanFran 195 Hartford 5 Miami 4374
How can I get the SUM of this group? Do I put this in PL SQL and do a procedure to carry out the selection? Is this the way to go on this?
I appreciate all the comments you can give.Thank you!
with
query_result as
(select 'Philly' acctloc, 15970 totalp Union double all the)
Select "NY", 8623 Union double all the
Select "Tacoma", 3 double Union all
Select "SanFran", 195 double Union all
Select "Hartford", 5 Union double all the
Select 'Miami', double 4374
)
Select acctloc, totalp, sum (totalp) on the_sum, avg (totalp) (on the_avg), ratio_to_report (totalp) (percentages))
of query_result
ACCTLOC TOTALP THE_SUM THE_AVG PERCENTAGES Philly 15970 29170 4861.66666666666666666666666666666666667 .547480287967089475488515598217346588961 NY 8623 29170 4861.66666666666666666666666666666666667 .295611930065135413095646211861501542681 Tacoma 3 29170 4861.66666666666666666666666666666666667 .000102845389098388755570791909496057593 SanFran 195 29170 4861.66666666666666666666666666666666667 .006684950291395269112101474117243743572 Hartford 5 29170 4861.66666666666666666666666666666666667 .000171408981830647925951319849160095989 Miami 4374 29170 4861.66666666666666666666666666666666667 .149948577305450805622214604045251971203 Concerning
Etbin
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HOW TO USE THE CONNECT_BY CLAUSE
Hi guys... I have a table like this
create table emp_del (ename varchar2 (10), mname varchar2 (10))
Insert into emp_del values ('ABC', 'MNO')
Insert into emp_del values ('MNO', 'XYZ')
Insert into emp_del values ('XYZ', 'king')
Insert into emp_del values ('king', NULL)
I use this sql to return the name of any employee senior...
SELECT SYS_CONNECT_BY_PATH (MNAME, '-->') "MANAGER_NAME".
OF EMP_DEL
CONNECT PRIOR MNAME = ENAME
START BY ENAME =: P_EMPLOYEE_NAME
ex: ename = ABC
released as: - > MNO
-> MNO-> XYZ
-> MNO-> XYZ-> King
-> MNO-> XYZ-> king - >
I just need the output to be-> King
can you guys help meOne way:
select ename from( select e.*,connect_by_isleaf lf from emp_del e connect by prior mname=ename start with ename=:P_EMPLOYEE_NAME ) where lf = 1
Note: it can be simplified as below, just used a subquery to understand...
select ename from emp_del e where connect_by_isleaf = 1 connect by prior mname=ename start with ename=:P_EMPLOYEE_NAME
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Hello
I have the sql query:
and this return:select k.id, listagg(a.first_name ||' '|| a.last_name, ', ') within group (order by a.last_name) as Autor from ksiazki k left join autorstwa at on k.id = at.ksi_id left join autorzy a on a.id = at.aut_id group by k.id
and I want to add to the query of WHERE clause, for example:k_id listagg 1 a_name_1 & a_last_name_1, a_name_2 & a_last_name_2 2 a_name_3 & a_last_name_3, a_name_4 & a_last_name_4 3 a_name_3 & a_last_name_3, a_name_2 & a_last_name_2 4 a_name_3 & a_last_name_3 5 null
query returns rank 1...where listagg(...) = 'a_name_1 & a_last_name_1'
or
query return rows 1 and 3....where listagg(...) = 'a_name_2 & a_last_name_2'
My version of oracle:
Oracle Database 11g Enterprise Edition Release 11.2.0.1.0 - Production
Published by: Lucie 2011-06-21 16:22
Published by: Lucie 2011-06-21 16:23Use the HAVING clause:
select k.id, listagg(a.first_name ||' '|| a.last_name, ', ') within group (order by a.last_name) as Autor from ksiazki k left join autorstwa at on k.id = at.ksi_id left join autorzy a on a.id = at.aut_id group by k.id having listagg(a.first_name ||' '|| a.last_name, ', ') within group (order by a.last_name) = 'a_name_1 & a_last_name_1' /
SY.
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Use of the place where and having clause
Hi all
I have always a doubt as to the use of HAVING and WHERE clause.
Suppose I have table T1 with a single column C1
CREATE TABLE T1
(C1 VARCHAR2 (1));
who data following INSERT scripts
INSERT INTO T1 VALUES ('A');
INSERT INTO T1 VALUES ('B');
INSERT INTO T1 VALUES('C');
INSERT INTO T1 VALUES ('A');
INSERT INTO T1 VALUES ('B');
INSERT INTO T1 VALUES ('A');
Now I want the result as follows
C1 = COUNT (C1)
==============
B = 2
A = 3
Then out of query 1 and 2, approach who is right?
(1) SELECT C1, COUNT (C1) FROM T1
WHERE C1 <>'C '.
GROUP BY C1
ORDER BY C1 DESC;
(2) SELECT C1, COUNT (C1) FROM T1
GROUP BY C1
SEEN C1 <>'C '.
ORDER BY C1 DESC;
Published by: user13306874 on June 21, 2010 02:36In SQL, it is always better to filter data as soon as possible of the moment.
In your example, the WHERE clause would be right now:SQL> explain plan for 2 select c1,count(c1) 3 from t1 4 where c1 != 'C' 5 group by c1 6* order by c1 desc; Explained. SQL> select * from table(dbms_xplan.display); PLAN_TABLE_OUTPUT ---------------------------------------------------- Plan hash value: 3946799371 ---------------------------------------------------- | Id | Operation | Name | Rows | Bytes | ---------------------------------------------------- | 0 | SELECT STATEMENT | | 5 | 10 | | 1 | SORT GROUP BY | | 5 | 10 | |* 2 | TABLE ACCESS FULL| T1 | 5 | 10 | ---------------------------------------------------- Predicate Information (identified by operation id): 2 - filter("C1"!='C') 18 rows selected. SQL>
As you can see that the filter is applied during the analysis of T1.
Whereas in the case of HAVING:
SQL> explain plan for 2 select c1,count(c1) 3 from t1 4 group by c1 5 having c1 != 'C' 6* order by c1 desc; Explained. SQL> select * from table(dbms_xplan.display); PLAN_TABLE_OUTPUT ---------------------------------------------------- Plan hash value: 3146800528 ---------------------------------------------------- | Id | Operation | Name | Rows | Bytes | ---------------------------------------------------- | 0 | SELECT STATEMENT | | 6 | 12 | |* 1 | FILTER | | | | | 2 | SORT GROUP BY | | 6 | 12 | | 3 | TABLE ACCESS FULL| T1 | 6 | 12 | ---------------------------------------------------- Predicate Information (identified by operation id): 1 - filter("C1"!='C') 18 rows selected. SQL>
The analysis is performed after all groups have been calculated: which was calculated in vain, because it will be further filtered because of the HAVING clause.
In general, I would like to use as a guide: If you do not use aggregate functions in your predicate in the HAVING clause, set this predicate to the WHERE of your query part.
Published by: Toon Koppelaars June 21, 2010 11:54
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PL/SQL parameter in fusion by using the clause
Hi all
I need to create a procedure where I use the Merge clause. However, by using the condition, I have to put value user_define (V_LOCALE_CD). This value checks table of locale and then to make a match with table of flex_labels_test.
There is no specific requirement and I don't have the test data.
My only question how do I use user set the value using the condition. Here is the procedure I created as follows.
create or replace the PROCEDURE UPSERT_FLEX_LABEL_3 (V_LOCALE_CD IN VARCHAR2,
V_VALUE IN VARCHAR2,
V_FIELDVALUE IN VARCHAR2,
V_FIELDNAME IN VARCHAR2,
V_TABLENAME IN VARCHAR2,
N_FLEX_TYPE NUMBER,
V_COLOR IN VARCHAR2 DEFAULT NULL,
N_IMAGE_LIBRARY_ID IN THE NUMBER DEFAULT NULL,
N_HIERARCHY_ID IN DEFAULT NUMBER 5237260000000000001,
N_IS_INHERITED IN THE DEFAULT NUMBER 1)
AS
L_COUNT NUMBER;
NUMBER OF N_LOCALE_ID;
NUMBER OF NN_HIERARCHY_ID: = 5237260000000000001;
NUMBER OF NN_IS_INHERITED: = 1;
NUMBER OF INSERTCOUNT;
UPDATECOUNT NUMBER;
NUMBER OF ERR_CODE;
ERR_MSG VARCHAR2 (100);
BEGIN
-SELECT ID IN N_LOCALE_ID OF PLACES WHERE LOCALE_CD = V_LOCALE_CD;
/ * IT WILL CHECK DUPLICATES, IF THEY ARE PRESENT, THEN IT WILL UPDATE RECORD ELSE IT WILL INSERT A NEW RECORD * /.
BEGIN
Merge into fl flex_labels_test
using (select locale id where locale_cd = V_LOCALE_CD) L
on (l.id = fl.locale_id)
When matched then
GAME UPDATE
HIERARCHY_ID = NVL (N_HIERARCHY_ID, NN_HIERARCHY_ID),
IS_INHERITED = NVL (N_IS_INHERITED, NN_IS_INHERITED),
FLEX_TYPE = N_FLEX_TYPE,
VALUE = V_VALUE,
IMAGE_LIBRARY_ID = N_IMAGE_LIBRARY_ID,
COLOR = V_COLOR
WHERE TABLENAME = V_TABLENAME
AND FIELDNAME = V_FIELDNAME
AND FIELDVALUE = V_FIELDVALUE
When not matched then
INSERT (HIERARCHY_ID, ID_PARAMETRES_REGIONAUX, IS_INHERITED, FLEX_TYPE, TABLENAME, FIELDNAME, FIELDVALUE, VALUE, IMAGE_LIBRARY_ID, COLOR)
VALUES (NVL (N_HIERARCHY_ID, NN_HIERARCHY_ID), N_LOCALE_ID, NVL (N_IS_INHERITED, NN_IS_INHERITED), N_FLEX_TYPE, V_TABLENAME, V_FIELDNAME, V_FIELDVALUE, V_VALUE, N_IMAGE_LIBRARY_ID, V_COLOR);
UPDATECOUNT: = NUMBER OF ROWS SQL %;
EXCEPTION
WHILE OTHERS THEN
ERR_CODE: = SQLCODE;
ERR_MSG: = SUBSTR (SQLERRM, 1, 200);
DBMS_OUTPUT. PUT_LINE ("ERRORS" |) ERR_CODE | ' AND ' | ERR_MSG);
END;
COMMIT;
DBMS_OUTPUT. PUT_LINE ('RECORD INSERTCOUNT =' |) NVL(INSERTCOUNT,0));
DBMS_OUTPUT. PUT_LINE (' UPDATECOUNT RECORD ='|) NVL(UPDATECOUNT,0));
EXCEPTION
WHEN NO_DATA_FOUND THEN
RAISE_APPLICATION_ERROR (-20001, "ID NOT FOUND REGIONAL SETTINGS");
END;
I guess that's what I was looking for. Thank you guys for your efforts.
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Not able to connect after changing the password using the VALUES ALTER clause
Hello
John explained earlier the clause VALUES below thread.
Status expired
I created a new account named SURI, and tried to use the password of the user account from the HR by using the VALUES clause. I was able to change the password but not able to connect SURI with HR password.
Please see below for details. And the SQL statements that I have tried.
Thank youSQL*Plus: Release 10.2.0.1.0 - Production on Mon Aug 13 18:44:50 2012 Copyright (c) 1982, 2005, Oracle. All rights reserved. Enter user-name: sys as sysdba Enter password: Connected to: Oracle Database 10g Express Edition Release 10.2.0.1.0 - Production SQL> SELECT password 2 FROM dba_users 3 WHERE username = 'HR'; PASSWORD ------------------------------ 4C6D73C3E8B0F0DA SQL> ALTER USER SURI IDENTIFIED BY VALUES '4C6D73C3E8B0F0DA'; User altered. SQL> SELECT password 2 FROM dba_users 3 WHERE username='SURI'; PASSWORD ------------------------------ 4C6D73C3E8B0F0DA SQL> conn suri/hr -- HR account's password is hr only ERROR: ORA-01017: invalid username/password; logon denied Warning: You are no longer connected to ORACLE. SQL>
SuriIts because you have used a different username.
Oracle produces a hash based on the user name and the password, not only the password.Therefore, you can not use the hashed password of a user to log on to the account of another user.
You need to get the password hashed Suri and then connect you to suri by using the password hashed Suri (using the identified by the syntax of values)
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How to use the "Order by" clause dynamically on values LOV Forms 10g r2
Hello
I have following requirement, please guide me.
1. create a list of values with 2 fields, Code and Description
2. do not use the command clause contained in the registration request Group
3. fix this LOV on a form field
4. when the user calls the user LOV will see two fields in LOV with header as Code and Description
5. when the user clicks the column header "Code" then LOV should be arranged on Code
6 and if the user clicks on the header of the column "Description" then LOV must be sorted on the Description
Thanks in advance.Please post this problem in this forum->
[Formulas Forum | http://forums.oracle.com/forums/forum.jspa?forumID=82]
And close this thread by he scored as replied. ;)
Kind regards.
LOULOU.
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Can I use the following script should set up rman DB only or non-rman configured DB
Hello
I need your help this following script
recover database using backup controlfile until Cancel;
I can only used in configured RMAN DB.
(or)
Can we used above usual script on database (IE. RMAN not configured the database)
Please suggest me. Thanks in advance.
If you use RMAN to create backup BackupSet, you use RMAN to RESTORE the database.
Subsequently, you can use RMAN or SQLPLUS to issue the command to RECOVER the DATABASE.
(RMAN has no clause 'using backup controlfile' because it identifies the controlfile as a backup, while sqlplus must use the following clause if the controlfile is a backup)
Hemant K Collette
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Database parameter determines the parallel clause?
Hi all
I come with a request that we can use the parallel clause in several ddl, dml statements etc, but where I got stucked was, what parameter in the database that controls or defines the parallel clause.
For example,.
What is the maximum that we can use for parallel.
Please help me in this
Search PARALLEL_MAX_SERVERS
This is the max in all concurrent sessions. If you are looking for a session limit, you will need to see if the resource manager is configured.
Hemant K Collette
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