value of multiple line in a single row (nclob)

Similar Questions

• Convert multiple lines in a single value separated by commas

  Is is possible to convert multiple lines in a single value by concatenating the value of each line in OBIEE. I think that IO had seem a blog related to this by I'm not able to find him. Essentially, here's what I would do:
  Number of customer location
  101
  101 NY
  101 PA
  102 TX
  102 CA
  
  This is to convert
  101. HE, NY, PA
  102 TX, CA
  
  Can you get it someone please let me know if this is possible and how to operate it.
  
  Thanks in advance for the help.

  You can do this by creating a DB function,

  Visit this link
  Re: Display of the horizontal values

  Thank you
  Vino

• How to insert multiple lines using a single query

  Hi all
  
  How to insert multiple lines using a single query to the emp table?
  I have the number of rows to insert into table x. consumes a lot of time. I tried to insert several lines using a single query, but get errors. I know exactly the query to do this.
  
  
  Thank you
  Sunil

  Like this?

  SQL> create table test(id number , dt date);
  
  Table created.
  
  SQL> insert into test values(&a,&b);
  Enter value for a: 1   --- It asked me and I entered 1
  Enter value for b: sysdate  --- It asked me and I entered sysdate
  old   1: insert into test values(&a,&b)
  new   1: insert into test values(1,sysdate)
  
  1 row created.
  
  SQL> 
  

  g.

• Compare the column values for multiple lines

  I am new to oracle and I have a requirement to compare the values of column across multiple lines.  If all column values are the same, I want to display that value, if the columns are not the same, I need to display 'no match' as value.   I need id to group values and display a status value based on the above logic.   Can anyone offer assistance with dispalying the result expected below?

  Sample

  Table

  State ID

  1         S

  2         L

  1         S

  2          S

  expected results

  State ID

  1         S

  2 no match

  
  

  Hello

  That's what you asked for:

  SELECT id

  CASE

  WHEN COUNT (DISTINCT status) > 1

  THEN "no match."

  For ANOTHER MIN (status)

  The END as status

  T

  GROUP BY id

  ;

  Want that if each State ID is NULL?  The CASE expression above returns NULL in this situation.

• SQL multiple columns in a single row

  Hi all
  
  I have 2 tables, product and Product_Name, a product can have several names.
  
  I need to recover what I show the Product_ID followed by all the names of this product has.
  
  I am not able to do, every way I try get the product ID duplicated several lines with a name of different product on each line as follows:
  
  ' 1, ' iron Z.
  1, "iron M.
  1, "iron N".
  2, 'wood P.
  2, 'wood M.
  
  What I need is:
  
  1, Z, M iron, iron N
  2, wood P, wood M
  
  Thank you and best regards.

  Hello

  user10103934 wrote:
  Thanks for the reply from Frank,

  Iron Z, iron and iron N M would be 3 different entries in the same column.

  I'm sure that the LISTAGG function should solve this problem, the problem is that I expected to find a solution on pure SQL or PL/SQL, perhaps with a nested Select statement.

  My version of Oracle's 10g Express Edition.

  LISTAGG is pure SQL, but it was introduced only in Oracle 11.2. All mentioned below should work in Oracle 10.

  The STRAGG from this page is very useful. You must copy and install approximately 60 line of PL/SQL code. Do it once, and then you can use hundreds of times in hundreds of motions, as if it were a built-in function. The main problem with STRAGG, it is difficult to get the output soprted. There is a modified version, designed for output sorted on this thread:
  http://asktom.Oracle.com/pls/asktom/f?p=100:11:0:P11_QUESTION_ID:15637744429336
  Never used. Can't vouch for it.

  SYS_CONNECT_BY_PATH seems to be the most popular way after the aggregation of the chain in Oracle 10. The example given on the page of the Oracle Base (that I posted in my last post) is a little clumsy and inefficient. See the next thread for a better example, using CONNECT_BY_ISLEAF:
  Re: Concatenate strings more lines in a single line.
  or, now that I see it, Pollywog example above.

  Published by: Frank Kulash, June 11, 2010 14:24

• Adding field values into multiple lines in a dynamic table

  Hello!

  I have create this form (timesheet) where I have a dynamic array with a variable number of lines (I'm adding instances with a single click of a button).

  All rows with a field of totalLinhaRelatorio , it is a time field and I need all of these fields to be added to get a total final.

  So, I tried these two lines of script (FormCalc):

  var finalTotal = sum (Time2Num (rio parteInferior.atividades.tabelaAtividades.linhaAtividade [*] [*] .totalLinhaRelato, "HH: mm"))

  $.formattedValue = Num2Time (finalTotal, "HH: mm")

  It doesn´t works as I expected. The field gets properly just the value of the first row.

  I tried other combinations, such as linhaAtividade.totalLinhaRelatorio [*] and .totalLinhaRelatorio linhaAtividade [*], but nothing seems to work.

  Help, please!

  Marcos
  

  You're welcome Marcos!

  Yes, it is possible, but I've never used FormCalc to do, preferring to JavaScript. As you use the time functions, it makes sense to stick with FormCalc.

  Take a look at the syntax here:

  http://help.adobe.com/en_US/livecycle/9.0/designerHelp/index.htm?content=000211.html.

  Hope that helps,

  Niall

• Combine multiple lines in a single line

  Hello

  I want the output of several data of line in a row.

  I try to display the supervisor of people and their supervisors and so on. I am able to display the Level1 supervisor and not able to display the next level.

  Here is the code:

  with

  Nobody like

  (select person_id 100299, employee_name 'VELASCO, OMAR' Union double all the)

  58293, select "UREÑA, PABLO" Union double all the

  Select 98539, 'USLENGHI, MATIAS slimani' Union double all the

  Select 68240, "Slimani, Mr. Vrishal A" Union double all the

  Select 72230, 'Harvey, Mr. Darin S' Union double all the

  Select 76200, 'CLARK, TIM MIDDLE EAST' of all the double union

  Select 67819, "BOEHLER, JEFF a." everything double union

  29202, select "FRADIN, ROGER" the double

  ),

  master_slave as

  (select 100299 slave, master 58293 Union double all the)

  Select 58293,98539 from all the double union

  Select 98539,68240 from all the double union

  Select 68240,72230 from all the double union

  Select 72230,76200 from all the double union

  Select 76200,67819 from all the double union

  Select 67819,29202 from all the double union

  Select 29202, the double null

  ),

  hierarchy as

  (select level lvl, sys_connect_by_path(slave,'|') path, max (level) on max_level)

  of master_slave

  where connect_by_isleaf = 1

  connect by slave = master prior

  ),

  Splitter (LVL, person_id, supervisor_1, supervisor_2, path) as

  (select lvl,

  regexp_substr (path '(\ |) [ ^|] +)', 1, 1, null, 1).

  regexp_substr (path '(\ |) [ ^|] +)', 1, 2, null, 1).

  regexp_substr (path '(\ |) [ ^|] +)', 1, 3, null, 1).

  regexp_replace (path,'^-|) [ ^|] +')

  of the hierarchy

  where lvl = max_level

  Union of all the

  Select lvl,

  regexp_substr (path '(\ |) [ ^|] +)', 1, 1, null, 1).

  regexp_substr (path '(\ |) [ ^|] +)', 1, 2, null, 1).

  regexp_substr (path '(\ |) [ ^|] +)', 1, 3, null, 1).

  regexp_replace (path,'^-|) [ ^|] +')

  between the separator

  where path is not null

  )

  Select person_id, to_number (ltrim(s.person_id,'|')),

  (select employee_name from person where person_id = to_number (ltrim(s.person_id,'|'))) employee_name,

  (select employee_name from person where person_id = to_number (ltrim(s.supervisor_1,'|'))) supervisor_1,

  (select employee_name from person where person_id = to_number (ltrim(s.supervisor_2,'|'))) supervisor_2

  s separator

  where s.person_id is not null

  order by length (s.path) desc nulls last

  PERSON_ID	Employee_name	SUPERVISOR_1	SUPERVISOR_2
  100299	VELASCO, OMAR	UREÑA, PABLO	USLENGHI, MATIAS slimani
  58293	UREÑA, PABLO	USLENGHI, MATIAS slimani	Slimani, Mr. Vrishal A
  98539	USLENGHI, MATIAS slimani	Slimani, Mr. Vrishal A	Harvey, Mr. Darin S
  68240	Slimani, Mr. Vrishal A	Harvey, Mr. Darin S	CLARK, TIM MIDDLE EAST
  72230	Harvey, Mr. Darin S	CLARK, TIM MIDDLE EAST	BOEHLER, JEFF HAS
  76200	CLARK, TIM MIDDLE EAST	BOEHLER, JEFF HAS	FRADIN, ROGER
  67819	BOEHLER, JEFF HAS	FRADIN, ROGER	-
  29202	FRADIN, ROGER	-	-

  Concerning

  Adrien

• Create views of data from multiple lines in a single column shows

  Hi all - it's probably posted in the wrong forum, but I couldn't find that was right.
  
  I'm almost a perfect beginner in sql, but I have a need to create a view that can be expanded to 10g (which effectively runs the volumes are likely to be high) who will do the following.
  
  Authentic table with columns Parent_code, Child_code
  Parent_Code Child_Code
  1000-2000
  1000-3000
  1000-4000
  2000 3000
  2000-5000
  
  (note that Parents may have several children and a child can have multiple parents!)
  
  What I have to finish with in my opinion is the following
  
  Child_Code Parent_List
  ' 2000 ' 1000 (3).
  3000 "1000 (3), 2000 (2)"
  ' 4000 ' 1000 (3).
  "5000 ' 2000 (2)"
  
  Note the number in parentheses is the number of children whose parent's - IE in the original parent a 1000, 3 table lines (one for each child)
  
  This point of view should be used as a quick glance upward (on the children's code) for a report of business objects.
  
  Is there someone who could you PLEASE, PLEASE help me quickly on what I have very little time to find a solution?

  Hello

  You can test these:

  select child_code
       , ltrim(sys_connect_by_path(parent_info,', '), ', ') as parent_list
  from (
    select child_code
         , to_char(parent_code) ||
           ' (' ||
           count(*) over(partition by parent_code) ||
           ')' as parent_info
         , row_number() over(partition by child_code order by parent_code) rn
    from your_table
  )
  where connect_by_isleaf = 1
  connect by prior rn = rn-1
         and prior child_code = child_code
  start with rn = 1
  ;
  

  select child_code,
         rtrim(
           extract(
             xmlagg(xmlelement("e",parent_info||', ') order by parent_info)
           , '//text()'
           )
         , ', '
         ) as parent_list
  from (
    select child_code,
           to_char(parent_code) ||
           ' (' ||
           count(*) over(partition by parent_code) ||
           ')' as parent_info
    from your_table
  )
  group by child_code
  ;
  

  What you need is called 'chain aggregation '.
  See here for the various techniques, including the two above: http://www.oracle-base.com/articles/misc/StringAggregationTechniques.php

• How elimate the grid lines in a single row of a table?

  I have a table that has 5 lines.  The table has a border of 1, so there are the grid lines.  How can I eliminate the horizontal border between the 1st row of row 2?

  There is never vertical grids.  You want to keep them?  Then, you need to use a slightly different approach.

  Consider this CSS-

  table {}

  border-collapse: collapse;

  border: 1px solid black;

  }

  TD {}

  border: 1px solid black;

  }

  TR. Top td {}

  border-bottom: none;

  }

  TR. Bottom td {}

  border-top: none;

  }

• Multiple lines in a single pipe delimited lines...

  Hi all
  
  I have the following data in multiple columns that should be converted online unique pipedelimited.
  Following is the example:
  
  DEPTNO ENAME
  ===== =====
  10A
  10 B
  10 C
  
  Now my requirement is to output, I should be able poster A | B | C|.........
  
  Note: The number of lines for any DEPTNO is not constant.
  
  Thank you
  Kalyan Kumar P

  The link that allowed to Hoek

  SELECT
         LTRIM(MAX(SYS_CONNECT_BY_PATH(ename,','))
         KEEP (DENSE_RANK LAST ORDER BY curr),',') AS employees
  FROM   (SELECT deptno,
                 ename,
                 ROW_NUMBER() OVER (PARTITION BY deptno ORDER BY ename) AS curr,
                 ROW_NUMBER() OVER (PARTITION BY deptno ORDER BY ename) -1 AS prev
          FROM   emp WHERE deptno=10)
  GROUP BY deptno
  CONNECT BY prev = PRIOR curr AND deptno = PRIOR deptno
  START WITH curr = 1
  

  If please visit once and read it.

  Kind regards
  Bobin

• Multiple lines in a single column in an SQL statement

  Can someone provide me with a simple sql that runs on the underside of the table (USERROLE table)
  
  ID ROLEUSER ROLENAME
  
  1 user1 GL
  User2 OBI_AP 2
  User1 3 OBI_AP
  User2 4 GL
  User1 5 OBI_AR
  User2 6 AR
  7 the GL util_3
  
  and give the result form
  
  ROLENAMES ROLEUSER
  
  User1 GL; OBI_AP; OBI_AR
  User2 OBI_AP; GL; AR
  the GL util_3
  
  
  Thank you
  Vikram

  Hello

  There is a similar thread, you can watch: concatenate the values of column in a row

  Kind regards

• Splitting of multiple lines on a single line with different fields

  Hi all
  
  I have a table. A Course_Code have section_codes several other words ('NUM' column is not sectype is just an order!)
  
  Code---num---Sec_code---Sectype---DESC---WEIGHT
  1603 1 - C 7427 - Coursework - 50
  1603--------2-------7428-----------E------------     Exam----------------     50
  
  I query this table I want to be able to see the course work, review divided on the same line. i.e.
  
  
  Code - Coursework - review
  1603 C = 50 - E = 50
  
  any help would be great

  Hello

  'Splitting' means take an element (such s as a string 'C = 50') and diviiding in smal; LER objects (such as the chains under "C" and "50"). Are you really trying to divide something, or are you trying to do exactly the opposite (for example, combine smaller chains in a larger string)?

  I think that what you are looking for is a Pivot . Like so many other things, exactly how do depends on your version of Oracle and your needs.
  Here's one way:

  SELECT       code
  ,       MIN (CASE WHEN descr = 'Coursework' THEN sectype END)
         ||  '='
         MIN (CASE WHEN descr = 'Coursework' THEN weight  END)     AS coursework
  ,       MIN (CASE WHEN descr = 'Exam'       THEN sectype END)
         ||  '='
         MIN (CASE WHEN descr = 'Exam'           THEN weight  END)     AS exam
  FROM       table_x
  GROUP BY  code
  ;
  

  It will work in Oracle 8.1 and higher. From Oracle 11.1, you can also use the SELECT... Function PIVOT.

  I hope that answers your question.
  If not, post a small example of data (CREATE TABLE and only relevant columns, INSERT statements) for all tables and also post the results desired from these data.
  Explain, using specific examples, how you get these results from these data.
  Always tell what version of Oracle you are using.

• Reg: Sys_Connect_By_Path: concatenation of multiple lines in a single line

  _*Oracle Version:*_
  Oracle Database 10g Express Edition Release 10.2.0.1.0 - Product
  PL/SQL Release 10.2.0.1.0 - Production
  CORE     10.2.0.1.0     Production
  TNS for 32-bit Windows: Version 10.2.0.1.0 - Production
  NLSRTL Version 10.2.0.1.0 - Production
  
  _Table Structure :_ 
  CREATE TABLE EMPTEST
  (
    EMPNO       NUMBER,
    TELEPHONE   NUMBER,
    STREETNAME  VARCHAR2(25 BYTE),
    CITY        VARCHAR2(2 BYTE),
    FLAG        VARCHAR2(1 BYTE),
    CONCAT1     CHAR(25 BYTE)
  )
  
  CREATE TABLE EMPTEST1
  (
    EMPNO       NUMBER,
    TELEPHONE   NUMBER,
    STREETNAME  VARCHAR2(25 BYTE),
    CITY        VARCHAR2(2 BYTE),
    FLAG        VARCHAR2(1 BYTE),
    CONCAT1     CHAR(25 BYTE)
  )
  
  INSERT INTO EMPTEST VALUES (102,88777,'JAC ST ',' ','Y',' ');
  INSERT INTO EMPTEST VALUES (102,0,'ROMA MAIN',' ','Y',' ');
  INSERT INTO EMPTEST VALUES (101,213566,' ',' ','Y',' ');
  INSERT INTO EMPTEST VALUES (101,0,'BLE ST',' ','Y',' ');
  INSERT INTO EMPTEST VALUES (101,0,' ','MT','Y',' ');
  
  INSERT INTO EMPTEST1 VALUES (102,88777,'JAC ST ',' ','Y',' ');
  INSERT INTO EMPTEST1 VALUES (102,0,'ROMA MAIN',' ','Y',' ');
  INSERT INTO EMPTEST1 VALUES (101,213566,' ',' ','Y',' ');
  INSERT INTO EMPTEST1 VALUES (101,0,'BLE ST',' ','Y',' ');
  INSERT INTO EMPTEST1 VALUES (101,0,' ','MT','Y',' ');

  ----------------------------------------------------------------------------------------------------------------------------------------------------------
  
  I am using the following query, That is expected and correct as well *.
  

  select EMPNO, ltrim(sys_connect_by_path(rtrim(CONCAT1,' '),';'),';') 
  EMPTEST1
  from (
  select EMPNO,
  row_number()over(partition by EMPNO order by EMPNO) rn,
  count(*)over(partition by EMPNO) cnt,
  CONCAT1
  from EMPTEST 
  )
  where 
  level = cnt
  start with rn=1
  connect by prior rn=rn-1
  and prior EMPNO=EMPNO

  I my get the output like

  {table}
  EMPNO     EMPTEST1
  
  101     213566  Y;0BLE ST Y;0 MTY
  102     88777JAC ST  Y;0ROMA MAIN Y
  {table}

  I always get 2500 records in my ouptut, even if I have more than 30 000.
  
  If I sys_connect_by_path manage no more than 2500... Someone can give me a reason why it handles no more than 2500 and how do I handle if I get more than 30000 reocrds
  
  Thank you
  Ananda
  
  Published by: Ananda on July 12, 2010 20:25

  Ananda says:
  I always get 2500 records in my ouptut, even if I have more than 30 000.

  If I sys_connect_by_path manage no more than 2500... Someone can give me a reason why it handles no more than 2500 and how do I handle if I get more than 30000 reocrds

  SYS_CONNECT_BY_PATH covers the CHAR/VARCHAR2 data type and returns a VARCHAR2. And VARCHAR2 limit is 4000 bytes. As soon as you exceed it it will be a mistake. Use rather XMLAGG. For example:

  SQL> select  xmlagg(xmlelement(e,ename,' ').extract('//text()')) ename
    2    from  emp
    3    group by deptno
    4  /
  
  ENAME
  ------------------------------------------------------------
  CLARK KING MILLER
  SMITH FORD ADAMS SCOTT JONES
  ALLEN BLAKE MARTIN TURNER JAMES WARD
  
  SQL> 
  

  SY.

• Multiple lines in a single count

  Hello
  
  I have a table (join actually) similar to the following:
  
  Tree leaf... TLigne
  1... 1... 1
  1... 2... 2
  2... 3... 1
  3... 4... 2
  3... 5... 3
  3... 6... 3
  3... 7... 3
  
  What would be the best approach if I wanted to count the frequency of each type of leaf per tree?
  The goal contains a line for each tree and three different columns representing
  the number of occurrences of each journal type.
  
  Example:
  
  tree... LT1... LT2... LT3
  1... 1... 1... 0
  2... 1... 0... 0
  3... 0... 1... 3
  
  Thanks for any help.

  >

  Select tree, sum (decode (TLigne, 1, 1, 0)), sum (decode (TLigne, 2, 1, 0)), sum (decode (TLigne, 3, 1, 0)))

  Select 1 tree, 1 extension, 1 TLigne of all the double union

  Select TLigne 1,2,2 Union double all the

  Select TLigne 2,3,1 Union double all the

  Select 3,4,2 TLigne from all the double union

  Select TLigne 3,5,3 of all the double union

  Select 3,6,3 TLigne from all the double union

  Select 3,7,3 double TLigne

  )

  Group by tree

  Kind regards
  Ritesh

  Published by: Ritesh Kumar S on December 25, 2008 15:56

• How to display the first value in the line in the second row and the second value of the line on the third row and so on...

  Hi all

  I have a requirement as below.

  Select * from my_tab;

  col1 col2 col3

  1 test1 January 1, 2014

  Test2 2 2 January 2013

  3 test5 February 9, 2015

  I need to display it as below.

  col1 col2 col3 req_col

  -----------------------------------------------------

  1 test1 January 1, 2014

  2 test2 January 2, 2013 January 1, 2014

  3 February 9, 2015 test5 January 2, 2013

  So how do?

  If it is not possible with sql then suggest me to do in peblisher xml (in rdf or rtf)

  Hello

  jagadekara wrote:

  Hi all

  I have a requirement as below.

  Select * from my_tab;

  col1 col2 col3

  1 test1 January 1, 2014

  Test2 2 2 January 2013

  3 test5 February 9, 2015

  I need to display it as below.

  col1 col2 col3 req_col

  -----------------------------------------------------

  1 test1 January 1, 2014

  2 test2 January 2, 2013 January 1, 2014

  3 February 9, 2015 test5 January 2, 2013

  So how do?

  If it is not possible with sql then suggest me to do in peblisher xml (in rdf or rtf)

  In SQL, you can use the analytic LAG function.

  http://docs.Oracle.com/database/121/SQLRF/functions093.htm#sthref1544

  Because I don't have a copy of your table, I'll use scott.dept to illustrate:

  SELECT DeptNo

  dname

  loc

  , Trolling (loc) over (ORDER BY deptno) AS prev_loc

  OF scott.dept

  ORDER BY deptno

  ;

  Output:

  DEPTNO DNAME LOC PREV_LOC

  ---------- -------------- ------------- -------------

  10 ACCOUNTS NEW YORK

  SEARCH 20 DALLAS NEW YORK

  30 SALES CHICAGO DALLAS

  40 OPERATIONS BOSTON CHICAGO