VALUES NOT IN AND NULL

Similar Questions

• How to return a NULL value in LOV and insert into a field of allowingNULL number 4?

  Hello
  
  I have the following LOV and the return_value is PeopleId which is number 4, allowing NULL. And the LOV options are as follows:
  
  LOV named--> select named LOV-
  Show Extra values-> no
  Dynamic translation-> - untranslated-
  The number of columns - > 1
  Display Null-> Yes
  Null-> - Select value-
  Return NULL,-> NULL value
  ^^^^^^^^^^^^^^^
  
  ----------------
  
  List of values definition:
  Select Lname | ', ' || Fname | ' ' || Mname as display_value, PeopleId as return_value
  of PEOPLETB
  where PEOPLETYPE ('i', 'HERE', 'IF')
  order by 1
  --------------
  
  Given that PoepleId is a number 4, allowing NULL. I want a NULL value will be inserted, if the user does not select anything in the drop-down list. It seems that I would get "ORA-01722: invalid number" error when the PeopleId msg is null (ie: user doesn't have a selection). What is the good 'return Null value' I need to put it in? I tried "NULL" (see above) or nothing, it still does not work.
  
  Any suggestions?
  
  Thank you very much
  Helen

  Hello Helen,.

  You have found one of the many sources of my frustration with APEX. Here's what I do:

  In the definition of the element in your page, go to the LOV part and implemented like this:

  Display Extra values: Yes a dynamic conversion (I ignore this)
  Number of columns: 1 display Null: No.
  Display null value: (leave blank) return Null value: (leave blank)

  An empty row is displayed when the user comes first to the screen. If they do NOT select the drop-down list, the value is left empty (null).

  If anyone has a better way, I will definitely experiment with it.

  Don.

• using script to get the values of percentage and not able to sum up to 100%

  Hi all

  I am trying to use a parseFloat() function to convert the string value as a percentage, and then try to add all the values of %.

  but for a few scenrios even if the amount is 100% of the service I get the PctValue be <>100.00%

  the calculation of the function is as follows: -.

  code-

  {iterating_through_all_the_fields}

  PctValue += parseFloat (this.getField("Percentage1").valueAsString);

  }

  sample-

  11.12

  11.11

  11.11

  11.11

  11.11

  11.11

  11.11

  11.11

  11.11

  amount is 100

  but through code mentioned above I return 99.99

  Any help is appreciated in this regard.

  It is a result using the floating point IEEE standard and conversion from decimal to binary values values. We need to round up all the calculations of money or mils will accumulate and cause errors. For percentages, it is better to round up receipts and total final eliminate the accumulation of amounts below the figure the least significant.

  It is possible to use the util.printf of rounding.

  The following script will show what is happening:

  function Round (nValue, nDec) {}
  If (typeof nDec == "undefined") nDec = 0;
  Return number (util.printf ('%, 1 0. nDec + "f", Number (nValue)));
  }

  var nValues = new Array (11.12 11.11 11.11, 11.11, 11.11, 11.11, 11.11, 11.11, 11.11);
  nSum var = 0;
  for (var i = 0; i)< nvalues.length;="" i++="" )="">
  nSum = nSum + Round (nValues [i], 2);
  Console.println (i + "" + nValues [i] + "" + nSum);
  }
  Console.println (nSum);
  nSum = Round (nSum, 2);
  Console.println (nSum);

  Progression of the sum at each stage.
  0 11,12 11.12
  1 11.11 22.229999999999997
  2 11.11 33.339999999999996
  3 11.11 44.449999999999996
  4 11.11 55.559999999999995
  5 11.11 66.66999999999999
  6 11.11 77.77999999999999
  7 11.11 88.88999999999999
  8 11.11 99.99999999999999
  99.99999999999999
  100

  true

  It's a good idea to use decimal values a percentage and leave the determination of the field format display and the borough. But for applications of the sum, the user can round up the value of the actual field and not only display.

• After that download site on the internet Web browser says page not found, file 'null' is not found.  Also in the Muse I can't preview the site or pages more. Never had a problem and now I don't know what to do. In Safari and Google Chrome it

  After that download site on the internet Web browser says page not found, file 'null' is not found.  Also in the Muse I can't preview the site or pages more. Never had a problem and now I don't know what to do. In Safari and Google Chrome there is no problem on the internet, but I can't be seen.

  OK, so your last post, it seems the widgets are the cause of the problem. Let's see if we can understand why:

  • Have you tried to create a NEW Widget of emptiness of Composition and which fill with new content?
  • Have you tried a full download instead of only changed files?
  • Also can you check with domain host that send you to the right directory, and whether or not they have made changes to the ftp upload?
  • When you export the site in HTML format instead of FTP download and compare the files that are generated in the HTML folder, they are identical to those published via FTP?

  If this does not help, it would be useful that you could provide us some screenshots of errors you are seeing, you use parameters of publication etc. (you can block-out user name and password for security reasons of course).

  CARI

• Join does not work for NULL values on the join condition

  Hello
  
  I have the following problem.
  
  SQL > select * from a;
  
  X Y
  ---------- --------------------
  1
  2
  3
  4
  
  SQL > select * from b;
  
  A:
  ---------- --------------------
  1
  2
  
  
  
  SQL > select f.x, f.y, s.b in f, s b
  2 where f.x = s.b (+);
  X Y B
  ---------- -------------------- ----------
  1 1
  2 2
  4
  3
  
  
  
  
  SQL > select f.x, f.y, s.b in f, s b
  2 where f.x = s.b (+)
  3 and f.y = s.y;
  
  no selected line
  
  
  So now if I include a join condition more where null = null situation arises, it's working now.
  Just tell her not to treat (1 and null) (1 and null) are the same.
  What is the solution. This is an expected behavior.
  
  
  Thank you
  Pramod Garre

  Pramod salvation,

  Another way to use the outer join is,

  Select f.x, f.y, s.b
  of a, f, s b
  where f.x = s.b (+)
  and nvl(f.y,0) = nvl (s.y (+), 0);

  Hope this will help you.

  Thank you
  Amit

• Checkbox value not passed during validation

  Hello

  JDev 11.1.2.4

  I have an EO/VO with an IsCmt attribute, which is the card to a database VARCHAR field (1), the possible values are Y and N. In the VO, advice of the UI control type is set to the box.

  In the page fragment, the VO is displayed in a table, and the field is displayed in the column with a check box. So far so good.

  I have also written a converter to handle the O/N conversion to Boolean.

  public class BooleanConverter implements converter, {ClientConverter}

  public Object getAsObject (FacesContext facesContext, UIComponent uiComponent, String value) {}

  return "" true ".equals (value)?". Y":"N";

  }

  public String getAsString (FacesContext facesContext, UIComponent uiComponent, Object value) {}

  Return "Y".equals (value)? "true": "false";

  }

  }

  The line contains Y, and if I use row.bindings.IsCmt.inputValue, the check box is not checked, but if I use the line. IsCmt, the box is checked.

  "<!-< af:selectBooleanCheckbox value =" #{row.bindings.IsCmt.inputValue} "label =" #{row.bindings.IsCmt.label} ".

  shortDesc = "#{bindings." BrdMassOtherDel1.hints.IsCmt.tooltip}"id ="sbc2 ".

  Converter = "booleanConverter" / >-->

  < af:selectBooleanCheckbox value = "#{rank." IsCmt}"label =" #{row.bindings.IsCmt.label} ' "

  shortDesc = "#{bindings." BrdMassOtherDel1.hints.IsCmt.tooltip}"id ="sbc2 ".

  Converter = "booleanConverter" / >

  Then I click on the box to deselect it, then validate. Before validation, the converter is called to convert "false" to "N". The correct SQL is generated by the validation, but the value passed is null and no "N".

  I don't understand why?

  Thank you

  You don't need all that.

  Delete the user interface control indicators.

  When table is deleted, do not drop this attribute. Instead, drop off separately, then choose

  

  You will be asked for the State selected and Unselected.

  Choose Y and N

• Remove the table if the value not in APEX_APPLICATION. G_f01?

  Hello again!

  I have an apex_application.g_f01 that contains the values in the boxes, now I want apex to remove rows from the table that contains values that are not present in the G_f01 (what are disabled) on submit.

  I can't understand the sql code to do this, could someone give an example?

  This can be a simple thing, but I'm getting confused a lot with sql, maybe because I just php and java.

  EgaSega wrote:

  I have an apex_application.g_f01 that contains the values in the boxes, now I want apex to remove rows from the table that contains values that are not present in the G_f01 (what are disabled) on submit.

  I can't understand the sql code to do this, could someone give an example?

  This can be a simple thing, but I'm getting confused a lot with sql, maybe because I just php and java.

  One possibility would be to create a collection of APEX containing key checked values and use that as the source of the lines to be kept in the SQL delete. Something like:

  begin
  
    apex_collection.create_or_truncate_collection('CHECKED_VALUES');
  
    for i in 1..apex_application.g_f01.count
    loop
      apex_collection.add_member(
          p_collection_name => 'CHECKED_VALUES'
        , p_c001 => apex_application.g_f01(i));
    end loop;
  
    delete from t
    where not exists (select
                         null
                     from
                          apex_collections c
                     where
                         collection_name = 'CHECKED_VALUES'
                     and c.c001 = t.id);
  
  end;
  

• test for the null value to IN request (null, 'a ', ' b', 'c')

  Hello

  Oracle 10.2.0.4

  I think the following query is incorrect, in my opinion. (there is an index on the collar, but NULL values are ignored?

  SELECT COUNT (*) < table > where col in (null, 'a ', ' b', 'c')

  It works (no errors) and forth fast enough.

  However, I think the correct query would

  SELECT COUNT (*) < table > where IS NULL or neck neck ('a', 'b', 'c')

  It takes a lot of time. As I see it, he performs a table scan for part of the value NULL and use the index for the rest, as the index cannot be used for NULL values.

  I would appreicate an explanation on this matter, particularly why Oracle accepts the first query "where col in (null, 'a ', ' b', 'c')" without any problem.

  Thank you

  A null value is not equal to what whatsoever, not even another null value. This is consistent with the definition of the ANSI. For your first request is not what you think it does, even if it is not syntactically incorrect.

  The second query is correct. If you want to use an index, you must create a bitmap index (which requires Enterprise Edition licenses), because they do not include the values NULL, unlike B * tree index.

• Difference between the operator NOT EXISTS and NOT IN

  Hi experts,

  I understand that this question has been asked several times, but I would like to have a clear understanding of the following:

  SELECT MEANING FROM FND_LOOKUPS WHERE LOOKUP_TYPE='WIS_WORK_DEFINITION_NAME';
  

  The results are:

  Spare

  Main working definition

  Rework

  Test

  User_Defined_WD

  Check

  I have run this query:

  select work_definition_name from  WIS_WORK_DEFINITIONS WSD WHERE WSD.ORGANIZATION_ID=207 AND WSD.INVENTORY_ITEM_ID=2686;;

  The query gives output below:

  MAIN

  REWORK

  When I run the sub query, I expect no result because the inner query in the NOT IN operator returns a NULL value.

  Query -1: the query is:

  SELECT fl.meaning FROM fnd_lookups fl WHERE fl.lookup_type='WIS_WORK_DEFINITION_NAME' AND fl.lookup_code NOT in
  (SELECT NULL FROM wis_work_Definitions wsd WHERE wsd.organization_id=207 AND wsd.inventory_item_id=2686
  AND  fl.lookup_code=wsd.work_Definition_name);
  

  If the inner query returns null, the query gives the result:

  Spare

  Test

  User_Defined_WD

  Check

  I was under the assumption that if the inner query returns null, then the global query would return no data. Example:

  Query-2:

  SELECT fl.meaning fl fnd_lookups WHERE fl.lookup_type = 'WIS_WORK_DEFINITION_NAME' fl.lookup_code AND NOT IN (SELECT NULL FROM dual);

  The query above pulled out no data as the inner query returned NULL. What I failed to understand was the difference between the query-1 and query-2.

  While Query1 returns data, query-2 not return all the data.

  There is no apparent difference between these two queries, because of the last sentence of your NOT IN query:

  AND fl.lookup_code = wsd.work_Definition_name

  Consider the row where lookup_code = HAND. The NOT IN query is a single line in wis_work_definitions where wsd.organization_id = 207 AND wsd.inventory_item_id = 2686 AND 'MAIN' = wsd.work_Definition_name. If your queries are actually like that for this line:

  SELECT fl.meaning fl fnd_lookups WHERE fl.lookup_type = 'WIS_WORK_DEFINITION_NAME' AND fl.lookup_code = 'MAIN' fl.lookup_code AND NOT in ('HAND')

  SELECT fl.meaning fl fnd_lookups WHERE fl.lookup_type = 'WIS_WORK_DEFINITION_NAME' AND fl.lookup_code = 'MAIN' fl.lookup_code AND NOT in (NULL)

  No one who will return a line, for reasons that are obvious, hopefully.

  Now consider the row where lookup_code = TEST. The NOT IN query finds a no line in wis_work_definitions where wsd.organization_id = 207 AND wsd.inventory_item_id = 2686 AND 'TEST' = wsd.work_Definition_name. A list NOT IN containing no words can be ignored, so the two queries become like this:

  SELECT fl.meaning fl fnd_lookups WHERE fl.lookup_type = 'WIS_WORK_DEFINITION_NAME' AND fl.lookup_code = 'TEST'

  Which returns a line.

  So the effect of these two queries is to return all values except those that appear in that particular (set of) definition (s) of work.

• Value not found in list field options...

  Hello
  I use RIDC on UCM 11 g in order to record content.
  UCM hosts different projects.
  I have the following problem: If someone (from another project) insert a new field of Information (e.g. xAnnoPubblicazione) of type Integer - list of options - select validated list and it's not a default value for this field when I perform the consignment using RIDC, it fails with the error:
  
  "oracle.stellent.ridc.protocol.ServiceException:"UCMRE010132"piece of content has not been verified successfully." Value not found in a permit the list of options for the field 'xAnnoPubblicazione '.
  
  How can I solve this problem? What is the recommended method?
  
  Thank you very much.
  
  Best regards
  S.

  In the language of database, you created a NON NULL column, and that you are trying to insert a record with a NULL value for the column. Of course, it cannot work.

  There are three options:

  -do not declare a field as NOT NULL (i.e. you option list must contain "blank" as possible value)
  -provide value when inserting
  -provide the default value

• difference between IS NULL and = NULL

  Hello guys,.
  
  10 gr 2, what is the difference between IS NULL and = NULL
  
  Thank you
  Imran

  NULL is not equal to zero or a specific value
  NULL means unknown

  the first form will work, given that the value of a field may be unknown (= IS NULL)

  the other will not work, because a specific value is not equal to unknown
  the first is the correct form, the second will always be false
  same NULL = NULL can be distorted, because unknown is unknown

• to fill the gaps with value of lead and the delay and make average and the gap between earned

  Thanks in advance
  
  I have table as below

  ID          TYPE     NUM     NAME     BEG_MP     END_MP     VALUE
  10001103N     3     1190001     WST     0.000     0.220     
  10001103N     3     1190002     WST     0.220     0.440     
  10001103N     3     1190003     WST     0.440     0.820     12800
  10001103N     3     1190003     WST     0.820     1.180     12800
  10001103N     3     1190004     WST     1.180     1.220     
  10001103N     3     1190004     WST     1.220     1.300     
  10001103N     3     1190005     WST     1.300     1.420     14800
  10001103N     3     1190005     WST     1.420     1.550     14800
  10001103N     3     1190006     WST     1.550     2.030     
  10001103N     3     1190006     WST     2.030     2.660     
  10001103N     3     1190007     WST     2.660     2.780     

  What I need is to fill the gaps with value of lead and the delay and make average and the gap between the values
  

  ID          TYPE     NUM     NAME     BEG_MP     END_MP     VALUE
  10001103N     3     1190001     WST     0.000     0.220     12800 ---> Lag value
  10001103N     3     1190002     WST     0.220     0.440     12800 ---> Lag Value
  10001103N     3     1190003     WST     0.440     0.820     12800
  10001103N     3     1190003     WST     0.820     1.180     12800
  10001103N     3     1190004     WST     1.180     1.220     13800 ---> Avg(12800,14800)
  10001103N     3     1190004     WST     1.220     1.300     13800 ---> Avg(12800,14800)
  10001103N     3     1190005     WST     1.300     1.420     14800
  10001103N     3     1190005     WST     1.420     1.550     14800
  10001103N     3     1190006     WST     1.550     2.030     14800 ---> Lead Value
  10001103N     3     1190006     WST     2.030     2.660     14800 ---> Lead Value
  10001103N     3     1190007     WST     2.660     2.780     14800 ---> Lead Value

  create table AVG_TABLE
  (
    ID     VARCHAR2(20),
    TYPE   NUMBER,
    NUM    NUMBER,
    NAME   VARCHAR2(10),
    VALUE  NUMBER,
    BEG_MP NUMBER(6,3),
    END_MP NUMBER(6,3)
  )
  ;
  
  insert into AVG_TABLE (ID, TYPE, NUM, NAME, VALUE, BEG_MP, END_MP)
  values ('10001103N', 3, 1190001, 'WST', null, 0, .22);
  insert into AVG_TABLE (ID, TYPE, NUM, NAME, VALUE, BEG_MP, END_MP)
  values ('10001103N', 3, 1190002, 'WST', null, .22, .44);
  insert into AVG_TABLE (ID, TYPE, NUM, NAME, VALUE, BEG_MP, END_MP)
  values ('10001103N', 3, 1190003, 'WST', 12800, .44, .82);
  insert into AVG_TABLE (ID, TYPE, NUM, NAME, VALUE, BEG_MP, END_MP)
  values ('10001103N', 3, 1190003, 'WST', 12800, .82, 1.18);
  insert into AVG_TABLE (ID, TYPE, NUM, NAME, VALUE, BEG_MP, END_MP)
  values ('10001103N', 3, 1190004, 'WST', null, 1.18, 1.22);
  insert into AVG_TABLE (ID, TYPE, NUM, NAME, VALUE, BEG_MP, END_MP)
  values ('10001103N', 3, 1190004, 'WST', null, 1.22, 1.3);
  insert into AVG_TABLE (ID, TYPE, NUM, NAME, VALUE, BEG_MP, END_MP)
  values ('10001103N', 3, 1190005, 'WST', 14800, 1.3, 1.42);
  insert into AVG_TABLE (ID, TYPE, NUM, NAME, VALUE, BEG_MP, END_MP)
  values ('10001103N', 3, 1190005, 'WST', 14800, 1.42, 1.55);
  insert into AVG_TABLE (ID, TYPE, NUM, NAME, VALUE, BEG_MP, END_MP)
  values ('10001103N', 3, 1190006, 'WST', null, 1.55, 2.03);
  insert into AVG_TABLE (ID, TYPE, NUM, NAME, VALUE, BEG_MP, END_MP)
  values ('10001103N', 3, 1190006, 'WST', null, 2.03, 2.66);
  insert into AVG_TABLE (ID, TYPE, NUM, NAME, VALUE, BEG_MP, END_MP)
  values ('10001103N', 3, 1190007, 'WST', null, 2.66, 2.78);
  commit;

  Hello

  Use LEAD and LAG when you know exactly how far is the target line (for example, if you know the desired value is on the next row).
  If you don't know exactly how far is the target line, then FIRST_VALUE and LAST_VALUE are more likely to be useful.

  WITH     got_neighbors     AS
  (
       SELECT     avg_table.*
       ,     LAST_VALUE (value IGNORE NULLS) OVER (ORDER BY beg_mp)          AS prev_value
       ,     LAST_VALUE (value IGNORE NULLS) OVER (ORDER BY beg_mp DESC)     AS next_value
       FROM     avg_table
  )
  SELECT       id, type, num, name, beg_mp, end_mp
  ,       COALESCE ( value
               , ( NVL (prev_value, next_value)
                 + NVL (next_value, prev_value)
                 ) / 2
               )     AS value
  FROM       got_neighbors
  ORDER BY  beg_mp to f
  ;
  

  Riedelme is correct: LAG LEAD (as well as FIRST_VALUE and LAST_VALUE) can return only the values that are there (or that you give as default values). This means that you can not solve this problem with these functions alone; you need something else (as NVL, above) to provide value when the function does not find it.

• SQL error: ORA-01840: value not long enough for the format of the date of entry

  It is a delete SQL in a driver of demand, which gives no error, but does remove all the lines either. I have converted the removal 'from' to ' Select * ' and may see the following error:
  
  Select * FROM PS_GPDE_DV_TRIG40 WHERE EXISTS (SELECT FROM 'X'
  PS_GPDE_DV_ELIG_MO ELG WHERE ELG. EMPLID = PS_GPDE_DV_TRIG40. EMPLID AND
  ELG. EMPL_RCD = PS_GPDE_DV_TRIG40. EMPL_RCD AND TO_DATE (TO_CHAR (ELG. PRD_END_DT
  "YYYY"). TO_CHAR (ELG. PRD_END_DT, "MM"). '01', "YYYY-MM-DD") =.
  PS_GPDE_DV_TRIG40. GPDE_DV_EVT_EFFDT AND ELG. CAL_RUN_ID = "CAL_0812")
  Error report:
  SQL error: ORA-01840: value not long enough for the format of the date of entry
  
  
  The interesting thing is that if I attach a condition of emplid, then the SQL above does not give an error and return lines:
  
  Select * FROM PS_GPDE_DV_TRIG40 WHERE EXISTS (SELECT FROM 'X'
  PS_GPDE_DV_ELIG_MO ELG WHERE ELG. EMPLID = PS_GPDE_DV_TRIG40. EMPLID AND
  ELG. EMPL_RCD = PS_GPDE_DV_TRIG40. EMPL_RCD AND TO_DATE (TO_CHAR (ELG. PRD_END_DT
  "YYYY"). TO_CHAR (ELG. PRD_END_DT, "MM"). '01', "YYYY-MM-DD") =.
  PS_GPDE_DV_TRIG40. GPDE_DV_EVT_EFFDT AND ELG. CAL_RUN_ID = "FM_CG_0812")
  and emplid = "1234"
  
  now, if the number of lines is identified (by giving more number of emplids), it begins to give the error when the number of rows returned is greater than about 30. It is completely independent of what employee is used, so there is no question of data dependence.
  
  Function optimizer cost is off and a subquery nest is off on the init.ora file
  
  subquery UNNEST= false
  
  optimizercost_based_transformation = off
  
  
  I don't know if it has something to do with this problem.
  
  Explanations would be welcome!
  
  Thank you
  Vikas

  I think it is question of data combined with a not very sensible date format mask (it could fail when the null data, because of your concatenation with '01' and work when not null data).
  Have you tried with a simple TRUNC?

  Your code:

  ...TO_DATE(TO_CHAR(ELG.PRD_END_DT, 'YYYY') || TO_CHAR(ELG.PRD_END_DT , 'MM') || '01' , 'YYYY-MM-DD') =PS_GPDE_DV_TRIG40.GPDE_DV_EVT_EFFDT...
  

  After change:

  ...TRUNC(ELG.PRD_END_DT , 'MM') =PS_GPDE_DV_TRIG40.GPDE_DV_EVT_EFFDT...
  

  Nicolas.

• How so avoid during a search, opening a new page or using the mouse-it flips page not found and "cltrda".

  How can I prevent the "page not found and cltrda information opening instead of my search?

  Try to use the extension SearchReset reset preferences to default values.

  • https://addons.Mozilla.org/firefox/addon/SearchReset/

  Note that the SearchReset extension runs only once and then uninstalls automatically, so it will not appear on the page "> Firefox Add-ons" (topic: addons).

  If you don't keep changes after a reboot then see:

  • http://KB.mozillazine.org/Preferences_not_saved
  • http://KB.mozillazine.org/about:config

• Look for the logic find the value of m and c of this equation y = mx + c.

  Hello

  I have 4 points for example = 3.38276, 0.375866 xi

  Yi = 3.37749, 0.281924

  using this tip, I want to find the value of m and c.

  You please suggest me some logic to solve this equation using labview programming.

  I tried with one solution, but in this case I do not have the correct answer. Here as an attachment, there is vi help I tried to solve my equation, but in this case the value that never got as a response it is dissatisfied with the equation, means if I replace the value of m and c eqation then it must be L.H.S = R.H.S, but I don't have the right solution.

  You please guide me.

  Thank you very much.

  Why do you think that the results are incorrect? I put your numbers in your code and the result on a XY Chart Wescott, I then bunk which with more than 20 values with a value ranging from 0.6 to 3.2 x and use factors calculated in your code to generate values of Y. The two overlap almost exactly...

  Mike...

  BTW: There is a linear adjustment integrated into LV VI