view the date to which I didn't get the interview
HelloI have interview_detail table with two columns
1. the date of the interview
2 personname
with the following data
Interview_ detail
Interview date personname
ARP / 10/09 aa
12 / Arp / 09 bb
13-Arp-09 aa
15-Arp-09 cc
17 / Arp / 09 dd
20 / Arp / 09 bb
21-Arp-09 aa
25-Arp-09 aa
27 Arp-09 aa
30 / Arp / 09 bb
In the table, the data is inserted only at the interview was taken and who took the interview
My question is I want to display the date to which I didn't get the interview
should be like this
ARP-11-09
14 / Arp / 09
16 / Arp / 09
18 Arp--09
ARP-19 / 09
22-Arp-09
ARP-23 / 09
ARP-24 / 09
ARP-26 / 09
28 / Arp / 09
ARP-29 / 09
PL give some examples for this
Thank you
>
Well, you hard 10 April 09 and you hardcoded the difference between the first and lst interview dates. Generic solution would be:
with interview_detail as (
select to_date('10-Apr-09','dd-mon-yy') interview_date,'aa' personname from dual union all
select to_date('12-Apr-09','dd-mon-yy'),'bb' from dual union all
select to_date('13-Apr-09','dd-mon-yy'),'aa' from dual union all
select to_date('15-Apr-09','dd-mon-yy'),'cc' from dual union all
select to_date('17-Apr-09','dd-mon-yy'),'dd' from dual union all
select to_date('20-Apr-09','dd-mon-yy'),'bb' from dual union all
select to_date('21-Apr-09','dd-mon-yy'),'aa' from dual union all
select to_date('25-Apr-09','dd-mon-yy'),'aa' from dual union all
select to_date('27-Apr-09','dd-mon-yy'),'aa' from dual union all
select to_date('30-Apr-09','dd-mon-yy'),'bb' from dual
)
select min_dt + level - 1 no_interview_date
from (
select min(interview_date) min_dt,
max(interview_date) max_dt
from interview_detail
)
connect by level <= max_dt - min_dt + 1
minus
select interview_date
from interview_detail
/
NO_INTERVIEW_DATE
--------------------
11-APR-09
14-APR-09
16-APR-09
18-APR-09
19-APR-09
22-APR-09
23-APR-09
24-APR-09
26-APR-09
28-APR-09
29-APR-09
11 rows selected.
SQL>
SY.
Tags: Database
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