Wise Dept sum sal differece

Similar Questions

• Wise Cumulatve sum line lines

  my tables are 
  CREATE TABLE LHEADER
  (HDT DATE,
  HSR NUMBER,
  HCODE VARCHAR2(6),
  HAMOUNT NUMBER);
  
  INSERT INTO LHEADER VALUES (TO_DATE('01012009','DD/MM/YYYY'),1,101,5000);
  INSERT INTO LHEADER VALUES (TO_DATE('01022009','DD/MM/YYYY'),2,102,3000);
  INSERT INTO LHEADER VALUES (TO_DATE('01032009','DD/MM/YYYY'),3,103,6000);
  
  CREATE TABLE DDETAIL
  (DDT DATE,
  DHSR NUMBER,
  DHCODE VARCHAR2(6),
  DAMOUNT NUMBER,
  D1 NUMBER,
  D2 NUMBER,
  D3 NUMBER);
  
  INSERT INTO DDETAIL VALUES (TO_DATE('31012009','DD/MM/YYYY'),1,101,1500,NULL,NULL,10);
  INSERT INTO DDETAIL VALUES (TO_DATE('31012009','DD/MM/YYYY'),1,101,NULL,20,15,20);
  INSERT INTO DDETAIL VALUES (TO_DATE('28022009','DD/MM/YYYY'),1,101,NULL,20,12,20);
  INSERT INTO DDETAIL VALUES (TO_DATE('31032009','DD/MM/YYYY'),1,101,NULL,20,16,20);
  INSERT INTO DDETAIL VALUES (TO_DATE('30042009','DD/MM/YYYY'),1,101,NULL,20,20,20);
  INSERT INTO DDETAIL VALUES (TO_DATE('28022009','DD/MM/YYYY'),2,102,2000,NULL,NULL,15);
  INSERT INTO DDETAIL VALUES (TO_DATE('28022009','DD/MM/YYYY'),2,102,NULL,12,10,15);
  INSERT INTO DDETAIL VALUES (TO_DATE('31032009','DD/MM/YYYY'),2,102,NULL,12,15,8);
  INSERT INTO DDETAIL VALUES (TO_DATE('30042009','DD/MM/YYYY'),2,102,NULL,12,12,15);
  INSERT INTO DDETAIL VALUES (TO_DATE('31012009','DD/MM/YYYY'),3,103,NULL,30,20,25);
  INSERT INTO DDETAIL VALUES (TO_DATE('28022009','DD/MM/YYYY'),3,103,NULL,30,20,25);
  INSERT INTO DDETAIL VALUES (TO_DATE('31032009','DD/MM/YYYY'),3,103,NULL,30,20,25);
  INSERT INTO DDETAIL VALUES (TO_DATE('30042009','DD/MM/YYYY'),3,103,3000,NULL,NULL,25);
  INSERT INTO DDETAIL VALUES (TO_DATE('30042009','DD/MM/YYYY'),3,103,NULL,30,20,25);
  
  i want the output to be;
  DDT              DHSR     DHCODE     HAMOUNT     D1     D2     D3     RUN_TOT
  31/01/2009     1     101     1500               10     
  31/01/2009     1     101     5000     20     15     20     4945
  31/01/2009     3     103     6000     30     20     25     5925
                                     
  28/02/2009     1     101     4945     20     12     20     4893
  28/02/2009     2     102     2000               15     
  28/02/2009     2     102     3000     12     10     15     2963
  28/02/2009     3     103     5925     30     20     25     5850
                                     
  31/03/2009     1     101     4893     20     12     20     4841
  31/03/2009     2     102     2963     12     10     15     2926
  31/03/2009     3     103     5850     30     20     25     5775
                                     
  30/04/2009     1     101     4841     20     12     20     4789
  30/04/2009     2     102     2926     12     10     15     2889
  30/04/2009     3     103     3000               20     
  30/04/2009     3     103     5775     30     20     25     5700

  The NON-NULL DAMOUNT (col 1500,2000,3000 value) value be need not in 'Running Total'
  I'm not able to separarate Prime, these value NON-NULL, then UNiON lines he alongwith operation total lines
  and sorting it wise of DDT.
  
  Please help with the code.
  
  TYVM in adv.
  Kind regards.
  
  Published by: user10967485 on January 7, 2010 08:15

  Hello

  As Centinul said, thank you for the samples, including in a usable form data!
  The results are really what you want from these data? My results are a little different. I'm guessing that you have published the wrong version of the data or the results, but if not, please explain the differences.

  You can calculate run_tot using the analytic function SUM. The column that you want to display the amount is actually calculated from run_tot, not the other way around. (Otherwise, row_tot and both would be based on previous versions of the other, and to do this in SQL requires a query CONNECT BY or MODEL, that is even more complex.)

  WITH    got_run_tot          AS
  (
       SELECT     d.ddt
       ,     d.dhsr
       ,     d.dhcode
       ,     NVL ( d.damount
                        , h.hamount
                    )               AS amount
       ,     d.d1
       ,     d.d2
       ,     d.d3
       ,     h.hamount - CASE
                         WHEN  d1 + d2 + d3     IS NULL
                      THEN  NULL
                      ELSE  SUM ( d.d1
                                       + d.d2
                                 + d.d3
                                 ) OVER ( PARTITION BY  d.dhcode
                                       ,                d.dhsr
                                               ORDER BY      d.ddt
                                         )
                        END          AS run_tot
       FROM     ddetail         d
       JOIN     lheader         h     ON     d.dhcode     = h.hcode
                          AND     d.dhsr          = h.hsr
  )
  SELECT       ddt
  ,       dhsr
  ,       dhcode
  ,       NVL ( CASE
                 WHEN  d1 + d2 + d3  IS NULL
                 THEN  LAG (run_tot) OVER ( PARTITION BY  dhcode
                                               ,                dhsr
                                                         ORDER BY       ddt
                                       )
            END
             , amount
             )          AS amount
  ,       d1
  ,       d2
  ,       d3
  ,       run_tot
  FROM       got_run_tot
  ORDER BY  ddt
  ,            dhcode
  ,       d1 + d2 + d3     NULLS FIRST
  ;
  

  My results:

  DDT             DHSR DHCODE     AMOUNT  D1  D2  D3    RUN_TOT
  --------- ---------- ------ ---------- --- --- --- ----------
  31-JAN-09          1 101          1500          10
  31-JAN-09          1 101          5000  20  15  20       4945
  31-JAN-09          3 103          6000  30  20  25       5925
  
  28-FEB-09          1 101          5000  20  12  20       4893
  28-FEB-09          2 102          2000          15
  28-FEB-09          2 102          3000  12  10  15       2963
  28-FEB-09          3 103          6000  30  20  25       5850
  
  31-MAR-09          1 101          5000  20  16  20       4837
  31-MAR-09          2 102          3000  12  15   8       2928
  31-MAR-09          3 103          6000  30  20  25       5775
  
  30-APR-09          1 101          5000  20  20  20       4777
  30-APR-09          2 102          3000  12  12  15       2889
  30-APR-09          3 103          5775          25
  30-APR-09          3 103          6000  30  20  25       5700
  

• need to sum all the sal

  My dear

  This query, I know sal sum in dept by job is

  I have to add new coumn in sum to give query for all dept

  and new line give sum for each Department

  as a matrix report

  WITH pivot_data AS (SELECT deptno, job, sal FROM emp)

  SELECT "JOB."

  "10."

  "20."

  '30 ',.

  "40".

  OF pivot_data PIVOT (SUM (sal)

  FOR deptno

  (10, 20, 30, 40)

  )

  Hello

  So, besides the total sal for each combination of deptno and job, you want also totals for each jdeptno (regardless of the job) and work (regardless of deptno) and a total general (no matter the deptno and employment).  This sounds like a job for the CUBE.  The following soLution uses the CUBE to calculate amounts and then uses the PIVOT just to combine lines.

  WITH all_jobs AS

  (

  SELECT DISTINCT job

  FROM scott.emp

  )

  data_to_pivot AS

  (

  SELECT deptno NVL (d.deptno, - 1)

  , NVL (j.job, 'ALL') AS job

  , NVL (SUM (e.sal), 0) AS sal

  GROUPING (j.job) AS job_agg

  OF scott.dept d

  CROSS JOIN all_jobs j

  LEFT OUTER JOIN scott.emp e ON e.deptno = d.deptno

  AND e.job = j.job

  GROUP BY CUBE (d.deptno, j.job)

  )

  Simply SELECT employment, '10', all_depts '20', '30', '40', - or everything *, if you don't mind saw job_agg

  OF data_to_pivot

  PIVOT (MIN (sal)

  TO deptno IN (10, 20, 30, 40

  All_depts AS-1

  )

  )

  ORDER BY job_agg

  work

  ;

  Output:

  ALL_DEPTS 10 20 30 40 JOB

  --------- ----- ----- ----- ----- ---------

  0 6000 0 0 6000 ANALYST

  1300 1900 950 0 4150 CLERK

  MANAGER OF 2450 2975 2850 0 8275

  THE PRESIDENT 5000 0 0 0 5000

  0 0 5600 0 5600 SELLER

  ALL THE 8750 10875 9400 0 29025

  Instead of deriving a "table" of all possible jobs, you should be able to use a partitioned outer join, something like this:

  WITH pivot_data AS

  (

  SELECT deptno NVL (d.deptno, - 1)

  , NVL (e.job, 'ALL') AS job

  , NVL (SUM (e.sal), 0) AS sal

  GROUPING (employment) AS job_agg

  OF scott.dept d

  LEFT OUTER JOIN scott.emp e PARTITION BY (e.job)

  ON e.deptno = d.deptno

  GROUP BY CUBE (e.job, d.deptno)

  )

  SELECT *.

  OF pivot_data

  PIVOT (MIN (sal)

  TO deptno IN (10, 20, 30, 40

  All_depts AS-1

  )

  )

  ORDER BY job_agg, job

  ;

  But the only effect of the outer join partitioned seems to cause CUBE to abandon some Super aggregates.  I do something ridiculous in this second request, or there is a bug in my version (11.2.0.2.0 Express).

  (Almost always, when people say "there must be a bug", they're just doing something stupid.)  There is no reason to think that I am an exception.  I don't have another version of Oracle at hand right now)

• How can I use the SUM function to calculate the number of employees in the comp. & deptnt?

  I have two tables: employees and their departments. I'm figuring the total employees by the Department and the total employees of the entire society. I know I have to use the SUM function, but I can only calculate total employees by Department and company separately. I need to get this result:
  
  

  DEPT_NAME     DEPT_TOTAL_SALARY         COMPANY_TOTAL_SALARY
  RESEARCH                  10875                        29025
  SALES                      9400                        29025    
  ACCOUNTING                 8750                        29025      
  
  
  This is my code:
  
  SELECT department_name, SUM(salary) as total_salary
  FROM employee, department
  WHERE employee.department_id = department.department_id
  GROUP BY department_name;
  
  SELECT SUM(salary)
  FROM employee;
  
  
  
  
  
  
  Can somebody help please?
  Thank you in advance.

  Published by: user13675672 on January 30, 2011 14:29
  
  Published by: user13675672 on January 30, 2011 14:31

  Hello

  Something like:

  SELECT dname,
         dept_tot_sal,
         SUM (dept_tot_sal) OVER () comp_tot_sal
  FROM   (SELECT   dname,
                   SUM (sal) dept_tot_sal
          FROM     dept, emp
          WHERE    dept.deptno = emp.deptno
          GROUP BY dname);
  

  There might be a smarter way, with no re - select.

  Concerning
  Peter

  Analytical functions:
  http://download.Oracle.com/docs/CD/E11882_01/server.112/e17118/functions004.htm

• How to only the totals using the native summary column (= "SUM () function

  Hi all, this is my data model:
  
  < name of dataTemplate 'Employees' description = 'Simple Dept - Emp' = >
  < dataQuery >
  < SQLStatement instance name = "Q1" >
  <! [CDATA]
  Select SERVICES. DEPTNO as DEPTNO,
  DEPARTMENTS. DNAME as a DNAME
  Scott. MINISTRIES DEPT order by DEPTNO]] >
  < / sqlStatement >
  < SQLStatement instance name = "Q2" >
  <! [CDATA [Select
  EMPLOYEES. ENAME like EMP_NAME,
  EMPLOYEES. EMPNO as EMPNO,
  EMPLOYEES. Hiring as HIREDATE date,
  EMPLOYEES. SAL as WAGES,
  EMPLOYEES. DEPTNO as EMP_DEPTNO
  Scott. EMPLOYEES OF THE EMP
  where EMPLOYED. [[DEPTNO =: DEPTNO]] >
  < / sqlStatement >
  < / dataQuery >
  < dataStructure >
  < name of group = "G_DEPT" source = "Q1" >
  < element name = "DEPTNO" value = "DEPTNO" / >
  < element name = "DNAME" value = "DNAME" / >
  < element name = "TOTAL_EMPS" value = "G_EMP. EMPNO"function ="COUNT ()"/ >
  < element name = "TOTAL_SALARY" value = "G_EMP. SALARY"function ="SUM ()"/ >
  < element name = "AVG_SALARY" value = "G_EMP. SALARY"function ="AVG ()"/ >
  < element name = "MAX_SALARY' value = 'G_EMP. SALARY"function ="MAX ()"/ >
  < element name = "MIN_SALARY" value = "G_EMP. SALARY"function ="MIN ()"/ >
  < name of group = "G_EMP" source = "Q2" >
  < feature name = 'EMPNO' value = 'EMPNO' / >
  < element name = "EMP_NAME" value = "EMP_NAME" / >
  < element name = "HIREDATE" value = "HIREDATE" / >
  < element name = "SALARY" value = "SALARY" / >
  < / Group >
  < / Group >
  < / dataStructure >
  < / dataTemplate >
  
  This datatemplate works very well with the TOTAL_EMPS, TOTAL_SALARY, AVG_SALARY, MAX_SALARY MIN_SALARY split for all departments; So these are subtotals.
  
  Now, I need to have the totals at the end of my report to the following:
  
  TOTAL_ALL_EMPS
  TOTAL_ALL_SALARY
  TOTAL_ALL_AVG_SALARY
  TOTAL_ALL_MAX_SALARY
  TOTAL_ALL_MIN_SALARY
  
  Add a new query (Q1) with all the totals, now the data model is the following:
  
  < name of dataTemplate 'Employees' description = 'Simple Dept - Emp' = >
  < dataQuery >
  < SQLStatement instance name = "Q1" >
  <! [CDATA]
  Select COUNT (empno) TOTAL_ALL_EMPS, SUM (sal) TOTAL_ALL_SALARY, AVG (sal) TOTAL_ALL_AVG_SALARY, MAX (sal) TOTAL_ALL_MAX_SALARY MIN (sal) scott TOTAL_ALL_MIN_SALARY. EMPLOYEES EMP]] >
  < / sqlStatement >
  < SQLStatement instance name = "Q2" >
  <! [CDATA]
  Select SERVICES. DEPTNO as DEPTNO,
  DEPARTMENTS. DNAME as a DNAME
  Scott. MINISTRIES DEPT order by DEPTNO]] >
  < / sqlStatement >
  < SQLStatement instance name = "Q3" >
  <! [CDATA [Select
  EMPLOYEES. ENAME like EMP_NAME,
  EMPLOYEES. EMPNO as EMPNO,
  EMPLOYEES. Hiring as HIREDATE date,
  EMPLOYEES. SAL as WAGES,
  EMPLOYEES. DEPTNO as EMP_DEPTNO
  Scott. EMPLOYEES OF THE EMP
  where EMPLOYED. [[DEPTNO =: DEPTNO]] >
  < / sqlStatement >
  < / dataQuery >
  < dataStructure >
  < name of group = "G_TOT" source = "Q1" >
  < element name = "TOTAL_ALL_EMPS" value = "TOTAL_ALL_EMPS" / >
  < element name = "TOTAL_ALL_SALARY" value = "TOTAL_ALL_SALARY" / >
  < element name = "TOTAL_ALL_AVG_SALARY" value = "TOTAL_ALL_AVG_SALARY" / >
  < element name = "TOTAL_ALL_MAX_SALARY" value = "TOTAL_ALL_MAX_SALARY" / >
  < element name = "TOTAL_ALL_MIN_SALARY" value = "TOTAL_ALL_MIN_SALARY" / >
  < / Group >
  < name of group = "G_DEPT" source = "Q2" >
  < element name = "DEPTNO" value = "DEPTNO" / >
  < element name = "DNAME" value = "DNAME" / >
  < element name = "TOTAL_EMPS" value = "G_EMP. EMPNO"function ="COUNT ()"/ >
  < element name = "TOTAL_SALARY" value = "G_EMP. SALARY"function ="SUM ()"/ >
  < element name = "AVG_SALARY" value = "G_EMP. SALARY"function ="AVG ()"/ >
  < element name = "MAX_SALARY' value = 'G_EMP. SALARY"function ="MAX ()"/ >
  < element name = "MIN_SALARY" value = "G_EMP. SALARY"function ="MIN ()"/ >
  < name of group = "G_EMP" source = "Q3" >
  < feature name = 'EMPNO' value = 'EMPNO' / >
  < element name = "EMP_NAME" value = "EMP_NAME" / >
  < element name = "HIREDATE" value = "HIREDATE" / >
  < element name = "SALARY" value = "SALARY" / >
  < / Group >
  < / Group >
  < / dataStructure >
  < / dataTemplate >
  
  It works fine, but my question is this:
  
  How can I change the data model and use the native summary column (function = "SUM (), for example) to collect data that I mentioned above (TOTAL_ALL_EMPS, TOTAL_ALL_SALARY, etc.), in order to avoid a third query SQL (Q1)?
  In a few words, I would only use the query Q2 and Q3 and have overall totals and subtotals.
  
  Thanks in advance for any help
  
  Alex

  
  
  
  Select 1 double DUMMY_FIELD]] >
  
  
  Select SERVICES. DEPTNO as DEPTNO,
  DEPARTMENTS. DNAME as a DNAME
  Scott. MINISTRIES DEPT order by DEPTNO]] >
  
  
  EMPLOYEES. ENAME like EMP_NAME,
  EMPLOYEES. EMPNO as EMPNO,
  EMPLOYEES. Hiring as HIREDATE date,
  EMPLOYEES. SAL as WAGES,
  EMPLOYEES. DEPTNO as EMP_DEPTNO
  Scott. EMPLOYEES OF THE EMP
  where EMPLOYED. [[DEPTNO =: DEPTNO]] >
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  

  Try this

  Concerning
  Charlotte

• Shows the columns having / sum not zero

  We have a report that HAV total of twenty columns.
  
  Whenever we run you report (dynamic query) random columns have sum = zero
  
  We want to show only eachtime the columns having the amount greater than zero.
  
  concerning
  
  Jean Marc

  Hi John,.

  OK - I've tested this here [http://htmldb.oracle.com/pls/otn/f?p=267:43]. The report on the left shows/hides the SAL and COMM columns according to totals. The report on the right shows the complete data. Change the Dept to see this implemented.

  There are other methods available, but that's what I did:

  The select dept list (item name is P43_DEPTNO) is simply a list of departments and a NULL option that returns 0 (zero).

  This report is a SQL statement of:

  SELECT EMPNO, ENAME, SAL, COMM
  FROM EMP
  WHERE :P43_DEPTNO = 0 OR :P43_DEPTNO = DEPTNO
  ORDER BY ENAME
  

  I have a region in the position after the header that uses "No. Template" and contains two pieces of Hidden - P43_SAL and P43_COMM.

  I have a calculation of element, running "Before Header", which sets P43_DEPTNO to 0 if it is NULL.

  I have a PL/SQL unconditional process, "to charge - before Header", which has the following code to the currently running process:

  DECLARE
   vSAL NUMBER;
   vCOMM NUMBER;
  BEGIN
   SELECT NVL(SUM(SAL),0), NVL(SUM(COMM),0)
   INTO vSAL, vCOMM
   FROM EMP
   WHERE :P43_DEPTNO = 0 OR :P43_DEPTNO = DEPTNO;
   :P43_SAL := vSAL;
   :P43_COMM := vCOMM;
  END;
  

  And, finally, on the SAL column in the report, I put the Condition Type for 'value of element in the Expression 1. = zero' and the Expression 1 is: P43_SAL. And even on the COMM, but the Expression 1 column: P43_COMM

  When the page is loaded, the process is executed and SAL and COMM totals are calculated and inserted in P43_SAL and P43_COMM. The report runs and conditions check the values of these two hidden items - if a is not null, then the column is displayed.

  Andy

• SUM on &amp; Partition BY... Try to get the correct total run.

  running: Oracle XE 11
  

  
  

  Hi all, I am using the analytical function of PARTITION BY to get my total race for a report. (in this case the bank balance)

  
  

  SUM (bank_stmts.amount) OVER (PARTITION BY bank_stmts.account_ID ORDER BY bank_stmts.tx_date, bank_stmts.id)

  
  

  I add a balance initial in the table at the beginning of the year, and everything works fine when I select on the recordings of the whole years...

  
  

  However, I need to interview a subset of the report, i.e. one month, or a selection of documents, rather than year-round. But I still want to see the total calculated for the whole year on the report, not a total operating for the subset of records. I'm not sure how to do that because when I select a subset, it totals only the subset...
  

  
  

  I see that there are a number of clauses on the analytical function, especially BETWEEN the LINES or RANGE, but my assumption is that these still only works on surveyed lines and not any of the table...

  
  

  My way of thinking for the moment, is that patients have to calculate and enter the total in the table when the row is inserted, probably via a trigger. However, I didn't keep far from...

  
  

  Kind regards

  Richard
  

  SQL > with t as)
  2. Select ename,
  3                     job,
  4 hiredate,
  5 sum (sal) over (partition by deptno arrested by hiredate) running_total_sal
  6 of PEM
  7            )
  8 select
  9 t
  10 order by hiredate
  11.

  HIREDATE RUNNING_TOTAL_SAL EMPLOYMENT ENAME
  ------ --------- --------- -----------------
  SMITH, CLERK DECEMBER 17, 80 800
  ALLEN SALESMAN FEBRUARY 20 81 1600
  WARD 22 FEBRUARY SALESMAN 81 2850
  MANAGER OF JONES 2 APRIL 81 3775
  BLAKE MANAGER MAY 1, 81 5700
  CLARK MANAGER JUNE 9, 81 2450
  SELLER OF 7200 08 - SEP - 81 TURNER
  MARTIN SELLER 28-SEP-81 8450
  PRESIDENT KING NOVEMBER 17 81-7450
  JAMES CLERK 9400 3 DECEMBER 81
  DECEMBER 3, 81 FORD ANALYST 6775

  HIREDATE RUNNING_TOTAL_SAL EMPLOYMENT ENAME
  ------ --------- --------- -----------------
  MILLER COMMITTED JANUARY 23, 82 8750
  SCOTT, ANALYST APRIL 19 87 9775
  ADAMS, CLERK MAY 23, 87 10875

  14 selected lines.

  SQL > with t as)
  2. Select ename,
  3                     job,
  4 hiredate,
  5 sum (sal) over (partition by deptno arrested by hiredate) running_total_sal
  6 of PEM
  7            )
  8 select
  9 t
  10 where hiredate > = date ' 1981-01-01'
  11 and hiredate<  date="">
  12 order by hiredate
  13.

  HIREDATE RUNNING_TOTAL_SAL EMPLOYMENT ENAME
  ------ --------- --------- -----------------
  ALLEN SALESMAN FEBRUARY 20 81 1600
  WARD 22 FEBRUARY SALESMAN 81 2850
  MANAGER OF JONES 2 APRIL 81 3775
  BLAKE MANAGER MAY 1, 81 5700
  CLARK MANAGER JUNE 9, 81 2450

  SQL >

  SY.

• What type of input parameter is used according to the SUM?

  Hello world
  As we know sum is an oracle function preset. But what these guys here oracle used for input parameters. How did they do that?
  I mean, we can write this sum fuction as many ways as as mentioned below. Please give me some ideas how to do this.
  

  SELECT SUM(salary) as "Total Salary" FROM employees;
  
  SELECT SUM(DISTINCT salary) as "Total Salary" FROM employees;
  
  SELECT SUM(income - expenses) as "Net Income" FROM gl_transactions;
  
  SELECT SUM(sales * 0.10) as "Commission" FROM order_details;

  Kind regards
  BS2012

  BS2012 wrote:
  Hello world
  As we know sum is an oracle function preset. But what these guys here oracle used for input parameters. How did they do that?
  I mean, we can write this sum fuction as many ways as as mentioned below. Please give me some ideas how to do this.

  SELECT SUM(salary) as "Total Salary" FROM employees;
  
  SELECT SUM(DISTINCT salary) as "Total Salary" FROM employees;
  
  SELECT SUM(income - expenses) as "Net Income" FROM gl_transactions;
  
  SELECT SUM(sales * 0.10) as "Commission" FROM order_details;
  

  Kind regards
  BS2012

  As others have said, your question is not very clear.

  There are many aspects and angles to look at what you're asking.

  First of all, a level superior, the sum function simply takes a numeric value as it's argument, so all of these examples you gave have expressions that evaluate to a numeric value to be provided to the sum function. (As someone else already mentioned you can have non-numeric data types, just as long as they can be implicitly converted to a numeric value).

  A statement analysis and the point of view of enforcement, the content of the expression inside the brackets is evaluated before being passed to the sum function. It is not the function sum that he himself takes the expression and evaluates it. The sum function is expecting just a single numeric value.

  Internally, what the function sum is the case, is more than just a single... call function and return a value, because it faces several values being passed in the aggregation group. As such, it must have the ability to know if to start in short, is to accept several input values, so he can add them together, you know give up adding entries and pass the result to the back.

  If we write our own defined aggregate function (others have already provided a link to explain this) we can see what is happening internally. In the following example, we'll write a function defined by the user that multiplies the values rather than the amounts...

  create or replace type mul_type as object(
    val number,
    static function ODCIAggregateInitialize(sctx in out mul_type) return number,
    member function ODCIAggregateIterate(self in out mul_type, value in number) return number,
    member function ODCIAggregateTerminate(self in mul_type, returnvalue out number, flags in number) return number,
    member function ODCIAggregateMerge(self in out mul_type, ctx2 in mul_type) return number
    );
  /
  create or replace type body mul_type is
    static function ODCIAggregateInitialize(sctx in out mul_type) return number is
    begin
      sctx := mul_type(null);
      return ODCIConst.Success;
    end;
    member function ODCIAggregateIterate(self in out mul_type, value in number) return number is
    begin
      self.val := nvl(self.val,1) * value;
      return ODCIConst.Success;
    end;
    member function ODCIAggregateTerminate(self in mul_type, returnvalue out number, flags in number) return number is
    begin
      returnValue := self.val;
      return ODCIConst.Success;
    end;
    member function ODCIAggregateMerge(self in out mul_type, ctx2 in mul_type) return number is
    begin
      self.val := self.val * ctx2.val;
      return ODCIConst.Success;
    end;
  end;
  /
  create or replace function mul(input number) return number deterministic parallel_enable aggregate using mul_type;
  /
  

  For example, our user-defined aggregate function is based on a total object type.
  This object keeps a value ("val" in our example).
  It has an Initialize method, so when the SQL engine indicates that this is the beginning of an aggregation of values it can set its value to an initial value (in this case zero).
  It has an Iterate method, the SQL engine passes the values to it in the context of all grouped values, it can treat them (in our case it multiplies the value of entry with the value already there for this game of aggregations (and takes a value of 1 for the first iteration basis))
  She has a Terminate method, so when the SQL engine indicates that the global set of values is completed, it can return the result.
  The last method there is a merger and is mandatory, so that when the aggregation is done parallel assessment tool (for better performance internally), the results of these parallel executed aggregations can be combined (see http://docs.oracle.com/cd/E11882_01/appdev.112/e10765/ext_agg_ref.htm#ADDCI5132). As we are multiplying numbers, in our case, it is simply a case of the multiplication of one single result with each other.

  And to see that it works...

  SQL> with t as (select 2 as x from dual union all
    2             select 3 from dual union all
    3             select 4 from dual union all
    4             select 5 from dual)
    5  --
    6  select mul(x)
    7  from t;
  
      MUL(X)
  ----------
         120
  

• cumulative sal

  Hello
  
  I'm new on OTN. This is my first question.
  
  I have to run a report with the AMT can be combined. If you can provide with the emp table, then I can implement logic with my table accordingly. But without analytical functions... I have to post.
  
  
  Need your valuable help
  
  Rekha

  Hello

  Welcome to OTN.

  Try like this...!

  select e1.empno, e1.ename, e1.sal,
                                                     (select sum(sal)
                                                       from emp e2
                                                       where e2.empno <= e1.empno )  AS cume_salary
                                                          from emp e1 order by empno
  

  KPR

• Calculate sales Accumalated

  Hello world
  
  Could someone suggest me how to calculate total sales. The scenario is
  
  My Table is like this
  
  Cardno sales accumulated sales
  101 100 100
  102 80 180
  103 20 200
  
  
  I need to calculate the third column "Accumulated Sales" from column 2 "sales".
  
  is there a formula in oracle to calculate cumulative sales? How did I need form the SQL for this requirement? Can anyone help?
  
  Thanks in advance
  
  Concerning

  select
  Cardno,
   Sales,
   sum(Sales) over(order by rownum) as "Accumulated Sales"
  from your_table
  

• list of employees where the sum of the salary must be less than an amount

  I take the list of employees from the employee table have a column 'Amount' where he sum of "amount" should be less than a certain amount say "100000".
  
  thanx

  What do you mean sum of the amount? Sum of the amount for a particular employee or you are talking about running here sum?

  anyway... This technique can lead you I guess

  SELECT * FROM)
  SELECT empno, ename, sal,
  Sum (SAL) (ORDER BY empno) total,
  Mgr
  FROM emp) WHERE total<>

  Published by: Buga on October 24, 2009 02:58

• How to get to the total/sum at the end of the production

  How can I get an output like below using SQL statements only;
  
  ENAME SAL
  ------------ ---
  SMITH, 800
  KING 5000
  ADAMS 1100
  Total 6900
  
  Best regards, Yacoub

  SELECT ENAME , Sal
  FROM EMP
  UNION
  SELECT 'TOTAL' A , SUM(Sal)
  FROM EMP
  GROUP BY 'TOTAL'
  

  Published by: AJ99 on July 6, 2009 14:57

• get the only recording where the sum is less

  Hello

  select EMPNO, SAL from EMP
  
  7369     800
  7499     1600
  7521     1250
  7566     2975
  7654     1250
  7698     2850
  7782     2450
  7788     3000
  7839     5000
  7844     1500
  7876     1100
  7900     950
  7902     3000
  7934     1300

  I need to find all the empno all together (sum) is equal in early 2000 by lowest SAL
  IF the sum is below 2000, I can then take an empno, also if, then, the sum will be longer than 2000
  It's
  800 +.
  950 + = 1750
  1100 +.
  = 2850
  I can get the first empno 3 discs = (7369,7900,7876)
  
  If I want to compare with 1750 instead of 2000, I get only two first empno = (7369,7900)
  
  How can he do?
  
  Thanks in advance

  SQL> select empno, sal
    2    from (
    3  select empno, sal, sal1, nvl(lag(sal1) over(order by sal),0) lsal
    4    from (select EMPNO, SAL, sum(sal) over(order by sal) sal1 from EMP))
    5  where lsal <2000
    6  /
  
       EMPNO        SAL
  ---------- ----------
        7369        800
        7900        950
        7876       1100
  
  SQL> select empno, sal
    2    from (
    3  select empno, sal, sal1, nvl(lag(sal1) over(order by sal),0) lsal
    4    from (select EMPNO, SAL, sum(sal) over(order by sal) sal1 from EMP))
    5  where lsal <1750
    6  /
  
       EMPNO        SAL
  ---------- ----------
        7369        800
        7900        950
  

• Single MAX of a SUM

  Hi all
  
  I am looking for a query that gives me something like:
  Select MAX (SUM (hard)) as maxDur, name of person
  This gives an ORA-00937: not a function of simple-group.
  
  That's why one translate only for
  
  Select max (sumDur) in the maxDur, name
  de)
  Select name, sum (hard) as sumDur of person
  Group BY name)
  Group by name
  
  And that's almost what I would like to have, but:
  It gives me the same result as the subquery "sum". A list of names...
  
  I wish I had 1 single name: one who has hard MAX...
  
  If I take the 'name' of the top application it gives me only one line, the MAX one. But I need to also know the name of the correspondent...
  
  Can I do something like "order by maxDur desc" and "select top 1"? sounds as a workaround...
  
  Any idea?
  
  Thank you!
  Refer

  Similar to already answers provided - you to achieve through subquery or with the first/last aggregate function (but in this case, you have to make sure, you have only a sum, which is the maximum).

  SQL> select sum(sal), job
    2    from emp
    3   group by job
    4  having sum(sal) = (select max(sum(sal)) from emp t group by job)
    5  ;
  
    SUM(SAL) JOB
  ---------- ---------------------------
        8275 MANAGER
  
  SQL>
  SQL> select
    2  max(sum(sal)),
    3  max(job) keep(dense_rank last order by sum(sal))
    4  from emp
    5  group by job
    6  ;
  
  MAX(SUM(SAL)) MAX(JOB)KEEP(DENSE_RANKLAST
  ------------- ---------------------------
           8275 MANAGER
  

  Best regards

  Maxim

• SQL query SUM and AVG

  Hi all
  
  I think I'm really stupid but I have problems of SQL query.
  
  I have a table with many lines of operations which all refer to different stores, for example:
  
  Store... _Sales_... _Month_
  Reading... 200 k... April
  Leeds... 50k................ April
  Manchester... 70k................ May
  Reading... 100 k... May
  
  I need to arrive at the average sales for the month combined as a total. That is the average income of store for a given period is 200 k + 50 k + 70 k + 100 k / * 3 * (because there are only 3 unique shops) - I hope this makes sense!
  
  So, basically, I'm doing both a query of the SUM (and company store) and then out of the average of all the stores together. Is this possible?
  
  
  Thank you

  Hello

  This query returns 140 which seems to be the correct value:

  with data as
  ( select 'Reading' Store
    , 200 sales
    from dual
    union
    select 'Leeds'
    , 50
    from dual
    union
    select 'Manchester'
    , 70
    from dual
    union
    select 'Reading'
    , 100
    from dual
  )
  select sum(sales)
  , count( distinct store )
  , sum(sales)/count(distinct store)
  from data
  

  There are several options:
  1. you can get two IR on one page (using IFRAMEs - search for that word on the Forum)...
  2. you create another region with the above query and that position just below the report
  3. in the foot of the region call a process of PL/SQL (using AJAX) that calculates the value using the query and print it (via htp.p)

  Greetings,
  Roel

  http://roelhartman.blogspot.com/
  http://www.bloggingaboutoracle.org/
  http://www.Logica.com/

  You can assign this answer to your question in marking it as useful or Correct ;-)