Word 2007-data of the previous document has now by default on every page!
I'm not sure what I did, but now whenever I open Word, a name I typed once when working in Word appears. It happens even when I click on the new icon of the page. Any ideas how to get rid of this so I default on a blank page again? I know that we can uninstall and reinstall the program, but there must be a better way.
Thank you
WAHOO! I FIXED IT! I JUST HAD to SEARCH for A NAME of THE FILE normal.dotm, AND DELETE IT! VOILA! WHITE PAGE AGAIN! CELEBRATE, CELEBRATE, DANCE TO THE MUSIC!
Hey Patty Sue,.
I'm glad to hear that you got this problem resolved, please let us know if you encounter other problems.
Kind regards
Manasa P-Microsoft Support.
Tags: Windows
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Hello
user12997203 wrote:
Hello
can someone give me an idea for situation belowI have a table with records
CREATE TABLE test1 ...
Thanks for the display of the data of the sample; It is very useful.
I want to merge the range date lines that overlap, break at intervals and set the indicator (A_IND, B_IND, Q_IND) accordingly. (IE, if a record in the source has a value for the 'cd' = 'B' column in a given date range, then the output should display 'Y' for the B_IND column for the date ranges in the source folder.)
Do not assume that everyone who wants to help you is familiar with your application and your needs. Explain what key role plays in this problem. See {message identifier: = 10865697}.
Here's one way:WITH change_points AS ( SELECT key , start_dt AS dt FROM test1 UNION SELECT key , end_dt AS dt FROM test1 ) , ranges AS ( SELECT key , dt AS start_dt , LEAD (dt) OVER ( PARTITION BY key ORDER BY dt ) AS next_dt FROM change_points ) SELECT r.key , r.start_dt , r.next_dt - CASE WHEN r.next_dt = MAX (r.next_dt) OVER () THEN 0 ELSE 1 END AS end_dt , MAX (CASE WHEN t.cd = 'A' THEN 'Y' ELSE 'N' END) AS a_ind , MAX (CASE WHEN t.cd = 'B' THEN 'Y' ELSE 'N' END) AS b_ind , MAX (CASE WHEN t.cd = 'Q' THEN 'Y' ELSE 'N' END) AS q_ind FROM ranges r JOIN test1 t ON t.key = r.key AND t.start_dt < r.next_dt AND t.end_dt > r.start_dt GROUP BY r.key , r.start_dt , r.next_dt ORDER BY r.start_dt ;
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