2.1: Data tab of the query about other users mix with current user [Fixed 2.1.1 Table

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  Can someone clarify what is the significance of this (processed or unprocessed form).

  
  

  Thank you.

  Why don't you ask the author of the book.

  How can we know what the author means when you take a quote out of context and don't provide any reference so that we can see exactly what is shown to you.

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  Stalin G wrote:
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• Problems with lines due double date/time in the query

  Hello
  
  I'm trying to draw a list of the counties of the test sample. I want only 1 rank by the test result so that I can build a report in Cognos showing the rate of an outcome determined as a percentage of the total causes a range of dates.
  
  My problem is that I get duplicate for the same result rows: in the example below, I have 2 to 5 lines for each result instead of only 1 for each result. I have this reduced up to caused by the date - the date is the same, but the times are different, if several lines are drawn. I tried to use tronque(), among other things, but although the output now shows the same date without the time part, duplicate rows are always drawn.
  
  Any help would be appreciated!
  
  This is the code for the query:
  

  SELECT DISTINCT
      io.lab_id AS "LAB ID",
      l.name AS "LAB NAME",
      mtr.marketingtest_id AS "TEST ID",
      mtl.name AS "TEST NAME",
      mtr.marketingresult AS "MARKETING RESULT",
      COUNT(DISTINCT mtr.sample_id) AS "NO OF SAMPLES",
      TRUNC(os.statusdate) AS "STATUS DATE",
      os.orderstatuscodes_id AS "ORDER STATUS",
      io.redoorderid AS "REDOORDERID",
      mtl.locale_id AS "LOCALE"
  FROM igen_sample s
  INNER JOIN igen_igenityorder io ON s.igenityorder_id = io.igenityorder_id
  INNER JOIN igen_orderstatus os ON io.igenityorder_id = os.igenityorder_id
  INNER JOIN igen_marketingtestresult mtr ON s.sample_id = mtr.sample_id
  INNER JOIN igen_lab l ON io.lab_id = l.lab_id
  INNER JOIN igen_marketingtestlocale mtl ON mtr.marketingtest_id = mtl.marketingtest_id
  
  WHERE mtl.locale_id = 1
  AND os.orderstatuscodes_id IN (8, 9)
  AND mtr.marketingtest_id = 84
  AND os.statusdate BETWEEN '24-OCT-2011' AND '31-OCT-2011'
  
  GROUP BY mtr.marketingtest_id, mtl.name, mtr.marketingresult, os.statusdate, os.orderstatuscodes_id, io.lab_id, l.name, io.redoorderid, mtl.locale_id
  ORDER BY mtl.name

  Hello

  893078 wrote:
  Hello

  I'm trying to draw a list of the counties of the test sample. I want only 1 rank by the test result so that I can build a report in Cognos showing the rate of an outcome determined as a percentage of the total causes a range of dates.

  My problem is that I get duplicate for the same result rows: in the example below, I have 2 to 5 lines for each result instead of only 1 for each result. I have this reduced up to caused by the date - the date is the same, but the times are different, if several lines are drawn. I tried to use tronque() among others...

  TRUNC looks like what you want. If you want a single line per calendar day, or need to GROUP BY TRUNC (os.statusdate).

  AND        os.statusdate  >= TO_DATE ( '24-OCT-2011'
                              , 'DD-MON-YYYY'
                          )
  AND       os.statusdate  <  TO_DATE ( '31-OCT-2011'
                               , 'DD-MON-YYYY'
                          ) + 1
  GROUP BY  mtr.marketingtest_id
  ,            mtl.name
  ,        mtr.marketingresult
  ,        TRUNC (os.statusdate)               --     <==  CHANGED
  ,        os.orderstatuscodes_id
  ,        io.lab_id
  ,        l.name
  ,        io.redoorderid
  ,        mtl.locale_id
  ORDER BY  mtl.name
  

  If os.statusdate is a DATE, don't try to compare it to a VARCHAR2, as 24 October 2011 "." Compare DATEs to other DATEs.

  Furthermore, GROUP BY product automatically separate results. If all GROUP expressions in the SELECT clause, there is not need to say SELECT DISTINCT .

  Published by: Frank Kulash, November 23, 2011 09:34

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  Hello

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  I hope this helps.

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  Lorien - MCSA/MCSE/network + / has + - if this post solves your problem, please click the 'Mark as answer' or 'Useful' button at the top of this message. Marking a post as answer, or relatively useful, you help others find the answer more quickly.

• I have a problem with the guest account, defined as the administrator and other users as standard.

  Original title: "Guest account" is defined as an administrator and other users are standard. Unable to create new accounts or edit the ranks.

  Hello.
  I have a Dell INSPIRON 1545
  Windows 7 Home Premium

  Somehow my "guest" account that you can toggle is administrator.
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  If this does not work then send me a note (pegasusDOTfnlATgmailDOTcom).

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  Works of password to log into the admin account

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  Hemant K Collette
  http://hemantoracledba.blogspot.com