3-way join

Gurus,

Kindly help me with this issue of SQL. Result of a wanted three tables and looking for ways to join them to get.

==========================================================

DROP TABLE TEST_T1;
DROP TABLE TEST_T2;
DROP TABLE TEST_T3;

--- Create Tables
CREATE TABLE TEST_T1(
id   NUMBER PRIMARY KEY,
name VARCHAR(15)
);

CREATE TABLE TEST_T2(
id   NUMBER REFERENCES TEST_T1(id) ON DELETE CASCADE,
prod VARCHAR(15) 
);

CREATE TABLE TEST_T3(
id   NUMBER REFERENCES TEST_T1(id) ON DELETE CASCADE,
tend VARCHAR(15) 
);

--- Populate data
DELETE FROM TEST_T1;
INSERT INTO TEST_T1 values(101, 'A');
INSERT INTO TEST_T1 values(102, 'B');
INSERT INTO TEST_T1 values(103, 'C');

DELETE FROM TEST_T2;
INSERT INTO TEST_T2 values(101, 'l1');
INSERT INTO TEST_T2 values(101, 'l2');
INSERT INTO TEST_T2 values(102, 'm1');
INSERT INTO TEST_T2 values(102, 'm2');
INSERT INTO TEST_T2 values(102, 'm3');
INSERT INTO TEST_T2 values(103, 'n1');
INSERT INTO TEST_T2 values(103, 'n2');

DELETE FROM TEST_T3;
INSERT INTO TEST_T3 values(101, 'x1');
INSERT INTO TEST_T3 values(101, 'x2');
INSERT INTO TEST_T3 values(102, 'y1');
INSERT INTO TEST_T3 values(103, 'z1');
INSERT INTO TEST_T3 values(103, 'z2');
INSERT INTO TEST_T3 values(103, 'z3');

==========================================================

Expected results:

++++++++++++++++++

A|l1|x1|
A|l2|x2|
B|m1|y1|
B|m2|NULL|
B|m3|NULL|
C|n1|z1|
C|n2|z2|
C|NULL|z3|

++++++++++++++++++

Version: 11.1.0.7

Thanks in advance.

Hello

That's what I call a Query of price-fixed, and this is a way to do it:

WITH test_t2_plus AS

(

SELECT id, prod

ROW_NUMBER () OVER (PARTITION BY ID.

ORDER BY prod

) AS r_num

OF test_t2

)

test_t3_plus AS

(

SELECT id, trend

ROW_NUMBER () OVER (PARTITION BY ID.

ORDER BY trend

) AS r_num

OF test_t3

)

SELECT t1.name

t2.prod

t3.tend

OF test_t2_plus t2

FULL OUTER JOIN test_t3_plus t3 ON t3.id = t2.id

AND t3.r_num = t2.r_num

JOIN test_t1 t1 ON t1.id = COALESCE (t2.id, t3.id)

ORDER BY t1.id

t2.r_num

t3.r_num

;

The tricky part is how to reach test_t2 and test_t3. Of course, we must join identification number, but we must join on something else, too. We must join as the 1st prod tfrom test_t2 is attached to the 1st tendency of test_t3, the 2nd prod to the 2nd trend and so on, in each id. Until we do that, we need to know who is the 1st, 2nd, etc., that is where ROW_NUMBER.

Since any number given may exist in one of these tables, we need to do the join between test_t2 and test_t3 an outer join complete, in order to include the rows in each table, even if they don't match anything in the other table.

See Re: Y at - it an easy/more simple way to achieve this?

for an explanation of the name 'Fixed price query'.

Thanks for posting the CREATE TABLE and INSERT statements; This is really useful!

Tags: Database

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Confused about the complex joins in joins Manager
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I know that when we create join in the physical layer, we must use "foreign key" this icon,.

and when we need create joins in the MDB layer, you need to use 'new joint complex. "

so, what is the purpose of the complex joined in the Manager of joins? I'm so confused on this subject...

Kind regards
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Please see the below a

http://obiee11gqna.blogspot.com/2011/02/interview-questions-on-joins-in-OBIEE.html

---> complex join is that join in join where as two tables has no way join foreign at this complex time key is used

--> Join complex:-join complex are used in the physical layer between two tables where ever who do not key primary and forgin key relationship.

Foregin Key:-using the forgin key we can define the join between two tables. joins between is 1:M or M:M., if we want to define: many relationships we use the bridge tables.

Thank you

Deva

Published by: Devarasu on October 18, 2011 10:27

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Effective way to manage multiple outer joins

I have a large refcursor currently being returned by an oracle 11g stored procedure. I need to add some addiotional columns to the record set before it is returned.   The logic to include new columns is not simple, and I have to WITH instructions to store the new columns. In total, I will have to WITH that contains results that are currently returned and 5 additional STATEMENTS that each contain an id column to join to the existing set of records and the new column. My question is, how I left outer join the Recordset existing (with id column) with each of the 5 WITH statement queries to include the new 5 column in the original dataset?
example:
WITH orginalresults AS)
SELECT id,
col1,
col2
...
)
WITH newcol1 AS)
SELECT id,
newcol1
)
WITH newcol2 AS)
SELECT id,
newcol2
)
Join them
Select. *, newcol1.newcol1, newcol2.newcol2, newcol3.newcol3, newcol4.newcol4...
of orginalresults
outer join newcol1 left orginalresults user.user = newcol1.id
outer join newcol2 let originalresults.id = newcol2.id
outer join newcol3 let originalresults.id = newcol2.id
outer join newcol4 let originalresults.id = newcol4.id
.....
I'll have to repeat joins five times.   This approach is valid? Is there a better way to do it?

Hello

what I understand: what about something like:

WITH original_set AS

(SELECT LEVEL Id

OF the double

CONNECT BY LEVEL<=>

)

an ACE

(SELECT id, "one" |) Col1 to_char (id)

Of original_set

WHERE id IN (1, 4)

)

two ACEs

(SELECT id, 'two' |) Col2 to_char (id)

Of original_set

WHERE id IN (1, 2)

)

three ACEs

(SELECT id, 'three' |) Col3 to_char (id)

Of original_set

WHERE 1 = 2 / * empty * /.

)

four ACEs

(SELECT id, 'four' |) Col4 to_char (id)

Of original_set

WHERE id IN (3, 4)

)

five ACEs

(SELECT id, 'five' |) Col5 to_char (id)

Of original_set

ID WHERE = 2

)

SELECT os.id, o.col1, tw.col2, th.col3, fo.col4, fi.col5

To original_set os

A LEFT OUTER JOIN o ON o.id = os.id

LEFT OUTER JOIN two tw ON os.id = tw.id

E three LEFT OUTER JOIN ON os.id = th.id

LEFT OUTER JOIN four fo WE os.id = fo.id

LEFT OUTER JOIN five fi WE os.id = fi.id

ORDER BY id

;

ID COL1 COL2 COL3 COL4 COL5

---- ------- ------- ------- ------- -------

1 one1 two1

2 two2 five2

3                         four3

4 one4 four4

5

But the same thing can be achieved with:

WITH original_set AS

(SELECT LEVEL Id

OF the double

CONNECT BY LEVEL<=>

)

SELECT os.id

CASE WHEN os.id IN (1, 4)

THEN 'a ' | To_char (id)

END col1

CASE WHEN os.id IN (1, 2)

THEN 'two ' | To_char (id)

END col2

CASE WHEN 1 = 2

THEN "three" | To_char (id)

END col3

CASE WHEN os.id IN (3, 4)

THEN "four". To_char (id)

END col4

CASE WHEN os.id = 2

THEN "five" | To_char (id)

END col5

To original_set os

ORDER BY id

;

(I mean: I just do a select on the main table and include the logic of 'creation' of the five 'WITH' tables directly in the select; see how this can be applied to your real situation)

HTH,

Bruno Vroman

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