39 AND FOLLOWING. Where the signature?

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  with

  data in the form of)

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  ---------

  (1) if the value, if the County (if null) value then it shows the ZIP with dot's (.) value, in the 31234 above..,.

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  (2) another possible to fix the code, I want to use substr and InStr.

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  Conditions:

  --------------

  (1) shipping_instructions column has the value with "Mary America.1234 Southridge Park Dr... Samna Lorie.MO.31234... »

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  =========================

  / * Use Substr and Instr * /.

  =========================

  I used substr and instr, but I'm getting the money results (no point in the address).

  "America Mary. 1234 Southridge Park Dr. Samna Lorie.MO.31234..'

  
  

  NAME ADDRESS CITY ZIP County SATE

  ---------                  --------                                ------------           ------           -------    -- -----

  Mary America 1234 Southridge Park Dr. Samna Lorie MO 31234  NULL VALUE

  But I need the results (no point in the address)

  NAME ADDRESS CITY ZIP County SATE

  ---------                  --------                                ------------           ------           -------    -- -----

  Mary America 1234 Southridge Park Dr.    Samna Lorie MO 31234  NULL VALUE

  Hello

  994122 wrote:

  Hello

  (1) how do to do this, use the substr and instr functions?

  Thank you

  You can't do all the work with SUBSTR and INSTR; you need regular expressions to obtain a string delimited by a #.

  Once you have such a string, then you can use SUBSTR and INSTR (instead of REGEXP_SUBSTR) to get the separate secondary strings:

  WITH got_delimited_string AS

  (

  SELECT REGEXP_REPLACE (val

  , '\. ([^ .]| $)'

  , '#\1'

  ) AS delimited_string

  FROM the data

  )

  got_pos AS

  (

  SELECT delimited_string

  , INSTR (delimited_string, "#", 1, 1) AS pos_1

  , INSTR (delimited_string, "#", 1, 2), pos_2

  , INSTR (delimited_string, "#", 1, 3) AS pos_3

  , INSTR (delimited_string, "#", 1, 4) AS pos_4

  , INSTR (delimited_string, "#", 1, 5) AS pos_5

  , INSTR (delimited_string, "#", 1, 6) AS pos_6

  OF got_delimited_string

  )

  SELECT SUBSTR (delimited_string, 1, pos_1 - 1) AS the name

  SUBSTR (delimited_string, pos_1 + 1, pos_2 - (pos_1 + 1)) AS address

  SUBSTR (delimited_string, pos_2 + 1, pos_3 - (pos_2 + 1)) AS city

  SUBSTR (delimited_string, pos_3 + 1, pos_4 - (pos_3 + 1)) AS State

  REPLACE (SUBSTR (delimited_string, pos_4 + 1, pos_5 - (pos_4 + 1))

  , '.'

  )                                                           AS zip

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  OF got_pos

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