A form of Google with http POST VI

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  PS:

  Simulator: 8300

  MDS: 4.1.4

  JDE: 4.5.0

  Eclipse: Version: 3.4.1
  Build id: M20080911-1700

  Dear community,

  I managed to solve the problem by myself. Its a classic copy & paste error.

  Lets take a look at:

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  https.setRequestProperty(HEADER_CONTENTTYPE, String.valueOf(length));
  

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  Hoe it helps

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  Hello

  I want to download the mp3 file on server and I need to pass two parameters with the post method.

  Here is my code for this.

                        String userid="id_user=8379";
                String filename="trackName=sample.mp3";
                String params=userid+"&"+filename;            
  
                          httpcon=(HttpConnection)Connector.open("http://api.upload.com/gStorage/uploadSong?output=json",Connector.READ_WRITE);
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              int ch;
              while ((ch=fileis.read(data,0,data.length))!=-1) {
                  bos.write(data,0,ch);
              }
              os.write(bos.toByteArray());
              os.close();
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              if(httpcon.getResponseCode()!=HttpConnection.HTTP_OK)
              {
                  System.out.println("Failed to upload bytes");
              }
              else
              {
                  //is=httpcon.openInputStream();
                  DataInputStream dis=httpcon.openDataInputStream();
                  int ch1;
                  StringBuffer buffer1=new StringBuffer();
                  while ((ch1=dis.read())!=-1) {
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          } i am getting response code ok but fail to upload file.
  

  may I passing the parameter in the wrong way?

  thankx.

  Hello

  Nitin I currently do a midlet project.

  So I used multipart post method.

  I just read this article. http://MindTouch.firmstep.com/AchieveForms/Design_Guide/Integration_Actions/types/HTTP_POST#top

  package com.http.main;
  
  import java.io.ByteArrayOutputStream;
  import java.io.InputStream;
  import java.io.OutputStream;
  import java.util.Enumeration;
  import java.util.Hashtable;
  
  import javax.microedition.io.Connector;
  import javax.microedition.io.HttpConnection;
  
  import com.sun.midp.io.BufferedConnectionAdapter;
  
  public class HttpMultipartRequest
  {
      static final String BOUNDARY = "----------V2ymHFg03ehbqgZCaKO6jy";
  
      byte[] postBytes = null;
      String url = null;
  
      public HttpMultipartRequest(String url, Hashtable params, String fileField, String fileName, String fileType, byte[] fileBytes) throws Exception
      {
          this.url = url;
  
          String boundary = getBoundaryString();
  
          String boundaryMessage = getBoundaryMessage(boundary, params, fileField, fileName, fileType);
  
          String endBoundary = "\r\n--" + boundary + "--\r\n";
  
          ByteArrayOutputStream bos = new ByteArrayOutputStream();
  
          bos.write(boundaryMessage.getBytes());
  
          bos.write(fileBytes);
  
          bos.write(endBoundary.getBytes());
  
          this.postBytes = bos.toByteArray();
  
          bos.close();
      }
  
      String getBoundaryString()
      {
          return BOUNDARY;
      }
  
      String getBoundaryMessage(String boundary, Hashtable params, String fileField, String fileName, String fileType)
      {
          StringBuffer res = new StringBuffer("--").append(boundary).append("\r\n");
  
          Enumeration keys = params.keys();
  
          while(keys.hasMoreElements())
          {
              String key = (String)keys.nextElement();
              String value = (String)params.get(key);
  
              res.append("Content-Disposition: form-data; name=\"").append(key).append("\"\r\n")
                  .append("\r\n").append(value).append("\r\n")
                  .append("--").append(boundary).append("\r\n");
              System.out.println("****In while Loop:-****"+res);
          }
          res.append("Content-Disposition: form-data; name=\"").append(fileField).append("\"; filename=\"").append(fileName).append("\"\r\n")
              .append("Content-Type: ").append(fileType).append("\r\n\r\n");
          return res.toString();
      }
  
      public byte[] send() throws Exception
      {
          HttpConnection hc = null;
  
          InputStream is = null;
  
          ByteArrayOutputStream bos = new ByteArrayOutputStream();
  
          byte[] res = null;
  
          try
          {
              hc = (HttpConnection) Connector.open(url);
  
              hc.setRequestProperty("Content-Type", "multipart/form-data; boundary=" + getBoundaryString());
              hc.setRequestProperty("Content-Length",postBytes+"");
  
              hc.setRequestMethod(HttpConnection.POST);
  
              OutputStream dout = hc.openOutputStream();
  
              dout.write(postBytes);
              dout.close();
  
              int ch;
  
              is = hc.openInputStream();
              StringBuffer buffer=new StringBuffer();
  
              while ((ch = is.read()) != -1)
              {
                  bos.write(ch);
                  buffer.append((char)ch);
              }
              res = bos.toByteArray();
              System.out.println(buffer.toString());
          }
          catch(Exception e)
          {
              e.printStackTrace();
          }
          finally
          {
              try
              {
                  if(bos != null)
                      bos.close();
  
                  if(is != null)
                      is.close();
  
                  if(hc != null)
                      hc.close();
              }
              catch(Exception e2)
              {
                  e2.printStackTrace();
              }
          }
          return res;
      }
  }
  

  and use it in this way

  public void getBytes()
      {
          ByteArrayOutputStream bos=null;
          try
          {
              bos=new ByteArrayOutputStream();
              InputStream fis=getClass().getResourceAsStream("/super.mp3");
              int ch;
              byte[] data=new byte[120];
              while((ch=fis.read(data,0,data.length))!=-1)
              {
                  bos.write(data,0,data.length);
              }
              Hashtable params=new Hashtable();
              //params.put("id_user","8474");
              params.put("id_user","8379");
              params.put("file1","audio.mp3");
              HttpMultipartRequest httpreq=new HttpMultipartRequest("http://api.upload.com/gStorage/uploadSong?", params,"file1","xpressMusic.mp3","audio/mpeg",bos.toByteArray());
              httpreq.send();
              bos.close();
              fis.close();
          }
          catch (Exception e) {
              System.out.println("Exception"+e);
          }
  

  Here, the key is contenttype, contentLength.you can get the info on it from the link above.

  thankx.

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  Hello

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  No detail message

  net_rim_cldc (4AAABCA5)

  DataBuffer

  ensureBuffer

  0 x 3690

  net_rim_cldc (4AAABCA5)

  DataBuffer

  To write

  0x3C52

  net_rim_crypto_1-3 (4AAAC974)

  TLSOutputStream

  To write

  0x45C7

  net_rim_cldc-1 (4AAABCA5)

  DataOutputStream

  To write

  0x221D

  net_rim_os-2 (4AAAC894)

  ClientProtocol

  0x1A1D

  net_rim_os-2 (4AAAC894)

  ClientProtocol

  writeRequest

  0 x 1422

  net_rim_os-3 (4AAAC894)

  HttpProtocolBase

  transitionToState

  0x33D7

  net_rim_os-2 (4AAAC894)

  ClientProtocol

  transitionToState

  0x23D4

  net_rim_os-3 (4AAAC894)

  HttpOutputStream

  Rinse

  0x334C

  ....

  When I test Simulator 8300, I got EOFException.

  No detail message
  net_rim_os-2
  ClientProtocol
   
  0 x 1917
  net_rim_os-2
  ClientProtocol
  readResponse
  0x148A
  net_rim_os-3
  HttpProtocolBase
  transitionToState
  0 x 1613
  net_rim_os-2
  ClientProtocol
  transitionToState
  0 x 2335
  net_rim_os-3
  HttpOutputStream
  Rinse
  0x157E

  ...

  This code seems to work for the file with a size less than 2 MB.

  Any suggestions would be very appeciated.

  Thank you

  Itthipon

  I was able to replicate that when you use an OutputStream.  OutputStream to DataOutputStream switching enabled me to show 3 MB of data.  Please give that a try and making me know if you encounter other problems.

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  Hello

  How can we run our applications Oracle Forms in Google chrome (with SSO)? This has not worked quite awhile and a lot of our other company activities revolve around Chrome in the standard user interface.

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  976327 wrote:

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  Hello

  I work with HTTP get and post at the moment, I have a server with a REST of apache based interface. Obtaining and displaying the data are no problem for 'normal' strings and characters, but I can't send characters like German "Umlaut" (Ä Ü Ö) or Japanese or Chinese characters. Coding for the Socket connection is UTF-8 and the command POST also contains a line of Content Type with character set UTF-8. The server expects UTF - 8, so I need my data in this encoding.

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  Thank you

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  OK, it took a while to find that - maybe someone else has the same problem and it is looking for a solution, I'll try to explain:

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• How to make http post in the Webcenter Portal Application?

  Hi all

  We have a requirement in which we must train to an external URL.

  We have created a Taskflow bounded with page fragment. Added a button on the page fragment and had to form POST to an external URL the button click. Expected features, the URL of the external site will open in the same tab.

  But we can not directly use html form tag in the page jspx because it cannot have two form elements.

  Example code snippet that we use:

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  < input type = "hidden" name = "userId" value = "12345" / >

  < / make >

  
  

  We have tried to do this programmatically as below. But it does not work.

  JSPX code:

  <? XML version = "1.0" encoding = "UTF - 8"? >

  " < = xmlns:jsp jsp:root ' http://Java.Sun.com/JSP/page "version ="2.1" "

            xmlns:f=" http://Java.Sun.com/JSF/core "

            xmlns:h=" http://Java.Sun.com/JSF/HTML "

  ' xmlns:af = ' http://xmlns.Oracle.com/ADF/faces/rich "> "

  < jsp:directive.page contentType = text/html"; Charset = UTF - 8 "/ >

  < f: view >

  < af:document id = "d1" >

  < af:form id = "f1" >

  < af:region value = "#{bindings." TestTF1.regionModel}"id ="r1"/ >

  < / af:form >

  < / af:document >

  < / f: view >

  < / jsp:root >

  JSFF code:

  <? XML version = "1.0" encoding = "UTF - 8"? >

  " < = xmlns:jsp jsp:root ' http://Java.Sun.com/JSP/page "version ="2.1" "

  ' xmlns:af = ' http://xmlns.Oracle.com/ADF/faces/rich "" "

            xmlns:f=" http://Java.Sun.com/JSF/core ">

  < af:resource type = "javascript" >

  function postToURL (url) {}

  var form = createElement ('form');

  form.setAttribute ("method", "POST");

  form.setAttribute ("action", url);

  Form._submit_function = form.submit;

  form.appendChild (document.createElement ("input", {type: "hidden", name: "userId", value: "12345"}));

  document.body.appendChild (form);

  Form._submit_function ();

  }

  < / af:resource >

  < af:panelGroupLayout id = "pgl1" layout = "horizontal" >

  < af:commandButton text = "Submit" id = "cb1".

  actionListener = "#{pageFlowScope.SampleBean.postToCvent}" > < / af:commandButton >

  < / af:panelGroupLayout >

  < / jsp:root >

  Managed Bean Code:

  	{} public void postToCvent (ActionEvent actionEvent)
  	FacesContext fctx = FacesContext.getCurrentInstance ();
  	String url = " " http://XYZ/reg.aspx ";
  	ExtendedRenderKitService service = Service.getRenderKitService (fctx, ExtendedRenderKitService.class);
  	StringBuffer script = new StringBuffer();
  	script. Append ("postToURL('");
  	script. Append (URL);
  	script. Append("')"); "
  	service.addScript (fctx, script.toString ()); }

  Thank you

  Bharat

  Abhijit salvation,

  sendRedirect don't GET, POST.

  in any case I solved the problem by substituting the attribute action for af:form using java script and adds input fields on the fly and able to reach the POST form to an external URL.

  JavaScript (test.js file):

  function postToCvent (event) {}

  If (event! = null) {}

  Get the source Customer attribute

  var url = event.getSource () .getProperty ('url');

  var userId = event.getSource () .getProperty ("userId");

  Get the form by Id element, it will be af:form Id

  var form = AdfPage.PAGE.findComponentByAbsoluteId ("mform");

  If (form! = null) {}

  formId var = form.getClientId ();

  document.getElementById (formId) .setAttribute ("method", "POST");

  document.getElementById (formId) .setAttribute ("action", url);

  Create and add the input field to your

  var hiddenField1 = document.createElement ("input");

  hiddenField1.setAttribute ("type", "hidden");

  hiddenField1.setAttribute ("name", "userId");

  hiddenField1.setAttribute ("value", username);

  document.getElementById (formId) .appendChild (hiddenField1);

  SubmitForm

  document.getElementById (formId) .submit ();

  }

  }

  JSFF code:

  
  

  http://XYZ/reg.aspx"/ >

  JSPX code:

  
  

  source="/resources/test.js"/ >

  Thank you

  Bharat

• Connect in HTTP-Post

  Hello
  
  am I right if I think that it is not possible to connect to rwservlet via http-post, only http-get.
  And that's the reason why I get REP-56048 when I try?
  
  Thank you.
  
  Concerning
  
  Chris

  Hi Chris,
  Take a look at the code in the following document can help.

  Reference
  REP-0788 warning message when the report with a form of parameter of the HTML form on the web (Doc ID 359819.1)

  Best regards, RZ