Add days to a date that a new release date?

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• How can I add days to a Date value in a Script time?

  How can I add days to a Date value in a Script (XPATH) time?

  XPATH:

  Add Date:

  xs:dateTime($yourCurrentDateVar) + xs:dayTimeDuration($yourDuration)
  

  Difference in date:

  move "fn:days-from-duration(xs:dayTimeDuration(xs:date($yourCurrentDateVar) - xs:date($yourPrevDateVar)))" to $diff;
  

  You did not mention the version of the Framework, you can take advantage of the Business Service (BS) to perform Date calculations, for example, for FW2.2.x, you can use BS: C1-DateMath with such options as the 'Resistance' to add to the Date, "DIFF" for Date-Diff and FW4.x, you can use BS: F1-DateMath with options such as "F1AD" to add to the Date etc.

  Find out more about XPATH herefunction.

• Add days to a date

  Hello world

  I am trying to add a (x) number of days to a date.

  example: 15-Aug-2011 + 6 = 21-sep-2011

  I tried several things with calendar, but didn't workout, suspicion

  Not a trivial exercise and don't forget that you can just add 24 * 60 * 60 * 1000 for one time to add 1 day, because the day could be a breakthrough in 'day '.  If you want only the day and not the time, so it's a little easier.  Here's a hat of suggestions, I think that will work for you.

  Take the date, convert it to a Calendar object, use DateTimeUtiltiies to ensure that the time is 0 (that is 12:00 midnight) get the delay in milliseconds of this calendar (get the Date, then get the shape of time this Date), adding n * DateTimeUtilities.ONEDAY, where n is the number of days that you want to add, and then add 12, ensure that move you in the "next day" without taking into account DST changes that could happen in the period , then put it in the calendar, zero once again, the time and do it.

  If it does not, show us the code that you have developed.

• Add days to a date is to be indented by year.

  Hello
  
  I have the problem on Oracle 10 g. I have run the following statement that adds 1 to a date, but, unless I have format, the date is back with a year less than expected.
  

  SQL> select effective_date, (effective_date + interval '1' year(1)) as addyear, add_months(to_date(to_char(effective_date, 'MM/DD/YYYY HH24:MI:SS'), 'MM/DD/YYYY HH24:MI:SS'), 12) as addyearformat
     from price_change
          where
          price_change_id = '794328'   ;
  
  EFFECTIVE_DATE  ADDYEAR         ADDYEARFORMAT
  --------------- --------------- ---------------
  28-SEP-09       28-SEP-08       28-SEP-10

  Has anyone ever seen anything like that?
  
  Effective_date is of type date and has data in the format "MM/DD/YYYY HH24:MI:SS. I think it's something with the format, perhaps something to do with the zone - not sure. If I just insert a value into the table with the format ' MM/DD/YYYY HH24:MI:SS' I don't have this problem. I don't know how the date could have been modified to do that, but I know not to go through a time zone function before be inserted in this table, but I don't know if that is the cause of the problem.
  
  Don't know if it's important but nls_database_parameters...
  VALUE OF THE PARAMETER
  NLS_DATE_FORMAT dd-MON-rr
  NLS_TIMESTAMP_FORMAT-DD-MON-RR HH.MI. SSXFF AM
  NLS_TIMESTAMP_TZ_FORMAT DD-MON-RR HH.MI. SSXFF AM TZR
  NLS_TIME_FORMAT HH.MI. SSXFF AM
  NLS_TIME_TZ_FORMAT HH.MI. SSXFF AM TZR
  
  
  Thanks for any help in advance.
  
  Published by: amcgator on October 15, 2010 11:52

  amcgator wrote:
  In fact, this would explain why, if I do not pass the end of the year mark (IE if I just add 30 days), everything looks OK. How in the world that is possible, or how can I confirm this?

  Did you read my response? Question:

  select  to_char(effective_date,'mm/dd/yyyy bc')
    from  price_change
    where price_change_id = '794328'
  / 
  

  If you see bc - it's confirmed :).

  SY.

• Add days to a date default of DateFields.

  I'm creating a DateField with default date and add to my screen. How can I create a second DateField and add three days to the current date and displays?

  Here is what it looks like when I open the screen initially:

  

  Here's what I want it to look like:

  

  Here is the code:

  SimpleDateFormat sdf = new SimpleDateFormat("MM/dd/yyyy");
  DateField dateStart = new DateField("", 0, sdf, Field.FIELD_RIGHT
          | DrawStyle.RIGHT | Field.FOCUSABLE) {
      protected void layout(int width, int height) {
          super.layout(100, height);
      };
  };
  dateStart.setMargin(new XYEdges(0, 15, 0, 0));
  dateStart.setDate(Calendar.getInstance().getTime());
  dateArea.add(dateStart);
  
  DateField dateFinish = new DateField("", 0, sdf, Field.FIELD_RIGHT
          | DrawStyle.RIGHT | Field.FOCUSABLE) {
      protected void layout(int width, int height) {
          super.layout(100, height);
      };
  };
  dateFinish.setDate(Calendar.getInstance().getTime());
  

  Hello

  long ldate = System.currentTimeMillis();
  String date = new SimpleDateFormat("dd.MM.yyyy").format(new Date(ldate));
  

  Gets the current date as long in ldate and as a string to a date.

  If you want to add a day, simply add 24 * 3600 * 1000 to ldate. If you have the new date in milliseconds.

  just convert to e string trick.

  hope it helps

• Add days to a Date/time stored

  Hello
  
  Here's what I'm trying to do.
  
  I am trying to add a field of records called #Warranty_Dump_Info.Reference # on a domain registration
  called #Warranty_Dump_Info.Purchase_Date # and get a later date representing the date of expiry of a factory warranty.
  
  #Warranty_Dump_Info.Reference # is a numeric value (30, 90, 180, etc.) that represents the number of days covered by the warranty and the #Warranty_Dump_Info.Purchase_Date # is the date/time value (example: 2009-01-01 00:00:00)
  
  I can get the date/time format (time deleted).
  with the help of < foutput > #dateformat(Warranty_Dump_Info.Purchase_Date, "mm-dd-yyy") # < / output >
  
  However, I can't seem to add the number of days value of #Warranty_Dump_Info.Reference # or to display
  in the right format of date (time stripped).
  
  I tried the time of #Warranty_Dump_Info.Purchase_Date # stripping and then saving them as a variable, then
  always using the Functionadds on the variable, but it fails to strip the time according to the results.
  
  Thanks in advance for your help.
  
  
  In addition, what it means when the date is displayed as follows: {ts ' 2009-01-01 00:00:00 '}
  Some of my attempts to CF have resulted in this weird display "ts". You can see at the bottom of the page here: http://devo.dns2go.com/Warranty_Dump.cfm (logon as Admin, password: admin). That's where I tried to experiment and understand.

  OK, now I see what you're saying...

  I use CF functions in the SQL...

  Here are the labour code for those who follow this thread:

  
  SELECT *.
  INNER JOIN Vendor_Table WARRANTY
  ON Warranty.Vendor_Num = Vendor_Table.Vendor_Num
  WHERE dateadd (would be ', Warranty_Days, Purchase_Date) > = Date)
  AND Warranty.Part_Number ='#URLDecode (URL. "PartNumber) #
  ORDER OF Part_Number, Serial_number CSA
  

  Thank you very much for the help!

  Eric

• Add days to date (integer format)

  Hi all

  I'm trying to add days to a date that is in numbers.

  Suppose I have a date 20140331 and if I add + 1 to her I me 20140332. How can I get 20140401 in digital format using pl/sql query.

  Also, I should be able to add any number of days existing dates to get the correct date. The example above is just a sample.

  Thank you

  Hello

  Here is an example showing how easy it is to use the arithmetic of dates with DATEs:

  CREATE TABLE table_x

  (x_id PRIMARY KEY NUMBER

  x_date DATE

  );

  ALTER SESSION SET NLS_DATE_FORMAT = 'YYYYMMDD ';

  INSERT INTO table_x (x_id, x_date) VALUES (1, TO_DATE ('20140331', 'YYYYMMDD'));

  INSERT INTO table_x (x_id, x_date) VALUES (2, SYSDATE);

  SELECT x.*

  x_date + 1 tomorrow

  x_date + 10 AS ten_days

  FROM table_x x

  ORDER BY x_id;

  Output:

  X_ID X_DATE TOMORROW TEN_DAYS

  ---------- -------- -------- --------

  1 20140331 20140401 20140410

  2 20150219 20150220 20150301

  Date arithmetic is also easy and intuitive, when using the DATEs as a number arithmetic is using numbers.

• How to add days, hours, minutes and seconds to a date?

  Hello
  
  I have the following problem.
  Saw 4 integers D, H, M, and S (each of them can be negative) and a date Da, I want to add days D, H hours, M minutes and seconds of S date Da.
  For example, if

  Da= to_date('28/06/2011 14:50:35','dd/mm/yyyy HH24:mi:ss'), and D = 3, H = -2, M = 20 and S = -12, 

  This means that I want to add 3 days, -2 hours, 20 minutes and -12 seconds to the date Da, and the new date must be in the following date:

  to_date('01/07/2011 13:10:23','dd/mm/yyyy HH24:mi:ss') 

  Is it possible to write a query for this problem or should I use PL/SQL?
  
  Thank you.

  There is no need of PL/SQL

  SQL> alter session set nls_date_format = 'DD/MM/YYYY HH24:MI:SS';
  
  Session altered.
  
  SQL> var d number
  SQL> var h number
  SQL> var m number
  SQL> var s number
  SQL> exec :d := 3; :h := -2; :m := 20; :s := -12
  
  PL/SQL procedure successfully completed.
  
  SQL> select to_date('28/06/2011 14:50:35','dd/mm/yyyy HH24:mi:ss')
    2     + :d
    3     + (:h / 24)
    4     + (:m / 24 / 60)
    5     + (:s / 24 / 60 / 60)
    6  from dual;
  
  TO_DATE('28/06/2011
  -------------------
  01/07/2011 13:10:23
  

• How do I add 7 days to a date and compare it to the current date in a cfquery?

  I have classes that are no longer active once after the date of the class. However, the class should be displayed for seven days more in the backend. I tried to use the script below to get there, but I get an error "Variable DATE is not defined." I'm going in the right direction or is there a better way to do this?

  < name cfquery = "getClasses" datasource = "#application.dsn #" >

  Select *.

  (break the classReg INNER JOIN classReg.classID = classes.classID) INNER JOIN instructors ON classreg.instID = instructors.instID

  <!-adding seven days to the date of the class (date) by comparing the current date->

  where #DateFormat (DateAdd (would be ', 7, date), 'yyyy-mm-dd') # > #DateFormat (now (), 'yyyy-mm-dd') #.

  < / cfquery >

  where #DateFormat (DateAdd (would be ', 7, date), 'yyyy-mm-dd') # > #DateFormat (now (), 'yyyy-mm-dd') #.

  As Coldfusion said you, quite rightly so, he knows no variable called "date". You're in a request and, apparently, 'date' is a column name. So use the SQL functions instead of Coldfusion functions.

  In MySQL, the appropriate where clause is:

  WHERE DATE_ADD (date, INTERVAL of 7 DAYS) > CURDATE)

  In SQL Server, the appropriate where clause is:

  WHERE DATEADD(day,7,date) > GETDATE()

  ---------------------------------

  Afterthought: I would rename the column 'date', as it is a reserved word in some database management systems

• Calculate the difference in days between two Dates

  Hello

  I'm trying to understand how to calculate the difference in days between two dates using JavaScript in LiveCycle. (Minimum = JavaScript knowledge)

  Where 'Start_Date' and 'Current_Date' are the names of the two dates in the palette of the hierarchy. (the two Date/time field)

  * Current date is using the object > value > execution property > current Date/time

  I need a text or number field showing the difference in days. (Difference_in_Days)

  I noticed the following code is pretty standard among other responses:

  var

  Start_date = new Date (Start_Date);

  var

  Current_Date = new Date (Current_Date);

  var

  nAgeMilliseconds = Current_Date.getTime) - Start_date.getTime ();

  var

  nMilliSecondsPerYear = 365 * 24 * 60 * 60 * 1000 ;

  I know there is lack of code and code above are may not be not correct.

  Please notify.

  OK, that's because of the way that javascript and works of the calculate event.  The field will be filled with whatever the script resolves at the end of execution. Technically, your script does not have a value because the last thing you do is an assignment to a variable.  Change the last line as follows:

  Math.ABS ((firstDate.getTime)

  ((- secondDate.getTime (()) / (oneDay));

  (eliminate the variable assignment) and get rid of the app.alert.  Your script will "return" (have) regardless of the value of calculation from the East and which will be stored in the field.

• Page Add-ons does not recognize that I have updated flash player

  I've recently updated to the latest version of Flash player (18.0.0.209), but the update and add-on pages tell me that I am using 18.0.0.194. I tried to reset the file pluginreg.dat and all the other options I've seen on through research to help but nothing works. Any help?

  What do you see on the topic: plugins page?

  You can find the installation path of the plugins on the topic: plugins page.

  • http://KB.mozillazine.org/Issues_related_to_plugins#Identifying_installed_plugins

  You can view the installation folder of Flash player for multiple Flash player plugins and delete older versions of the plugin (NPSWF32) and possibly (re) install the latest Flash Player.

  • (32-bit Windows) C:\Windows\System32\Macromed\Flash\
  • (Windows 64 bit) C:\Windows\SysWOW64\Macromed\Flash\

  You can find the latest versions of Flash player for Firefox on this page:

  • http://www.Adobe.com/special/products/flashplayer/fp_distribution3.html

• I want that my new tabs to open to my home instead of blank page. I can't have this?

  When I opened a new tab, I want to open my home page, not to be a Virgin. Seems so simple and obvious, but I did not understand how to get there. Thank you!

  Install an extension that adds this functionality to Firefox.

  New tab homepage extension:
  https://addons.Mozilla.org/en-us/Firefox/addon/777
  or
  NewTabURL extension
  https://addons.Mozilla.org/Firefox/2221/

• Technical support Epson says that my new Stylus Photo R2000 does not print wireless in my permisions o/s Microsoft. Please notify.

  Technical support Epson says that my new Stylus Photo R2000 does not print wireless in my permisions o/s Microsoft.

  My Toshiba Laptop Windows XP Media Center OS is currently being updated with the exception of a point to update MS Office 2003 #KB949074

  has no size to him.

  Please notify.

  Kind regards

  Adolph Moret

  A call back to Epson says my Windows Firewall blocks printing Epson Status Monitor and by disabling the firewall every thing returns to normal.  Turning on the firewall without exception is still no difference and I should contact Microsoft for that matter.

  If the application works when the firewall is disabled, but not when the firewall is turned on, so you must create an exception for the application.

  I don't know what you mean by "turning on the firewall without exceptions still makes no difference" - no difference of what?

  You must determine the name of print Epson Status Monitor, then go to control panel > Windows Firewall (if your control panel is using "Category view", you will find Windows Firewall in the Security Center).

  Once in the Firewall dialog box, click the Exceptions tab, click the button "Add a program" and find printing Epson Status Monitor.  If it is not in the list that appears, click on the button "Browse".  After selecting the program and click OK, make sure that on the general tab of the Firewall properties dialog box that the "do not allow the box exceptions" is NOT checked.

• get the name of the day of a date (format yyyy/mm/dd)

  Hello

  In blackberry java application development is possible to get the name of the day of a date (format yyyy/mm/dd).

  I have a date as 09/15/2013. I want the output like Sunday

  Thank you and best regards.

  Thank you reply Erwan fo...

  I post my code using... It can be used to get the name of the day for a date string.

  //SimpleDateFormat write = new SimpleDateFormat("EEEE-MMM-dd");//It will return Weekday name as full plus monthe name plus date
  SimpleDateFormat write = new SimpleDateFormat("EEEE");//It will return Weekday name
  Date date = new Date(HttpDateParser.parse("2013/09/12"));
  System.out.println(write.format(parsedDate));
  

  Best regards.

• My students use the filling and the signature on a package of .pdf tool I'm going to fill them, but when they record and open the next day their text boxes, that they created with the bucket fill tool and sign all went and many are overlapping.

  My students use the filling and the signature on a package of .pdf tool I'm going to fill them, but when they record and open the next day their text boxes, that they created with the bucket fill tool and sign all went and many are overlapping.

  Hi chbradshaw,

  Instead of filling & signature, tool, use the text comment comment tool, KB doc option. using comments in the PDF, Adobe Acrobat DC files (keyword: Add a text comment).

  Kind regards

  Nicos