addition of populated table's primary key column

Similar Questions

• How can I update the primary key column

  Hello
  Can you suggest me best workaround/algorithm for task below:
  
  (Oracle 10g, Solaris OS.)
  Location:
  Table a primary key column P 'Code', tables children F1, F2,..., reference to F15 "Code_P' foreign key column"P.Code"column, and we do not know which of the child tables data available for a particular value"P.Code.
  Task:
  Change the value "P.Code" from 100 to 200. So that the result would be that record P [Code = 100] should be updated:

  update P set
  Code = 200
  where Code = 100;

  And child tables 'Code_P' column should be updated as:

  update F1, F2, .., F15 set
  P_code = 200
  where P_code = 100;

  The best solution would be that you can easily repeat this task.
  
  Edited by: CharlesRoos the 28.12.2010 12:10

  Will there be FK constraints in place?
  If so, you may need to modify them so that their application may be temporarily deferred.

  The gameplan would be something like this:

  -Making of CF can be deferred, immediate departure.
  -Alter FK set delay.
  -Update of Parent table.
  -Update of the children tables.
  -Immediate constraints set
  s ' engage;

• How to find the primary key columns in the tables in MS Access using SQL queries

  How to find the primary key columns in the tables in MS Access using SQL queries

  Hello

  This is the forum for Windows Vista programs related issues.

  For better assistance, please try instead the Forums in SQL Server .

  Thank you! Vincenzo Di Russo - Microsoft MVP Windows Internet Explorer, Windows Desktop Experience & security - since 2003. ~ ~ ~ My MVP profile: https://mvp.support.microsoft.com/profile/Vincenzo

• Diagram of all the tables list of primary key column names

  Hi people,
  
  I have a Scott user for example, I want to retrieve all tables primary key column names in the user Scott.
  
  can someone help me please.
  
  Thanks in advance,
  karmaya

  You can log in to SCOTT and try this

  select c.constraint_name
       , cc.table_name
       , cc.column_name
    from user_constraints c
    join user_cons_columns cc
      on c.constraint_name = cc.constraint_name
   where c.constraint_type = 'P';
  

• How to refer to the primary key column of newly inserted rows of tabular form

  Hello

  I use APEX 4.2.0.00.27 with Oracle DB 11.2.0.3.0.

  I work with a tabular presentation wizard-created for insert and update a table using the integrated SRM process (sequence 10).  I'm trying to use a process of anonymous block of PL/SQL (sequence 30) to make another manipulation of table after the records were inserted or updated.  The manual process is associated with my tabular form and I use the variables of name of column binding in my program block.

  My (rsn_test) table has 3 columns: test_id (number), test_nbr (number), test_id2 (number).  Test_id column is identified as the primary key and the type of the source already exists a sequence rsn_test_seq.  Column test_id2 gets its default value 0 to a hidden page element.

  I would use my manual process for updating the value of the test_id2 column.  If it's 0 then I want to put the value of the column test_id.  If it is any other value, then it must remain at this value.  My logic works very well for an existing line, but I'm running into a problem with the newly added lines.  The new lines get inserted, but the test_id2 column remains the default value 0.  I can tell the debugger that the SRM process is triggered first and inserts the line, then my manual dealing with fires.  The problem seems to be that the connection variable: TEST_ID for the primary key column remains NULL after insertion.  I don't know how to get the value of the column test_id of my newly created line to use in my PL/SQL block to my update.

  Process of PL/SQL:

  DECLARE
  BEGIN
     :P7_SHOW := NULL;
     :P7_SHOW := NVL(:TEST_ID2,555) || ' and ' || NVL(:TEST_ID,787) || ' and ' || NVL(:TEST_NBR,9999);
     IF :TEST_ID2 = 0 AND :TEST_ID IS NOT NULL THEN
        UPDATE rsn_test
           SET test_id2 = :TEST_ID
         WHERE test_id = :TEST_ID;
     ELSE
        :TEST_ID2 := :TEST_ID2;
     END IF;
  END;
  
  

  Excerpt from the debugger:

  0.01625 0.00010 Processes - point: ON_SUBMIT_BEFORE_COMPUTATION
  0.01635 0.00008 Branch point: Before Computation
  0.01643 0.00003 Process point: AFTER_SUBMIT
  0.01646 0.00022 Tabs: Perform Branching for Tab Requests
  0.01668 0.00008 Branch point: Before Validation
  0.01676 0.00024 Validations:
  0.01700 0.00135 Perform basic and predefined validations:
  0.01835 0.00020 Perform custom validations:
  0.01855 0.00049 ...Validation "TEST_NBR must be numeric" - Type: ITEM_IS_NUMERIC
  0.01904 0.00007 ......Skip for row 1 because row hasn't changed
  0.01911 0.00016 ......Skip for row 2 because row hasn't changed
  0.01927 0.00012 ...Validation "TEST_ID2 must be numeric" - Type: ITEM_IS_NUMERIC
  0.01939 0.00007 ......Skip for row 1 because row hasn't changed
  0.01945 0.00018 ......Skip for row 2 because row hasn't changed
  0.01964 0.00005 Branch point: Before Processing
  0.01968 0.00004 Processes - point: AFTER_SUBMIT
  0.01972 0.00588 ...Process "ApplyMRU" - Type: MULTI_ROW_UPDATE
  0.02560 0.00154 ...Execute Statement: declare function x return varchar2 is begin begin for c1 in ( select "RSN_TEST_SEQ".nextval pk from sys.dual ) loop return c1.pk; end loop; end; return null; end; begin wwv_flow.g_value := x; end;
  0.02714 0.00140 ......Row 3: insert into "APPPCSRSN"."RSN_TEST" ( "TEST_ID", "TEST_NBR", "TEST_ID2") values ( :b1, :b2, :b3)
  0.02854 0.00011 ...Process "ApplyMRD" - Type: MULTI_ROW_DELETE
  0.02865 0.00004 ......Skip because condition or authorization evaluates to FALSE
  0.02869 0.00015 ...Process "Process Submit" - Type: PLSQL
  0.02884 0.00007 ......Skip for row 1 because row hasn't changed
  0.02891 0.00012 ......Skip for row 2 because row hasn't changed
  0.02903 0.00012 ......Process row 3
  0.02915 0.00429 ...Execute Statement: begin DECLARE BEGIN :P7_SHOW := NULL; :P7_SHOW := NVL(:TEST_ID2,555) || ' and ' || NVL(:TEST_ID,787) || ' and ' || NVL(:TEST_NBR,9999); IF :TEST_ID2 = 0 AND :TEST_ID IS NOT NULL THEN UPDATE rsn_test SET test_id2 = :TEST_NBR WHERE test_id = :TEST_ID; ELSE :TEST_ID2 := :TEST_ID2; END IF; END; end;
  0.03344 0.00013 ...Session State: Saved Item "P7_SHOW" New Value="0 and 787 and 1300"
  0.03356 0.00004 Branch point: After Processing
  0.03360 0.00048 ...Evaluating Branch: "AFTER_PROCESSING" Type: REDIRECT_URL Button: (No Button Pressed) Condition: (Unconditional)
  0.03407 0.00013 Redirecting to f?p=290:7:8717971109610:::::&success_msg=0%20row(s)%20updated%2C%201%20row(s)%20inserted.Success%2FEBD244168556408CBA714E3974918C09%2F
  0.03420 0.00012 Stop APEX Engine detected
  0.03432 0.00007 Stop APEX Engine detected
  0.03439 - Final commit
  
  

  Any suggestions?

  I have run tests on

  https://apex.Oracle.com/pls/apex/f?p=83488:1 demo/demo

  to see your problem.

  I have 2 solution for your problem.
  I add trial NOT tabular just usual block of PL/SQL

  	BEGIN
  	I'm IN (SELECT TEST_ID FROM RSN_TEST WHERE TEST_ID2 = 0)
  	LOOP
  	UPDATE RSN_TEST
  	SET test_id2 = TEST_ID
  	WHERE test_id = i.TEST_ID;
  	END LOOP;
  	END;

  and works very well, you can see in the sample.

  The other solution is to show new generated TEST_ID

  Adding a sequence as a default value for a column in a table field

  And to execute your procedure.

  I get how is with the good luck of time.

  By

• You would design Tables without primary key?

  If you were asked to design a schema, if you create a table (however irrelevant) without a primary key? For example, a 'unprofessional' table such as a logging of errors table that records exceptions thrown from stored procedures, create you this table without a primary key?

  In a relational database you define und work with entities (tables) and you put in relationship to each other by joins. An entity must by definition always be identified by a unique key.
  If you don't know what kind of unique key identifies your entries in the table, it is almost certain that working from home in your datamodel and table designs had not been made. Your database objects contain tables, and they must have a unique identifier. Often it is a primary key (PK) composed of several columns.

  By definition a datamodel that contains the tables without primary keys is nomore a relational datamodel and one of the fundamental bases for the creation of a relational database is violated.

  Frankly I do not understand why Oracle allows the tables without primary key. Another system such as SAP R/3 are more stringent. Primary keys are required in the SAP and believe, when starting, it is sometimes tedious to define the primary key structures, but it's the basis of designing together relational datamodel you will put in place. You now SAP is based often on a DB ORACLE layer. They could do it, and these "extend" their functionality. But they are smart guys in Walldorf, and they always refrained to do. It's a good guess to believe, they have a good reason for it.

  Tables without primary key are NO relational tables, they are dungpiles. As Oracle needs priimary key itself in order to operate a relational database, ROWID have been defined. ROWID is the primary keys of the tables where the customer does not have a PK. But nice as ORACLE is, they strongly recommend not to use these ROWID in the application or database layer. ROWID is no identifier object that are stable in time and space (eg. two different databases in a distributed design oder a DEV and PROD-system).

  Definition of PK implies certain rules for the programming of your application and your DML operations. Especially you often MERGE in a relational table instead of simply INSERT'ing piece in a dungpile.

  When it later on with SELECT large datavolumes dataaccess, again the differences between well-defined joins (all based on the PK-relations) and joins non-unique keys will be the order of magnitude. Not only that, the latest degrades in performance much more quickly with the growth of result sets. When you start fumbling with no UNIQUE INDEXES, speed up performance in the operations of dungpiling you are already closer to hell than on a sunny day in the world of relational data.

  Othmar Lippuner
  SQL Reporting professional

• A composite primary key column cannot be null

  Hi all
  It will be a silly question, but still, I would like to ask if a composite primary key column can be null?
  
  
  Thank you
  Rafi.

  Rafi,

  Why you think he would be allowed?

  SQL> drop table test purge;
  drop table test purge
             *
  ERROR at line 1:
  ORA-00942: table or view does not exist
  
  SQL> create table test as select * from dba_objects;
  
  Table created.
  
  SQL> alter table test add primary key(object_id, owner);
  
  Table altered.
  
  SQL> insert into test(object_id, owner) values(null, 'aman');
  insert into test(object_id, owner) values(null, 'aman')
                                            *
  ERROR at line 1:
  ORA-01400: cannot insert NULL into ("SYS"."TEST"."OBJECT_ID")
  
  SQL> insert into test(object_id, owner) values(1,null);
  insert into test(object_id, owner) values(1,null)
                                              *
  ERROR at line 1:
  ORA-01400: cannot insert NULL into ("SYS"."TEST"."OWNER")
  
  SQL>
  

  HTH
  Aman...

• How to convert a single column in the primary key column

  Hi all
  
  I have a column that's unique cnstraint, this column contains the value as digital and also null.
  
  So how do you convert to primary key column
  
  Concerning
  Prashant

  Prashant wrote:
  Hi all

  I have a column that's unique cnstraint, this column contains the value as digital and also null.

  So how do you convert to primary key column

  Concerning
  Prashant

  Prashant,

  You must assign new values to null values. You can use a sequence to produce the figures in this column.

  Select max (your_unique_column) from your_table; -find the maximum value of this column, so you can start the sequence of this number.

  create sequence seq_for_your_table with XXXX - value max + 1 you have found

  Update your_table set your_unique_column = seq_for_your_table.nextval () where your_unique_column is null

  You can create a primary key on this column.

  Best regards

  Grosbois

  -------------------------------------------------------
  If you answer this question, please mark appropriate as correct/useful messages and the thread as closed. Thank you

• Get 2 amounts of 2 columns of 2 tables without primary key

  I would like to get the sum of column A of table 1 and the sum of column D in table 2 without using the primary key.

  Because I can't link the two tables, the only corresponding value is not the primary key.

  TABLE 1

  COLUMN A.     COLUMN B |    COLUMN C

  PAID NUMBER DESCRIPTION

  15472 blabla1 S15-875

  18515

  S15-875 blabla1

  215526.52 blabla2 D17-517

  ...                               ...                           ...

  TABLE 2

  COLUMN D |     COLUMN E |    COLUMN F

  INVOICE

  NUMBER

  DESCRIPTION

  185525 blabla1 S15-875

  158520 D17-517 blabla2

  8964

  D17-517

  blabla2

  I would like to see the number, the sum of which should be paid and what has been paid.

  But as you can see, you can pay in several times and there may be several invoices.

  There is therefore no link between two tables which is a primary key in both entities.

  No idea how I could get it?

  NUMBER |    DESCRIPTION |    BILL |     PAID

  S15-875 185525 33987 blabla1

  D17-517 blabla2 167484 215526.52

  The tables can be attached on «NUMBER», regardless of weather conditions, as a primary key is defined.

  sql> with table_1 as
    2    (         select 15472     as paid, 'S15-875' as "NUMBER", 'blabla1' as description from dual
    3    union all select 18515     as paid, 'S15-875' as "NUMBER", 'blabla1' as description from dual
    4    union all select 215526.52 as paid, 'D17-517' as "NUMBER", 'blabla2' as description from dual
    5    )
    6  , table_2 as
    7    (         select 185525    as invoice, 'S15-875' as "NUMBER", 'blabla1' as description from dual
    8    union all select 158520    as invoice, 'D17-517' as "NUMBER", 'blabla2' as description from dual
    9    union all select 8964      as invoice, 'D17-517' as "NUMBER", 'blabla2' as description from dual
   10    )
   11  select t1."NUMBER"     as "NUMBER"
   12  ,      t1.description  as description
   13  ,      ( select sum(t2.invoice) from table_2 t2 where t2."NUMBER" = t1."NUMBER" ) as invoice
   14  ,      sum(t1.paid)    as paid
   15  from   table_1 t1
   16  group by t1."NUMBER"
   17  ,        t1.description
   18  /
  
  NUMBER  DESCRIP    INVOICE       PAID
  ------- ------- ---------- ----------
  D17-517 blabla2     167484  215526.52
  S15-875 blabla1     185525      33987
  

  BTW: 'NUMBER' is a horrible name for a column. I strongly recommend to change something that is not a reserved word.

• update of a primary key column

  Hello

  I have a problem I want to expose you for your opinion.

  In a table of the source, I have a primary key consisting of four columns (let's call them A, B, C and D).

  Columns D must be updated with a different value (a Mappin with another table)

  My ODI interface, I set the update keys a, B, C, but of course, it does not work because there is violation of the primary key

  I thought, the first value of D in a new column (D_OLD) and use as a 4th update key.

  What do you think?

  Please suggest me the right way to do it

  Thank you for your return

  Hello

  Maybe I did not understand your problem correctly, but you say that you want to update the value of col D what happens to the part b of your primary key. You cannot update the row using columns A, B and C, because they are not unique. Am I wrong? If this is the case, then how will you identify which line you want to update the value of col D for. Tell if you have 2 lines with the same value for columns A, B and C, and a different value of D so how do you know which line you want to update? If you have the answer to this question, then you should be able to update as well.

  Thank you

  Ajay

• Add new ID/Primary Key column with custom ID generation

  I use Hibernate as ORM to interact with Oracle.

  This issue is no longer on the side of SQL to emulate the generator ID seqHiLo

  that we use to generate the primary key for tables, the column ID i.e.

  Now I want to add a new column to the ID of an already created table, and this table has data.

  I have a procedure to add the ID column in a table:

  For example:

  ALTER table TableName add (columnName NUMBER);

  Then create the sequence

  CREATE SEQUENCE SEQ_ID

  START WITH 1

  INCREMENT BY 1

  MAXVALUE 99999999

  MINVALUE 1

  NOCYCLE;

  and after that he use the UPDATE statement to insert some values into the column like this

  UPDATE tableName SET columnName is seq_test_id. NEXTVAL

  Here I intend to use hibernate_sequence, to be in harmony with the hibernation of generation mode the ID's

  The question is:

  UPDATE tableName SET columnName = hibernate_sequence. NEXTVAL, generates the ID in the order.

  However, I need identifiers according to the algorithm of seqHiLo.

  Is there a way to do this in pure SQL?

  In short, can we have a personalized way to generate IDS to use in the new column, rather than a sequential,

  as stated above?

  If you update every row of a session, it won't make any difference if you select from a sequence and use this value immediately (as in your example) or if you go through the algorithm of HiLo: be it you will end up with sequentially numbered lines without leaving space. Then after the update block of existing lines, you will need to create the sequence to be used by your Hibernate application with an initial value of your current value divided by the low value.

  If you really want to implement the algorithm of HiLo for the bulk loading, you can of course do so. But it is not necessary: the effect will be the same.

• Update a table with primary key

  Hello

  I have a table called Temp

  CREATE TABLE TEMP
  (
     A   VARCHAR2 (50 CHAR),
     B   VARCHAR2 (50 CHAR),
     C   VARCHAR2 (50 CHAR),
     D   VARCHAR2 (18 CHAR),
     E   DATE,
     F   NUMBER,
     G   VARCHAR2 (18 CHAR),
     H   FLOAT
  );
  

  The primary key is the PRIMARY KEY: (A, B, C, D, E, F, G).

  I HAVE THE TEMPORARY TABLE 48052365 COUNTY,

  HOWEVER I HAVE A REQUIREMENT TO UPDATE WHERE E (COLUMN) IS WEDNESDAY, THE SAME DAY IN MONDAY (I.E., C - 2 TO EXISTING DATE)

  Approach;

  I CREATED the TABLE TEMP_WED_TO_MONDAY AND SELECTED ALL THE RECORDINGS ELIGIBLE IN CE AND TABLE AND INDEX UNIQUE CREATED on this SUBJECT. TO UPDATE, I WROTE UNDER ANONYMOUS BLOCK.

  Number of Tables: TEMP_WED_TO_MONDAY is 46,921,912 and count of total of the table is 48052365

  Anonymous block:

  DECLARE
     CURSOR UPDATE_TEMP_DATE
     IS
        SELECT A,
               B,
               C,
               D,
               E,
               F,
               G,
               E - 2 NEW_E
          FROM TEMP_WED_TO_MOONDAY;
  
  
     TYPE UPDATE_TEMP_DATE_REC IS RECORD
     (
        A       VARCHAR2 (50 CHAR),
        B       VARCHAR2 (50 CHAR),
        C       VARCHAR2 (50 CHAR),
        D       VARCHAR2 (18 CHAR),
        E       DATE,
        F       NUMBER,
        G       VARCHAR2 (50 CHAR),
        NEW_E   DATE
     );
  
  
     TYPE UPDATE_TEMP_DATE_TBL_TYPE IS TABLE OF UPDATE_TEMP_DATE_REC;
  
  
     UPDATE_TEMP_DATE_TBL   UPDATE_TEMP_DATE_TBL_TYPE;
  BEGIN
     OPEN UPDATE_TEMP_DATE;
  
  
     LOOP
        FETCH UPDATE_TEMP_DATE
           BULK COLLECT INTO UPDATE_TEMP_DATE_TBL
           LIMIT 1000000;
  
  
        EXIT WHEN UPDATE_TEMP_DATE_TBL.COUNT = 0;
  
  
        FORALL I IN UPDATE_TEMP_DATE_TBL.FIRST .. UPDATE_TEMP_DATE_TBL.LAST
           UPDATE TEMP
              SET E = UPDATE_TEMP_DATE_TBL (I).NEW_E
            WHERE     A = UPDATE_TEMP_DATE_TBL (I).A
                  AND B = UPDATE_TEMP_DATE_TBL (I).B
                  AND C = UPDATE_TEMP_DATE_TBL (I).C
                  AND D = UPDATE_TEMP_DATE_TBL (I).D
                  AND E = UPDATE_TEMP_DATE_TBL (I).E
                  AND F = UPDATE_TEMP_DATE_TBL (I).F
                  AND G = UPDATE_TEMP_DATE_TBL (I).G;
  
  
        COMMIT;
     END LOOP;
  
  
     CLOSE UPDATE_TEMP_DATE;
  END;
  
  

  But for the past 6 hours, it only updated records 20,00,000(Twenty lakh) only. because this update in the table and is also part of the teaching primary key I think it takes time, but pointers to improve/acceleration of the update

  Explain the plan:

  update statement all_rows (Cost 4)
    3 update hr.temp 
      2   table access by index rowid table hr.temp (Cost 4, Bytes : 64 ,Cardinality 1)
        1    index range scan index hr.temp_wed_to_monday (Cost 3: Cardinality 1)
  

  Thank you guys, I would be grateful if someone provides the solution for the scenario, rather than highlight the design. Please understand someone designed to best with whatever the limits it has during this period. (and this isn't me).

• Great advice table no primary key on the table.

  Dear gurus,

  Version: Oracle 11.2.0.3.0 running on Linux HAVE 6.

  I have a big standard table (400 million lines) which is a data dump, it was created with no primary key Yes crazy but it happens (very rare).  I have a few key columns indexed for the purpose of the motion, but I would like to know what are the options I have different indexing on a table to make it more efficient for running a query against it.

  Looking for simple opinion where further research.  I won't not give an example of the table structure - neither include the details, I'm looking for advice.

  Easy points for everyone.

  Thank you.

  Content

• Potential problems for tables without primary keys and unique keys

  GoldenGate 11.2.1.0.3/Solaris 10
  DB: Oracle for Oracle (Source and target is 11.2.0.3)
  Topology: unidirectional
  
  
  In our one-way configuration GG, little of the tables being replicated is not a primary key or a Unique key.
  
  Last week when we have implemented GG for the test, we received warnings for these table below.
  

  GGSCI > add trandata WMHS_UD.crtn_dtl
  
  2013-01-12 11:34:33  WARNING OGG-00869  No unique key is defined for table 'CRTN_DTL'. All viable columns will be used to represent the key, but may not guarantee uniqueness.  KEYCOLS may be used to define the key.
  
  Logging of supplemental redo data enabled for table WMHS_UD.crtn_dtl.

  Replication seems to work very well for these tables.
  
  Googling, I think that there may be performance degradation when you replicate tables without PK or the United Kingdom.
  
  But are there other potential problems such as data of a certain kind not replicated to the lack of PK/UK?

  It really depends on the data.

  By default, GG is combining all columns as a virtual primary key but don't no conflict control by default. So when you can be sure that the record you insert into the table is unique, then it will work.
  BUT as soon as you insert the same record, which is already inserted, then you will encounter problems.

  Let me show what happens when you use an initial charge because it makes it easier to describe:
  We start at 10:00 the capture for a table. Now, you insert a record at 10:00 in the tables. When you now start an initial charge to 10.02, then check you have inserted in the database to 10.01 will be repeated two times. During the IPL as the initial charge is made to 10.02 and it includes data of 10.01 AND it will be replicated again through the process of capture/replicate.

• How to use a Select list on a second primary key column in a tabular presentation?

  Hello
  
  I created a tabular presentation located on the details page of the user (form), that allows to manage roles for this user.
  
  The shape of table contains 3 elements:
  -> a checkbox
  -> user (PK) column is hidden, and its default value is generated by a function pl/sql (to submit the time), which refers to the element to username.
  -> the role of the column is displayed as a named select list LOV: add you a line, choose a role, submit, etc..
  
  But my ROLES table (not created by me...) contains 2 columns: USER and GRANTED_ROLE.
  The USER is the primary key, but a user can have multiple roles (= one line per role).
  GRANTED_ROLE is the second primary key, so that we can differentiate between one line of another.
  
  At the moment my tabular form has only one primary key (USER), so the GRANTED_ROLE can display as a list select.
  But, for this reason, in my opinion, remove the button do not work: all the lines of the user have the same key, so when I select a few lines to remove these, all lines in the form of tables are deleted.
  
  I don't know how my button Delete could recognize the subkey to remove only selected rows...
  Or maybe I should use a different type of region?
  
  Thanks for your help!
  Fanny

  In the process of ApplyMRD, try to specify the 'secondary key' column in the section "Source: Multi line Update and Delete"to the second column key in tabular form.»

  I have not tested this with your situation, but worth it.