AE 4.2.2 AnyChart, column, only 15 cases
Hello
I would like to generate a SQL 2D histogram.
I found the restriction to 15 columns.
Is it true or my bug?
How can I generate graphics with more columns and 15?
See you soon
Go to the collection of data and find the setting lines max .
It is default to 15, but for most of the graphics you must set higher.
Tags: Database
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You mean like this?
-------------
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{code}
Select
ItemType,
sum (case monthname when "JAN" then Val else 0 end) such as JAN,.
sum (case when monthname 'FEB', then Val 0 otherwise end) by Feb.
sum (case when monthname 'MAR', then Val 0 otherwise end) like MARS,
sum (case monthname when "APR" then Val else 0 end) as APR.
sum (case when monthname 'MAY', then Val else 0 end) either.
sum (case when monthname "JUN", then Val 0 otherwise end) as JUN.
sum (case monthname when "JUL" then Val else 0 end) as JUL,.
sum (case monthname when "AUG" then Val else 0 end) as AUG.
sum (case monthname when "MS" then Val else 0 end) as MS.
sum (case monthname when "OCTS" then Val else 0 end) OCT.
sum (case monthname when "NOV" then Val else 0 end) as NOV.
sum (case monthname when 'DEC' then Val else 0 end) as DEC
FROM MyTable
Group of itemtype
less
Select
ItemType,
Jan, Feb, mar, Apr, may, June, July, August, Sept, oct, nov, dec
de)
Select
ItemType,
sum (case monthname when "JAN" then Val else 0 end) such as JAN,.
sum (case when monthname 'FEB', then Val 0 otherwise end) by Feb.
sum (case when monthname 'MAR', then Val 0 otherwise end) like MARS,
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sum (case when monthname 'MAY', then Val else 0 end) either.
sum (case when monthname "JUN", then Val 0 otherwise end) as JUN.
sum (case monthname when "JUL" then Val else 0 end) as JUL,.
sum (case monthname when "AUG" then Val else 0 end) as AUG.
sum (case monthname when "MS" then Val else 0 end) as MS.
sum (case monthname when "OCTS" then Val else 0 end) OCT.
sum (case monthname when "NOV" then Val else 0 end) as NOV.
sum (case monthname when 'DEC' then Val else 0 end) as DEC
FROM MyTable
Group of itemtype
)
where (oct = 0 & nov = 0 and dec = 0 and jan = 0 and 0 = Feb and mar = 0
apr = 0 and may = 0 and = 0 jun and Jul = 0 and aug = 0 and Ms = 0
)
order of itemtype
{code}
Change again... OK, I guess that I am answering my own question here, but I think that by using a WITH to write the main request once clause and then selecting * twice using the MINUS operator between where the second query is where (oct = 0, etc.) is what I need. If anyone has better suggestions, please let me know! Here's the logic of nickname for what I come up with to date...
{code}
WITH mainquery as (select all)
Select * from mainquery
less
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{code}
Thanks again!
Mark
Published by: user455268 on March 1, 2012 19:13
Published by: user455268 on March 1, 2012 19:16Hello
You can do it with a HAVING clause:
select itemtype, sum (case monthname when 'JAN' then theval else 0 end) as JAN, sum (case monthname when 'FEB' then theval else 0 end) as FEB, sum (case monthname when 'MAR' then theval else 0 end) as MAR, sum (case monthname when 'APR' then theval else 0 end) as APR, sum (case monthname when 'MAY' then theval else 0 end) as MAY, sum (case monthname when 'JUN' then theval else 0 end) as JUN, sum (case monthname when 'JUL' then theval else 0 end) as JUL, sum (case monthname when 'AUG' then theval else 0 end) as AUG, sum (case monthname when 'SEP' then theval else 0 end) as SEP, sum (case monthname when 'OCT' then theval else 0 end) as OCT, sum (case monthname when 'NOV' then theval else 0 end) as NOV, sum (case monthname when 'DEC' then theval else 0 end) as DEC from mytable group by itemtype HAVING MIN (theval) != 0 OR MAX (theval) != 0 order by itemtype ;
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If the MIN or MAX is not 0, the values are all 0.This assumes that the combination (itemtype, monthname) is unique, because it is in your sample data.
If this is not the case, start with a subquery that GROUPs BY itemtype, monthname, so that when you get to the main request, this combination will be unique.
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