Another REGEXP question: how to extract multiple values from a string

Hi, how can I retrieve multiple values to a string with RegExp with Oracle SQL constructs?

Have looked at the various examples, I cannot understand this.
the following Sql code
select
   regexp_substr(sessie."rollen", 'CN=A_role') "A_role"
   from ( 
select '
CN=A_role,OU=a_org_unit,OU=another_org_unit,DC=bz,DC=ad,DC=min,DC=local
CN=Another_role,OU=some_org_unit,DC=bz,DC=ad,DC=min,DC=local
CN=Users,OU=Dep,DC=bz,DC=ad,DC=min,DC=local
'   "rollen" from dual
) sessie;
Returns CN = A_role.
I want him back all of the CN = concatenated values with a semicolon and stripped of the CN = bit.
So: A_role; Another_role; Users .

Any help would be much appreciated. Here I use database 11g 11.2.0.2.0.

Does anyone have an idea how to do this in SQL?

best regards Mike

Hello
If using Oracle 11 g

with tst
  as (select   'CN=A_role,OU=a_org_unit,OU=another_org_unit,DC=bz,DC=ad,DC=min,DC=local,'
             ||'CN=Another_role,OU=some_org_unit,DC=bz,DC=ad,DC=min,DC=local,'
             ||'CN=Users,OU=Dep,DC=bz,DC=ad,DC=min,DC=local' as rollen
        from dual
      )
select listagg(sub, ',') within group (order by rn) as res
  from (select regexp_substr(rollen, '(CN=)([[:alnum:]_]+)',1,rownum,'i',2) sub, rownum rn
          from tst
       connect by level <=length(rollen)
       )
 where sub is not null       

Tags: Database

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