Application of distribution for the bucket a bound column
HelloI need connect chain for the table data and assign a number of unique to those bucket.
Here is the example (Col1 and Col2 are the table columns and bucket is aquery column):
| Col1 | Col2. Bucket |
| A1 | B1 | 1.
| A1 | B2 | 1.
| A2 | B2 | 1.
| A3 | B3 | 2.
| A4 | B3 | 2.
| A4 | B4 | 2.
| A5 | B2 | 1.
In the above example you can see that there is a string A1-> B2-> A2 and A5, so they have the same number of bucket 1. It is also interesting to note that all lines containing A1 in Col1 will reside in the same compartment, and therefore A1-> B1 is assigned also bucket 1.
Another example is a String->->-> B4 A4 B3 A3 and therefore have bucket number 2.
I tried the hierarchical queries, but wasn't able to get the desired result.
Can anyone suggest an approach or a query?
Thanks in advance.
Rgds,
AKS.
Hi, Aks,
We don't know what you want.
Do you want to assign the bucket such that all rows that have the same value of col1 or col2 the same value receive the same number of bucket?
Maybe you want something like this:
WITH got_relatives AS
(
SELECT col1
, CONNECT_BY_ROOT col2 AS relative
FROM table_x
CONNECT BY NOCYCLE col1 = PRIOR col1
OR col2 = PRIOR col2
)
, got_bucket AS
(
SELECT col1
, DENSE_RANK () OVER ( ORDER BY MIN (relative)
) AS bucket
FROM got_relatives
GROUP BY col1
)
SELECT x.*
, b.bucket
FROM table_x x
JOIN got_bucket b ON x.col1 = b.col1
;
I hope that answers your question.
If not, post CREATE TABLE and INSERT to your sample data and results statements you like from these data (otherwise what you've posted already).
Explain, using specific examples, how you get these results from these data.
Always tell what version of Oracle you are using. This is particularly important with CONNECT BY queries, because each version since Oracle 7 has had major improvements in this area.
You will answer sooner if you always include this information whenever you have a question.
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