As I corrected the error?  ORA-06550-PLS-00357

Similar Questions

• ADR 3.0.1 install ORDS_PUBLIC_USER of error: ORA-06550, PLS-00103

  Try the Advanced installation of new ADR in a clean PDB 12 c (12.1.0.1) installation.

  If someone had the same problem and a work around?

  Error at startup to the line: 48 in command.

  Start

  run immediately "create user ORDS_PUBLIC_USER identified by ' ^ PUB_PWD ' account unlock default tablespace ^ temporary tablespace PUB_DATATBS ^ PUB_TEMPTBS';"

  end;

  Error report-

  ORA-06550: Line 2, column 23:

  PLS-00103: Fand das symbol "create user ORDS_PUBLIC_USER identified by 'mySecretPwd' als eines der following works wurde:

  (- + new case mod not null < an ID >)

  < between double quote delimited identifiers of > < a variable binding >

  continue the current avg County are min max sql stddev prior

  variance of the sum run forall fusion timestamp interval

  Date < a literal string with the specified set of characters >

  < a > < a SQL string between single quotes > hose

  < ein alternativ in Anfuhrungszeichen geset

  force_print

  It seems to be related to the change here:

  https://community.Oracle.com/thread/3731913

  Finally the installation of ADR is running. However still not showing apex, but which appear to be a different problem.

  Here is my solution to overcome the problem of creation of ORDS_PUBLIC_USER.

  The problem was that they changed it to use execute_immediate. However, lexical surrogates have ' included.

  Gives problems when adding to the string of immediate execution. And also problems for the password in quotation marks.

  In the ords.war file to find the ords_create_rest_users.sql and replace the relevant parts marked with blue lines.

  ...

  set PUB_PWD = ^ 1

  set PUB_DATATBS = ' ^ 2'

  set PUB_TEMPTBS = ' ^ 3'

  ALTER session set current_schema = SYS;

  -Remove user REST if exists

  ...

  -Create user ORDS_PUBLIC_USER and unlock the account

  create user ORDS_PUBLIC_USER identified by ' ^ PUB_PWD ' account unlock default tablespace ^ temporary tablespace PUB_DATATBS ^ PUB_TEMPTBS;

  ...

• Get the error ora-06550: line 1, column 28 met the symbol «;»

  The code is:
  
  create or replace procedure while (empid number, varchar2 lname) is
  Meter number;
  fact number;
  Start
  Select max (department_id) in terms of employees where employee_id = empid;
  All counter < = loop 3
  insert into employees (department_id, last_name, employee_id) values ((did+counter), empid, lname);
  counter: = counter + 1;
  end loop;
  end;
  /

  I think I got it. You named the procedure WHILE. And althouh everything IN is not a reserved word, but a key word, I'd stay away from that name. What is your version complete:

  Select * from version of v$.

  SY.

• Oracle 11g {ORA-06550, PLS-00905}

  Hi all
  I am new to Oracle and I am trying to execute the procedure, but I get the error ORA-06550, PLS-00905
  Here is the procedure:
  create or replace PROCEDURE add_job
  (p_jobid IN jobs.empno%TYPE,
  p_jobtitle IN jobs.job%TYPE)
  IS
  BEGIN
  INSERT INTO scott.jobs (empno, job) VALUES (p_jobid, p_jobtitle);
  END add_job;
  /
  I type the following command to run the proc:
  Start
  add_job (6000, "ANALYST");
  end;
  
  Can anyone suggest something to remedy?
  Thanks in advance.
  
  Edited by: 994323 16/03/2013 15:37

  So mark your ANSWER question and provide your Oracle version 4-digit and use.

   tags next time you post.                                                                                                                                                                                                                                    
  

• ORA-06550: PLS-00394: wrong number of values in the list INTO a mesh FETCH

  Dear friends,
  I ask you a suggestion:
  
  The following code inserts a table errors (errori_work), the IDS of the records repeat (in the work of the table), but gives me this error:
  ORA-06550: PLS-00394: wrong number of values in the list of a FETCH statement INTO.
  
  The work of the table has the 78 columns: the problem of the fields used in the slider flew against the 78% ROWTYPE fields?
  I could use a record declared as the cursor (rec_tabwork cu_tabwork % ROWTYPE;), but in the MANUAL I need a field (ID_WORK) is not present in the cursor.
  
  declare
  CURSOR cu_tabwork IS
  SELECT CD_STRUTTURA, CD_SUB_STRUTTURA, NR_PRATICA, likelihood
  Work
  CD_STRUTTURA, CD_SUB_STRUTTURA, NR_PRATICA, applications GROUP
  HAVING COUNT (rowid) > 1
  UNION ALL
  SELECT CD_STRUTTURA, CD_SUB_STRUTTURA, NR_PRATICA, likelihood
  Work
  CD_STRUTTURA, CD_SUB_STRUTTURA, NR_PRATICA, applications GROUP
  After HAVING COUNT (rowid) > 2.
  rec_tabwork work % ROWTYPE;
  BEGIN
  Open cu_tabwork;
  loop
  extract the cu_tabwork in rec_tabwork;
  If FOUND then % cu_tabwork
  dbms_output.put_line (rec_tabwork. (ASL); -test
  INSERT INTO errori_work
  (cd_errore, note, ID_WORK)
  )
  VALUES ("ACC", "Record ripetuto nella table work", rec_tabwork.ID_WORK)
  );
  end if;
  EXIT WHEN cu_tabwork % NOTFOUND;
  end loop;
  close cu_tabwork;
  end;
  
  Can you help me?
  Thank you
  Leo

  Hello

  I loaded your data and ran the query. It's coz the NR_RICETTA contains a null value, so your State A.NR_RICETTA = B.NR_RICETTA will fail when it checks for NULL = NULL. Here is your output from the query

  PRAZY@orcl> select count(ID_AMBS) FROM WORK A
    2  WHERE A.ROWID > ANY (SELECT B.ROWID FROM WORK B
    3  WHERE A.CD_PRESIDIO        =B.CD_PRESIDIO
    4  AND A.GGMM_CONTATTO        =B.GGMM_CONTATTO
    5  AND A.NR_RICETTA   =B.NR_RICETTA
    6  AND A.CD_CONT_PRESCR       =B.CD_CONT_PRESCR
    7  AND A.NR_PROG_INT  =B.NR_PROG_INT
    8  AND A.DESTINAZIONE =B.DESTINAZIONE)
    9  /
  
  COUNT(ID_AMBS)
  --------------
              48
  
  Elapsed: 00:00:00.00
  

  Therefore, I have included NVL to A.NR_RICETTA, which will produce true when it finds null checking 0 = 0 and you will get your result. and this is what you are looking for

  PRAZY@orcl> select count(ID_AMBS) FROM WORK A
    2  WHERE A.ROWID > ANY (SELECT B.ROWID FROM WORK B
    3  WHERE A.CD_PRESIDIO        =B.CD_PRESIDIO
    4  AND A.GGMM_CONTATTO        =B.GGMM_CONTATTO
    5  AND NVL(A.NR_RICETTA,0)    =NVL(B.NR_RICETTA,0)
    6  AND A.CD_CONT_PRESCR       =B.CD_CONT_PRESCR
    7  AND A.NR_PROG_INT  =B.NR_PROG_INT
    8  AND A.DESTINAZIONE =B.DESTINAZIONE)
    9  /
  
  COUNT(ID_AMBS)
  --------------
              61
  
  Elapsed: 00:00:00.01
  

  If you want to insert the duplicate ID in a Table of errors, do an insert with the following select statement.

  INSERT INTO errori_work(cd_errore, note, ID_AMBS)
  SELECT 'CAC', 'Record ripetuto nella tabella Work',ID_AMBS FROM WORK A
  WHERE A.ROWID > ANY (SELECT B.ROWID FROM WORK B
  WHERE A.CD_PRESIDIO     =B.CD_PRESIDIO
  AND A.GGMM_CONTATTO     =B.GGMM_CONTATTO
  AND NVL(A.NR_RICETTA,0)     =NVL(B.NR_RICETTA,0)
  AND A.CD_CONT_PRESCR     =B.CD_CONT_PRESCR
  AND A.NR_PROG_INT     =B.NR_PROG_INT
  AND A.DESTINAZIONE     =B.DESTINAZIONE);
  

  Hope that solves your problem.

  See you soon!

• ORA-06550 PLS-00382: expression is of the wrong type

  Please help me with the following script:
  
  declare
  cursor c1 is
  Select prod_country_id
  of prod_country
  where eccnum = "NOCLASS-SG" and ccode = 'SG ';
  New_data_type TYPE IS TABLE C1% ROWTYPE;
  new_data_tab new_data_type;
  Start
  Open c1;
  loop
  collect fetch c1 into bulk
  in new_data_tab limit 500000;
  OUTPUT WHEN c1% NOTFOUND;
  ForAll i in 1... new_data_tab. Count
  Update prod_country
  Set eccnum = "NOCLASS".
  where prod_country_id = new_data_tab (i);
  end loop;
  Close c1;
  commit;
  end;
  
  Gives following error:
  
  ORA-06550: line 17, column 32:
  PLS-00382: expression is of the wrong type
  
  
  Please help immediately.
  Need to update block.
  
  Thanks in advance

  user13759851 wrote:
  Just change my query and now its execution without the previous error:

  So what? It is always wrong.

  The correct way using just SQL to perform the update - which is the most effective and scalable way. And much faster.

  As for your code? Everything is fake.

  You read the update lines. Without locking of these lines. And these same lines are changed in the code. This is false.

  Then you agree inside the loop. This is false.

  You now get a cursor (where the lines are not locked) and changes of committng to these same lines. It is a violation of the standard ANSI SQL - get everywhere is committed. You consume more resources Oracle doing this. If this process crashes - and there is an excellent chance that Oracle will not provide a coherent reading/snapshot while the data are changed and committed - you what? A process that has changed some data and no other data. We ask that the corruption of data. A total lack of data integrity.

  You set the limit to a ridiculous 500000. This is false.

  It's not faster than with a 1000 limit. But she will consume 500 times more memory. And not just any memory. The more expensive server memory that a process of PL/SQL can consume - PGA.

  You have provided a perfect example of How not to Code for Oracle+.

  Now trash. You never forget retry such an erroneous approach. Use a single SQL UPDATE statement. And then a COMMIT.

• ORA-06550-PLS-00302 error on execution mapping

  I have a mapping in OWB 11.2.0.3, I can bend and validate.
  But if I like him to run it it fails with the following error:
  ORA-06550: line 1, column 1487: PLS-00302: component 'MAPPING_NAME' must be declared ORA-06550: line 1, column 1470: PL/SQL: statement ignored
  
  I've already found a post that said: grant run owner_name. "' name map ' to user_name;
  In my case it does solve the problem.
  
  Someone at - it an idea of what the problem might be?
  
  
  Thanks for any help,
  
  Benjamin

  We have the same problem on OWB 11.2.0.3 and resolved to rename a schema name, because it was the same thing to another database object. If this is your case, you can change the name of the database schema and the location on OWB.
  We hope this help you.

  To view the possible duplicate objects (drawing object):

  SELECT *.
  FROM DBA_OBJECTS
  WHERE OBJECT_NAME = '';

  On the Oracle document is much better explained:

  [http://docs.oracle.com/cd/E11882_01/relnotes.112/e24470/toc.htm]

  Oracle® Warehouse Builder Release Notes
  * 11g Release 2 (11.2) part number E24470-05 *.

  [...]

  7.14 existence of an object in the schema with the same name as the schema target in the database
  12776878: If an object exists in the schema with the same name as the schema target in the database, an error is displayed.

  For example:

  Named A schema has an object called q. schema named Q exists and has an object called Z.
  When you call from SchemaQ.ObjectZ to a scheme A, it looks in schema A Q.Z. Z is not found and displays the following error:

  ORA-06550:... : PLS-00302: component 'XYZ' must be declared
  Workaround: rename one of the objects Q to R or one letter other than Q.

  [...]

• Execution of procedure error: ORA-06550 and PLS-00103

  Hi, I created the stored procedure as,
  
  

  CREATE OR REPLACE PACKAGE BODY APPS.TMP_IMPORT_ITEMS_PKG AS
  
  
    PROCEDURE LOAD_INTERFACE_TABLE(organization_code IN VARCHAR2, errbuf OUT VARCHAR2, retcode OUT NUMBER) IS
  
  
    org_code varchar2(3);
  
  
    BEGIN
  
  
      org_code:= organization_code;
  
  
      DBMS_OUTPUT.PUT_LINE('Organization Code is...' || org_code);
  
  
    END LOAD_TABLE;
  
  
  END TMP_IMPORT_ITEMS_PKG;

  And here is the code I am trying to run:
  

  DECLARE
  
  
    V_ERRBUF VARCHAR2(1000);
  
  
    V_RETCODE NUMBER;
  
  
  BEGIN
  
  
    EXEC TMP_IMPORT_ITEMS_PKG.LOAD_INTERFACE_TABLE('x1', V_ERRBUF, V_RETCODE);
  
  
  END;

  When I run the above code, I get the following error:
  
  
  ORA-06550: line 5, column 10:
  PLS-00103: encountered the symbol "TMP_IMPORT_ITEMS_PKG" during the expected in the following way:
  
  
  := . ( @ % ;
  The symbol ': = ' was replaced by 'TMP_IMPORT_ITEMS_PKG' continue.
  
  Can any body tell me what is the problem with the above code
  Thanks in advance,
  Kumar K
  
  Published by: user2054206 on December 17, 2008 21:09
  
  Published by: user2054206 on December 17, 2008 21:27

  Hello

  In PL/SQL, you cannot call the procedure like exec... in sql, you can call exec but in PL/SQL, you can call as follows.

  DECLARE
  V_ERRBUF VARCHAR2 (1000);
  NUMBER OF V_RETCODE;
  BEGIN
  TMP_IMPORT_ITEMS_PKG. LOAD_INTERFACE_TABLE ('x 1', V_ERRBUF, V_RETCODE);
  END;

  I hope this works.

• "VI a error 1002288.The full version of LabVIEW Development is necessary to correct the errors."

  Hello

  I had created an executable in LabVIEW 8.6 on a PC windows XP 32-bit. The application uses some screws of Vision. The executable is running in most of the PC except one. the PC is a windows 7 64 bit. I first got the error "Labview support 3 error code: could not load front". "" I fixed this by changing the settings of the source file in the application builder. Now I get the error message "VI a error 1002288.The full version of LabVIEW Development is necessary to correct the errors"and the exe displays a run button broken.»

  But if I build the exe in the same PC I get no error and it works very well. Moreover, I tested this exe in another PC with the same configuration, it works. I tried to reinstall labview in the PC, the problem persists.

  Hi Nitrox,

  There is no official adapter for LabVIEW 8.6 in Windows 7. See link below.

  www.ni.com/LabVIEW/OS-support/

  Upgrade to SP1 LV2009 should solve your problem. We had this problem with another client and update SP1 LV2009 solved his problem and should solve your problem too. If you have a problem after the update let me know.

  Kind regards

  Christophe P

  Technical sales engineer

  National Instruments

• The version of LabVIEW full development is necessary to correct the errors

  I gradually developed a large application of GOOP, he has been developing since 2012.  We have never had problems with the executable files before, but now when we're creating a generation, when you run the executable file, the arrow of execution is broken and you get the message "the LabVIEW full development version is necessary to correct the errors.  The search of the forums there are many people who have experienced the same error message but many different solutions.

  The same phenomenon occurs on any PC, I can create the version on another PC, same result.

  I can go back through SVN revsions until I found the latest copy of the project that will actually build, but then I needed to repeat all the coding done since.  Is that what I can do to track down the problem?  I suspect, it could be related to types incompatible cluster or a bad link to a sub VI, but the demand is so great, that it is impossible to look through all the code.

  Brian

  
  

• How can I correct the error that my XML page cannot be displayed?

  When I run the Microsoft Fix it Center each item comes up with the same answer that I can't watch my XML input using XSL style sheet and to correct the error. How can I fix the error?

  Hello

  ·         Who solve this are you referring to and why do you run the hotfix on the system?

  ·         Outside this Web site you are able to view websites without any problems?

  ·         What browser are you using and what version?

  The error means that web browser is unable to display information from a database file (XML) using the rules defined for the display of information (XSL). Rules XSL on the site you access may be unavailable, corrupted, or currently modified and made available later.

  If it is not then your site, I suggest to try after a while and check if you are able to view the Web site. If this is your site then, I suggest you check the code you have created and then try to view the Web site.

  If you use internet explore, then I suggest you to reset Internet explorer and see if the problem is resolved. Follow the steps mentioned in the article below.

  How to reset Internet Explorer settings

  http://support.Microsoft.com/kb/923737

  I suggest you return the item mentioned below.

  Error message "Cannot display the Page XML" when you open an XML file as an attachment in an e-mail message

  http://support.Microsoft.com/kb/303487

• What deletion XMLSchema received the error ORA-04022 no waiting asked, but had to wait to lock the dictionary objects

  I recorded a XMLschem in the Oracle XDB repository to load the XML file into the oracle tables using storage relational object. In this process, I'm trying to remove the xmlschema to sign up again with a few changes in the XSD file, but I'm not able to remove it and I get the error ORA 04022 no waiting asked, but had to wait to lock the dictionary objects... Before that, I deleted the xmlschem 2 - 3 times and it worked fine. But now I have this error.

  I tried to remove it with "DELETE_CASCADE" and also tried "DELETE_CASCADE_FORCE" and in both cases, I get the same error.

  I've waited 2-3 days and then retried still had the same error.

  Could you please help me to solve this problem.

  Here is the screenshot of the error

  

  I also tried to purge the schema, as shown below, but I get the error access denied. I'm stuck here, could not move before working on it.

  Select * from dba_xml_schemas, where qual_schema_url like '% HPO484% '; -1B01B74F95BE1C91E0540021287E70DC

  BEGIN

  DBMS_XMLSCHEMA. PURGESCHEMA (schema_id = > '1B01B74F95BE1C91E0540021287E70DC');

  END;

  It throws below error

  ORA-31050: access denied

  ORA-06512: at "XDB". DBMS_XMLSCHEMA", line 109

  ORA-06512: at line 1

  Could you please help me with this.

  Thank you

  Reva

  Is it possible to reproduce the problem?

  You have a table that references the schema?

  Check with your DBA if there is no locking assets library.

• has received the error ORA-44416: invalid ACL, while trying to enable network services

  Hi guys I got the ERROR ORA-44416 after the activation of services network in 11 GR 2 to send emails, so I ran this command found just as shown below in the Oracle document library

  SELECT THE ACL, PRINCIPAL

  OF NACL, XDS_ACE ACE DBA_NETWORK_ACLS

  WHERE HOST = ' *' AND LOWER_PORT IS NULL AND UPPER_PORT IS NULL AND

  NACL. ACLID = ACE. ACLID AND

  ARE NOT (SELECT NULL FROM ALL_USERS WHERE USERNAME = MAIN);

  That returned a result of

  no selected line

  What could this mean

  The installation is done on a localhost and the APEX version is 4.2.2 browser is mozilla fire fox

  ORA-44416 means that the ACL that you tried to create to refer to a valid principle - that is, the user does not exist.

  The SQL code that you included above seems to be looking for associated ACL principles which are more database users. I don't see a direct link between this request and the ORA-44416.

  What was your original script of ACL?

  Also, because it is a question of database rather APEX you might get a better answer on the forums of the database.

• Get the error ora-02021

  I'm trying to truncate a table but oracle throws the error ORA-02021: DDL operations are not allowed on a remote database.
  
  02021, 00000, "DDL operations are not allowed on a remote database"
  * Cause: An attempt was made to use a DDL operation on a remote database.
  For example, "CREATE TABLE tablename@remotedbname... ».
  * Action: To change the remote database structure, you must connect to the
  remote database with the appropriate privileges.
  
  
  I'm pretty sure you have the appropriate privileges.

  You can even call a procedure:
  dbms_utility.exec_ddl_statement@DB_LINK exec ('your stmt');

• How to solve the error ORA-00001 in SQL Insert?

  Hi all, I need your help appreciated.
  
  I do a plsql procedure that inserts a line according to the value of the slider, I have error oracle ORA-00001: unique constraint (constraint_name) violated.
  
  This message may appear if a duplicate entry exists at a different level: in the RDBMS MySQL, I have the syntax IGNORES to solve this error of duplication... and in Oracle?
  
  Thanks for your time and your advice.
  Miguelito

  user6317803 wrote:
  How to solve the error ORA-00001 in SQL Insert?

  ORA-00001 means table a unique/primary key / index and you attempt to insert a row with the key value already exists in the table. I'll assume table has a primary key on COUNTRY_ID. Then modify SQL for:

  SQL = "INSERT INTO COUNTRIES (COUNTRY_ID, COUNTRY_NAME, REGION_ID) SELECT"BZ","BLZ", 3 DOUBLE WHERE DOES NOT EXIST (SELECT 1 FROM COUNTRIES WHERE COUNTRY_ID ="BZ").

  There is a good chance COUNTRY table also has unique key/index on COUNTRY_NAME. If so use:

  SQL = "INSERT INTO COUNTRIES (COUNTRY_ID, COUNTRY_NAME, REGION_ID) SELECT"BZ","BLZ", 3 DOUBLE WHERE DOES NOT EXIST (SELECT 1 FROM COUNTRIES WHERE COUNTRY_ID = 'BZ' OR 'BLZ' = COUNTRY_NAME).

  SY.