Assign a value to a populated table cell [in BULK]

Similar Questions

• Multiple values in a single Table cell

  Hello

  I have a requirement of the customer. I need to show multiple values within a table cell

  Example of

  Location	City	Shop
  North	City A	HS-200, SH-210, SH310
  South	City B	SH - 100, SH341
  East	City C	SH-20

  But my table shows repeating cell as follows.

  Location	City	Shop
  North	City A	SH-200
  North	City A	SH-210
  North	City A	SH310
  South	City B	SH-100
  South	City B	SH341
  East	City C	SH-20

  So I need your help to show repeated STORE name in a single column of the Table.

  Thank you

  Try this

  EVALUATE_AGGR ('LISTAGG (%1, %2) within THE GROUP (ORDER BY DESC %3)', TableName.ColumnName, ',', TableName.ColumnName)

• How to assign values to the nested table and passes as a parameter for the procedure?

  How to assign values to the nested table and passes as a parameter for the procedure?
  
  Here are the object and its type
  
  create or replace type test_object1 as an object
  (
  val1 varchar2 (50).
  val2 varchar2 (50).
  VARCHAR2 (50) val3
  );
  
  
  create or replace type test_type1 is table of the test_object1;
  
  
  create or replace type test_object2 as an object
  (
  val1 varchar2 (50).
  val2 varchar2 (50).
  VARCHAR2 (50) val3
  );
  
  
  create or replace type test_type2 is table of the test_object2;
  
  
  GRANT ALL ON test_object1 to PUBLIC;
  
  
  GRANT ALL ON test_type1 to PUBLIC;
  
  
  GRANT ALL ON test_object2 to PUBLIC;
  
  
  GRANT ALL ON test_type2 to PUBLIC;
  
  Here is the table object type:
  
  create the table test_object_tpe
  (
  sl_num NUMBER,
  Description VARCHAR2 (100),
  main_val1 test_type1,
  main_val2 test_type2
  )
  
  
  NESTED TABLE main_val1 STORE AS tot1
  NESTED TABLE main_val2 STORE AS earlier2;
  
  
  -----------------------------------------------------------------------------------------------------------
  
  Here is the procedure that inserts values into the nested table:
  
  PROCEDURE INSERT_TEST_DATA (sl_num in NUMBER,
  Description in VARCHAR2,
  p_main_val1 IN test_type1,
  p_main_val2 IN test_type2
  )
  IS
  BEGIN
  
  FOR rec in p_main_val1.first... p_main_val1. Last
  LOOP
  
  INSERT INTO xxdl.test_object_tpe
  (
  sl_num,
  Description,
  main_val1,
  main_val2
  )
  VALUES
  (
  sl_num
  description
  test_type1 (test_object1)
  p_main_val1 .val1 (CRE),
  p_main_val1 .val2 (CRE),
  p_main_val1 .val3 (rec)
  )
  )
  test_type2 (test_object2 (p_main_val2 .val1 (CRE),
  p_main_val2 .val2 (CRE),
  p_main_val2 .val3 (rec)
  )
  )
  
  );
  
  END LOOP;
  
  commit;
  
  END INSERT_TEST_DATA;
  
  -------------------------------------------------------------------------------------------
  
  Here are the block anonymoys what values attributed to the object type and pass values in the procedure:
  
  Set serveroutput on;
  
  declare
  
  p_sl_num NUMBER: = 1001;
  p_description VARCHAR2 (50): = 'Test Val1;
  
  inval1 test_type1: = test_type1();
  inval2 test_type2: = test_type2();
  
  Start
  
  
  inval1 (1) .val1: = "testx1";
  inval1 (1) .val2: = "testx2";
  inval1 (1) .val3: = "testx3";
  
  inval2 (1) .val1: = "testy1";
  inval2 (1) .val2: = "testy2";
  inval2 (1) .val3: = "testy3";
  
  CSI_PKG. INSERT_TEST_DATA (sl_num = > p_sl_num,)
  Description = > p_description,
  p_main_val1 = > inval1,
  p_main_val2 = > inval2
  );
  
  end;
  /
  Someone can correct me.
  
  Thank you
  Lavan

  Thanks for posting the DOF and the sample code but whenever you post provide your Oracle version 4-digit (result of SELECT * FROM V$ VERSION).
  >
  How to assign values to the nested table and passes as a parameter for the procedure?
  >
  Well you do almost everything bad that could be hurt.

  Here is the code that works to insert data into your table (the procedure is not even necessary).

  declare
  p_sl_num NUMBER := 1001;
  p_description VARCHAR2(50) := 'Testing Val1';
  inval1 test_type1 := test_type1();
  inval2 test_type2 := test_type2();
  begin
  inval1.extend();
  inval1(1) := test_object1('testx1', 'testx2', 'testx3');
  inval2.extend();
  inval2(1) := test_object2('testy1', 'testy2', 'testy3');
  
  INSERT INTO test_object_tpe
  (
  sl_num,
  description,
  main_val1,
  main_val2
  )
  VALUES
  (p_sl_num, p_description, inval1, inval2);
  commit;
  end;
  /
  

  See example 5-15 making reference to an element of nested Table Chapter 5 using PL/SQL collections and records in the PL/SQL doc
  http://docs.Oracle.com/CD/B28359_01/AppDev.111/b28370/Collections.htm#CJABEBEA

  1. you don't even have the procedure because it is a simple INSERTION in the table you can do directly (see my above code)

  inval1(1).val1 := 'testx1';
  

  Since you have not yet created all the elements, there is no element 1 "inval1". You need EXTEND the collection to add an element

  inval1.extend();
  

  And then, there is an empty element, but "inval1" is a container for objects of type 'test_object1' not for scalars as "val1", "val2", and "val3".
  If you can not do

  inval1(1).val1 := 'testx1';
  

  You must create an instance of 'test_object1 '.

  inval1(1) := test_object1('testx1', 'testx2', 'testx3');
  

  And so on for the other collection

  You don't need the procedure (as my code example shows), but once you fill in the variables correctly it will work.

• the display of ssize_t value in table cell

  Hello

  I want to display a number of type ssize_t in a digital table cell. In the user interface editor, the cell has been set to intptr_t.

  Runs the code in debug64 works fine, in debugging I get the error message:

  FATAL RUN - TIME ERROR: Invalid argument type: found "int", "__int64" expected.

  I have to add: in the user interface editor, I created the table with one row only, I have add as many rows programmatically using InsertTableRows (but the cell types need to be inherited). The error appears when filling out the cell in the last row.

  Ideas?

  
  

• How to disable the change (the value read-only) on an editable Table cell?

  Hi friends
  How to disable the change on an editable on certain conditions Table cell?
  are there example links?
  concerning
  
  Published by: sak on December 22, 2009 11:28

  No, in the apex_item attributes for example

  select
    APEX_ITEM.CHECKBOX(1,empid,nvl(empid,'readonly')) test
  from emp
  

  Shunt

• access to table cells

  Hello

  Could someone please help me understand how to access the cells in a table (to do)?  I have a report with a table full of a channel.  In a column, it shows a list of names (which come from a channel).  I have another string with a list of colors and I want to associate each name in the table with a color of the second round. I tried unsuccessfully to access even a cell using D2TabRow and D2TabCol and the content...

  Any help is appreciated

  Thank you

  Hi Muskeg,

  Edna has sent two times it shows the only way to change the font of the text in individual table cells properties.  You create, save and call a UserCommand, so is not simple.  The main problem you use is that the table in the REPORT object does not generally contain cells.  If you happen to have chosen a column type in the 'list of text', then you can access the contents of individual table cells, but otherwise, your only options are to get and set the values outside the table that the table is referencing - be they channel values or the values of variables or expressions.

  The easiest option is to get/set of string values and assign each column of the table or row to display the channel values.

  Brad Turpin

  Tiara Product Support Engineer

  National Instruments

• table cell shift problem

  Get a weird selection indicator displacement effect in the cells when using tables in LV 2013 (32) on Win 7 (64).   Hesitate to call it a "scroll" because that which has other meanings in the context of the table.

  Click on the letters in the attached VI to see - same effects if the table is in a VI running or not.

  + clicking on 'A' has no effect.  You remove 'A', the cell to move.

  + clicking on one of the cells located below "A" act as above

  + clicking on the header cell 'x' causes a big drift.  Put the other values in the cell has other effects (some travel a lot, some not at all)

  + clicking on the cell of the table "y" causes a big bend on the side.  Put the other values in the cell has other effects (some travel a lot, some not at all)

  + clicking on the "z" table cell is not moving.  You delete 'z', a big bend on the side

  + I noticed the change which occurs when you remove "A" stops at the same place in the landscape as if you

  Comments:

  + Seems to be related to the cells to justify = center.

  + Shifting is always is from right to left.

  + I noticed the change which occurs when you remove "A" stops at the same horizontal location as if you click on 'y '.

  + occurs at least two different machines from different mfg both 2013-32 running on Win7-64.

  In the case where you are still interested, see 5 message in this thread.

• How can I write in a table cell (row, column appear) in a databae?

  How can I write in a table cell (row, column appear) in a database using LabVIEW Database Toolkit? I use Ms Access. Suppose I have three columns in a table, I write 1 row of the 1st column, then 1st rank of the 3rd column. The problem I have is after writing the 1st column of 1st row, the reference goes to the second row, and if I write in the 3rd column, he goes to the 2nd row 3rd column. Any suggestion?

  When you perform a SQL INSERT command, you create a new line. If you want to change an existing line, you must use the UPDATE command (i.e. UPDATE tablename SET column = value WHERE some_column = some_value). The some_column could be the unique ID of each line, date and time, etc.

  I don't know what is the function to use in the Toolbox to execute a SQL command, since I do not use the Toolbox. Also, I don't understand why you don't do a single INSERT. It would be much faster.

• How to fill the value in the nested table by using the object type

  
  Hi gurus

  I created an object type and able to fill the values in it, now I want to create a nested table type of this object and fill it but looks like I'm doing something wrong, see my code below.

  Code example

  CREATE or REPLACE TYPE countries_o
  AS
  OBJECT
  (
  COUNTRY_ID TANK (2 BYTES),
  COUNTRY_NAME VARCHAR2 (40 BYTE),
  REGION_ID NUMBER);
  /

  create or replace type countries_t is table of the countries_o;
  
  /

  CREATE OR REPLACE

  ABC of the PROCEDURE

  IS

  v_print countries_t; -: = arr_countries_t('01','Aus',1);

  BEGIN

  v_print: = countries_t('01','A',11);

  DBMS_OUTPUT. Put_line (v_print. COUNTRY_ID | v_print. COUNTRY_NAME | v_print. REGION_ID);

  END;

  /

  Error

  • Error (6.3): PL/SQL: statement ignored
    
  • Error (6,12): PLS-00306: wrong number or types of arguments in the call to 'COUNTRIES_T '.
    
  • Error (7.3): PL/SQL: statement ignored
    
  • Error (7.32): PLS-00302: component 'COUNTRY_ID' must be declared

  Thanks in advance

  Concerning

  Muzz

  Hi user,

  Here is another method that you can try-

  CREATE OR REPLACE

  ABC of the PROCEDURE

  IS

  v_print countries_t: = countries_t (countries_o('01','A',11));

  BEGIN

  DBMS_OUTPUT. Put_line (v_print (1).) COUNTRY_ID | v_print (1). COUNTRY_NAME | v_print (1). REGION_ID); -you're accessinf the first element of the nested table, which in turn points to the object.

  END;

  In the sections of the declaration you have assigned values to the nested table.

  Kind regards
  Maxou

• How to assign the value to the application-level element

  Hello

  I'm learning to APEX.  I use version 4.2.6.

  My question is, I set a text field called 'FINANCIAL_YEAR' in the login page.  I wanted to know how to assign this value to a text element of Application level (on page sent), so that I can get this value through at my request.

  Thank you

  -Anand

  anand_gp wrote:

  Yes, I created a 'text area' under 'HTML' in the 'Home' page  Who accepts the exercise of a table through LOV.  I intend to assign this value to a global variable so that this variable can be read in any of the application to filter the result set from different tables (not yet built the rest of the application).  To do this, I was intending to use "Shared components"-> "Elements of Application".  I'm still not quite sure how it works.

  Start by reading the documentation on elements of application.

  Go to the shared components > Application parts and create your G_FINANCIAL_YEAR item. Value Session State Protection Restricted - can not be set the browser so that the value is not editable by the user, falsification of URLS or scripts.

  On the home page, if there is not already a button to submit the value of the fiscal year, add one in the HTML area, with the Action as a submit Pageclick. Otherwise, you can do without the button and using submit Page in Page Action when the changed value select the parameter in the list so he can undergo.

  Then, in the section of the Page processing, create a calculation:

  Point Type: Application-level element

  Calculate Item: Application: G_FINANCIAL_YEAR

  Point calculation: After submit

  Type of calculation: Value of the element

  Calculation:

  Run the application, select a value in the list of the fiscal year and submit the page. Review of current session state in the viewer of session state by clicking on the link of Session in the toolbar developer. Select the Elements of Application in the view list, and then click set. The element of your application and its current value must be visible. You can now reference value throughout your application by using the appropriate syntax.

  You should also consider if a default value (for example the current year) using a calculation Application from the point of calculation on the new Instance and coordinate the application point and part of the homepage using point application as the Source of value or an expression with Source page element, the value always, replacement of value that exists in the session state.

• With the help of several styles of paragraph in a table cell

  Hello

  I'm stuck using several styles of paragraph within a cell. I guess the solution is that I need to start a new paragraph, but so far I have not found a way to do it. When I directly in InDesign, it works fine, but I can not start a new paragraph when you use the script.

  Here's a solution I've tried:

  with {(table)

  .properties de.insertionPoints.item-(1) lines [0] .cells [0] = {}

  content: '1 ' Format string,

  appliedParagraphStyle: styleFormat1

  };

  .properties de.insertionPoints.item-(1) lines [0] .cells [0] = {}

  content: "\rString in size 2',

  appliedParagraphStyle: styleFormat2

  };

  }

  But until now I did not get a new paragraph. When you look at the IDMLs, you can see that InDesign adds a new paragraph inside the cell, while my code remains in the same paragraph.

  Here the IDML result when I do in InDesign:

  "< cell auto ="ue0ie4i0"Name =" "0:0" RowSpan = "1" ColumnSpan = "1" AppliedCellStyle = "CellStyle / $ID / [no]" AppliedCellStylePriority = "0" >

  < ParagraphStyleRange AppliedParagraphStyle = "ParagraphStyle/Format1" >

  < CharacterStyleRange AppliedCharacterStyle = "CharacterStyle / $ID / [no style character]" >

  < content > string to Format 1 < / content >

  < Br / >

  < / CharacterStyleRange >

  < / ParagraphStyleRange >

  < ParagraphStyleRange AppliedParagraphStyle = "ParagraphStyle/Format2" >

  < CharacterStyleRange AppliedCharacterStyle = "CharacterStyle / $ID / [no style character]" >

  < content > string to Format 2 < / content >

  < / CharacterStyleRange >

  < / ParagraphStyleRange >

  < / cell >

  And here is that when I use the script:

  "< cell auto ="ue0ie4i0"Name =" "0:0" RowSpan = "1" ColumnSpan = "1" AppliedCellStyle = "CellStyle / $ID / [no]" AppliedCellStylePriority = "0" >

  < ParagraphStyleRange AppliedParagraphStyle = "ParagraphStyle/Format2" >

  < CharacterStyleRange AppliedCharacterStyle = "CharacterStyle / $ID / [no style character]" >

  < content > string to Format 1 < / content >

  < Br / >

  < content > string to Format 2 < / content >

  < / CharacterStyleRange >

  < / ParagraphStyleRange >

  < / cell >

  It is therefore quite clear my script is not adding a new paragraph. Any ideas how to get a new paragraph so I can use more than one paragraph style?

  I don't have test nore debug your code, but I suggest you another method to apply the content and style of two paragraphs. Do not use a with statement.

  What is your version of InDesign?

  Example:

  // Add new document:
  var doc = app.documents.add();
  // Add two paragraph styles:
  var paraStyle1 = doc.paragraphStyles.add({name : "ParaStyle-1" , pointSize : 20});
  var paraStyle2 = doc.paragraphStyles.add({name : "ParaStyle-2" , pointSize : 15});
  
  // Add a new text frame (default is on page 1):
  var newTextFrame = doc.textFrames.add();
  newTextFrame.geometricBounds = [0,0,"150mm","150mm"];
  
  // Add a table to this text frame:
  var table = newTextFrame.tables.add
  (
      {
          bodyRowCount : 4 ,
          columnCount : 3 ,
          width : "150mm"
      }
  
  );
  
  // Assign the contents as array:
  // The fisrt and only entry in this array will give the first cell its contents:
  table.contents =
  [
      "Paragraph 1"+"\r"+"Paragraph 2"
  ]
  
  // Assign the formatting of the two paragraphs:
  table.cells[0].paragraphs[0].appliedParagraphStyle = paraStyle1;
  table.cells[0].paragraphs[1].appliedParagraphStyle = paraStyle2;
  

  Strategic outcome with InDesign CS6 Mac OS x 10.6.8 v8.1.0:

  

  Hope, that helps.
  Uwe

• Assign a value of zero for no. selected lines

  Try to find a way to assign a value to null if my account has no line.
  
  What I have right now is:

  CREATE OR REPLACE FUNCTION count_deductions (empno IN emp.empno%TYPE)
  RETURN NUMBER
  IS
    ded_count      NUMBER(2);
  BEGIN
    SELECT count(deduction_amount)
    INTO   ded_count
    FROM   emp_deductions
    WHERE  fk_empno = empno;
  EXCEPTION 
    WHEN NO_DATA_FOUND THEN
      ded_count :=0;
    RETURN ded_count;
  END;
  /

  Have tried different ways but I still get the message:
  SQL > select * from show_deduction_v where empno = 7169;
  
  no selected line
  
  Instead of the zero value by filling in the field.

  Ok. So the problem is that the view returns no rows. It has nothing to do with the service. The function returns 0 if there is no such thing as the EMPNO spent. The problem is that there is no line in the EMP with a 7169 EMPNO. This means that the function is never called.

  Why do you want the view to return a row for an EMPNO that does not exist? Is there a table somewhere in the database where a 7169 EMPNO is? If so, your vision may outer join to that table.

  Justin

• ADF: Assigning the value of column VO to OutputText.

  Hi all
  
  I have a VO who im showing as ADF read Table only. And one column that VO should be included outside of this table, I mean, I don't want to include this column in the table that I want to assign the value of the column to Text output component (Active).
  I want to assign the value of the column to the output text component.
  How can I achieve this.
  I think im clear with my requirement.
  
  Any answer will be really grateful.

  Please read this before posting
  https://forums.Oracle.com/forums/Ann.jspa?annID=56

  am now back to the topic.

  tell as an example.
  Here, I had to employee vo drag and drop as readonly af:table employee.
  in this readonly af:table no need to show their id of employee, but you don't want to show this id used as some text output at the top / bottom of the table.
  I think reason?. as it comes to your condition.

  If am so right, moving later.
  Drag and drop the af: table without employee id. and then drag and drop the employee as af text id: output
  important: employee select id in the user interface that came out text go to partial property inspector trigger are at table.

  You may wonder why I like this mean?
  If you like this then means that move through the records of documents / select in af:table means revalent employee id get you. This way you get the desired results. :)

  Thanks & cordially
  ADF7.

• Assigning selected value of tree to an element node

  Hi guys,.
  
  I want to assign the value of the node in the tree selected to a page element. This can be a text box or label (view only). How can I do? I tried to use the 'Element of Page node selected' property that is available on the attributes of the tree. But I couldn't assign the value without refreshing the entire page.
  You have an idea?
  
  Thank you.

  I'll assume that you have a table in your database with columns (ID, PARENT_ID, VALUE) or something like that.

  OK, first go to your region of the tree and look at the SQL query. You will see that it is link attribute. By default, link attribute is set to redirect you to another or even from one page.
  You need modify this attribute of link with something like this:

  ' javascript:pageItemValue('_||) 'VALUE ' | ')' As link

  So click on the tree node, you ask function javascript and passing as the parameter value.

  Now, you just need to be pageItemValue. Go to Edit Page, header HTML and write this function:

  You can change (P1_ITEM) at what you want.

• Dreamweaver keeps adding an additional line in a table cell

  I'm not sure why this is happening, but for some weird reason, the second column of the first row of a table always has the text starts as if there is a blank line. I checked the code to see if something has been inserted by accident, but there is no break line or anything else between the td tag and text in my table cell. I checked the alignment and vertical alignment of the cell is set to "high".

  In the editor, everything seems normal. But once I go to see live or download the file on the web, the blank line appears in the second cell of the table.

  I think I found the problem. In Design mode in the properties box, a column has the value Format paragraph and the other was set to None. Unifying it on all of them seems to have solved the problem.