automatic release to run a procedure

I created a procedure that I would like to be run automatically after a few updates in another table. I know easier is for the automatic execution of a procedure by creating a job, even if I assume that by creating a trigger even should be possible, correct? Please advise? Thank you!!


CREATE OR REPLACE TRIGGER trigger_run_procedure
AFTER the update on zainet_dev_mig.zn_tec_infra_run
FOR each LINE
BEGIN

IF (: NEW.active = 'Y' and: NEW.) TS_end is not null) THEN

Call run_test_cases)
*;*

END IF;

END;
following error occurs:

13:29:37 ORA-24344: success with compilation error
13:29:37 4/9 PLS-00103: encountered the symbol "RUN_TEST_CASES" when expects it one of the following values:
13:29:37: =. ( @ % ;
13:29:37 the symbol ': = ' was replaced by 'RUN_TEST_CASES' continue.
13:29:37 7/8 PLS-00103: encountered the symbol "end-of-file" when it is waiting for one of the following values:
13:29:37 begin case declare exit end exception for goto if loop mod
13:29:37 lift pragma null return select update while with
13:29:37 < an ID > < a between double quote delimited identifiers of >
13:29:37 < a variable binding > < < close current delete fetch locking insert
13:29:37 point backup restore opened the sql value run commit forall fusion
13:29:37 pipe

Published by: 845498 on August 2, 2011 04:32

Hello

You can run a procedure without APPEAL

CREATE OR REPLACE TRIGGER trigger_run_procedure
AFTER UPDATE ON zainet_dev_mig.zn_tec_infra_run
FOR each ROW
  BEGIN
   IF (:NEW.active = 'Y' and :NEW.TS_end is not null ) THEN
     run_test_cases;
   END IF;
END;

Tags: Database

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